0 like 0 dislike
10.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 10.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** ** ** ****** * x[] = {77,22,88,11,22};
** * * *** ** * * ***** size = 5;
    
* *** * ***** * ** * * print the array */
***** ** ** ** * ** * i = 0; i < size; i++){
* * ** * ** ** *** * * *** ***** * * **** ** * ** ", x[i]); ** * * * ** ***** * ** ** *** * * **
** * *** ***** * *
*** ** * ** ** * *** ** ******** * ** * * * *
*** ** * * * ***
* * ** * ** I need this to happen size-times */
* * **** * * *** ** j = 0; j < size; j++){
* ** ** * ** * * * *** * * * ** ** from left to right */
* * * * *** ** * ***** *** * **** * * * **** * * i = 0; i < size-1; i++){
* ** * ** * * * * ** * *** ** *** ** * * * * * * ** * * ** i-th element with its neighbor to check if they are in order */
* ** * * *** ** **** * * ** *** ** * ** ** ** * * ** * * ** *** * * > x[i+1]){
** ** * ** * ** * * *** * ** ** * * ** *** ****** ****** * *** * ** * ** * *** ** ****** ******** exchange the values of x[i] and x[i+1] */
* ** ** * * ** * * ***** * * *** * * ****** *** * *** * * ** * *** * * **** *** ***** ** * ** temporary; *** ** * * ** ** *** ** *** *
* ******* ******** * **** **** * * *** **** ********** * * ** * **** * *** * * * *** * **** ** = x[i];
******* * * ** * * ** * * ********** **** *** * ******** * ***** * ***** * * ** * = x[i+1];
* * ** ** * * ** *** ** * *** ** * *** * ** * *** * * * * *** ** * * **** *** * = temporary;
* * * ***** * *** * * * * * ** * * *** ** * **** * ** *
*** *** * ** * * * * *** * * * ******
* * * * * *** *
* ** * * * ** *
** * * *** ** ** **** print the array */
* * *** * ** * *** ** ** ** sorting: \n");
* * ** * *** **** i = 0; i < size; i++){
* * * ** ** * ** * *** ** * *** **** ** ** * ** ** ** ", x[i]); * * *** * ** * * * **
* * ** ** ** ** ***
** ** * * * * ***** * ** ** * ** * * * ** ** ** **
** * *** * * ***
* **** * * ** * *** ** **
*** * ** *** * * **** * * **** ******
**** * * * ** ** * * * **** ** * * * *  
******* **** ** * **** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** ** **** * ** * x[] = {77,22,88,11,22};
******* * * * * * ** size = 5;
    
** ** * ** ** ***** print the array */
**** * *** * ** ** i = 0; i < size; i++){
** * *** * *** ** * ** * * * * * *** ** *** *** * ", x[i]); *** ** * **** ** ******* * * ***
*** * *** *** *** *
* * *** * * * ** * * * * ****** * ** *
* * * ** ** ** ** *
** ** ** *** * * * *** ** I need this to happen size-times */
*** ***** * * * *** ** j = 0; j < size; j++){
** * * ** * ******* ** * * ** ** * * ******* ** ** from left to right */
* *** * ** ** * * * ** ** * *** ** * ** **** *** **** * * i = 0; i < size-1; i++){
***** **** **** ** **** ** * * * ** ** * *** * ** *** * * ** ** i-th element with its neighbor to check if they are in order */
* ** * ** **** ***** *** *** * ** * ****** * * *** ***** * * **** * ** * > x[i+1]){
* ***** * *** ** * ** **** ** ****** * * * ** * * * ** * ** * ** * * **** * * ** **** exchange the values of x[i] and x[i+1] */
**** * * * * *** ** * * * * **** *** *** *** * **** * ** * **** ****** *** ** temporary; ** *** * *** * ***** ** ** **
** * *** * ** * **** * ** * * * * * ** * ** ** * * *** ** * ** * *** * * = x[i];
* * * * ** * **** *** ** * **** ** ** *** * *** ** ** ********* ** *** ***** * * = x[i+1];
*** *** * ** * **** * ** * * ** * ** ** *** **** * ** * * ***** ** * * ** * = temporary;
** *** * ** * * * * * * ** **** ** * * **** ** *
* *** * * ** ***** ** *** * * * * ***** * *** *
* * * ** ********* *
* ** ** * *** *** **** **
* * * * * * *** **** print the array */
* * ** * * *** **** **** **** sorting: \n");
* * * ** * * i = 0; i < size; i++){
**** **** ***** * *** *** ** **** *** * * ", x[i]); * *** * * ** * ** ** ** *
* * *** * **** * * ** **
** * ** * * * * * * **** * * *** *** *
** * ***** ** * ****
* *** * * * * **
*** * * ** *** * *** * *** **** ** * ***
* * **** * * * ****** * * * **** ** **  
** * * *** * * *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * ** *** * * * * x[] = {77,22,88,11,22};
* *** * ***** * * * size = 5;
    
* * * * ** *** *** print the array */
** * ***** *** * * ** * i = 0; i < size; i++){
** **** * * * *** * ** * * ** * * * *** * ** ** ", x[i]); * * *** ** ** * *** * * **
** ***** * **** **
* * * * * * *** **** * * * ***
*********** ** * *
* * *** * * * ** ** * I need this to happen size-times */
*** *** * * * * * ** j = 0; j < size; j++){
** ** ** ** *** ** * ** ** * ** * ** * * ** *** from left to right */
** * ** * * *** * ***** ** * * * * * ** *** * i = 0; i < size-1; i++){
* *** * *** ** * *** * ** *** ******* **** * * *** * * * * * * ** * i-th element with its neighbor to check if they are in order */
*** ** * ** *** ** * **** ****** ** ** * * ** * ** * * ** ** > x[i+1]){
**** *** **** *** ** ** * **** ** * * *** ** * * * * * * * *** ***** ** **** ** * * *** ** ** * exchange the values of x[i] and x[i+1] */
** *** * ** ** * **** * * ** ** * * *** * * *** ** * * **** * * * ** * *** * ** * temporary; * ** * ****** * *** *** * ** * *
** **** ** **** ** * *** ** **** *** *** * ** **** *** * ******** ** ** ** **** * ** * ** * * * = x[i];
** ** ** ** ***** *** ********* ** **** ** * ** * * * * ** * * * * * * ** ** ** ** = x[i+1];
* * *** **** ** *** ** * * * * ** * ***** ** ** * ** ** * ** * ***** * * = temporary;
* **** * * ******* ******* *** * **** *** *** *** ** ** ** *
*** **** * * *** **** * ** *** * *** *
** * * * ** ** * ** ****
* *** ** * * * *** **** *
* * * ** **** * * * * print the array */
** **** * * * * *** *** * * ** sorting: \n");
** * * * * i = 0; i < size; i++){
*** *** * ** ** ** ** ** ******** * * * * * * ** * ", x[i]); ** * * ***** * * * *
* * * *** * *** * * **
* * *** * *** * ** ** **** ** * **
** * *** *** * *
*** *** * ** ** * * * *
***** * ** ** ***** * * * * *** * * * **
***** * *** * * ** * * **** ***** **** ***** *  
* **** *** * ** ********* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ***** ** *** * x[] = {77,22,88,11,22};
* ***** * **** * ** size = 5;
    
* *** *** * * ** ** **** print the array */
***** ** * ***** *** * **** * i = 0; i < size; i++){
* ***** *** ** *** **** *** * *** *** * ***** * * ** * *** ", x[i]); * **** * * ** * * * ** * ****
**** ** * ** * * * **** *
**** ** * ** *** * * * ***** ***** **
* * * * ***** ** *
** * *** ** ****** * ****** I need this to happen size-times */
* ****** * ***** * * ** j = 0; j < size; j++){
* * * * * *** ** * *** * * ****** ** * * ** from left to right */
*** * * ** ** *** **** ** ********* *** * * i = 0; i < size-1; i++){
**** * * * * ** * * ** * * * ***** *** * * * * * ** * * * * i-th element with its neighbor to check if they are in order */
* * * ***** ** **** * * ** * ** ** * *** **** * *** * * * **** *** > x[i+1]){
** *** ** *** * * * * ** * ****** *** ** ** ** * ** * * * ***** * * * * ** ** exchange the values of x[i] and x[i+1] */
** * * ***** * ** * *** * **** * **** ****** ** ** ** *** * ** * * ** ** ** *** temporary; * * * * ** * * * * ** * ** *****
* * * *** * ** * ** ** ** *** **** * * * ** * ** * ** * **** * *** *** **** * * *** * *** ** * = x[i];
* ** * ****** ***** *** * * ** ** * **** * *** ** * ** * *** *** *** * * * ****** ** * * **** = x[i+1];
* ** ** * * * ***** ** ** * * * * *** * * ** * **** * * * **** ** ** ***** ** * ** = temporary;
* * ** **** * ** * * **** * ** * ** ** ** * ** * * * *** ***
* *** * **** ** * * * *** ** ** ** * * * *
* **** ***** * ** ***
* * * * * **** ** * *
* * * ** * * * print the array */
** * ** *** ** * * **** ** ** * **** sorting: \n");
**** **** * * * * * i = 0; i < size; i++){
** ** ** * ** ***** * * * ** * *** ** *** * * ", x[i]); *** *** ** * * * * **** ** **** **
* ** ** * ** * ** * *
** * **** * *** * **** ** * *** * **
* ** *** ** ***** **
** ******** *** * **
*** *** * ** ** * * *** *** * ** ***
* * * ** * ** * * **** * * **** ** * * * * ** * *  
* ********* * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** * * ** * **** x[] = {77,22,88,11,22};
* * * * ** ** * * ***** size = 5;
    
** * ** * * ******* * * print the array */
** ****** ** ** * ** ** i = 0; i < size; i++){
**** * * **** * ** * ** * * * * *************** **** ***** *** ", x[i]); * *** * * * * ** * ** * * ** *
* ** * * ** * **** * *
* ** * * * *** ** * * *** * *** * * ****
* ** ****** * * * *
** * *** *** * ** *** I need this to happen size-times */
** *** * * * * * * * j = 0; j < size; j++){
* ** ******** * ** *** * ** * **** * ** ** * * ** from left to right */
******** **** ** ** ** ** ******** * * i = 0; i < size-1; i++){
* * ** ***** ** * ***** * * ** **** * * *** *** * * ** * * i-th element with its neighbor to check if they are in order */
** ** ** * * * ** ***** * *** * * * * * * *** ** * * * * > x[i+1]){
* ** *** **** ** * * **** ** ** ** *** ** *** *** ** *** ** * *** * ** * * * * ****** exchange the values of x[i] and x[i+1] */
* * * **** * * * **** * ** * * * * ****** * *** *** * *** ** * ** * ** * * **** temporary; *** **** ** * * * * *** *
** * ** * * ** * * * * ** *** **** * * ****** * ** *** * ** * ** *********** ** ** = x[i];
** * ***** * ** ** ** *** * * * *** * * *** * ** ** ** ** * * * ** ** ** * * *** * = x[i+1];
* * *** ** ** **** *** * **** *** * * ** ** * * * ** * * ** * * *** *** = temporary;
** *** * ** ******* * *** * * *** ******* * * * *** *** * ***
* ** ** * * ** * * ** * ** *
*** * ** * * **** * * *
**** * *** * *** *** **
*** * ** ** ** * print the array */
* *** ** * *** * * ** ** **** sorting: \n");
** ***** * *** ** * i = 0; i < size; i++){
*** * * * **** * * *** * *** * ** **** ** * ** *** ", x[i]); * ** * *** * ** * * ** ** *
* *** * *** ** **
* ** * * ** * ** * ** * * **
** *** *** ** * **
**** * *** * * ** ** * *
**** * * ** *** ** * ** ****
* * *** * * **** **** * *** * **** *** ** * * *  
* * ** * * ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ***** * ** * x[] = {77,22,88,11,22};
*** * ** * * * size = 5;
    
** * * * ** * ***** print the array */
* *** ***** * ******** ** ** i = 0; i < size; i++){
*** * * *** * *** *** * * ***** ******* ** * * ** * *** * * ", x[i]); * * * * ** * **** ** ****
** * ** * ****** * * *
* *** *** * * ** ** * ** ** ** * * *
* * *** * * * **
* ** * * **** *** ** I need this to happen size-times */
**** ** * * *** * ** ** ** j = 0; j < size; j++){
** * ********* ***** ***** * ** * * **** ** from left to right */
*** * * * *** * ** * * **** * *** *** i = 0; i < size-1; i++){
* ** * *** * **** ** * * * * * ** * *** * * * * * *** i-th element with its neighbor to check if they are in order */
** ** * * ** * ** *** ** *** * * * ** ** * * ***** * * * > x[i+1]){
* * ** *** ******* * * * * * * ***** ** * * ** * *** * * ** * *** **** * * exchange the values of x[i] and x[i+1] */
** * **** ** ** ****** ** * *** ** * ** *** * ** ** * * * * ***** ** ** ** *** * * ** temporary; * ** ****** * * * * ** *** *
* ** * * *** ** ** **** ** **** ** * * * * ** ** *** **** * * * * * * * * = x[i];
** * ** ** *** ** * * ** * * *** * * *** ** ********** ** * * * *** ** * = x[i+1];
** * ** * ***** * ** * * *** ** **** * * ******* ** ** * ** ** * * * * = temporary;
* *** ** * * * *** * *** **** * *** * ** * *** ** * *
**** ** * * ***** * **** * * *********** * * *
** **** * ** ** * * ** *
* * * *** **** ** ***
**** * * **** ******* *** ** print the array */
** ***** * * **** **** ** * ** * * * * sorting: \n");
** * * *** ** **** * i = 0; i < size; i++){
* ** * ** * * * * ** * ** * ** * * * ", x[i]); * ** ** * *** *** * *
* * * ** ** * * ** * **
* * *** * * *** ** ** * ** * *
** * ** * ** ** ***
** * * *** ** ** * **
**** ** * ******* * * ******** * ** * ***** **
******* ***** ** ** ******* ******* * ** * ** *  
*** * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** * ******* **** * x[] = {77,22,88,11,22};
** * *** * * ** * * *** * * size = 5;
    
*** * *** ** * * ** ** * print the array */
* * * * * * *** *** ** i = 0; i < size; i++){
**** * * ****************** ***** * *** *** * ** * * * ** ", x[i]); ** * *** * * ** * * ** ** ***
*** * ** *** *** * *
*** **** ** **** *** ** ** * ** **
*** ** ******* * * * *
* ** * * ****** * * ** I need this to happen size-times */
**** * * *** * ** * *** j = 0; j < size; j++){
*** ** * *** ** * * * * * ** ** *** ****** * from left to right */
* *** **** * ****** *** * ** * * * * * * i = 0; i < size-1; i++){
* * ** *** * * * * * * ******* ** * ** * *** ** **** ** * i-th element with its neighbor to check if they are in order */
* ** * * * *** *** * ** ** ** * ****** ** ** * * ** ***** * * ** > x[i+1]){
* **** * * ** * *** ** * ** *** * * * ****** * ** ** * * * * ** *** * * * ** exchange the values of x[i] and x[i+1] */
* * * * * * ****** * * * ** * * ** ** *** ***** * * * *** * ****** **** * ** * ** * ** temporary; *** * * *** ***** ** * ** *
** ** * *** ** * *** * ** ** ** * ** ** *** * ** * **** ** *** * * * ** ** = x[i];
* * * * * *** **** * * * **** **** * ** * *** * * ** *** **** ** *** *** * ** *** ** ** = x[i+1];
* * * * ** * * ** ***** * * * * * ** * * * *** * ***** *** *** * ** = temporary;
** * ** ** * *** ** *** * ** * ** * * ** ***
* ** * * * * * ** * * * *** *
* * * * * * * **** ** **
*** * * *** ** ** *
* ** * * ** * * * * print the array */
*** ** *** ** ** * * ** * * * sorting: \n");
* ** **** * ** i = 0; i < size; i++){
**** * ***** ** * ******** * ** * * * *** * * ** ", x[i]); ** * *** * ** ** * * * * **
* **** * * * *** ** *
***** * * ** ** * * ** ** *** * * * *
** ** ** ** ** * ***
*** ** * * * *** *** **
* * ***** * ** ** ** ** ** ** ********
**** * ** ** * * * * * * *** * ** *** **  
** ****** *** *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * * **** ***** * x[] = {77,22,88,11,22};
** ** * * * ** ** ** * * size = 5;
    
* * ** ** * * ** print the array */
**** * ** *** ** ** ** i = 0; i < size; i++){
* * * ** ** * ** ** * * * * ** **** * * * * *** ", x[i]); ***** ** ***** ** ** * * ** *
* * * ** ** * ** *
* * ** * * ** * * ** ** ** *** ** *
**** ** * * * * **
* *** *** * * * * * * ** I need this to happen size-times */
** ** ** ** *** ** ** **** j = 0; j < size; j++){
* * ******* **** * ** ***** *** **** * from left to right */
** *** * * * ** ***** *** * *** ***** * ** ***** ** * i = 0; i < size-1; i++){
*** ********* *** **** * *** ** ** ** * * * **** ** ***** ** * i-th element with its neighbor to check if they are in order */
* * *** * **** * ** ** * ** **** * * * ** ** ** **** **** * > x[i+1]){
** ***** * ** **** * * ** ** * *** * * *** ** ****** ** **** * ***** * *** **** ** ** * ** * exchange the values of x[i] and x[i+1] */
* ** ** * *** * * * * ** * * * ** * ** * * ********* * * * * ** * * ****** ** * temporary; **** * * * *** * * * ** * ***
* ** ******** * *** ** *** * * ** **** ** * * *** ** **** * ** ** * * * * * *** ***** ** * = x[i];
* **** * ** ** ** ** * * * ** *** *** *** * **** * * * ** * * *** ** * * ** = x[i+1];
** ** * **** *** ** *** ** * * * *** * *** **** ** *** * * *** *** * = temporary;
* *** *** * * * * ** * * ***** * ** * * **** * * ****** * * * *** * * * **
* * ** *** ** ** * * * * *** **** * *
* **** * ** *** ** ***
********** * **
** * ** ** * *** * * print the array */
** * ** * * * ** * * * * * sorting: \n");
* * * * ***** * * * i = 0; i < size; i++){
* *** * ** ** *** * * * * * **** * * * *** ", x[i]); *** *** *** * ********** ** *
**** ** *** ** *
** * *** * * * *** * * * **** * * ** **
** ** * ******* ** * * * *
** *** **** * *
* * ** * ** * **** * ** * **** * ** * * *
* *** ***** * * * ** **** **** *** ** * * * * *  
****** ** *** *** * ***** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** ** *** * * * * * * x[] = {77,22,88,11,22};
* ** *** *** * *** ** size = 5;
    
** * * * * ** ***** * ** * * print the array */
* ** ** ** *** * * ** *** * i = 0; i < size; i++){
* ** * * * ** * * **** ** *** ****** * *** *** ** * * ", x[i]); ** ** ** **** * * ***** * * ***** * *
**** * * ** * * *
* ************* *** * **** * ** *
* * *** ** ** *****
** *** * *** **** * I need this to happen size-times */
*** ** * *** **** * ** * j = 0; j < size; j++){
**** **** ** ** * * ** ***** ** *** ** *** ** * * * from left to right */
** * ***** * *** *** ** ** ***** ** ** * * * i = 0; i < size-1; i++){
* * * ** * ** * * * * * * *** ** **** ** * ** ****** ** * * i-th element with its neighbor to check if they are in order */
**** * * **** ** * ****** ** ** *** *** * * *** * ********* * > x[i+1]){
** ** * ** * * * * ** ** ** * **** * *** ** * ****** * * *********** * ** exchange the values of x[i] and x[i+1] */
** * * * *** ******* * **** * ** * *** *** * * ** * * * * *** ****** ** ***** * ***** temporary; * * * *** ****** * *** ** *** *
** ***** ** *** * ***** * * * ** *** ** *** * * * * * * *** *** *** **** ** ** **** ** ** *** * = x[i];
* ** * * ** * ** * * * **** *** * * * *** * * * *** * * * **** ******** **** ** ** = x[i+1];
* * ** * * * * *** * * * ** *** * * *** **** ** *** * * * *** * * * * **** * **** = temporary;
*** ** * * * *** * ** ** ** * ** **** * *** ** ** ** *
* ****** ** *** * * **** * ***** * ** * * * *
**** ** * ** ***
* * * * * * * * * *
** * ****** * ** * ** print the array */
** *** ** * **** * *** * sorting: \n");
*** * * ** *** * * * * i = 0; i < size; i++){
* ** **** * *** ** ** * * * * *** * *** * * *** ", x[i]); * * * * * ****** ** * * ** * * *
** **** ** * ***** * ** * *
** ** ** ** * **** *** ** ** ******* ***
* * * * * * ** *** * **
** *** * * * * **** *
* ***** * *** * ** *** * ** * * ***
** * * * * *** ** * ** *** ***** * *** *  
******* ***** ******* *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** ** ** ** x[] = {77,22,88,11,22};
* * ** **** * ***** *** size = 5;
    
*** * * ** ***** ** * *** * print the array */
** * ** ***** **** **** i = 0; i < size; i++){
*** * * * * * ** *** * * *** * ** *** * * ", x[i]); * *** ** ** * * * * * **
* ** *** ** * * ** ** ** **
***** * * * *** * * ** * * * * ** * * **** *
* ** ****** * * *** * *
* ***** * * * ** * * * I need this to happen size-times */
* ***** * * *** * * *** j = 0; j < size; j++){
*** ** **** * ****** * * *** * * **** * ** from left to right */
* ** * * *** * ** ** *** * ** * *** * i = 0; i < size-1; i++){
** ****** ** ****** ** ***** **** * * * ** * ** * **** * * * **** * *** i-th element with its neighbor to check if they are in order */
****** ** * * * * * ** * ** *** ** * ** * ***** **** > x[i+1]){
* ***** *** * ** * * ** * ** *** *** *** ** * * * **** **** ** *** ** *** * * ***** * *** * exchange the values of x[i] and x[i+1] */
* ** ** * * * * *** *** * ** * ** ** **** * * * ** * * * * * * * ****** * ****** temporary; ** * ******* * ** * * * **** * ** *
** ******** * ** ** ** * * **** ** * ** *** * * * ****** * * * * * * **** * ******* *** **** ** * *** = x[i];
****** * *** ** ** * * * *** * * ****** * * * * *** ** * **** ** *** **** * * * * * ** = x[i+1];
***** * *** ** * ** ** * *** ** * ****** * ****** * * * *** * * ** * **** * = temporary;
* * * * *** * *** * * * * * * * * * *** * * ** ****** *
* ** ** ********* *** ** ** ** *** ** * * *
***** ** * ***** * * ** *
* ******* * **** * *
** * * * **** *** * * * * * print the array */
** * ****** * **** ** ** * * sorting: \n");
** ***** * **** * ** ** i = 0; i < size; i++){
*** ** * ** *** * * ** ** * *** * * ** ** ** ** * ****** ** ", x[i]); * ** * *** * ***** **** * * **** *
* ** * * * *** * ******
* * * ******** ** **** ***** ** * ** ****
****** * * *** * *
* ** ** * ** *
* * * * *** *** ******* * * *
** * **** ** * * ** *** ** ****** ** **** *** * **  
* ** * *** * * ** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.245
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users