1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** *
#include * * * ***** **
* * * * * **
**** * ***** * * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** ** *

** *** * * * * * * *** *
* *** * * * **** * * == b[i]){
** ** * ***** ** * **** ** * **** *** ** * ** **
*** * * *** *** * * * *

* * * ** ****
if (cnt == n){
**** * * * ** **** * ** * ** **** ** * 1;
* ** * **** *** ** * ** * * ** ** **** * **
*** ****** * * **** ***** *
** * ******* * ***** * ***** * * * 0;

}

int main()
{
* ** *** *** ** s1[100], s2[100];
** *** ** * **** * * i,j;

****** * ** * ** * * ** ** * s1);
** * * ** * *** * **** ******* * * * s2);
** ***** ** * (prefix(s1, s2)){

* ** ***** ** * ** ** *** ** * * is a prefix of %s", s1,s2);
*** * ***** * **** * ** ** ** * * **
**** ****** * *** * * * * * * * *** **** *
* * ** * ****** * ** ** * * **** * ** * * * * * *** ** * * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** * ** * * ** * *** c;
* ** * * *** *** ** * a[100],b[100];
** ** * * * * ** * * * * %s",a,b);
* * *** ** * * ** * **** ******** ****
** *** * * * * * ** * ** * * *** ** 0;
* * * ** ** ** * ** * * ** %d",strlen(a),strlen(b));
** ** * * * * ** * * * *
** ** *** * ** * * * ** * **** **** * * * *** * * * * * * **
* * * *** * * ** ** ** ** *** ** ****** *** *** * *** ****** * ** * ** * *** * ** * * *** ***** * is not a prefix of %s",a,b);
* * * ***** ****** * ** ** **** *** ** ** **** * *** ** * ** * * * ****** **
**** * ** * * * ** ** * ******** ** * ***** * * * *** * **** * *
**** ** *** ** * ** ** * * ** * * * ***** *** * ** *** ** if(c==strlen(a)-1)
* * ** * * **** * ** * *** ** **** ** * ** * * ** * ** ** ***** ***** * *** *** ****** * ** * is a prefix of %s",a,b);
    }
* * * * ** * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** * * ***** *** n,count;
* * ** * * * ** ** * *** *** **** ** * * *
* *** **** * *** * ***** * %s",a,b);
* ** * *** * ** * ** ** * * *

**** * * ** *** * ** ** ** *
* ** ** ******* * **
* ****** * ** * *** * * *** *** **** *** * *** * *******
* ** * * * * *****

*** * ****** *** * * * (strcmp(a,c)==0)
** ****** * *** *
* * * * ** *** * * * * *** * ** ** * * * * ** is a prefix of %s",a,b);
** * * ** *** * *** **
* * ** * * * *
* ** * *** ** * * * * *
* *** * ***** * ***** ***** * * ******* ** *** ** * *** ** is not a prefix of %s",a,b);
* ** * * * **** ***
*** * ** * ** * ******* * *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
**** *** *** ** ** * *** a[100],b[100];
*** * * ***** * * * * * ** ** ** *** ** * * *
    int l1,l2;
*** *** *** *** *** **** *
** * * ** * * * ** ** *
* * ** *** * ** * *** *** *
*** * ** ** *** * *** * * *** * **** * ** ** is not a prefix of %s",a,b);

    }
** *** **** **** ** ** * * if(l1<=l2){
*** *** *** **** * ** ** * * * * *** prefix=1;
**** * ** ** * * * ** ** * ** * ** **** * ** * i=0;
** * **** ** * * *** ** ** ** * *** *** *** ***** *
** * ** **** * * * ***** * ****** ** ** ** * *** * * *** * * * (a[i]!=b[i]){
**** * ** *** *** **** *** * ** **** **** ** ** ** * *** * * *** ** *** * *** * ** ***** **
* *** ***** **** ** ********** * *** ** ** ** * * * ** * *** * * * * * * **** *
** * ** * * **** * ** * * ** * *** ** ** * **** ** *


* * * ** * ** * ** ** * * * * * * * **
**** **** * ** ** ** * **** ** ** ** ** ** ***** ** **
* * ******* *** * * *** * ** * * * * * * * * * ***** * is not a prefix of %s",a,b);
** ** ***** * * *** * * * ****** * ** * *
** * **** ** * * ** ** * *** * * * ** *** * ***
****** * ** ** * ** * *** *** **** ** * * * *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
***** * ** * *
int main(void)
{

* * **** * ** *** ** * pre[100];
** *** ** * *** ** * **** ** * word[100];
* * * ** * * * * * * %s",pre,word);
** * **************** * ** * ** *
* ** * * * * * * ***** * *** * * ** *** *

* *** ***** ** i;
** * * * * ** * **** * ** ***
* ** * ** * * * * ****
** * * ** ** *** ** * * * **** ****** ** ** * * * * *
**** ** * *** * ** **** ** * ** ** ***
* ** ** *** * **** * * ** * ** * * * *** * * ***** * * ***** ** ** is not a prefix of %s",pre,word);
* * ** *** * * * * ** * * * * * **** ** *** **** 0;
** *** * ** * ** ****** ** ** *** *

* ** ****** ** ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** * * ** *** **** * *** pre [100],a[100];
** *** * ** * * ***** ** n ,i;
* **** * ** * * ** **** ***** * **
** * ** **** * *** * * *** * ***** ** **
* * * **** *** **** ** ** **** *** **
* * ** * **** *** * * *
* * *** * **** *** * **** **** * ** * ** * * * * (n=0;n<strlen(pre);n++)
******* *** * **** * * ****** * ** * * * * *
** * * * **** *** ***** *** ** ** * * * * * * ** * ** * ** * ** ** ** (pre[n]==a[n])
******* ** ** * *** * * ** * * *** ****** * ** * * is a prefix of %s",pre,a);
*** ** **** ** ** * * * ** * * ** * ** * * * ** *** * * ** *** *
* *** * ** *** ** * * * ** * ** * ** * ** ** * ** * *** * ** ** ****** * ********* * * is not a prefix of %s",pre,a);return 0;
* ** * ** * *** ** **
*** * * * ** ** ** *** **** ** * * * *** ** * * * *** ****

*** * * * * * ** * ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * ** *
#include ** **

int main()
{
* * **** * * ***** * ******* a[100];

* ** *** * ** ** ** b[100];

* * * * * **** * * *** *** %s", a, b);

** * ** **** * **** ** * len_a = strlen(a);

** ** ** * * ** * * * i = 0;

* ** *** * ** ** * **** flag = 1;

* ** * ** **** ** ** ** = 0; i < len_a; i++)
** * ** **** * *******
* ************** **** * *** * ** ** * *** *** * *** != b[i])
** * *** ** **** * *** * * **** *
**** ** * * ** ** * ** * * * * * ** ** *** **** * ** * ***** **** ****** ** * * = 0;
* * ******* ***** *** * ** * **** * **
* * * ** ** * * * ****

** * ** *** ** * * ***** * * == 0)
**** * *** ***** ***
*** * *** * ****** ** * * * ******** * ** *** *** * is not a prefix of %s", a, b);
* **** ****** **
*** * * ******** * *
* **** * * * ** * *******
*** ** ** * ** * ** ** ** * * ** * *** * ** ** ** is a prefix of %s", a, b);
***** * * ** * **
* * * *** * *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** ** * * **
int main()
{
* *** ********* * **** i,n;
* ****** * * **** **** p[100],s[100],a[100]={};
*** ****** * * * *** ** * * *** %s",p,s);
* **** ********** * * * ** *
** **** * * **** *** * *
* * * * ** ** * * ***** ** * * * * *****
* ** ****** * * * * * * **
** * * *** * * **** * ** * * * ** * * * ** * * ** * * * * is a prefix of %s",p,s);
**** ** * * *** *** *
**** * * *** * * ** *
** ** * * ** ** ** ** * * * * ** * * * * ** * * * is not a prefix of %s",p,s);
* ** *** * *** ***
* ***** **** ** * *** * * * * *** * ** *
**** * * *** ** ******** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * * *********** * * * ** ** ** ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ** **** * * * ** ** ** **** *
* * ** * * *** * ***** * * * *** ** ** * ** * ** * * * * *** != b[i])
* * ** * * * * * **** * * *** * ** * *** * **** * ** ** *** * * ** * * * * **
* ** * ** * *** * ** *** ** * * * *** *** *** * ** *** * * ** ********* * * * * ***** ** *** *** **** * * ** * * **** is not a prefix of %s",a,b);
* * ** ** * *** * * * * * ** ** ** *** **** * * * * * ** ** *** ******* ***** * * **** ** * *
* *** ** * **** * ** * ** *** * **** * ****** ** *** ** * **** * *** * *** * ** *
**** **** ** * * *** *** * * * ** * * ** ** * * * * * * * ***** * ** *** * == b[strlen(a)-1])
* ** ** ** ** ****** ** * ** **** * * * ** * * ** * ** *** *** * * * * * ** ** ******
* ** * * * * ****** ** ** * * ** * **** ********* * * * ** * * ** ** * ** ** * * * * ** * * ** **** ** is a prefix of %s",a,b);
** ** * ** * * * * *** * ** *** * ** ** ** ** ***** * ** * * ** * *** * ** * * * * * ** *
** * ** * ** *** ** *** ****** ** ** * * * * * * ** * * ** * * * ** ****** ** * * * * *
* * * ** * *** * * * *** ** * *** ****** * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * *** ** * *** * ** i;
* ******** *** * * * ** * (a[0]!=b[0]){
*** * * *** *** * * ** *** * *** * *** * * * 0;
* * ** * * ** * * * ***
** * * *** * * *** * * * * * ***** *
** *** ** * *** ** ** * ** ** * ** * ** **** * a[i]==b[i])
* * * * * *** *** * ** *** *** *** ** *** *
*** * * * * *** * * ** **** ** ** * * * * **** * ** **** * *** ********* 1;
* * ** * **** * *** *** ****** ***** * * * ** * ** ** * ***
* * ** ** ***** * * * ** * ** ** ** *
** **** *** ** * *
* ** ****** ** *** ** ** * *** ** *** 0;

}

int main(){
* * *** * ** ** * ** ** c[n],d[n],e[n];
* * * **** *** * * i;
**** *** * * **** ** ***** * ** * * %s",c,d);

* ** ***** *** ****** *** * *
* * *** *** **** ** ** ****** * * ** * *** * is a prefix of %s",c,d);

** * ** * * ** * * ** *
******** * * * ** ** ** *** * * ***** * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.94
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users