1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * *****
#include * * **
***** * *** * * * ** *
***** * ** ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * **** * ***

** * ** ** *** * ** * * ****
**** *** * *** ** * * * == b[i]){
** ** * ** * **** ** * * *** * ** * * * ** * ** ***
*** * ***** * **** ** *

* * * ** * * * ** *
if (cnt == n){
* **** * * * * *** * * **** * * * * ** * * * 1;
* * * ** *** * *** ** *** ** * **** *
** ** ** ** *** *
* ** ** *** * *** * * * * * ** ** * ** ** 0;

}

int main()
{
** * * **** * * * *** s1[100], s2[100];
* * * ** * *** ** * i,j;

* ** *** * * ** * ** *** ** s1);
* * * ** * ********* * **** * s2);
* ** * ****** (prefix(s1, s2)){

*** *** * * * ********* * * *** *** * *** ** is a prefix of %s", s1,s2);
**** ** ** * * * ** ***** ** * ** *** *
* * * ** * * ** ** * ** ** ******* * **
** * ** * ** *** *************** ** * ** ** * * * * ** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** * ****** ******* * * c;
** * * * * ** ** * * a[100],b[100];
* * * **** *** ** * * * * * * * * ** ** %s",a,b);
** * * ***** ***** ** *** ******* *
* * ** * * * **** ** * * ***** * 0;
* * * * * *** * * ** * * ** * %d",strlen(a),strlen(b));
* ** ** * * * *** * * * ***** ** *
* * ****** * ****** * ** * *** **** *** *** *** * ***** * *** *
* ****** * * * ** ***** ******* * * ** *** * *** *** * ** * ** **** ** * *** * * is not a prefix of %s",a,b);
** ** * *** ** * *** ** **** * * * ** * * ** ** ** ***** ******* ** ****** *
* **** * ** *********** ** *** ** ** * ****** ****** ** ** * *
* * * *** ** * *** * * ** ** * ** ** * * ***** *** *** ****** ** * if(c==strlen(a)-1)
* * ** ** **** **** **** * ** * ** * * * * ** * * * * ** ** ******* * ** ** ** * *** * ****** * is a prefix of %s",a,b);
    }
** ** ** ***** * ** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * ***** ** *** n,count;
*** ** *** ** * ** * * ** * ** * *** *
**** ** *** ** ** * * * **** * * * %s",a,b);
** **** ** * * * ** ** * *

** * * ** * * *** * ***** * ** ** *
* ** *** * ** ***** ***
** * **** ** ** **** ** *** **** *** ***** * *
** * *** * * * ** *

* * * **** ****** * (strcmp(a,c)==0)
*** ** ** * ** * * ****
** *** * ** * ** ** * * ** ** ** ** *** ** ** * is a prefix of %s",a,b);
*** * **** * ****** *** **
*** * ***** * *** **
**** * * * ** * *** **
** ******* * **** * * *** * * * **** * ****** is not a prefix of %s",a,b);
****** * * ** * * * ** * **
** * * * * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** * **** * * * * a[100],b[100];
* ** ** * ** * * * * * ** * *** **
    int l1,l2;
***** ** * ** * * ** *
** ** ***** * ** ** ** * * * ** *
** ** *** ** * * * ** **
** * * * * * * * **** ** * * ** * **** * * ** *** is not a prefix of %s",a,b);

    }
*** * ** * ** *** if(l1<=l2){
* ******** * ** * ** * * * * *** ** **** prefix=1;
* * * ** * * **** ** * * ** ** * ** i=0;
****** ** ***** *** **** * ** * ** * * * * ****** * ** * ** *
** *** ** * * **** *** * * * ** * * * ** *** **** **** (a[i]!=b[i]){
******* ****** **** * * * * **** ** * * * **** * * *** *** ** ** ** * **** * **** ****
*** * **** *** * **** * * * ** * ** ** * *** * ** * ** * ***** ** * *
*** *** * * * * * * ** ** *** ** **** ******** * ***** * ** * * *


****** * ** ** **** ** * * * ** ****
** * * * **** **** * * ** * ** * * ** ** ** * * * * * **
** ** **** * * *** *** ** * * * **** * ** ** ** ** * * ******** is not a prefix of %s",a,b);
* *** * * * **** ** ** * *** ** ** ** *
** ** * ** ** ***** *** * * *
* * * **** ** * **** * **** *** ***** ****** *** *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * **** *
int main(void)
{

*** * *** ******* * * * * * pre[100];
** *** ** **** * *** *** word[100];
* ** * * * * * ** ** ** %s",pre,word);
************* *** *** * * **** **
* * ** * ** * * * ** ****** **

*** *** ** * * ****** i;
** ***** *** * ** *** *** ** ** *** *
***** * ** **** *
* * * * * * * * ** * ** **** **** * * * * *** **** *******
****** ** * * ** * ***** *** * * * ***** *** ** *
* * * * * * *** * * ** * * * ** ** * * * * *** *** ** ***** * * ***** * is not a prefix of %s",pre,word);
******** ** * * ** * ** ***** ** ** * ** ** * ** *** * ** ** * * * **** ** * 0;
** * ** ** * *** ** *** * * **

** *** * * * * *** ** ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * ** ** ** * * ** * pre [100],a[100];
****** ** *** ** * * n ,i;
******* ****** * ** * * ** **
* ** **** ** ** * ** * *
*** * * ***** *** * *** * * * ***
* *** ** ***** *
** ** *** * ** **** * * * ** * ** *** * **** * * (n=0;n<strlen(pre);n++)
**** * * ** ** ** ** ** ** * ******* **** **
* * ** *** ** ** *** * **** *** * * * * ** *** ** * ** * *** * (pre[n]==a[n])
*** ** * * * ** * *** *** ********* * ** ** * * * *** * ** ** * ** ** * is a prefix of %s",pre,a);
* * *** ** **** * ** * ** * * ** * * ** * * ** * * * ******
** * ** ** *** ****** ** * *** *** * ** ** **** *** * ** **** * *** **** **** * * * ******* is not a prefix of %s",pre,a);return 0;
* * **** *** *** * *
* * ******* * * * * ** *** * * ** ***** * * ** * ** **** * *** *

* ** **** **** * * ****** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * *** *
#include ****** * **

int main()
{
* * **** * **** a[100];

* * ** * * *** ** ** b[100];

* * * ** * * ** * * ** * * %s", a, b);

* **** ******** * * *** len_a = strlen(a);

** * *** * * * ** * i = 0;

* *** ** ** * ** * *** *** flag = 1;

* ** * ** ** **** * * ** = 0; i < len_a; i++)
* ** * * * * * * *
*** * * * * * ** *** *** * ** ** * ** ** * * != b[i])
* * *** * *** ** ** *** ** * ***
* **** * * ** *********** ** *** * *** ** ** * ** * *** * *** = 0;
* * * * * ** * * * **** ** ****** * **** *
* * *** * *** * **

** * ** ** * ** * == 0)
*** ** * * * *
**** ********** ** *** * *** * ** * * **** * * * * * * ** ***** is not a prefix of %s", a, b);
* ** ** * * *
* *** * * * **** * * **
**** * ***** ** *
** *** * ****** ****** *** ** ***** ** ** * ***** **** *** is a prefix of %s", a, b);
* ** * *** * **
*** * ** *** * ******* * ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** * * * *
int main()
{
******** * *** * * * i,n;
* ** ***** * ** p[100],s[100],a[100]={};
* * ** ** ** * *** * * * * * %s",p,s);
* * *** **** ***** ***** *
***** *** * * * *** ** **
** * ** * ** * ***** **** ** * * * ** * * * *
* ** *** ** * * ** ****** * *
** *** *** ** ***** * ** * * * * *** *** * *** is a prefix of %s",p,s);
** * *** ** *** ** * **
*** * * * ** * *
****** * * ******** * ** * ***** * * ** * *** ***** * * * is not a prefix of %s",p,s);
** * ** ** * ** ** * * *
*** * ** * ** * * * ** *** * * ** * * * **
* * *** **** ***** * * * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** ** * ** ** ** **** * * ** ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * * * **** * ***** * ** * *** * * ** **** *
** **** * ** *** * * * * *** * ** * ** * * * * *** *** * != b[i])
* ***** * * ********** ** * * ** *** * * * * * * * * * * * *** *** **** ****** *** * * * *** *
* ** ******** *** * *** * * * ***** * ** * * *** * ** ** *** * * * * *** *** * * ** * ***** ** * ** ** * * * *** is not a prefix of %s",a,b);
* ******* *** **** ***** *** ** * * * ** ***** * * * *** ** * * *** * ** * * ** * * * * * ** *
* * * * ** ** * ***** * * * * ** **** * * * ** * * * * ***** ** * * *** ** *
*** *** * ** ** ** * * ** ** * * *** * * * *** * ** * * ** ** ** *** == b[strlen(a)-1])
* * * ** ** **** ** *** ***** * * * *** ** *** ** * * * * * * *** **** * * * * * *
* * * *** ** * * * * *** **** * ** ** ***** ** * *** ** * ***** *** * ***** * * * **** **** * ***** * * * is a prefix of %s",a,b);
** * * **** * * * * *** **** * ** ** **** * * ** * ** * **** * ****** * ** ** *** * * * ** ** ** *** * * * * *
* * ** ** *** * ** * *** *** ***** * * ** * * * * ** * * * * ********* *
* *** ***** **** ** * * * * * ** * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ** *** ** *** ** i;
* * ***** ** * ** * * * **** (a[0]!=b[0]){
* * * * * ** *** **** * **** *** ** ** 0;
* ** ******* * * *
**** * * * ** * * *** * ** * * * ***
* * * *** **** * *** * *** * * * **** ** ** a[i]==b[i])
* ** ** ****** * * * * ** * * * ** * * ********
*** * * * * *** * * * * * *** * **** * * * * ** **** * * 1;
* * * * ***** * * *** *** * * ** * ** **** * ** *** * * * ***** * * *
* ** * ** ** **** * ***** ***** * * *
** ** * ** * ** * *** * ****
*** * * ** ** ** *** **** * ** * 0;

}

int main(){
***** * * *** ** ** ** * c[n],d[n],e[n];
* * ** ** **** * * i;
*** * *** * * *** ** ** **** * %s",c,d);

* *** * *** *** * ***** * * *
* * *** * * *** ** * * * ** * * * ***** ** * ** * is a prefix of %s",c,d);

* ** * * **** * * * **
* * * * ** ** * * * * ** ** ** ** ****** **** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.85
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users