1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include * *** *
#include ** *** **
***** * *** *
* **** ** * ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ***** * * *

*** ** *** * ** * *** ****
* ** * * * ** ** * == b[i]){
** **** ****** ** **** * * * * ** * ****
**** *** * ** ** * *

*** ** * *** * *****
if (cnt == n){
* * * * ** ** *** ** * ***** ** * ** ***** * ** ** 1;
* ** *** ** *** * ** **** ** * **** * * ***** * * *
* * * **** ** * * * * ** **
*** ** **** ** ** * * **** * * * ** * 0;

}

int main()
{
*** * * * * ** ** s1[100], s2[100];
* * **** ** i,j;

***** * * *** *** ***** *** ** ** s1);
** * * ** * ** ** * ** ***** * s2);
* ****** **** * * (prefix(s1, s2)){

**** ** ** * * *** * * * * **** * * is a prefix of %s", s1,s2);
*** * * * * ** * ** *** *** ** * *
* ***** * * *** ** * * * * ** ** ***
** * ** * * *** * * ** * * *** * ** * *** * * ** *** *** *** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * ** **** * *** c;
* * * * *** ** * * * a[100],b[100];
** ** **** * * * *** **** * %s",a,b);
* * **** * * ** * ** *** *** * * **
** * * ** ****** ***** * ** * * * * * * * *** ** * 0;
**** ** * ** * * ** * * ** *** %d",strlen(a),strlen(b));
* ** * ** * * * ** * * ** * * * **
** * ** **** ** ** * * ** ** * * * * ** **** ** ** ** * * * * **** * *** **** **
* * ** * * * * * * * * **** * **** ** ** * * ** * ** **** ********** ** *** * *** *** ******** * is not a prefix of %s",a,b);
**** ** * * * * ** ** *** * * *** * * ** *** * ** * * * * ** **** * * *** * ***** * ** ** ***** **
* * * * ** *** * ** * * ** ** ** ***** ** ** * * ** ** *
* ** ****** **** ** * ** * ** ***** * * * * **** * * * ***** * * * if(c==strlen(a)-1)
* * * * ** * ** *** * ** *** * * ** ** * ** ** ***** *** * * * * ** *** * * is a prefix of %s",a,b);
    }
**** **** **** *** * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ***** * * *** * n,count;
* *** * ** *** ** ** * * * * **** * * **
** *** **** **** ** * ************ **** %s",a,b);
** ** * * * * ** *

* * ******* ** ** *** * * * *** ****
* * *** * ** * **
*** ** * * * *** ** * * * * * *** * ***** * ** ****** ***
* * *** *** *** ***

** * ** * ** * ** ***** (strcmp(a,c)==0)
*** * **** ** ******
* ** * **** *** * * ** * ** *** * ** * *** *** * is a prefix of %s",a,b);
** * ** *** * ** * ** *
* * *** * ** * * *
*** * ** *** ****
** * * * * * * ** ** ** *** * *** * * * ******* is not a prefix of %s",a,b);
* * * *******
** **** * * ** ** ** * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** *** * *** a[100],b[100];
**** * * * * *** * ** ******* * *** *
    int l1,l2;
** ** ** * ** * * * ** * * **
*** * * *** * * ** *
* *** * * ** * * ***** ** ***
* * *** * ** * *** *** * ** * ** ******** * * * * **** * is not a prefix of %s",a,b);

    }
*** * * ** * * if(l1<=l2){
* *** * ***** ** ****** * * * *** *** * *** prefix=1;
**** * ****** * * * * ** * * * * * * i=0;
* *** ** ** ** ** ***** * * ** *** * * * ** * *** * *******
*** ***** ***** ** * *** ** ** * ** ** * * * * * * *** * **** *** *** * (a[i]!=b[i]){
* * ** * ** * * ** * *** **** ***** * ** * * * ***** *** ** * ** ****** * * * * **
* ** * * *** * * ** *** ** * * * ** * * * * * * ** * ** * * * ** ** *** * ** *** *** ** *
**** ** **** * ** ****** * ** * * * *** ***** *** ** ** * * ** * *** **


* * ** * * **** *** * ** * * * **
* *** * * * ** ***** ****** ** * **** *** *
**** * * **** *** * ***** ****** * *** * ** ******** * *** ** * * ******* ** *** ***** * is not a prefix of %s",a,b);
* * * ** * * * *** *** * * *** ****
** ** * ** * **** * * *** * * **
* * * ** ** * * ** * ** ** ** * * * * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** ** * * **
int main(void)
{

*** * *** * * * * **** ** ** pre[100];
**** ** * * * * word[100];
** * ** * * * * ** * * *** %s",pre,word);
****** * ***** ** *** * * ** ***** *
*** **** *** ** ** **** *** *

*** * * * * * ***** **** i;
* ** * ** * * * ***** *** ** * *** * *** ** *
** ** * * * *
** * * * *** *** ** * * **** *** ** ***** * *
* * * * *** ***** ** * * * * ** ** **
** ** ** * ** *** * **** * **** * ****** ** ** ***** * * * * ******** * is not a prefix of %s",pre,word);
*** **** * ** * * * ** * ** ** * **** ** * ** **** **** * * **** * 0;
* * **** ***** *** * ****** * * ** *

* * * * * ** * * ** *** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* *** * * * * * ***** pre [100],a[100];
* ** * ** ***** ****** * n ,i;
* * * * *** * ** * ** *******
* ** * * ** * * *** * *** * * *
*** * * * ***** ** * * ** * ***** **** **
** * * *** * * * * *
** * * * ***** * * ***** ****** * ****** (n=0;n<strlen(pre);n++)
*** ** ** * * * * ** **** ** *** ** * *
** * * ***** ** * ** * * ****** **** * * ****** **** *** ** * (pre[n]==a[n])
* ** ** * * *** ***** ** ****** * * **** * ***** ******** * * ** * is a prefix of %s",pre,a);
* * * ** * **** * * ** **** ** *** ***** * ** * ** *** ** * **
** *** * ***** * ** * * * ** * *** * * * * * * *** **** *** * * ** ** * **** ** * is not a prefix of %s",pre,a);return 0;
** * * * * **
* * * * * *** * ** ****** * * ***** ** * ***** ** * **

* ** * ** * * * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ** * * * ** *
#include * ***** *

int main()
{
** * ** ***** * * a[100];

* ** *** * * * ** * * * b[100];

** ** ** * * * ** * ** * * %s", a, b);

* * * ** *** ** * ** len_a = strlen(a);

* *** *** * * ** ** ** i = 0;

* *** ** *** ** * * *** flag = 1;

*** **** ***** ** * ** = 0; i < len_a; i++)
* * * ** * * ***** ****
*** ** *** * * ** ** * * * ** != b[i])
** * * ***** ** *** * * * ** * * * ** *
* ***** * ****** * * ***** * ***** * ** *** ** * * **** ** * * * = 0;
* ****** *** ** ** ** * ** ********** * * ***
****** ** ** * * * *** *

* * ** ** ** * * ****** ** *** == 0)
** * ** * * * *** ***
** * * **** ***** * *** * * * * * ** *** * * ** * is not a prefix of %s", a, b);
* *** * * ** * *** *
** * *** ** **** * *
* * * ** * * ** **
* ***** ********** * ** * * * * * ** * * ***** * *** is a prefix of %s", a, b);
** **** * ******
* * * * * * ** ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** * * * *
int main()
{
*** ** ** ** * * *** i,n;
* * **** ********** * **** p[100],s[100],a[100]={};
** ** * *** *** *** ****** ** ** * %s",p,s);
* ** *** ** * *** * * *** * **
***** ** ** ** *** * * *
* * * * ** * ** **** * ** * * ** **
** *** ***** ***** ***** ** ** ***
** * ** *** ** * *** *** * ***** ** *** ******* * *** is a prefix of %s",p,s);
* **** ****** * ****** **
* *** ** * ** * * ** *
* * **** *** ** ** * * ** * ***** * ** * ** ** * *** *** is not a prefix of %s",p,s);
* * * * **** * ** *
* ** * ** ** ****** * * * *** ** * *
* ** ** * ** * * ****** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
******* ** * * ** ** * ** * * ****** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * ** ** *** ** **** ** * * * ** ** ** *
* *** * * ** * * ** ** * ** * * * *** * ** * * *** * ** * ** ** * != b[i])
* * * ** ** *** * *** * * ** *** ** * ** ** *** ** * ** * * * * ** ** *** *** ***
** ** * * * * * **** **** *** * ****** * *** * * * *** ** * *** ***** *** * * * **** * * * ** *** ** ** ** *** ** ******* * is not a prefix of %s",a,b);
** ** *** ** * * * * * ***** * * * ***** * ** * * **** ***** ** * * * * * *** ** ** * **** ** ** * * *** * * ** *
** * **** * ** * * * * * * *** ** * *** * * * * ** * *** * * * * * **** * *** ** ****
*** ** * * *** * ** * ***** ** * *** * * * *** ** ** * * * * ********** * == b[strlen(a)-1])
** *** * * ** * ** ***** * * * *** ** ** ** * * * * ** *** ****** ** ** *** ** *****
****** ** *** * * *** * * * * * ** ***** * * ****** *** * * ** * * * * * ******* * *** * * ** * ** * * is a prefix of %s",a,b);
** *** * ** * ***** *** * ** * * ** ** *** * * * **** * ** * ***** *** * *** * * * ** *
* * * * ** **** ** * * ** *** * * *** * * * *** ** ** ** ** * * * **** * * ** ** ***
* * ** ** *** ****** * * **** * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * * * ** ******* * ***** i;
** * ** ***** *** * * ** *** (a[0]!=b[0]){
** * ** ***** * ** ** * * * *** * * * *** * 0;
* * ** **** *** * ** * * **
* ****** * * ***** * ** ** ** ** * **
* * *** ** * * * * **** ** * ** ** * ***** * ** * a[i]==b[i])
* * ** * * * * ** ** **** ** ** * * *** * *
* ****** **** * ** * ** ** ** ** ** * * * * **** ** * * * * * * 1;
* * * * * * ******* *** * * ** * * ** ** *
** ** * * * ** * **** * * * ****** **** * * *
** * * ***** ** * * **
* * * * ** * ***** ***** 0;

}

int main(){
* * * ** **** *** *** *** * c[n],d[n],e[n];
***** * * ** * * ** * i;
**** * ** * **** ** *** ***** * %s",c,d);

* * * * *** ** ** * * * * * *
***** * ****** * * ** ** * ** * * * **** ****** * *** * is a prefix of %s",c,d);

*** ** * *** * * * * **
* ** * * * *** ** **** * ** ** * ****** *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.14
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users