1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * **
#include * ** * * ****
* * **** ** **
*** * * ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ***** * ***

***** *** * * **** ** ****** **
***** * ** * ***** ** ** == b[i]){
* * * * * ** * * * * * *** * * *** *
** * ***** ***** ****

**** * ** ****
if (cnt == n){
** * *** ** * **** *** * *** ** * * * * * 1;
***** * * * ** * *** ** **** * **** ****
** * ** * * * **
* *** ** * * * * * ** * ** * *** 0;

}

int main()
{
* ** * ** * * s1[100], s2[100];
** ** * ** * ** * * i,j;

* * * **** ** * * ******* * s1);
* * * **** ** ** ** * * * * * * s2);
** * * ** ** *** (prefix(s1, s2)){

** * * * ** ******* ** ** * * * * * *** ** is a prefix of %s", s1,s2);
* *** * ** * * * * ** *** ***** ****
* *** **** * * ****** * * ** * * * **
** * **** ** * * * ** ** * * * ** *** * ** ** ** ****** * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ** * ** * * ** **** c;
** * * ** * ** **** ** * a[100],b[100];
********* * * *** ** * %s",a,b);
** * *** ** * * **** *** ** * *
* ***** * * * * *** *** * * * * * *** 0;
**** * * *** * *** * ******* ** ** ****** %d",strlen(a),strlen(b));
*** * * * ** ** * * ** ** **** * * *
* * ** * ** * * ** ***** * * *** ** ** ***** * *** ** * * * *
*** * ** * * * * * * ** *** *** ** ** ** ** * *** * **** * * * * * ** ** * * * * **** *** is not a prefix of %s",a,b);
* *** * * * *** ** *** * * *** * ** * ** **** * * * **** ** * * * *** * *** * * *
* **** * * **** ** * **** ** ** * * ** **** *** ** * *** * ** * ** *
* ** * ** * ** * * ** ** *** * * * *** * * * * ** ** * *** if(c==strlen(a)-1)
*** * ** ** * * ** * * * * * * ** * ** *** * * * * *** * * ** * ** * ** ***** is a prefix of %s",a,b);
    }
** ** * * ** * **** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** * ** * * ** * n,count;
********** * * * * * ****** * * **
* ** *** * ***** * * **** * ** * %s",a,b);
* *** ** * * ** ** * ** *

* *** * * * * ** ** *** **** * ** **
*** * *** ******
* * ** ** * ** ******* ** ** *** ** * ***
* ***** * **** * *

* * * **** * * * ** * ** (strcmp(a,c)==0)
*** * * **** ** ****
** ** ** * * * ** * * * ** **** *** ** ***** is a prefix of %s",a,b);
* ** * * **** ** **
* * * *** * * ** * *
* ** * ** * **
* **** * ** * ** * * * * * ** **** * *** * * is not a prefix of %s",a,b);
***** ***** *****
** * * * *** * *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* *** **** * * ** * * * a[100],b[100];
** *** ***** * ** *** ******* ** ** **
    int l1,l2;
**** * ** * * ** ******** * *
**** ** ** ** ** ** * **
** **** * * ** * * ***
* *** * ** * * ***** ** * **** ** * *** * * * * is not a prefix of %s",a,b);

    }
* ** **** ***** * * if(l1<=l2){
** * * * ********* *** * ** * * *** * ** *** prefix=1;
***** ****** * * * * ***** * ** *** * **** *** ** i=0;
** **** * ** * * ** * ** * ****** * ****** * * *** * * *
**** **** * * **** ** *** * * ** * * * * ** ** * * * ** * * * * * (a[i]!=b[i]){
* * ** ******* *** * * ****** ** * * *** * *** ** * * ** *** * * * * * *** *** *
* * * ** * ** * *** *** * * ******* * * *** * * * * ** * * * * ** * ** *
******** ** ** ** *** ** ***** ** ** * ****** ** * * ** ** ** ***** * ** *


* ** * **** **** ** ** **** * *** ** ******
* ** ** **** * ** * ** * * * * ****** ** * *
*** * * * *** * *** ** * * ** * * * * * ** * * **** * ** * * *** * * is not a prefix of %s",a,b);
* *** * * * *** ** ** * * ** * * ** ** ***
**** ** ***** **** ** * * ** *** ** *** **
* ** ** ****** * *** ** * ******* ** ** *** * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** ** ***** *
int main(void)
{

** * * * ** ** * * * * pre[100];
** ** * * * *** ******* word[100];
* * ** ***** * * * * * %s",pre,word);
* * * ** *** * * * **** *
**** * ** * * * ** ** **** * * **** *

* *** ***** *** * * **** i;
* * ***** * ** ** ** ** *** ** *** ****
* * * * ** *
********** * * * * * ** *** **** * * *** ** ** * ** * * *
** * **** * ** ** * ** * *** * **** * ***
** * * ** * * * * ******** ** * * *** ** ** * ** ** * * **** *** * **** is not a prefix of %s",pre,word);
***** * ** **** *** * ** ** ** * * * ** * ********* * * * *** * * **** 0;
** ** ** * *** * **** ** *** * *** ** * *

** ** ** * * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * * ***** *** * * pre [100],a[100];
* ** * ** * * ** ** * n ,i;
** * *** * * * *** * ** * * ** * *
* ** * ** *** ****** ** * ** *** * *
* * * ** * * * ** *** ** * * *
** ** ** *** *
* * * * * *** ** ** ** *** * * * ***** ** (n=0;n<strlen(pre);n++)
******** ** ****** **** **** * * ** *** **** * **
******* * ** *** *** ** * * * * * * ****** ***** * * * **** (pre[n]==a[n])
* **** ** ***** * * * * ** * ** ** ****** * ** * * *** ** ***** * ** * * ** is a prefix of %s",pre,a);
* * * * *** * **** * *** *** ** * ****** * ** ** ** * ** *** * ** ** ***
* *** *** ** * * *** * * *** * *** ****** *** * * * ** * * * * **** * * * **** *** ***** * * ** *** is not a prefix of %s",pre,a);return 0;
* ******* * * * * *
* *** * * *** * * * * *** * **** ** * * * * * *****

* * ******** *** ******* * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** *** *
#include * ** ** * ** *

int main()
{
* ** ** * **** * * * a[100];

* **** ** * * b[100];

***** **** **** ** * *** * %s", a, b);

** *** ** * * * * len_a = strlen(a);

* ** ** * * ** ** ** * i = 0;

*** * * * *** **** ** * * * flag = 1;

**** * * ** * * ** * * * * = 0; i < len_a; i++)
* ***** *** * ** * * **
*** ******* * ***** * * ** ** * ** * * ** * * * != b[i])
* * **** ** ** *** * * * ** * * * ** * * ****
* *** *** ********* * *** *** * * * * ******** ** ***** *** *** * * * ***** = 0;
* *** ** ** * * * * * ** ** * *** ** * *
* ** ********* *

* *** * ** *** * * == 0)
* ****** * ** ** *
* ** *** *** ** * ** * ** ** * ** * ** ** ** * * is not a prefix of %s", a, b);
* ** * ** *** * *
* ** *** ** *** * * *** *****
**** * * * * * **
* ** ** * ** * ** *** * ** **** * ************ **** is a prefix of %s", a, b);
* **** * * *
* * * * ** * ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * * *
int main()
{
*** *** * ** * *** ** i,n;
*** *** * ** * * **** p[100],s[100],a[100]={};
* **** *** ** * * * * * **** %s",p,s);
* * * * ** *** ** * *
* * **** * * * * * * **** *
* * * ** * * **** * * * * *** * *** * *
* ** * ** *** * *** *** ***
*** * *** *** * * **** * * * ** ** * * * ** *** is a prefix of %s",p,s);
* ** ***** ** ** * ** * *
* * * ** ** * **** ** *** *
********* * **** * * *** * ** * * **** ** *** ** **** is not a prefix of %s",p,s);
*** *** *
* ** * ****** ** * * ** * * * * ** ** ** ** * * * ***
* * * ** ** ** ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* *** * * * * ** **** ** ** * ** * ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** **** * * * ** ** **** * ****** **
*** ** *** ****** *** * *** *** * * * * * * ** *** * * * *** * * != b[i])
* * * * * ** **** * ** *** * ** ***** * ** *** *** * * ***** * ** *** *
* *** *** *** * **** ** ** * **** * * ** * ** * ** * * * * * ***** * * * **** * * ****** * * *** ** ****** * ** is not a prefix of %s",a,b);
** ** * *** * * * * * ** *** ******** ***** * **** * * * * ** **** ** * * * ** * * ** * * *
* * * ********* **** * * * *** ******** * ** * * * * ** * ***** ** **** *** ** ***
* * * ** * *** * * ** * *** ** ***** * * *** ** * *** * **** * == b[strlen(a)-1])
*** ** * * ** *** * ** * * * ** * * * **** * ** * *** * ** ** ** * *** *** *
* * * ** * **** * * * *** * **** * * * * *** * *** * * ******* * * * *** ** * *** * ** **** ** ** *** * * * is a prefix of %s",a,b);
* * **** **** * * ***** ** ** * * ** * ** **** * * ** ** * ** ****** ** * ** * ** **** ** * *** ****
** ** * ** * ** * *** **** ** ** *** * *** ** ** ** *** ** ***** * * * * *
* * *** ** * * *** *** ** * * * ** * ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
**** * *** * *** * * **** * * ** i;
** * * **** * * **** (a[0]!=b[0]){
*** **** * ** * *** ***** * ** ***** * ** * ***** 0;
*** * ** * ** * * * ** **
*** * * ** ** ***** * ***** * * ****** * *
* * * * * * * ** * ** * *** * *** * * ** * ** ** * a[i]==b[i])
* * ******* * * ** *** ************ * *
* * * * *** ** *** * * *** * **** ** * ********* *** * * *** **** * * 1;
*** * ** * * ** *** * ** ** ** ** ** ******* *** *** *** *
* *** ** **** * ** *** * **** *****
* * ** *** ****** ** ***
* * ** * * ** ** * * * ** * 0;

}

int main(){
** ** ** * * **** * ** ** c[n],d[n],e[n];
** * * *** * ** * * * ** i;
* * ***** ** ** ** * %s",c,d);

** * * * * * * * ** * * *
** ** *** ** * * ** **** * * * * *** ***** * ** **** * is a prefix of %s",c,d);

* * **** * * *
* *** ** **** * ** * ******* ** * * ** * ** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.175
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users