0 like 0 dislike
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 71 views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* ** *** *** * * ** * * *** * **** * ** *
* ** **** * ** * ** ** * ** ** * *** **

    {
* * * ******** **** * * * * **** *** * * ** ****
* ** ***** * ** * * * ***** * * ** * * **
* ** * ** *** * * * ** *** ** * * ** * * * * * *** *** * *** ** *
* ** * ** ** ***** ***** *** ** ** ** **** * **** ** * * ** * ** * * *** * * ** * * * * * = a[n] + b[n];
* * * * ** ** * * * * * * * ** * ****** * *** ***** * if(a[n]+b[n]>='10')
*** *** * ** *** * ** *** *** * ** * * ** ****** *
****** ** * ******** ***** ***** * * ** ** * * *** * * ** ** ** **** ** * ** * ** * ** ** = a[n] + b[n] - '10';
* * *** *** *** ** *** **** * ** * * ***** * ** **** * * * * ** **** **** * *** **** *
**** ***** * * * * ** * ** * * *** * *** ****** ** * * ***
* **** ** * * * * ** * * * *** **** ** *
* * * ** ****** * * * *** * ** if(t == 1)
*** * ** * * *** **** * * * * ** **** * *
* *** * * * * * ** * **** * *** ** **** **** ** ** * ** * * ******** **** ** *** * **
** *** *** ** * ** *** **** * ** * ** * * ** *** *** * ** * ******* * ** ** ** * * = a[n] + b[n] + '1';
* *** * * *** * * * **** *** ** *** * * *** **** * ***** **** * * * * if(a[n]+b[n]>='9')
* *** ** *** **** * * * * *** * ********* ** * ***** * * *
* * * * *** ** ** ** * *** *** ** *** ** ******* * * *** * * * * ** = a[n] + b[n] - '9';
* ** ** *** * ** * * * * * **** *** * ***** * * * * *** * * * * * * * * * * * ** **** * *
** ****** * * ****** * * *** *** ***** * ** * * * * *
** * * ** * **** ** **** ** * *** ** * * * *

    }
* ****** * * * * * * * ** ***

    {
* * ***** *** *** *** * ******** * ** **** ** ** ** * * **** ** * *

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
*** ** *** ** ****
** ** * ** *

int main ()

{

int * **


*** **** ** **** ***** *** *
*** **** *** * * *


**** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * **** * **

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
** ** ** ** * * * * a[100],b[100];
*** * *** * * * ** sum[200];
* * * ** * * ** * * * la,lb,lm,i,j,k;
** * ** ** **** * *** %s",a,b);
** *** * * * * * *** = strlen(a);
* *** ** * * * * = strlen(b);
* ** *** ****** ** *** **** ** *** * ***
* *** **** * ** ** **** ** ***** ** **** ** = a[i];
** ** *** ***** * *** * *** *** * ** * * *** * * * *** ** *
* *** * ** * ** *
* * *** ** ** * ** ** *** ******* **** * *
* * ** * ** ***** * * *** *** * ** * ** * * * *** * += b[i]-48;
** ** * ** * * * * * *** * * ** * * * **** ** ** * * * ***
* * * * ** * * * *
** * ** * **** ** ** = strlen(sum);
* ** * ** *** ** * ****** ** * ** * *
* ** * ***** * * * ** * *** ***** * ***** ********* * * *
**** ** *** ** * *
** ** **** *** *** * * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
****** **** * *** * *
**** * **** * *





int main ()

{
** a , b ;
**** ** * * ** ** , * **
** *** * * ** , * * *
**** * **** ,a+b);
****** * * * *** **** * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
*** * ***** * ** ****** * *** * *
**** * * * * * * ** * * *** ****

    {
** *** * * **** ***** ** ***** ** *** *** *
*** *** ** ** ** * *** * ** ** ** * ** * ** **
** * ** **** ** * * ** * * ** **** * **** * * * * * ** ** * ***
** * * *** ** *** ** ** * ** ** * * ***** ***** * * * **** * * * ** * * ** * * * * * * * * ** * = a[n] + b[n];
* * *** **** * * * ** * * ***** ** * * * ***** ** ** * ** *** ****** *** ** if(a[n]+b[n]>=10)
*** ** * ** *** ** ******** ** *** ** *** * ******* ** *
** * ** * ** * ********* * * **** ** ** * * * * ** * ** * * * **** ** * * ** ******* * = a[n] + b[n] - 10;
***** * *** * * ** ******* * ** * * * ***** ** * ** ** * * ***** * * ******* * ** * * ***** * *
* * **** * ** **** * * * * ********* * * ** *** * *** * *
* ** *** * * * * ** * * **** * * ****** *** * ***
*** * * * * ** ** * ** ** *** * * * if(t == 1)
*** ** ** * * * ** * * *** * * **** * *** *
*** * * * * ** ** * * * ***** *** *** *** ** *** ** * ****
* *** ** *** * * * * ** ** ** ** ** * * * * * * * ** **** * * * * *** ** ** * * * * * ** ** * * * = a[n] + b[n] + 1;
***** ***** ** ** *** * ** **** ** * ***** * * ** if(a[n]+b[n]>=9)
* * * * * * * * * * *** **** *** * *** * ** * * *
** * * ** * * ** ******* **** *** ** **** *** * * * * * * *** ** *** * * = a[n] + b[n] - 9;
***** ** * ******** * **** * * * ** ** ** * * * * **** * * ** * *** ** ** * ** * **** * * **
* ** *** *** ** * * * * *** ** *** * *** * * **** ** * * *** *
* ******** * * ******* * *** * *** *** * **** **

    }
** ** * * * **** ****** ** * **

    {
*** **** * * * * ** * *** * ** * * ** ********** * *** * ** ** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* ** **** * * * * * data[2];
* *** ********** * * ***** sum;
* *** * *** *** * ** i;
* * ***** ****** *** **** *** **
** * * * * ** *
** ** *** * *** * * ** **** * ** * ***** * * * **** * ****** * * * **
* ** * * * * * **** **
**** * * ** * ** *** * * *
*** * * ** *** ** ** * * *** * *
****** * * ***

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** *
* ** * ** ** * *
* ** **** ***** **
* ***** * * * * * * **







int * * **

{


* *** * int **** * ** ** *
** * * * *** **

** * * ** scanf * *** * ********* * **
** ***** **

* while (a[i]!= ' ')

{
* ***** ** **

** * * **** i++;
* ** * * **** **

** * * scanf ****** **** ** * * *

* * **

}


** ** * ** scanf * ******* * * * ****


** * * ***** while ** **** * ** * **
**** * * * *

***** * ** ** {
* * *** ** ** * ****

* ** ******* * * j++;
* *** ** * * ** * *** * * * *

* ** * *** ** ** ** *** scanf *** * ***** * ** *** *** ** * ** *

* * ** * *** *

* *** * * ***** }
* **** ****

}
* *

**** ** * for (i = 0,j = 0;;i++)
**** * * * *

* * ****** return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include *** * * *

int main()

{
** * * ** ** * ** a,b,c;
** ** * *** *** ** * *** * * ** ** **** * * * * **
**** ** * **** = a + b;
* ** * * **** * ** ****** **** * **** * *** *
* * *** *** * ***** ** **
* * ** ***** **** * **
*** * * * ** ** *** ** * * ***
* * ** * **** *** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include ** * ** *

int * *** y=999999999;

int main()

{
* ** * *** *** * **** ** * * *
** * ** * * ** *
* ****** ** ** * * ****** *** ** * * * * * * **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** * *** * * ** *

int main(){
* * * ** * * * * ***** a,b,c=0;
** **** * **** * * * * * * ** ** ** * * ** *
**** ** *** ******* ** *** *** * ** * **
*** ***** **** *** * * **
***** * *** * * ** * * **** *** * * ** **
* **** * ** ** ** * * 0;





}
answered by (-140 points)
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.62.220
©2016-2019

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 128 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: Unlimited - Due to: Unlimited
| 82 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 90 views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 67 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: Unlimited - Due to: Unlimited
| 10 views
8,792 questions
72,361 answers
47,172 comments
2,043 users