1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include **** * ** * * *
#include ** *****
** **** ** **** * ***
* * * * * * * * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * *** *** **

********** **** ** * ***** *
* **** *** * ** *** * ** * == b[i]){
* ** ** **** ** *** * * ***** * ** * ** * * *
** ** * * * * * **

*** * ***** ** * *
if (cnt == n){
* *** * * * **** ** * * * * * * ** * * ** ** * * 1;
* ** * * * **** * ** ** **** * ** ** ** **** * *
* ** ** * * * ** * **** *
* * * ** * * *** * * ** * * * ** * *** * ** * 0;

}

int main()
{
* * ***** ** * * s1[100], s2[100];
******** * *** ** *** i,j;

* ** *** * * * * * ** * *** * * * *** s1);
* *** * * ** * * ****** * * **** *** *** s2);
***** * ***** * * (prefix(s1, s2)){

*** ** * *** *** * **** * * ** ** *** is a prefix of %s", s1,s2);
* ****** ** ** * *** ** * * * ** * ** **
*** ** ** * ** ** * * *** **** *** * * *
* * * * * ** ** * ** ********** ***** * * * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
**** ** *** ** * ** *** c;
* ** *** * ** ** * * * a[100],b[100];
** ***** ***** * ****** * * *** * %s",a,b);
**** * *** ** ** * * * ***** *** **
* ********* ** * * * * * * * **** ** * *** * 0;
** ** * ** * *** *** * * ** %d",strlen(a),strlen(b));
* * *** * ******* *** ***** ** ** *** **
** * * * * ** * * ** *** * ** * **** ** * * ** *** *** * ** ** **
**** * * ** ** * ** * * ** * * * ** * ** ** * *** * *** * **** * * * * *** **** **** * ** * is not a prefix of %s",a,b);
* ** ** ** ** * ** ** * ** ** ** * * ** * * ** * * *** * * * ** ** * * * * ***** ******
* ** **** * ***** * *** * * ** ** **** * **** * ** *
***** * * * * ** * ** ** *** * ** *** * *** *** ** * ***** ** ** if(c==strlen(a)-1)
* * *** ** ** ** ** *** * ** ** **** ** * ** * ** **** ** ** ** * * * * * *** **** * * * ** is a prefix of %s",a,b);
    }
** ** * * * * * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** * * ** n,count;
**** * * ** * *** * ****** * ** ** **** * ****
* * * * * * **** * * * %s",a,b);
* * * ** ** * ***

* ** * * ** ** *** *** * **** ** ** ****
** ** * *** *** ** **** ** *
* * *** * ******* * * * ** * ** * ** ** * * * ****
* ** * ** *** * ****

** **** *** *** * ** (strcmp(a,c)==0)
*** ** * ** * ** * **
***** ** *** *** **** ** *** *** * *** * **** * * * * is a prefix of %s",a,b);
** ** * * * *** *
** ** ** * *** ** **
* *** **** *** *
*** * **** ** ** * * ** * ** **** * * ******* * * ** ** ** is not a prefix of %s",a,b);
* * * * * ** * *
* * * ** * ** ***** *** ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * ****** ** ****** a[100],b[100];
* * **** * ** * *** ** **** * *** *
    int l1,l2;
** ** *** * * * ******* ** *
***** * ** ** **** * ** *
* ** *** * ** ** * * ***
** ** *** ** * *** * * * ***** * * * * ** * * is not a prefix of %s",a,b);

    }
** ** * * ** ** * if(l1<=l2){
**** * ** * * ** * ** ** ** * ** ****** * prefix=1;
* * * *** ******* * **** * * *** ** ** ** * ** i=0;
* ** *** *** ***** * *** * ** ** * * * * ** *** * *
** *** * * * * * ** ** * *** ***** * * ** * *** * * *** * * ** (a[i]!=b[i]){
*** * * * ** * * ** * * *** ** *** * * ** * * * * * ** *** * ** * ** * * * ** * * ** * ** **
*** ** ** *** * * ****** ** * * ** * * * ** **** ** * ****** ** * ** * *** ****** **** * * *
* ** ** * * ****** * * * * * **** * ** * * * * * * * *** ** *


* ** * * * ******* * *** ** ** *
* * * *** ** *** ** *** ********* * * * * ** * * * * ***
* * ** * * * * *** * **** * * *** ** ** * ** ** * * * * * * * ** * ** *** **** * is not a prefix of %s",a,b);
** * * *** ** ** * **** *** **** *
* ***** *** *** * * * * **** * * ** * ****** *** * * *****
* * * * ***** *** * ** ** ****** *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * ***** **
int main(void)
{

* * ******** **** *** pre[100];
* ****** ** * * * **** * word[100];
* **** ** ** *** ** * %s",pre,word);
* * * * ** *** * * * *** ** *
** * ** * * ** ** ****

* ** ** *** * * ***** i;
* ** * ***** **** *** ** * * * * ** * **
** ** * * **** *
* ** * * ** ***** * * ** * * * * * *****
*** ***** ******* *** * **** * * **** * * *** **
* ** * ** *** ** * ***** ** *** **** * * * * ** ** * * ** **** * * ** is not a prefix of %s",pre,word);
** * ** * ** * * ** ** * * * * * *** *** * * ** *** * * 0;
* * * ****** * * ** * **** * ** * * ***

* *** * **** * ** *** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** * ** * ***** ** * ***** pre [100],a[100];
* *** ** * ** * * ** * * n ,i;
*** ** ******* * *** *** ** * *
****** *** *** ***** ** * * * ***
* * ** ****** * * *** * * **** ***
** * * * * **** * * * * *
* * * *** *** * ** * * ***** * **** (n=0;n<strlen(pre);n++)
*** *** * ** * ***** * * ****** * *** *
* * * **** **** * * * * * * ** ** ** * * * * **** (pre[n]==a[n])
* * * *** ** ** * ** ** * *** * **** * * ***** * * ** * ** ** * * * is a prefix of %s",pre,a);
* * *** ** ***** **** * * ****** *** *** *** ** *** ** *** * * ****
**** ** * * *** ** *** *** ** * * ** *** ****** ** * ** * * **** ***** ** * * * ** * ***** * is not a prefix of %s",pre,a);return 0;
****** ** * * * ***
* *** ** **** * * *** * **** ** * *** ** ** **** * *** **** * *

***** * * ** * * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** ****** **
#include ** * * ** * **

int main()
{
** * * * * * * * a[100];

** ***** * * * ** * ** * b[100];

* *** ***** *** *** * * * ** ****** %s", a, b);

** * * **** ** * ** * len_a = strlen(a);

* * * * ** ** * *** ** i = 0;

* ** **** * * * ** flag = 1;

** ** * *** **** * ** * ** = 0; i < len_a; i++)
*** * ***** * *** * ** *
* ** ***** *** ** * * ** * * * **** *** *** != b[i])
** * * ** * * ** * **** * ** * *** * ***
* * ** * **** ** * ** ****** * *** * * ** * * * = 0;
* ** ***** ** *** * * * **** * *
* ***** * ** ** ***

* *** * **** * *** **** == 0)
** * * * * *** ***
** * ** ** * * *** * * * * * **** * **** * is not a prefix of %s", a, b);
* * ******* ** *
*** * ** *** ** * ** *
* * * *** * ***
** * *** * * *** *** ****** *** * ** *** * * *** * **** ** is a prefix of %s", a, b);
* * * ******** ***
*** ** * * * * *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** *** *
int main()
{
*** ** * *** * * ***** * i,n;
** *** *** *** ***** p[100],s[100],a[100]={};
* ** * ** * ** ***** * ** ** **** *** %s",p,s);
* ** * ******* ** ***** *** *
** * ** *** * * * * *** *
** * ** *** *** *** * * * ***** * ** * * *
* **** ** * ** * * * * ** * ** * *
*** ** * * * * ** *** * **** * *** ** ** * * * * is a prefix of %s",p,s);
* *** ** ***** *****
* ** * *** *** ** *
**** * * * ***** ******* * * * * * * ** *** * * * * * * is not a prefix of %s",p,s);
**** * * * * *** ***
**** *** * * * *** ** **** *** * ** * **** ***
* * * ** ** ** * * ** * ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * * ** ** * ** ***** *** ** * *** ** * **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * ** ** * ** ** ** ** **** * * * * ** *
* **** ** *** ** * * * * ***** * ** * ** ***** * != b[i])
**** * ** *** * ** * * *** * ** * ** *** ***** *** * * * * *** *** ** ** *******
* **** * * ** *** * * ** ** * * * ** **** ** * ** * **** *** **** ** **** * ** * * * * ** ** ***** * ** **** * *** * is not a prefix of %s",a,b);
* * * * ** ****** ** ***** ** * * * ** ** ** ** * ** * ** * *** ** * * * * * *** *** ** ** **** * ***
** * * *** ** ** ** * * *** ******** *** ** * **** *** * ** * * * *** ** ** * ** * * * * *
* * **** * ** ** * * * ** * *** * * * * ** ** * *** ******** ** == b[strlen(a)-1])
****** * * * *** **** ** * ** ***** * * * * ** *** ** ** *** ** * * * ** * * *
* **** * * * *** * * ** * * * **** ** ** * * * *** * * * *** * * ** * *** *** * *** *** * * *** * is a prefix of %s",a,b);
* * *** ** * * * * * * ** ** * ** * * * *** * * * ** * * * * **** ** ** **** ***** * * ** * *
** * * *** * *** **** * * * ** **** ** *** * ** ** ** *** * * **** * ***** ** * *
*** *** ******* * **** * ********* * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** ** **** **** * * *** ** i;
* * * * ****** **** ***** * *** (a[0]!=b[0]){
* **** * * **** *** * *** * **** ** 0;
* ** *** * * * ********
*** * * * * * **** * * * * * *** ** *
* ** ****** * ** ** * ** * ** ** **** * ******** * * **** * *** * a[i]==b[i])
**** * **** *** ** * ** ** **** *** * ***
* **** ** *** * * ** * * * ** ** ***** * * * * * ** **** ** 1;
** * ** * **** ** ** * * * * * ** * * * * * * * *** **** * **
*** ***** * *** *** * * * ***** ** * ***
* ** * * ** ** ****** *
* ** **** * *** *** ** * 0;

}

int main(){
** *** **** * * * ** * c[n],d[n],e[n];
* *** * ***** ** **** *** * i;
****** *** * * * * * *** *** * * %s",c,d);

* * * * ** * **** * ** * *
** *** **** * ** * ** * * * * * * * * ** * *** is a prefix of %s",c,d);

** ********* **
* ** **** *** *** * *** ** * * * * * * * **** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.23
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users