1 like 0 dislike
2.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** ** **** *
#include * ***** * * *
* ** * **
**** * * * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * *** *

** ** ** * * ** * * *
*** ***** * ** * * * *** == b[i]){
* * *** ** * * ** * ** * ** * **** ** ** * ** *
** *** * ***

** * * ** * *** ** ***
if (cnt == n){
** * * * * *** * ****** *** ** ** * * * 1;
** ** ** *** **** * ** * * * ** * ** *
* * ** ** * ** ** ***
* ** * * ** ** ** * * ***** * * * ****** 0;

}

int main()
{
* * ** ****** ** * * * s1[100], s2[100];
* *** * **** * * ** * * * i,j;

* ** ** * *** * * * * *** * s1);
* * * * ** * ***** ***** * ** *** s2);
**** * ** ***** (prefix(s1, s2)){

** * ** * * * **** * ** * * ** * * * is a prefix of %s", s1,s2);
**** * **** ** ** * ** * *** ******** ** * *
** * ** * *** ********* * ** ***** * * *** ***
** ** * * *** * ** ***** * ** * *** * ****** ** * ** *** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * ** *** ** *** c;
* * * ** * * *** ******* a[100],b[100];
* *** * *** *** ** *** * %s",a,b);
* ** * * * * * **** ** ** *
* * * * ** *** * * * ** ** * ** ** * * * 0;
** * *** * * *** *** * * * * ** * * %d",strlen(a),strlen(b));
** *** * *** * *** ** ****** ** * ** ***
* ***** * * **** ** * ** ****** * * ** *** **** *** * **** **
*** * ****** ** * * ** ******* ***** ** * *** * ******* * ** **** * ** * * ** * ** * ***** is not a prefix of %s",a,b);
* * * **** ****** ** *** ** ** * * ** * * * **** ** * * * ** **** ***** * ** ** *****
* ** * * * * ** * ** *** **** **** *** * * * * * * ****** * ** *
* **** * * ** * ** ** * * * * ** ** *** * ** ** ** * * if(c==strlen(a)-1)
* ** ** ** * * * ** ** * ** * * ** * *** **** *** * **** * * * ** ** * *** * ** ** ** * * * ** is a prefix of %s",a,b);
    }
* * * ** * * ***** * *** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * * * **** *** * * n,count;
*** **** * ** ** * *** * ** *** * ****
* *** *** ** **** * ** ** * ** ** %s",a,b);
* * * **** ***** * * **

* * * ****** * ******** ** ** * **** * ***
* * * *** * * *** *
*** * *** * * * ** ** * ** * * ***** * *
**** ** * * * *

* ** *** * *** * * * ** (strcmp(a,c)==0)
* ** * *** * * * * *
* * * ** ** ** * *** * * **** * ** * * ** ** * * is a prefix of %s",a,b);
**** ** * ** * ***** * *
* * *** ** * * ** ** ** *
* ** *** ** * ** ** *
* **** * ** * * ** ***** **** * ** * ******* ** is not a prefix of %s",a,b);
** ** * * *** * ** *
* * * *** ******** ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ******* * * * ** * ** ** a[100],b[100];
* ** **** * * * * ***** ** * ** *** ** * * **
    int l1,l2;
******* * * ** * ** * ** *
* * * * *** ** * * **
* * ****** * **** * * **** * ** *
* ** * *** *** **** ** ** * ** * *** ** * * * is not a prefix of %s",a,b);

    }
* * *** * *** * * * * if(l1<=l2){
* * ****** ** * *** * ****** * * ** * ***** * ** prefix=1;
* *** ** * * **** * * * ** **** ** i=0;
** ** ** ** * * * * * * *** * * ** * ** ****** * * * * **
** * ** ** * * * * *** * ***** * ******* * * * ** ** * (a[i]!=b[i]){
** * * **** * * *** * *** * ** ******* * * ** * * ****** * ** * * ** ** **** * **
* * *** ** ** *** * * ** * * ******* * * *** ** *** * * ** * **** * * * ** ** ** * * **** ***** *
*** *** ** * * ** * **** * * * * ** * ** **** ** * ** * * **


** * ** ** **** * * * * * ** * ** **** * *
* * ** * * ** ** ** ** * ** ** ** ********* ** * * * ** *
* * * * * * * * *** * ** ** * ** * ** * ** * * ** **** * ** ** **** ** *** * is not a prefix of %s",a,b);
* ** * ** ** * ** * ** * ** ****** * ******* ****
*** * * * * ** ** * *** ***** *** ** *** * * **
** * *** **** * * * ** * ** * * *** **** ** * * * * * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * *** * * **
int main(void)
{

* * ** * * * * *** pre[100];
*** ***** * ** *** **** word[100];
* *** *** *** **** * ** * * *** ** %s",pre,word);
****** ** *** *** *** * * *
* ** * * * **** *** * *** ** *

*** * *** ** ** * **** *** i;
* ** *** **** ** *** * * * * ***** * * ** **
**** **** ** * *
* * **** * ** ** ** * * ** * ** **** ** * * *
* * * *** * * * ** * * * ** * ** * **
** * **** ** ** ** * *** ** * * * * * * * **** * ** * **** *** ******** *** ** is not a prefix of %s",pre,word);
* ** * * * *** ** * *** * ** ** * ** ******** * ** * ** ** 0;
* * * * ** **** * * ** * ** ****** **

** ** *** ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * ** ** *** * *** * * pre [100],a[100];
* ** * ***** **** n ,i;
* * * ** ** * ***** ***
** * * ** * ******** *** **
* **** * * * ** ** * * ** **
* *** ** * *** * ** *
*** * * * * * *** **** * *** * *** ******* * (n=0;n<strlen(pre);n++)
** * *** * * *** * * * * * * * ****** ** **** *
**** ** ** ** * *** **** * * * *** *** ** ** * * ** ***** *** (pre[n]==a[n])
** * *** *** *** * * * * ** ** * * * ** ******* * * * *** * *** * ** * is a prefix of %s",pre,a);
*** * ** *** ** * ***** *** * * * * ** * ** ** ** * *** * **** *
**** * * *** ** * * ** ** * * * * * ** *** ** *** * **** * ** * **** * *** ***** *** * * *** * is not a prefix of %s",pre,a);return 0;
* **** ** ** * **
** *** * * * ** * * ** ** * *** * * ****** * **** * ****** * *** **

* ***** * * * ** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** ** ** ***
#include * ** ** * **

int main()
{
** ** * ** *** ** a[100];

* **** ** *** ** *** ** b[100];

** **** * * * ** ** * **** * %s", a, b);

*** * * * ** ** * len_a = strlen(a);

* * * * ***** * ** ** ** i = 0;

* * * ** *** ****** * * flag = 1;

* * * * * ** ** * ** * = 0; i < len_a; i++)
* *** * * * * *** * *
******* * * * *** * * ********** ** ** ** * * * ** *** != b[i])
* **** * **** ** **** * ** * * ** ** *** * *
** ** ** **** ** * * * * ** * * ** * * ** * * *** *** *** *** * = 0;
* ** * * *** * * ** * *** * **** *** *** * ***
* * * * * ** ***

******** *** ***** ***** * ** * ** == 0)
*** * * *** * **
**** ****** *** ** ** * * ** * *** * * ** * is not a prefix of %s", a, b);
*** *** * **** ***** ** *
* * ** ***** * **** *** *
** *** * * *** ***
* * * * ** ** * ** **** ** * ********** ** * * **** ***** is a prefix of %s", a, b);
* ** ** * *** *
* ***** ** * * * *** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * ****
int main()
{
* * * * * **** * * i,n;
* ** ** ** *** ***** *** *** * p[100],s[100],a[100]={};
* * *** ** * * ** ** * *** ***** * *** %s",p,s);
* * **** * * * *** ** *
* * *** * *** * * *** * **
** **** * ** **** *** *** ** **** ** ** ***
* ***** ** ****** ***** * **** ****
* ** * **** * * * * ** ** ** ** **** *** **** *** * * * ** is a prefix of %s",p,s);
*** *** **** ** * * **
** ** ** **** *** ** *
** * *** *** ** * ** * * * ** *** * ** **** **** * * is not a prefix of %s",p,s);
* ** ** ***** ** * *
* * ** *** * **** * *** *** ***
** * ** * * * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** ****** * *** ** * ** * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * * ** * * *** * ** * ***** * ** ** * *
*** * * * * * * ** * * * ** *** ** * * * **** ***** ** * * * * * ** != b[i])
* * ** * * * * * * * * * * *** *** ** *** **** ***** * * * ***** * * * **
* * **** ** * ** * * ** * * * ** * * ** * ** ** * * * *** *** * ** **** * * **** ** * ** **** * is not a prefix of %s",a,b);
** **** ** * ** *** **** ** * * * ** *** **** * **** ** * ** * * *** * ** * * * ** ***** * ** *** * *** *
* * ***** * ** ********* * ** * * * * * * ** * * * ** * * * *** * ** * ** * * *
** * * *** ** ***** * * *** ** * ** ** ******* **** * *** * * * *** == b[strlen(a)-1])
* * * ** * ** ** * **** * * *** ****** * ** * * ** ** * ** *** * ** * ** * ** ****** * * *
**** * ** ** *** ** * **** ***** * * * ** * ** * * **** * * * ******* ** * * * ********* * * * * ** * ** **** ** * ** is a prefix of %s",a,b);
* * * * * *** * ** *** *** **** * * ** ** **** ** *** * **** ** ** * * *** ****** ** ** * **
*** * * * * * ** **** **** *** * * ** * *** * ** * * ** * * * ** ** * **
* * * **** *** ** **** * ***** ******* * * ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** * ** * * * * * ***** *** **** i;
*** * * *** * ** * * *** (a[0]!=b[0]){
* **** * * * * * **** ** ***** ***** * 0;
* * ** * * *** * * * ***
** * * * * * ** ** **** **** * *
* * *** * * ** * * * * * **** * ** **** *** * *** * * * * a[i]==b[i])
* * * * * ******** ** * ** * * *
**** * * ****** * *** * ** * * * * * ****** ** * * ** **** * ** * * * 1;
* ******** * ** * * * ** **** ** ** * * * ***** * * * ** *
* ** * * * **** ****** ** *** * ** * * * ******
** * **** * * * * ** *
* * ** * * ** * * * * ** ** * 0;

}

int main(){
***** **** ** * c[n],d[n],e[n];
*** * * ** ** * * ****** * i;
** ***** * * ** * * ** **** %s",c,d);

* ** * * **** * * ** *** *
** ******* * ** * *** ** * * ** * * * * * * * is a prefix of %s",c,d);

* * ** * **** * ** ****
** * * * ***** ** * * ** * ** ******** *** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.73
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 478 views
12,783 questions
183,443 answers
172,219 comments
4,824 users