0 like 0 dislike
1.7k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
* * * * ** ** *** ** * %s",&s1,&s2);
*** *** * ** * * * *** ** * ** *

///get space
* * ***** *** * * *** * * * ******* * * **
* * * * ** ****** *** ** ** ** ** *** * **** '){space=i;}
    }

///get s1
* * ** *** * **** * * * * ** ** ';i++){
** * * * **** * *** ** ** * *** ** * ***
    }

** * * *** * * * *** ****** ****
///reverse input
** *** * * * **** * * *** * ****
* *** *** ** * * ** * ** * ***** * ** ** * **
** *** * ** ** ** * * ** * * **** ** ** * ** ********** * * * ****
* *** * ** *** *** * ** * ***** * *** **
    }

///get reversed s2
** ** * * ** * ** ***** * ** ** * ';i++){
*** ****** ** * * ******* * *** * *** * * * *
    }

///reverse s1

**** ** ** * ** * ** ** ** ****
* ** * * ** * ** ** * * ***** **

** * * ** * *** *** * * ** *** * ** *** ** * ** * **
** * * *** * ***** ************ * ** * *** ** *
    }

///sum s1 and s2
**** ****** * * * **** ** *
** * * **** * *** **** * ** ** * **
* ***** *** * ** **** * ** ** ** * * ** * **** * ** * ****
* * ** * ** ** * ** * * * * * * * * * ***** * *** * *
* ** ** * * * * ***** **** * ** * * * * *** ** * **
* * ** * * ** ** * ** * * * * ** * *** * * * **
*********** *** * * *** * ** * ** * * ** * ** * ** *

    }

* ** * * * ** * * **** rev:%s\n",input);
*** **** * ***** * ** *** *** rev:%s\n",s1);
** ***** * ** ******* ******* ** *** * ** ** rev:%s\n",s2);
* ** ** **** * * * ** * ** * ** ** * * * ** * * * * * * **

///reverse output
* * * **** * * * * * *** *** * * ****
* * ** ** **** **** ** * * * ** **** *** * ***** * **

* * ** * * ** ** ** * *** * ** *** *** * * *****
* * ***** ** ** * *** * * ** ** ** * ** * * ** * * *
    }

///print
* * ***** **** * * ** * * * ** *** * ****
* * * *** * *** * * ** ** * ***** * * *** **** * *** * ** * *** *
* ** * * * ** * ** * * **** * * * * ** * *** * * * * * **** * * * ** ******
* *** *** ** ** * * * * * * *** ** **** ** * * *** * * * * * * * *** * * * * * * * *** * * * * *
** ** *** ****** * * * ** * * * *** * ** * **** * * * * * * *** *** * **** ** * * *** ** * **
**** *** ** ** * ***** ** * * ** * ** * * *** * * ***

** * * ** * * * *** ** ** *** ** ** * * *** ** *

    }
*** * *** * ****** * ** ** * * * ** **
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ***** ** * ** * * ** * * string1[50];
* * **** * ***** * ** string2[50];

* ** * ** *** * ** * * ***** * string1);
* * * * ** * *** * * * * * ** string2);
* * ** *** * ** * ** * * ** arr[51]={0},i;

**** * * * * * *** * * **** i<strlen(string1); i++)
***** ** * * * * *
*** * ** ***** * ** * * * ** **** * ** ** += string1[strlen(string1) - 1 - i] - 48;
    }

** ** * **** ** * *** * ** i<strlen(string2); i++)
******* * * * ******* ***
* *** *** ******** ** * ***** * **** ** *** += string2[strlen(string2) - 1 - i] - 48;
* * *** *** ****

* * * * * ** **** * * * i<50; i++)
* *** ** **** ** *
* *** **** * *** * **** **** * *** ** ****** > 9)
* ** ** *** **** ** *** ** **** *** **** * *
* ****** *** * * ******* ***** ** *** ** * * ****** ** ** * -= 10;
** ** * *** *** ** ** ** * * ** * * * * * * ** ** * * ** * * *** * ** *
* * ** * *** ***** ** ** **** ** *** ** ** *
* ** * *** **** *** *

*** * * *** * * * i>=0; i--)
* * ** * **** ****
**** * *** * * * * *** ** * ** *** ** * != 0)
*** * * *** ** **** ** ***** * **** * * *** * **** * ***** ** ***
** * ** *** ** *** ** *

* * *** ** * *** * *** ****** i--)
* *** ***** ** *** ** ** * * * * * * * * ** * ** * * * ** * ** arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
* * ***** * * * ** *** * *
printf("enter input 2: ");
* * ** **** * * ** * **
for(l1=s1[l1]!='\0')
*** * ** ** **** * **
for(l2=s2[l2]!='\0')
* * * * * * * ***
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
* * * * ** ** ** *
{
* * * * * * **** ********* *** **
* ****** * * *** * *
* ** *** ** * ** **** *** **** * * * ** ** * *
* ** *** * *** *** * * * * ***** ** *** * * *** ** * ** ** * ** * ******
* * ** ** * ****** ******* * * * ********* ***** ****** * **** **** * * ***
*** ** ** * ** * ** if (j>=0)
* * ** * *** ** ** ** * *** ** * * ** * *** ***
* ** ** * * **** * * ** * * * * * *** ** * ** * ** ******* **** * * * *** * *
** ** *** * ** ** * * *** * * ** ** ****** ****** * ** ************ * * **** * * *
** * ** * ** ******** *** ** * **** ***** * *** if(carr>0)
** *** * * ***** * * ***** * **** ** * ***
* ** * *** ** * **** ***** ***** * ** ** ** * ");
** * *** ** * * * * * *** * **** ** ** **** *
}
for(k--;k>=0;k--)
* **** ** * * * ** *
** ** *** * * * ** **** * ** ***
*** * *** ** ** **
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
* ** **** **** * * a[50],b[50];
* * * ** ** * * * * ** c[51]={0};
********* * * * * *** i;
*** * * * * * ** ** * * x=0;

* *** ** * ** ** ** ** ** * %s",a,b);

* * ** * ** * * ** ** ** * *** ***
    {
** * * * * * * ** * ** * * * * *** * ***** *** ** *** *
    }

* * ** *** ** * * * *** ** **** ** ***
* * * ** * * * * * * *
**** *** ** * * * * * * * ** *** * * * ** **** * *** **** ** *
* *** * **** * *** ***** *


*** *** ** ** ****** * ** * *
* * ** * *** **** *
******* ** * ** ** * *** ** * ** **** ** ** *
* *** ** ** ** * * *** * * **** **** **
* ** * * * * * * * * ******** *** ** * * ** ** * ** * * ******
*** * ** ** * * *** * * ********* * * * ** ** *** ** ** * *
** *** * ** * ** * * * * *** * * *** *
    }

** ** * * * * * * ** * * **
* ** ** * * * **
*** * ** **** * ***** * * *** ** * * **** *** != 0)
** ** *** ***** *** * ******* *** * *** ** **
* * * * * * * ** * * *** ** * *** *** * * * * ** * ** **** ***
* * *** * ** ** **** ** **** ** * *** ** ** * ** * * * ** ** ** *
*** * **** * * ***** * ** * * * ******* * * *
    }

**** * ** * ** ***** * * **
    {
** * * **** * * * * * ** ** ** * * *** * ** ** ** * *
    }


* * ** ** * ** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.50
©2016-2025

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.9k views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.9k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users