0 like 0 dislike
13k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 13k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******* ** * **** * * * x[] = {77,22,88,11,22};
* * ***** * ** * size = 5;
    
**** ** * * ** * * ** print the array */
* * * ****** * * * *** * i = 0; i < size; i++){
** ** * ** ** * *** * ** *** * **** ** * ** * * * ", x[i]); * *** * ***** ** *** * **** * *
******** ** * ***
* ** **** * ** **** * * * * * * * ** **
** *** * ** *
*** * * ** ** * * *** I need this to happen size-times */
*** * * **** **** j = 0; j < size; j++){
* * * * ** * *** *** * ** * * ** *** *** from left to right */
** * ** * *** * * **** * * * * **** i = 0; i < size-1; i++){
* * * * * * ** *** * ** * ** * * ** * * * ** * * * ***** * i-th element with its neighbor to check if they are in order */
** * * ** * ** * * ** **** *** * *** * ******* ** *** ** * * * ** * > x[i+1]){
**** * ** * * * * * **** ******* ** *** * * * * * ** ** * *** *** *** ** ** *** ****** *** * exchange the values of x[i] and x[i+1] */
**** * * * * *** * * *** * ** * **** **** * * ** * * **** * * *** ** * * * temporary; ** ** ** ** * ** * * * * *
*** * *** * * ***** *** **** * *********** ***** * * *** * * * * *** * *** ** ** * ****** = x[i];
****** **** **** ***** * * ** * * ** * ** * * * * * ** *** * ** *** * *** * ** * *** ** * = x[i+1];
* * * * * ** * * ** * ** * * ** **** ** ** ** * * * * * * ** ** * **** * ** ** * * ** = temporary;
* * *** *** * * * * * ** *** **** * * *** * * ** * * *** *
* * * * ** * * * * ***** ** * * ** *
***** ** * * *
* *** * * * *** *
**** * **** ** **** print the array */
* * ***** * * ** * * * * ** *** **** * * sorting: \n");
* ** **** **** * * ** ** ***** * i = 0; i < size; i++){
***** ** * * * * * * * ** ** *** ** * **** *** ** ", x[i]); * * *** * * * * ** * * *** **
** **** ***** ** * * *** *
* ** ** **** * **** ** *** **
** * * * * ***** **
* *** *** * *** * *
**** * *** * **** *** **** ** * *** **
**** * * * ** ******* * **** * * ** ****  
****** * ******** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** * * * * x[] = {77,22,88,11,22};
* ** * * * ** * size = 5;
    
* * * **** ** * * * * print the array */
** *** * ***** *** * *** i = 0; i < size; i++){
* ** ** * ** * * * * **** * * * * *** *** *** *** ", x[i]); * * * **** ** * **** * * ** ****
** ** ** * * *** *
***** * * ** *** * *** * *****
* ** * * * ******** * ***
* ** *** *** ** * * ** I need this to happen size-times */
** * * * ** *** * * ***** j = 0; j < size; j++){
*** * * * * ** ** ******** * * *** * * from left to right */
** * * * * * ** *** * ** ** ** ** ** *** * i = 0; i < size-1; i++){
**** *** ** * * *** * * ** *** * * *** ** **** ***** ** * ** ** *** **** * **** i-th element with its neighbor to check if they are in order */
* ******* *** ** *** ** *** * * * * *** ** ** ** * * * * * * **** > x[i+1]){
* ** * * * * * * **** * * ** * ** ** ** ******* * ** **** ****** * ********** * * exchange the values of x[i] and x[i+1] */
** * * ** * **** * * ** ****** * * * *** ** ** ** *** * ** * * * * * *** * * * * *** ** temporary; * * *** * * ** *** ** ** *******
* ** * *** * ** *** * * * * *** ** * * ***** * * ****** ** ** * ** * * * * ** * * = x[i];
* * * * ***** * ** * * * ***** * * ***** ** * * * ** * ** *** ** * * ** * ********* * * = x[i+1];
* * * * ** * * * ***** * * *** **** * * ** * * * *** ***** ** *** ** * ** ** * = temporary;
* ** * ** * ** * ***** ** * *** * * *** *** * * ****
** * **** *** * **** *** * ** * * ** * ** **
** * ***** ** ***
* * * * ** ****** **
** ** ****** * **** * print the array */
* * ** ** *** ** ** * * * * **** sorting: \n");
***** ***** **** *** *** * ** i = 0; i < size; i++){
* * * ** * * ** * * * * * ** *** * ", x[i]); *** ****** * **** * **** * * *
* *** *** *** * ***
* ******* * ***** * * * * *** ** **
* ** ** * ** ** ******* *
** *** * * * **
* * * *** ** *** **** * * * * *
* **** * ** * *** *** * **** *** * * *** * * * *  
** * ** * * ** ** *** ** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * ** ******** * x[] = {77,22,88,11,22};
***** ** *** * * * * ** * size = 5;
    
* ** ** **** *** * ***** print the array */
* *** * ** * * * * * * i = 0; i < size; i++){
** ***** ***** * *** ** * ** * * * * ** ** ** * ** ", x[i]); * ** * * ** * * * ***** *
* * *** **** * * ***
* ** **** * * * *** * * * *** * **
* **** * ****** *** * *
* * ****** ** ** ** I need this to happen size-times */
* * * *** ** *** * ** *** j = 0; j < size; j++){
* * **** * * *** * * * * * * ** * * * ** from left to right */
** ** ** ** *** ** *** ** ** * * **** i = 0; i < size-1; i++){
* * ** *** ** * * ** *** ** * * * ** * **** * * * * *** * * *** ** * * i-th element with its neighbor to check if they are in order */
** *** ** ** ** * * ** ** * * * * * ** * *** *** ** * **** * > x[i+1]){
** * ****** ** * ** * * ** *** * ** * ** * **** * * ** ** ** * *** * *** ** ** * * exchange the values of x[i] and x[i+1] */
* * * * * ** ** *** ** ** * * * * ** * **** ** ** *** *** * **** * * ** ** * *** * ** * temporary; ******* ** * ** * **** * ***** *
* **** * * * *** * ** * ** * * * **** ** * * ** * **** *** * ** * * *** * ***** ** ** *** ** ** = x[i];
* *** ** ** * * *** * ** ** *** * **** **** ** * * * * ** * ** * ** * ** *** * = x[i+1];
* ** *** * * * * * * ******* ** ** ** * **** ***** * * ** **** *** * * * * **** * ***** ** = temporary;
*** *** * *** * *** ** * * *** ** ** * ** * ** * * ** ** ***
* * * * * * *** **** ** ***** **
**** ** ** **** * * ** * **
* * *** * * **** **** *
*** * ** * * * ** print the array */
** * * ** ****** * * * ** * ** * * ** sorting: \n");
* *** ******* * * *** * ** i = 0; i < size; i++){
* ** ** * * * * *** * ***** **** * *** * ** ** * * * ", x[i]); * ** * ** ** * *** *** * ** * ** ***
* * * * * ** *** **
****** **** ** * * * * ********
* *** * * * **** *
* * * * ** * * *****
***** ** *** * ** ** ** *** *
* ** * * ***** * ** *** * ** *** ** ****  
* ** * *** * ******** ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** * ** * * ** x[] = {77,22,88,11,22};
*** ** ** * * * * ** * * size = 5;
    
* **** * * ***** * * * * print the array */
* *** * * ** ** * * i = 0; i < size; i++){
* **** * * ** * * * * * * * * * * *** *** ", x[i]); * *** ** * ** * **** *** * *****
** ** *** * *** *
* ** * * * **** ** * * * * ** * *
* ** ** * ** *** * ***
* ******* ** * ** *** ** * I need this to happen size-times */
* ** * * * ***** ** j = 0; j < size; j++){
* * * ** ** *** ** ** **** ** ** *** * *** from left to right */
*** * ** *** ** ** ** ** ****** * i = 0; i < size-1; i++){
*** * * **** * * * * * *** ** *** ** *** ** **** * ** * *** ** i-th element with its neighbor to check if they are in order */
* *** * * **** *** ** ** ******** * * * * ** * * *** * ** * * > x[i+1]){
** ** ***** * *** * ** * ** ** * * * ** ** * ** **** * * * ** * * * * * ** ** * * ** * exchange the values of x[i] and x[i+1] */
** * * * ** **** *** ** * *** * ******* * * ****** ** * * * ** ** *** ** * * ***** * * *** temporary; * **** * *** * * ** * * *
** ** ***** ** ** * * * * ** ****** *** * ** *** * ** ** * * ** ***** *** **** * * * ** = x[i];
** * ** ****** ** * ***** * ** ** ******* * **** **** * * * * * * * **** * * * * = x[i+1];
* * ***** * ** * ** ** *** ** **** * * * * *** ******** * * ** * ** * ** * ** * * *** = temporary;
** *** * ***** ** ** * * *** *** ***** * * **** * ** * ** * ***
** * **** * ***** *** * * * *** * * ***
* **** * * * ** *
********* ** * **
***** *** * *** * *** **** *** print the array */
*** *** **** * *** *** * * sorting: \n");
** * *** * * * * *** i = 0; i < size; i++){
** ** * ** **** * *** ** ** *** * * ", x[i]); **** * ********* * * **** * *
** ** *** ***** ***
** ** * * * *** **** ** * * * * * *
* *** ****** ******
* ** ** ***** * * * ****
*** ** * * **** * **** * * *
* * ** *** *** *** * * ******* * *** * ****** ** * **  
**** ***** ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * ** x[] = {77,22,88,11,22};
****** *** ** ** ****** size = 5;
    
* ** *** * **** * **** print the array */
* * * ** **** * * * *** ** ** i = 0; i < size; i++){
* * * * * ** ** * ** *** *** *** * ** ", x[i]); * *** ** * * **** * *** *
** * **** ** ******
* * ** * * * *** * * ** * ***
** * * * * * * *
*** *** *** * I need this to happen size-times */
* * ** ******* * * * j = 0; j < size; j++){
* * * * * ******* * * ** ***** *** * from left to right */
* ***** ** *** * ** ** * ** * * ** * * *** * i = 0; i < size-1; i++){
* *** * ******* ******** * * **** * * ** * **** * **** * ** ** * * ** i-th element with its neighbor to check if they are in order */
*** * ** * * ** ** * ** * * * * ** **** ** * ** * * **** ** > x[i+1]){
* ** * * ** * * * * * * * * * ** * * * * ******* * * * * ** * *** **** **** ** * *** * * ** *** exchange the values of x[i] and x[i+1] */
** ** **** * * ***** * **** ****** ** ** ** * ** * * * * * * ***** * ** ***** * temporary; * ******* ** ** * ** ** *
** ******* *** ***** * ** * * * *** *** **** * ****** * *** * * ****** **** ** ** * ** ** * *** = x[i];
** **** *** ******** ** ** * * *** * * * * ** **** * * ** * * *** *** * ** * = x[i+1];
* * ** *** ** * * * *** * * ** * *** * *** * ** *** ** * * * * **** * * * * = temporary;
** ** * *** * * * * * **** ***** **** *** * * * ** ** **** * *
** ** * ** * * ** * * * ** **** **** * *
* * * **** * ** * ***
** * * * ** * **
* **** *** * ******* * print the array */
* ** ** * *** * * ** ** sorting: \n");
* *** * * ** * ** * i = 0; i < size; i++){
* ** * * * *** *** **** * ***** * * ** * *** ** * ** * * ", x[i]); * * * * * * * ***** * * *
** * * *** *** ** * ** *
** * * *** **** ** *** * * * * ** *** * * *
** * ** ****** ** *
** ** ** **** * ***
******* * *** *** ** * ** *** *** * * *
* *** * ******* * **** *** * * **** *** *** ***** **  
**** * * ** ** ********** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** *** * ** * * * x[] = {77,22,88,11,22};
** * *** * ****** ** * * size = 5;
    
* * ** * * * * ** * ** print the array */
* ** *** * *** * * * **** * i = 0; i < size; i++){
**** * ** * * * * *** * * * *** * ** ", x[i]); * * ** * *** * *** ** ** ** ***
* * ** ** * * *** ** *
* *** * * **** ** * ** *
* **** * *** * ** *** **
* * ***** * * I need this to happen size-times */
* * * * ** * ** ***** *** * * * j = 0; j < size; j++){
* * ***** ** **** ** * *** ** *** * ***** from left to right */
*** * ** * * * * * * * * * * * * * * *** * i = 0; i < size-1; i++){
* ** ** * * *** ** * ** ** ** ** * * **** ** * * * * * ** * ***** i-th element with its neighbor to check if they are in order */
* ** * * * ** * * * * *** *** * * * * * * * ** * * * > x[i+1]){
** * ** **** * * ** * * *** ******** * ** * **** * **** * * * ** ** * ** *** * exchange the values of x[i] and x[i+1] */
** ** *** * *** ** * *** ** * **** * *** *** * ** * * ** * ** **** ** **** * * ********* ** * temporary; *** ***** ** ** * * * * **** **** *
** * * * * **** ** * *** * **** *** ** ** * * *** * * *** *** ** ** * * * ** * ** ***** = x[i];
* ** ***** ** * * *** * * * ** ** **** *** * * * * ****** ** * **** ** **** * = x[i+1];
***** * ** *** * * * ** * * ** * * * * * * * *** ** ******** * **** ** *** * ** * = temporary;
***** ****** **** * ** * * * ** * *** ** * ** ****** * * *
** * ** ** ** * * ** *** ** * * ** * * **
*** * * * ** ** ****
* ** * * * * ** **
** ** * ** * * ***** *** print the array */
* ** ** *** * * * * * ** *** sorting: \n");
* * ** *** * * * * i = 0; i < size; i++){
**** *** **** ** * * ** ** * ** **** ***** * ", x[i]); *** **** *** *** * ***** ** * *
* ***** * * *** ** **
** ** ** * ** * ** * ***** ** * ***** * ** **
* ** * ** * * ****
**** *** * *** * *****
* **** * ** * * ** * * * * * *** **
* * *** ** * * *** * ** ** * ** * *  
* *** * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** ** **** * x[] = {77,22,88,11,22};
** * * ****** * * *** * size = 5;
    
* *** **** ** print the array */
* * * * ** ** * ***** i = 0; i < size; i++){
* *********** ********* * *** *** ** ** **** * ** * * ** ", x[i]); ** * * * * * * *** * * ** * * *
* ** ** * * *** ** * **
*** ** * * * * * ** * * *** ** **
*** *** * ** ** * **
* * * * * *** I need this to happen size-times */
* * ** **** *** ** **** j = 0; j < size; j++){
** * ** * ********* * * *** ***** ** from left to right */
**** * ** ** ** **** *** **** * * * ** *** *** i = 0; i < size-1; i++){
*** ** *** * * ***** *** * **** * ******** * * *** ** * ** * **** * *** * i-th element with its neighbor to check if they are in order */
* *** * * *** *** **** ** ** * * ******** *** * * * *** * * * *** * ** > x[i+1]){
* ** **** ** ** **** * * ********** * * ** **** * ** ** *** ****** * ** * * * * * exchange the values of x[i] and x[i+1] */
**** * * **** * * * * * *** ** * * ***** * * * * * ** * *** ** ** ** * temporary; * **** * ** * * ** * ** * **
* ***** ** * * * * ** *** *** * **** * * * * * * * ** * * * *** ** * **** * = x[i];
* * *** * * *** * *** * * *** * * ** ** * * * **** * * * ** ** *** ** * *** ******* ***** ** = x[i+1];
* ****** *** * ****** ** * * * ****** * ********* * * * * *** * **** * **** ** * = temporary;
* * * * * ** * * * *** *** * * *** ***** * * ** * *** * * **
** * ** * *** * ****** ** * ** *** *** * * * *
* ** * **** **** **
* * ** *** * * * *
* ******* ** ***** **** print the array */
* * *** * ***** ** **** * * **** sorting: \n");
* *** * * ** * ***** i = 0; i < size; i++){
*** * ** ***** **** *** * ***** * ** * * **** ** * * ** ", x[i]); * ** **** ********* * * * * **
** ** **** ** * ***
** * ** * *** * * ******** * **
** ******** ***** *
* * * *** **** * ** **
* *** * ** **** * * **** *** * ** * * ****
* * * ** * * * ***** * * * * * * * * ***** ** **** *  
* * ** ** * ** *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ******* * *** * * * *** x[] = {77,22,88,11,22};
* * * ** ***** ** * * size = 5;
    
***** * * * * ** ** *** ** print the array */
** * ** *** * ** i = 0; i < size; i++){
* * *** ** * * * **** * *** * ** * * *** * ", x[i]); ** * *** ** * ** ** **** ** * ***
* ** ** ** * ** *
* ** ** * * **** ******* * * * ***** **
** * **** **
**** * * ***** * ** *** I need this to happen size-times */
* *** ** ** * * * ** **** ** j = 0; j < size; j++){
*** * * ** ** ****** * *** * ** ** ** from left to right */
* ** ****** * * * *** * * * * * ***** *** * * * i = 0; i < size-1; i++){
** ** * ** * *** * * ** * * * ***** * **** * * **** *** **** **** **** * **** i-th element with its neighbor to check if they are in order */
* ** * ** ** ** ** ** * * ** *** * * ** ** ** * ** ** *** ***** ** * * > x[i+1]){
* * * *** ** ****** **** * * * *** ******** * * ** ******** ******* * * **** * * ** * exchange the values of x[i] and x[i+1] */
*** * * * * **** ** ** * ** * ** ** ** * ** ** * ** * ** * * ** * * ** * * * * ** * ** temporary; * ** ** * * * *** ** *** * ***
* * * ****** *** ** * ** * * ** ** *** ** *** ** ********* * *** * *** **** ** * * = x[i];
* * * ** * * *** ** ******* * * * ** ** *** ** *** * * ****** * **** ** * ** * ** ** = x[i+1];
***** * * ***** * * * * ** ** * *** * ** * *** * * ** * * * ** *** * * *** * * *** * ** * * * * *** = temporary;
* * * * * * *** * *** * ** **** ** * * ** * * * ***
* * ** * *** * *** * **** ***** * ** * * * **
* * * ** * * * ** ** *
** *** * ** *** ** ***
* **** *** * *** *** * print the array */
** * ** ** * **** *** ****** sorting: \n");
* * ** * **** * ** ** i = 0; i < size; i++){
*** * * ** * * **** ** * ** * * *** ***** ** * * ", x[i]); * **** *** ***** *** * ****** ** ** ** * *
* * * * * * * ** * *** **
* * ***** ** * ** ** ***** * ** * ** **
* * *** * * *** *** ** ***
* *** * * ****** **
** * * **** * ***** **** ** * *** ** * ****
**** * ***** ** ***** * ** **** * * * * ** **  
****** *** * ******** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * ** * ***** *** x[] = {77,22,88,11,22};
* * ** * * * * *** *** size = 5;
    
* * ** *** *** * * print the array */
*** ***** ** * * * * ** * i = 0; i < size; i++){
** **** ** * **** ** * ** * * ** * * *** * * * ** * *** ** *** ", x[i]); ****** **** * * ****** * * *** *****
** ***** ** * * ** * * * **
* * * ** * *** ** * * * *** *
** **** ** * * *****
* *** * * ** ** * * * * I need this to happen size-times */
** **** **** * **** ** j = 0; j < size; j++){
** ** * * *** ** ** **** * * * **** ** * from left to right */
*** ***** *** *** ** **** *** *** * * ******* *** * i = 0; i < size-1; i++){
**** **** ** **** ** * ** * **** *** ** * * **** * * ** * * * * **** * *** i-th element with its neighbor to check if they are in order */
* *** * * **** * *** * ** * **** *** * ** ** **** * * > x[i+1]){
**** ** * * * * *** * *** * ** * ** * * * * * * ** ** ** * * ** ** ** * exchange the values of x[i] and x[i+1] */
** * *** *** * ** * * ** * * * * ** *** * ** ** ** ** ** * * * *** temporary; * ** * ****** * ** *** ** ** *** * *
* * ** * *** ***** * * * ** * * * **** * * **** * ***** *** * * * ** * ***** *** * * ** = x[i];
***** *** * * ** * * ** **** *** * * ** * ** * * * * ** ** ***** ** * ** ** * ** *** * *** * = x[i+1];
****** * ** ***** * * * *** *** ** ** ** * * * *** *** ** ** ** ** ** * *** * * = temporary;
* ** ***** *** ** * * * ** * * *** ***** * ** * * **** *** * ** *
*** ** *** * * ** ** * * ** *** ** *
* * * * ****** ***
** * * ****** * * * * *
* ** * ** ****** * * print the array */
***** ** ** * * **** ** * ** **** sorting: \n");
* ** * ***** *** * * ** i = 0; i < size; i++){
* *** ***** ** ** ***** * * **** *** ** * ** ", x[i]); **** * * ** ** * * *** * *** * * * *** ***
** * * * * *** ***
* *** ** ** * * ** * ** **** ***** *
* * * * ** ******
* * * *** ****
* ** * * *** * * * ** *
* * * * * * ** ** ** ** * * * *  
* * *** ** ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** * * * * ***** x[] = {77,22,88,11,22};
* * ** * *** * ** ** size = 5;
    
** *** * ** * * * *** print the array */
* * ** * *** *** * * ** * i = 0; i < size; i++){
* **** * ** ** * * * * * *** * * * ** * * ** * * ", x[i]); ** *** **** *** * * * ** ** ** * * * *
* *** *** ** *** * **** *
*** ** * ** *********** * * ** *
** **** * * * ******
*** ** **** *** ** *** * I need this to happen size-times */
***** *** **** ** ** j = 0; j < size; j++){
* **** * ** * **** * ** *** ** **** from left to right */
* ** ** *** * ** *** * * ** * * *** i = 0; i < size-1; i++){
*** * * * * * * * * * * * ** * ** * * ** *** *** **** * ** * *** ***** * **** i-th element with its neighbor to check if they are in order */
* ** ******* * * ** ** * * * *** ** * ****** ** ** *** * *** ** *** > x[i+1]){
* **** * *** *** ** * * *** **** * * * * ** *** * * * * ** * *** * *** * **** ** * exchange the values of x[i] and x[i+1] */
* *** * ** ***** * * * ** * *** * *** * *** ** * * * ***** *** ** ******* * *** * * * * temporary; * *** ** * * ** * ** * **
* * * * *** ** **** ***** **** * ** * * ** * * **** ** ** ** * * * * * *** * * = x[i];
** * * **** * * * ************ * * **** * ** ** * * ** ** ** ** **** *** ** *** ** * *** ** = x[i+1];
** ** ** * **** ** **** * * * * **** ** * * * * * * ****** ********* * * *** ** = temporary;
* *** ** ** * ** *** * * * * * * * * * * * ** *
* ** *** * * ** * *** ** ** *** ** * **
* *** ** * * * * ****
* * * * * * **** *
** * * * ** *** **** print the array */
* ***** * *** ** **** *** * * * * * sorting: \n");
*** ** **** * * * ** * * ** i = 0; i < size; i++){
* * * *** * * ** * * *** * *** ** * ** ", x[i]); ** * * ** * * * *** ** * *** * ****
** * * * ** ** * **
* * *** ****** ** ** **** * * * ** *
*** * * ***** * * ** **
* ** * * ** * *
* * ** * * **** *** *** **** ** ** *
* * ** ** ** ** * * * * **  
********* *** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.8k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 7k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users