0 like 0 dislike
9.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * **** * **** ** x[] = {77,22,88,11,22};
* * *** ** ** * * * size = 5;
    
* * * **** ** * print the array */
**** *** * * ** * ** * ** i = 0; i < size; i++){
*** * ** ** ***** * ** * * * * ** * *** * * *** ***** ", x[i]); * * * *** ****** ** * * * **** **
*** * ** * **
* ** * ** **** * ** *
* *** * * * * ***
** * * *** * * * ***** I need this to happen size-times */
* * * ***** * * *** ** j = 0; j < size; j++){
*** ** * **** * * *** * * * * * ** ** *** * from left to right */
* * ********* *** ** *** *** * ** *** *** *** *** i = 0; i < size-1; i++){
** ** * ** ** * ** ** *** * * **** ** * *** ********** * * ** * i-th element with its neighbor to check if they are in order */
* * * * * * **** ** * * ** ***** * *** * * * * * ** * ** * * > x[i+1]){
* ** ***** * * *** **** ** *** *** ***** **** * * * ** **** * * *** **** exchange the values of x[i] and x[i+1] */
** * ** * * * ** ******* ********* ***** ** **** * *** ******* * * **** * * **** * temporary; * ** *** *** *** * * **
* * * ** * ** * ** * ** * ** **** * *** * ******* ** ***** *** * **** = x[i];
* ** ***** * * * ** * * *** ** * * * * **** * * ****** **** ** **** * ** ** * = x[i+1];
** * * *** * * ****** *** * ** * * *** ** *** **** * * **** * ** * ** ** * * * ****** ** = temporary;
* * **** * **** * * **** **** ***** * ********
** ** * ****** * * * ** * ** ** * * *
** ** * * ******* *
* * ** * * *****
* ** **** * *** * * * print the array */
* * ** * ***** * * * *** ** ** * ** sorting: \n");
* * ***** **** * ** i = 0; i < size; i++){
* * * * * * * ** * ** * ** * ** * *** **** * ** * * * ** ", x[i]); ** **** **** * * *** ** ** * ** *** *
* ***** * ******* *
* * * ** *** ****** * * ** *
* * *** ** *
* * * * *** *** *
* * **** *** ***** ** ** * ** * **
* **** ***** * * ** * ** *** **** ** ** ** *  
* *** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** ** *** * ** x[] = {77,22,88,11,22};
* * ** * ***** ***** size = 5;
    
** ** * * * *** * print the array */
** *** **** ** ** * i = 0; i < size; i++){
*** * * * ** ** * ** * * * * **** *** * ** ** *** * * * * * ", x[i]); *** * * * **** * * * * * ** ** * *
** * * * ***** ***
* ***** * ** * ** *** * * * **** **
* * * ** * * ** *****
** * ** ** * * **** ** * ** I need this to happen size-times */
*** * ** * * ** j = 0; j < size; j++){
*** * *** * ** ** ** ** ** *** ** ****** * * from left to right */
**** *** **** * *** * * ** * * * * *** **** **** i = 0; i < size-1; i++){
* * * **** * * ** * * * ** **** *** * ** ** ****** * * ** ** * * * ** * i-th element with its neighbor to check if they are in order */
*** **** * * *** ** * * * ******* * * * * * **** * ** * * ** ** > x[i+1]){
******** * * * ** ** * * * *** * ** *** * ** *** * ** ** * * *** *** * ** * * exchange the values of x[i] and x[i+1] */
* ***** * * * * ** * *** * ** ** ** * * ** * * ** **** ***** * *** * ** * *** * **** * * * * ** temporary; *** * ** * ** * * * **
* * * **** * * * * * *** ** * * * ** * * ** ** * * ** ** ** * ***** ***** ***** *** = x[i];
* * *** * * * * ** *** ** ** ** ** ** ** ** ** ** * ***** * *** * * ** * * = x[i+1];
*** * * * * ** * *** **** * * *** * *** **** * ***** * * * * ***** **** * * * * *** ** = temporary;
* *** ** * **** *** ** **** * ***** * * * * * * ***
* **** ***** * * ** * ** * * **** *** *
***** ** * ** ** * *
*** ** * *** ** * * *
* * ** * * * ** ***** print the array */
* * * ** * * * * *** * * ***** sorting: \n");
**** ******* ** **** * * * i = 0; i < size; i++){
* * ** ** * *** * * * ** *** * ** *** * * *** * ** ", x[i]); ** *** * *** * * * *** * * *
***** **** **** * * **
* * ****** * ** ** * * ***** *
** *** ** **** * ** *
** * * * * *
* * *** *** ** * ** **** *** * *
* *** * * * * *** ** * * * ** * ****** *** * *  
****** * * * * * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** * * * * * ** * x[] = {77,22,88,11,22};
* **** * ** * *** * * size = 5;
    
* ** * * * * *** * * print the array */
* *** ** ** * *** ** ** * * * i = 0; i < size; i++){
*** **** ** *** * * ** ** ** ** * **** ** ****** ", x[i]); ** * * * * **** ** *
** * *** * * * ***
* * ** *** * ** * * * * * *** ******* * *
** * * *** * *
* **** ** ** * * I need this to happen size-times */
* * ** * * ** ** * * * * ** j = 0; j < size; j++){
*** ** * * *** *** * ** ** * * * ** * * * from left to right */
*** *** *** ** * *** ** ** ** * ** * * ** **** i = 0; i < size-1; i++){
**** ** * ** ***** * * * * *** ** * * *** * * * * * ** * ** * i-th element with its neighbor to check if they are in order */
** ** ***** ******** ** * ******** ** * * * * * ** * ***** * *** * **** > x[i+1]){
* * * * **** * * **** * * *** ** * ** ** ** * * ******* **** ** * ** **** **** exchange the values of x[i] and x[i+1] */
*** * * **** * *** * * ** * * ** *** ***** *** *** * * * * * * ** * * * ** *** ** ** ** temporary; * ** * * * * * *** ***** *
*** * * * ** * * **** * ** * **** **** *** *** * *** **** **** *** * ** ** *** * = x[i];
***** * * * ** * * * *** *** *** ** * ***** * * *** ** * ****** ** * * ** * * * *** ** = x[i+1];
* * **** ** **** * * * * * ** **** * * * * ** * ** * * ******* *** = temporary;
* * ** * * * ** * *** ** * * * ***** * * **** **** ** ** **
** * * * ** ** *** ** ***** * *** ** *
* ********* * **** * *
**** ** * ** * ****
* * * * * * * * print the array */
** ** * * ** * * * * ** * *** sorting: \n");
* * **** * * *** * * *** i = 0; i < size; i++){
* * ** * * ** *** ** * * ** * * * * * * * * ", x[i]); **** ** * * ***** ** *** * * **
* ** * ** * ****** *
** * *** ** * ** * ** ** ***
**** * * *** **
* *** ** ** * ** *** *
** * * * ******* ** *** *** * *** *
* ** * * * * * * * * ** ****** * ****  
* *** * * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** ** ***** *** ** x[] = {77,22,88,11,22};
* * ** * * * * * * *** size = 5;
    
* * * * * * * *** print the array */
* **** * ** * * * ** i = 0; i < size; i++){
* *** * * ** * ** * ****** * * ** ** * * ", x[i]); ****** * *** ** * * ** * ** ** *
** ** *** ** ** *
* *** * *** * * * *** *** * * **** * *
*** *** ** * **** ** *
* ** *** *** * * *** I need this to happen size-times */
** * **** ** * * * * ** ** * j = 0; j < size; j++){
*** * ** ** * * * **** * ******** **** ** * * from left to right */
** * ** * **** ** *** ** * ** *** ** *** ** ** * i = 0; i < size-1; i++){
* ***** ****** * * * ** * ** ** * * * ** ** i-th element with its neighbor to check if they are in order */
**** * * * *** * * * * *** ** * ** * *** ** * *** * **** > x[i+1]){
* ** * * ** *** * * * * * ***** ****** * * * * *** * ***** ** * ** * * *** exchange the values of x[i] and x[i+1] */
* **** ********* * ** * * * ** **** *** **** **** * * * ** * ** ** ** * **** * * *** * temporary; *** ** * *** **** * ** ** * ** *** *
**** **** * * ** ** ****** * ** *** * ** ** ** ***** ** **** *** * *** *** * * ** *** * = x[i];
* **** * * * ** * ** *** * * ****** ** **** * *** * ***** * ***** * * * * * ** ** * ** * * **** = x[i+1];
**** * **** *** **** * * ***** ** * * * *** ** * **** * ** ** * * *** **** ** * * * * * ** * *** = temporary;
**** *** * *** * ** * * * ** ***** * * ** *** * * * * *** * **
* ** * ** * * * ** ** * * * **
* * * ** ** * **** *
** **** *** * ** * *
* * * * * * * *** print the array */
* * * * ** * * ** ** * * sorting: \n");
* ** ** * * * * **** * * i = 0; i < size; i++){
** * * ** ** * * **** *** * *** ****** * ** ** ** ** * ** * ", x[i]); * ***** * ** *** ** ******
** * * * * **** ** *
** ** ** *********** **** * * *** ***
* ** * ******** ***** *
** ** **** * * * * ***
* ** * *** *** * * * ** * * * ******
* * *** * ** **** * * ** ** ** * * * *  
******** *** *** **** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** *** *** x[] = {77,22,88,11,22};
* * * ** * **** * ** *** size = 5;
    
* * ** * * * **** *** * print the array */
* * * ******* ****** i = 0; i < size; i++){
* * * * **** * ** **** * *** *** * ** * * ******* ", x[i]); *** * * * *** * ** * * ***
*** **** *** * * **
*** * ** * * * * * ***** * ** ** ****
* *** * * * * *
** * * ** *** ** *** * I need this to happen size-times */
*** *** ** **** ** **** j = 0; j < size; j++){
**** * * ******* * *** *** * * * *** * * *** * from left to right */
** ******** ** ****** ** * * * *** ** ** ** * * i = 0; i < size-1; i++){
* ** * * ** ** * * **** ** **** ** *** ** *** ** * *** *** ** i-th element with its neighbor to check if they are in order */
*** * * *** ** ***** *** * *** * * *** ** *** *** * ** ** ** ** * > x[i+1]){
* ** * ** * *** ****** ** * **** *** * * ***** ** * *** * * * * *** * exchange the values of x[i] and x[i+1] */
******* *** * **** * ****** * * ***** *** * ** **** *** * * * ** * * * ** **** ** * *** temporary; ** * *** * **** ** *
** **** ***** *** ***** **** ******** * * *** * **** * * * ** ** * * = x[i];
* ** ** * * * * * *** *** ** * ** * ** ******* ***** **** ** * *** * * ** * * * * ** = x[i+1];
* **** * ** ** * * * ** ** * ** ** ** * * ** *** * **** * ** ** * * * **** *** * = temporary;
* * ** * **** * ** * ** * * **** *** **** * ** * * ** ** ***
* ** * *** *** ** ****** ** ****** * ** ** *
* * * * ** ** ** ***
* *** *** *** * ** *** **
*** * * ** * ** ** print the array */
* ** ** ** * * ** * * * ** * * sorting: \n");
* * ** ** * * ** *** * i = 0; i < size; i++){
* * * ** * ** * * *** * *** *** * **** * * ", x[i]); * * **** * ******* ** * * ** *
** * ** ** * ** **
* * ** *** * * ** *** **** **
* * * ** * ** * * **
* * ** ** * ***
* ** * ** * *** ** * * * * * ** *
** * * * * * ** *** **** * ** * *****  
** ** * ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * ** ** x[] = {77,22,88,11,22};
**** ** **** **** * * size = 5;
    
** ** ** * * ** * *** * print the array */
******* ** *** *** * * * * i = 0; i < size; i++){
** ** * * * * *** ** * *** ** * * * * * ", x[i]); * * * * * * * * *** * ** **
*** * **** * * *** **
** **** * * * * * ** * *** * * *** * *
** * * * * ********
*** *** **** * * *** I need this to happen size-times */
* ** * * * * *** * j = 0; j < size; j++){
* *** * * ** * * * *** * ** * * * ***** from left to right */
** *** * ** ** ** ** *** * *** ** ** * ****** ** i = 0; i < size-1; i++){
***** ** * * ** * *** * ** * * *** * * * * * * ** ** * * i-th element with its neighbor to check if they are in order */
* ** ** * ** ** * * * * * ** * ** ** * * **** ***** * ** *** * *** > x[i+1]){
** **** *** ** * * * ** * ** * ** ** ** ** * * * * * * ***** ** * * * * ** exchange the values of x[i] and x[i+1] */
* * ** *** ** * * * **** * ** * ** * * * ** * ***** *** * ** * * * * * * ** * ** * **** * temporary; * **** * * * * ** *** *****
* * * ** *** * * * * ** * * * ** * * *** * * * ** * ** **** * ** *** * * * * * * = x[i];
* *** ** * *** ** *** ** * * **** ** *** *** ** * * **** ** * * ***** ** *** * * = x[i+1];
* * * *** ******* ** * * * * * * * * * *** * * * ** * ****** ** ** * * ** * **** * * * = temporary;
* ** ** * * ** ** ** ** ** * ** * *** * * *** ***
* ** **** * * * *** *** ** * * *** *
* **** * ** * * ***
*** * ** ** *
*** * * * * *** *** ** ** * print the array */
* * * * **** ** * * * * ******** sorting: \n");
**** ******** **** i = 0; i < size; i++){
**** * *** * ** * * *** * ** * * * * * * ** * * ", x[i]); * * ** ****** * * * ***** * *
** * ***** * ** ** *
*** * * * * * ** ** * ** ** * ****
* * *** **** * *
* * * * ** * ** ***
* ** *** * * ** * * * * * **** ***** *
** ** ** ***** **** * ** * ** * ** * * *** *  
*** * ******** ***** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** *** ***** ** x[] = {77,22,88,11,22};
* **** **** * * ** **** * * size = 5;
    
* *** **** * ** * * print the array */
* ** ** ** * *** ** * i = 0; i < size; i++){
* * **** *** * ** *** * **** * **** *** **** **** * ", x[i]); ********* * ** * * ****** * **
** * *** * *********
**** ** ** ******** * * * * * **
* ** * *** * * ******
* *** * * * * ** * I need this to happen size-times */
* * * * ***** *** ** j = 0; j < size; j++){
** *** ** * * **** * ** * * * * *** ** * * ** * from left to right */
** ** * * * *** ***** *** ** * *** **** * ** * * ***** i = 0; i < size-1; i++){
* * *** **** *** ** ** ** ** * *** * * * ** ** ** *** * * ***** * i-th element with its neighbor to check if they are in order */
* * **** ** ** ** ****** * * *** * * ******* * *** * ** ** **** * **** * * > x[i+1]){
* * * * **** ** * * * *** *** * * *** *** * * ** * * * ** * * ** ** ****** * * exchange the values of x[i] and x[i+1] */
* *** * * * *** **** *** ** * * *** *** * * * * * *** ** ** * ** * * * * *** * * ***** temporary; * *** **** ** * * * * * ** **
***** * * * ** ** * * * ** ** * **** * * *** *** ** * ** **** ** *** ****** ** * = x[i];
** * * * ** ** * * * * **** ***** *** ** * *** **** * *** ******* * * * ** * ***** = x[i+1];
** ** * ** **** *** ******* * **** ****** * ** ** * **** *** * ** * ** * * * **** = temporary;
*** ** * ** *** * * * ********* * ** * * *** * * * * * ** * ** * * ****
** ** * ** **** * * **** ** * * * * ** *
** ******** * * * *
* ** * *** * ** * * * *
* * ** ********* * * ** ** print the array */
** * * *** * **** * * **** *** sorting: \n");
** ** **** ** * ** i = 0; i < size; i++){
** **** *** * ** * *** * ** * * * * ** ** * ", x[i]); * **** **** *** * * * * *
** * *** ***** ** *
* * * * * ** *** * ** ******* * ** *
***** ******* * ** * *
* * *** ** * ***** *** *
*** * *** * ** ** * ** * ** * * *** *** * *
** ** **** * ** * * ** **** ** * * ** * *  
* **** ** ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * *** * * ** x[] = {77,22,88,11,22};
*** * **** * ** *** size = 5;
    
***** *** * ** *** print the array */
* * *** * *** *** ** * ***** i = 0; i < size; i++){
* * ****** * ****** * ***** *** ** * ** * ** * ** ** ** ", x[i]); *** ***** * * * ** *** * ***** *
*** ** * ** ** * ** *
* * *** * * * ** ** ****** ** * * **
***** ** * * * * ** ** * **
* * ** ** * * *** * I need this to happen size-times */
* * * ***** * j = 0; j < size; j++){
* *** * ** ** ** ***** ** ** * * *** ** ** from left to right */
** *** ** * *** ***** *** * **** *** *** * i = 0; i < size-1; i++){
***** * ******* * ** **** * ** *** ** * * ** * ** ******** * *** i-th element with its neighbor to check if they are in order */
*** * ** * *** ** *** ** **** * * * *** * ** * * * * * > x[i+1]){
******* * ** * * * * * ** **** ** ** ** * * * ** ** * * * ** * ** ** ** * ****** * **** * exchange the values of x[i] and x[i+1] */
*** * *** * * *** ** ** *** ** ** * ** *** * * * *** * *** * * * ** ** * ****** * temporary; ****** * ** * ** * ** ** * * **** *** **
* * * * ** * ** * * ** ** *** * **** * ****** *** ***** ** *** * * * * * * * * = x[i];
** *** * * *** * * ** ** * * *** * * ** * * ** ****** * * ** ** * * * * ** * * = x[i+1];
**** *** *** * ******* ** *** * ** * ** *** * ******* * ** **** * * ** ***** *** = temporary;
*** *** *** * * ** ** **** * * * ** * **** * * ** * * * ****** * *
* **** * **** * * **** * ******** * * **** *
** *** * * * **** **
*** ***** ** * **** ** *
* * *** ** *** ** * print the array */
* *** ** * ** * **** ** *** * * * sorting: \n");
** **** * *** *** i = 0; i < size; i++){
* * ** * * *** ** ** * * * ** * ** * ** ", x[i]); *** * * * * * ** ** * * * * *
** ** * * * * ** **
** ** * * * *** *** * ** ** **** * ** **
** ** * * **** ** ***
**** * * * *** * *
** ** ** ********** * ** ** * * *** ***
**** * * * * ** * ****** *** * * * *** ** * * **  
* * * ** ** * * ** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ** ** * x[] = {77,22,88,11,22};
* ** **** * *** ** size = 5;
    
** * * ** * *** * ** print the array */
* ***** * *** * * ** ** i = 0; i < size; i++){
* * * *** ** * * * ** ** ** * * ** * * * ** * ** * * * ", x[i]); * ***** *** ****** *** * ***** ** *
* * * * * * ** * *** **
****** *** ** *** * *********** *
**** **** * **** *
** * * **** ** I need this to happen size-times */
* ** ** * ** * ** ** j = 0; j < size; j++){
*** ** ** * * * ***** * * * ***** * ** * ** from left to right */
* ** * * * * * ***** * ******* * * * i = 0; i < size-1; i++){
** * * ** ****** ****** * ** ** **** *** * * * * * ** * * ** ** * ** * i-th element with its neighbor to check if they are in order */
** ** * ** ** ** * * ** * ** ** ** ** *** * ** ***** * *** * * *** > x[i+1]){
**** ** *** ** ** ** * ** ******* * ** * ** * * * * * * * * * * ** ** ** * * *** ** exchange the values of x[i] and x[i+1] */
* *** ** * ***** ** **** *** * * **** ** * * * * * * * **** * **** * * * ***** * ** temporary; * * ** * * * ** * * * * * **** *
**** * ** ** * ****** * * ** **** * * ****** * * * ** * ** * * * * * **** *** * * ** * * * = x[i];
* ** *** *** ***** * ** * ** ** ** ** * * *** * * * * * * * *** ** ** * * * * = x[i+1];
* *** *** *** * *** * * ** ** ** * ***** ***** * * ***** ** *** ******* *** * * *** * = temporary;
** * * * *** *** * * ***** ****** ***** * ** * * * *** * * *
* * * ***** * ** ** * * * *** **** *
* ** ******* * *
* * **** * ***** ** ** *
*** ** * * * ******* * * print the array */
** * * **** ** *** ** * ******* sorting: \n");
* ** *** *** ** * ** i = 0; i < size; i++){
** * *** *** * * **** ** * **** * * * ***** * * *** **** ", x[i]); ** ** ** * * *** * * * * ** ** ** *
* * ** * * * ** *
* ** ** * * ***** *** *** ** ***
* ** * * ****** * * ****
** ******* * * ** * ** ***
** * * * * * **** ** ** ** ** ** * ** **
** * ** ** *** * **** * *** * * * *  
*** ** * * **** *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** ***** *** x[] = {77,22,88,11,22};
* *** * ***** * * ****** size = 5;
    
** ** **** * * *** print the array */
* ** *** *** * ** * *** * i = 0; i < size; i++){
********** * ***** ** *** * *** ** * *** * *** ", x[i]); *** *** ** * *** * ** * * ** *
* * * ** * *** * * * **
** ** * * * ** ** * ** ***
*** * * * * * * * * *** ***
* * **** * * * ** * * * I need this to happen size-times */
* * *** * ** * *** * j = 0; j < size; j++){
**** * ** * * ***** ** ** ** * ** * * from left to right */
** ****** * * ***** * * * *** * * *** **** * i = 0; i < size-1; i++){
* * *** * * *** * ** * *** * *** * * * * * ** * * * * * * *** ** i-th element with its neighbor to check if they are in order */
* *** *** * ** ** * * *** **** * ** ** *** **** ** *** * * *** * *** > x[i+1]){
* * * *** * * * ** * ** ** * * ** ** * * ***** * * ** * ** * ******** * ** * **** exchange the values of x[i] and x[i+1] */
*** * ** * * **** * * * ** ** ** * *** ** ** ** ** ** * **** * ** *** ** * * ** * temporary; ** * * * * ** *** * **** ** *
* ***** *** ** * ***** * *** ******* ** * * **** * * ** **** *** ** *** * ** ** ** ** ** = x[i];
* ** ***** *** ** * ** ***** *** * * * **** * *** * *** ** ** **** *** *** * * ******* * = x[i+1];
* ** * ** ** ** * ** ** ***** ** **** * * **** * ***** * * * * *** ** *** * * * * * * = temporary;
* * * * * * ** * * ** * * * *** * * * *** *** *** * *
*** * * ** * ** * * * *** * ** *** ** ** * *
* ** * ** * * * * ** ***
* * ***** * ** * * **
*** ** ***** * *** *** ** print the array */
* * *** * * * * ** *** * * **** * sorting: \n");
** *** * ******* ** ** * i = 0; i < size; i++){
* ** **** ** * *** ** ** * ** ***** * ", x[i]); ** ** * ***** * * * * * ***********
** ** *** * * * ***
** ** * ** *** ** *** * *****
*** *** **** * ** **
* *** ** ******* * *
****** ***** **** * * *** * * ** *
** ***** ** * ***** * *** * *** * * * * **  
* ** ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.190.141
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users