Final Exam 2 (20%)

1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.5k views

37 Answers

0 like 0 dislike 
Hidden content!
#include *  ** ****** 
#include *  *****   **
 * ***** *  * *    **  * 
*  ***  * ** *   * * *  

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * *  * **** 

** ** *** *** *  *  ** ****  ** *  **
    * ** * *** *** * *  * * ** *  == b[i]){
*  *    **  * * *  *  ** *  *   *** *   * ********   **
*  ***   *     * * *  * *  

    *   **     * *
if (cnt == n){
 **** *  * *** ********* * *** *** * *    ** *   * *   * * * 1;
   *  ** **  * ** ****  *** * ***      **   *  * ***   ** * 
**   **     ** **  * * * 
** **   * * **   * **  * *** *         *   *   * *** *   * **  * 0;

}

int main()
{
**  **  ** ** * * * * * *** s1[100], s2[100];
*  ***  ***** ********** i,j;

* ** *   *      **** ** ** ** *  ** ******** s1);
  * *  * * * *  *  ** *  * **  ** **** * ** ** s2);
**   *  *  * ** **  * (prefix(s1, s2)){

* *  * ***  * ***  **   *  * *  *  * * **     ***   ***  *  is a prefix of %s", s1,s2);
*    ********** **   **** *    ***  * ***   **
** ***   *   *  *** **   *** ***    *  *****  ** **  
***      * ****  *  ** **   **   * *  *** **    ** *       * *    ** *** *    * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*     *  **    * * **    *  c;
 ********   * *    *   * ** * * a[100],b[100];
* *    **** ****  *    ****  ** *  *    **  %s",a,b);
  *   *** *    *  * *    ** *  *  ****  ****** **
  * * ** *     * **   ** **** *    * *** * * * *  **      * * * 0;
*        ** ****  *   * **  * * %d",strlen(a),strlen(b));
    *  *********  ***  ****    * *    * * **  
*  *    *** *  * *  ** ****       *  * *** *** ** *     *  **       ***** ** ** * ****
 **   *   *******       ** ***  *  ***  **     ** ***** *  *  *****  ***   *  ****   ***** * ** **  ***** * ** ** *  *  is not a prefix of %s",a,b);
  ***         *    ********  ** ** **** * *  * *** *** * *** **     *  *   * *  ******  * *   *     **  **   
*** *  ***  ******  *  ****    *** *  **  *  ***   ** ** *   *  **       * * *** ****
 ******* * ****   * * ** *   ***  **   * * * ** *** ** ***  *   ***  **    *   *     * if(c==strlen(a)-1)
** *  * * ********* *  *** **** * * *** ****  ***** ***    * **  *** * * **  *  * *    * *     * * **   **   *  is a prefix of %s",a,b);
    }
      **  **    ** *   *  * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* **** *   ****  ***  * *  *** n,count;
  *   * * ** *    **  *   **** * **  **  *   ****
  ** ** * *****      * *   *****        *     %s",a,b);
* * *** *** *    ****    *  *  ***

 *  **  ***   ** ** ** * ** *   *  ** ****  **  ***  * 
**    * ** ****  ** *  ** *
*  * *  ***  ** **  * * * **     *   ***  *******  *   ***  ***    *  
*  * ** *** *** * **  ***

* ***  * *     **    *   * * ** **  (strcmp(a,c)==0)
    *  *  *   *   **  * * 
**   *** **  *  * **   ****   *   ** ***  *   *  *** *** *** **** is a prefix of %s",a,b);
*   * **   * **     ***  * * *
 *  * ***  * *   *  * ***
     **     * *   *** ***   * 
 * *** ** * *    ****** *  ****** ** *  *  *     *   *** ** **  * *    ** is not a prefix of %s",a,b);
 * *  * ***  ****    * * **   *
  ** **    ****  * **     ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
   ***     ***  *  *   * ** a[100],b[100];
 * * *      * * * **       * *   * ** * *  *  **
    int l1,l2;
 *    *   *      ** ******* *  *
* **** *  *    ** ***   ** * *  ** ** *
*   *  *  * **  ****  * *** * **   *  *
*  *    * * * * *******  *   **   *** *     ** ******  *** **   *** is not a prefix of %s",a,b);

    }
 *  ***        * *****  * ****** if(l1<=l2){
**  * ** * *  **  *  *      *** *  *  **  *  *  **    * prefix=1;
* **   ** ******  **   *    ***   **   ***********    ** **   i=0;
**      ** *** **** * * **    *  *** *   ********* *** * *  ** **
   *** * * * *   ** *   *    *** **      ******   *** **  * *    * *  * * **** (a[i]!=b[i]){
****  * * *  ***   * *   *** ***    ***     *  **** ***  *  ******** *  ****  * * **** *** *** *     *
 ****  *   * **   *  * ***   *   ** * *    **  *** ** *  ***  * * * ** **  * *    *  * ** ** * * * * * * *
 ****    * ****  ****   ****   *  * *  * ** * * * * ** *** *  *   *  * * **  *    


****   *** **  *   ***    * * *      * * *   **  ** *   
** ***  * *    *     *** *   * *    * * ********* ** * *  *  ***  **** 
** **  * ***** *  *      *    *** *  ** ***  *   *   *   * ** ****   **  *  **** ** ** *  *  is not a prefix of %s",a,b);
*   * ** *  *    ** *** *  * ** * * *   *  ** * 
   ** **  **  *  * **  *** ****  **** *    *   ** **
**   ** * ** * **  *     ***   * *** **** *** **         * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 * *    * **   * ***
int main(void)
{

* * *    **  **  *** *** * * *  pre[100];
* **  *  *****  * **  *** ** word[100];
  *  *  ****     * *  **  *** * %s",pre,word);
   **** * **  *   * **  *  * ***  * ** 
**    *  * *          **  * **   * **  *** 

*** ***  ***** ** *  ***  * * ** i;
 *  ***  * ** * **** * **   *  *    *  **  
****   * *       *  ** *** **
*******  *  *  **  **   ******* **   *     *  * ****   ** *   
****  *  * *    ****** ** *  * **  *           *  *** **
 *   *  *  ** **    * **      *  ** ** **** *  **  ****  * *  *   * ****    * *** * * *  * *   *  **   is not a prefix of %s",pre,word);
  ** *****    *   ** **  *  * **    * * *** *    * * *  **   **     **** **** *   ** *  0;
  ****    * ** ****   * ** *   ** *    *******   *** *

* ***  *  *******  ** ** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * *** *****  ********* ****  * pre [100],a[100];
 *   *   ** ***  *** * *   * n ,i;
 **   *  *   ** *** * *   **** ***  * ** ***
 * **   **     *   *****  ** *** ***
***  *** *** *    * * *** *  ****  **  ***  ****
** * ******* * *** * ** **** 
**  * * *  ** ** * * * *****   ** * * **  *** * * **  *  *  ** (n=0;n<strlen(pre);n++)
*  ** * *   * *      *  *  *  ** **** **** * **    
    * **   * **   *** *  *     ****  * **  **    ** ****    ** **** **   *  (pre[n]==a[n])
 ***  *  ***  *    ** *  ** ***  *** *****  *    * **    **  * * *  ***   **** *  * *** is a prefix of %s",pre,a);
 **  ****   **   * ***  ***** * **  ******   *  *    *    * *********   *   **  
* * *       *    *  ***  ***   * ******   *     ****  *  * * * *   ***** * *    *****   *  *** *    ***     ** *****  *         is not a prefix of %s",pre,a);return 0;
   *  *    * *  * * * ***
* * ** *** ******   ******         * **     * * ***   ** ** **** *  

***  *       *****  * *  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** *** * * *
#include  *  ** * * * ***** 

int main()
{
 ** * **  *    *** **   ** a[100];

*  * ** *  * **** **  * **      b[100];

 ** ** **  *** ** *       *  * *   *   *  %s", a, b);

 **** * * ******* *****  * *  * len_a = strlen(a);

**   *  ** **  * ** *   * * i = 0;

*   *   ****    ** ***  * flag = 1;

**    **         *     * *** ** *  ** = 0; i < len_a; i++)
    *   ***** ** * *   ** **
* ** *      ** **** *  ***     *  ** * **** *  **     **  *   != b[i])
** ****** ** *  * **      *       ********** * ** ** *   
    ** **  ** * **** *   * *   * *** * ** *  *  ***  ** ** ** *** ***    ** * = 0;
 ******  ** *  * * * *  * * ********    * * ***** **   **
  ** * * ***** ** * **   ** ** 

* **    ****  *  ***  **   ****  == 0)
* ***** *  *   * **       * ** ** *
  *   ******     ** * **** *** *    ** ** * ***    *** * is not a prefix of %s", a, b);
 *** *  *  * * * *  * *
 *  **   * * **     * ****  
**  *     *  *     *  **** *
* * * *    *   **  *   **   **** ** ****** * ** ** ***   * * **   ****** ** is a prefix of %s", a, b);
 **** * * **    * **     **
 ****** ****  * * **** ** ** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 *  **  * ** *****  * 
int main()
{
* *** *  *** ** * *** *   *  i,n;
 ******* *** ** ***     ** p[100],s[100],a[100]={};
  ****  **** ************ ****  *** %s",p,s);
*** *  *** * ***  ** * * **   
 * ***   *   **  * * * *** *      **
 *** *   ***** *  ***  ** **  *    *   * *   
   *  *  *      * ** ***   **    **** 
 **** ***    * * ** ******  * * ** * * * *     ** ***  ** * **  *   ** is a prefix of %s",p,s);
*    *** *** **    ** **  *  
  ****    ** * ***** * * * *   * 
  *     * ***   **  **    ** **  *   ** ***  * ** *  ** * **     *  is not a prefix of %s",p,s);
* ** *** ** *   * *** ** * *   * 
  **    *  * ** * **  **    ********** **   * **   ******** 
  **  * ***           ** ***   * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*    * **  *** ***     *  **** ** * *  ***  ****  *  **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*  * ** *** *   *   *   *  * * * ***** * ** *    ********
   * **** ***  ***** ** * ****   * **     **   * *** *** * * ** * **** *** *     *** *** *** **   != b[i])
 ** * **    *   *****  ** * ******  **   * ** **   *  * **     **  ****   * ** *  * ******  * * ** ** *  ***     **   
** * ** * * * **  ** *  * * *   *  * *** **    * ***  * * ***** *  ** * *****  *   ***** ***  ** ** ** ** * * * *   *  * * *    **  *   * * *  is not a prefix of %s",a,b);
* *** *  ** **        *     *    ****  ******   **      ***  ** *****  *  ****  *  **  *  ** *   *       *** * **   **** **  ** ** ********* * 
   *  **       * ******   **  ** ** *   *****    * * *   *****  * *     ****  ***   *** * *   * ** *   *
* *  ******   ** ***    ** **  ****** ** ***  *     ** * *   ****  **    ***   *****   * **    ** ** == b[strlen(a)-1])
  * * *** ** **    * * * *** * ***  **** ***** * * * *****    * *** *** *     * * **   *  *  **      ** * *  **
 ***  **    *  **  **  ** **  *    * **  *****  **  *** ***  **  *** ******* **  *  *   * * * *** *     **  *** *  **** **     *** ***  * *  * * is a prefix of %s",a,b);
* * * ***  *** ** *    **** **   *   ** *  **** *       *    *******  *  * *      *** * *  *    ****** * **** * * *** *      *  ** ** 
 * **** * ** *  ***   ** **  ** *     *  *    *  *  **  *      *** ** * **  *  **  *    ** ** **
**** ***  * ** ** *******  * ***  * ** **   *   * *  ***
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 **       **      *****   * *  *   * * * i;
* ** **   **     *** * **   ** (a[0]!=b[0]){
 ***  ** *  *   *    ***    ** ****  *****    ** * 0;
*    **   **** * * ****   *   ***** **** *
 ****  *  **** ** ***  ** *    * * *** ****    ** *** 
 *  ***   * * ** * *    *      ***   ** * *** ***   * **       ** * *  * a[i]==b[i])
* *    ****   *  *  * * *  *  ** ***  *  * **  ** ***  *
 * **  * * *** * * **     * ***  * **** * * *  *  ** *** ****  *  **      *    *      * **   * 1;
*  ** *******  *** *** **  * * *  *     ** * **    ****** *     **  ****     ** **  
   ** ******   **  * **  *** ****     *  ** **     
***   *    *     * ***  * **   ****
****     *  ** ***** * **** *  *** **     0;

}

int main(){
* * **  *******   **        c[n],d[n],e[n];
***** **** ******** *    ** ***   i;
  **** *  * *** **  *  **  ***   ***   ** %s",c,d);

**    ** * ***** ** *** * *  *  
 *** * *  **  *   * *     ***  ** *** *    * * *** ***   ** *    *  is a prefix of %s",c,d);

* **     *    ***  **** * ** 
*  *  ****  * *  **  * * **  * **  *    **  * *   *  ***** ***   is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.70
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.5k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users