0 like 0 dislike
12k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** * * *** * * x[] = {77,22,88,11,22};
*** *** * **** ** *** size = 5;
    
* * * ** * ****** ** print the array */
** ***** * ** **** * * ***** i = 0; i < size; i++){
******* **** ** * * * ** *** * **** * * * * *** ", x[i]); * **** *** ** * * * * ** ***** *
*** * * * ** *
** ** **** *** * *** ****** *** ** *
*** **** * * * * *** *
***** * ** ** ** * *** I need this to happen size-times */
*** ** * ** ** ***** * * j = 0; j < size; j++){
*** * ** *** * ****** * ** **** *** ** ** ** **** from left to right */
* ** ** * *** * ** ** * * * *** * ** ** ***** * * i = 0; i < size-1; i++){
**** *** * * ** * **** * * * ** ** * ** * *** ** **** * *** * * *** i-th element with its neighbor to check if they are in order */
** * * * ** ******* ** ** * ** ** ****** * ** **** * * ** * ** * > x[i+1]){
***** * ** * * ** * ** * * *** ** ** * *** *** ** *** ** *** * * * * *** * exchange the values of x[i] and x[i+1] */
*** ** * * ** **** **** * *** ** **** * ** * * ** * * * * * ***** * * ** **** * * * * temporary; *** * * *** * * ** ****** **** *
** *** ** ** * * ** ** *** ** ** * * *** ** * * ** *** * ******* *** ** ** * *** *** ** ** = x[i];
*** ** * ** * **** * * * ***** * * * * * *** ** * ** * * * **** ********* ** * = x[i+1];
* ** * * * ***** * ** *** * * * * *** ** ** * * * * ** ** * *** ** * * * ** * **** ** = temporary;
**** ** * * * * *** ***** * *** * * * ** * * *** * *** * *
*** * * * ** * ** * ** ** * ****
** * ** * * * *
* ***** * ** * * ***
* *** * *** **** ** * * print the array */
* ** * ** ** ** * * * * ** sorting: \n");
** ** * * ** * ** * *** ** i = 0; i < size; i++){
**** * *** * *** * * * ** **** * ** *** *** ** *** ** ** * ", x[i]); *** * ** * ** ** ** ** * * *** * * *
* ** ******* ***
** * ** * ***** *** ***** * * * * ** *
** ** **** *** *** ***
* **** *** * * * * *
*** ** ***** * ** ** * * *
* * * *** ** * ** *** *** *******  
** *** * ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** * * * * ** ** x[] = {77,22,88,11,22};
** ** *** * ** ** ** * * size = 5;
    
** **** **** *** ** print the array */
**** * * * *** * * * ** i = 0; i < size; i++){
* * ** * * * * ** ** * * **** **** * * * ****** * * ** ", x[i]); * * ** ** *** * * * * *
*** ** * **** * * *** *
*** * ** * ** ** * * ***** *** * **
* **** ***** * *** *
** * * ** * * ** * * I need this to happen size-times */
*** * ** **** * ** j = 0; j < size; j++){
** * ** * * * ** * ** *** ****** ** from left to right */
* * *** * ** **** * * * * * * **** i = 0; i < size-1; i++){
* ** ** *** ** * * * *** * * ** *** ** * ** ** ** **** ** * ** * i-th element with its neighbor to check if they are in order */
* * ** * ** * ** **** ** **** * ** * **** *** **** * * *** ** * * > x[i+1]){
** ** * **** * * * **** * * ***** ** * ** * ** *** ** * * ** *** *** * * *** **** * * * * ** exchange the values of x[i] and x[i+1] */
* * * *** ** *** *** * * * * ** * ** *** * * *** * *** **** ** ** * * *** ***** ** *** * temporary; * * ** * *** ** *** * * ** *
*** ** ***** * * ***** * * * ** ** * ** ** *** * * * ** ** * * * ** ** **** * * * * *** ** ** ** * * = x[i];
*** ** ** * *** * * ** ***** **** ** ** * * * *** * ** * * *** * ** ** = x[i+1];
* ** * ** ** ********** *** *** *** * * * * ****** * ***** **** **** * *** * ** **** *** ** = temporary;
* * ** * * * *** ** * * * ** * * ** * ** * * ** *
** ** * * ** * ** * * ***** * * *** * **
***** ****** ** ** *
** * ******** **** * *** **
* ****** * ** ** ** * print the array */
****** * **** * * * * *** * * sorting: \n");
***** *** **** *** **** * i = 0; i < size; i++){
*** ** * * ** *** ** ** ** ******** *** *** ******* ** ", x[i]); * **** * * ** *** * ** * * *
** * ** *** * *** *
** *** **** * * * * * ** * *** ** **
* * ** **** ** * * ** **
** *** ** * * *** *
* ** * * ** ** ***** * ** * ****
**** **** * *** **** *** * * * * * *** * ** * *** * *  
* ** **** * * ** * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * ** ** * * x[] = {77,22,88,11,22};
* * * ** * *** ****** * size = 5;
    
* * * * * ***** * print the array */
* ** *** * ** **** *** * * i = 0; i < size; i++){
**** *** ** ** ** ***** ******* * ** ***** *** * * ** * ", x[i]); * ** ** * * ** ** * ** ***
* * ***** ** ****** * *
* * * * ***** **** * ****** * ** * ***
*** * ** * **** * *
**** ** ******** ** * * I need this to happen size-times */
* ** * **** * * * * * * ** j = 0; j < size; j++){
** * ** * **** * ** * * * * * * ***** * from left to right */
** * * * ** * ** * * * ** ** **** * **** *** i = 0; i < size-1; i++){
*** ****** *** * ** ***** * * ** **** * ********* * * * * ***** *** * **** i-th element with its neighbor to check if they are in order */
***** ** * *** ** ***** ** * ** *** ** **** * ** *** ***** * * ***** *** ** > x[i+1]){
** ***** * ** *** * * * **** * * * * ** ** * ** *** ** **** * **** * ** ** * exchange the values of x[i] and x[i+1] */
** *** * * * * *** * ** * * ** *** * ** * **** ** ***** *** * ** ** ** * * **** temporary; * ** *** * * ** *** * * * * * * ** *
* *** * ***** ** * ** ** **** * *** * * * * * ** **** **** ** * * ***** *** = x[i];
** ** *** *** * ** * ** *** ****** * * * * ** *** **** * * * ** * * * ** ** = x[i+1];
* *** ** **** *** **** ** ** * * ***** * * **** **** * * *** * *** ** **** = temporary;
****** *** * *** *** *** ** * * * ** * ***** * ***** * *
** * *** **** * * * * ** **** * * * **** * *
* * *** ** *** * **** *
* ** ** *** * * *
* ***** ** ****** ****** print the array */
* * * ** * *** ** * * * * ** * * sorting: \n");
* * ****** *** ** * ** ** i = 0; i < size; i++){
** **** ***** * * * * * * * * * * * * * * ** ", x[i]); ** * * ** * * * ** ** **
* ** ** * * * *** * * * *
**** **** ** * * * * * **** * * * *
* ** * * * * **
* * ****** *** *
** * *** * ***** * **** *
* * ** ** * * * **** * * * * ** * **** ** * * ***  
* ** *** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** * * * * ***** x[] = {77,22,88,11,22};
**** ** * * * ** *** * * *** size = 5;
    
* * * *** * * * print the array */
** * * ** ******* * *** *** i = 0; i < size; i++){
*** * * * *** * ** **** * ** ** ** *** * * * ** ", x[i]); * * * *** *** *** * ** *
*** * ** * *** * *
** *** ** ** * * * * ** * ** * *
* **** * * * ***** *
* ** ** ** *** * * * *** I need this to happen size-times */
* * * * * ********* ** *** * j = 0; j < size; j++){
*** * **** * * ** ** *** * * ** * from left to right */
* * * **** * ** * * * * * **** * * *** * * i = 0; i < size-1; i++){
*** ***** * * * ** * * ** ** * *** * ** **** * ****** ** ** ** ** i-th element with its neighbor to check if they are in order */
** *** * ***** ** * * ** ** * ** * ** * * * *** * ** *** * * * * * * > x[i+1]){
** *** ** * *** ** * * * * * * *** * * *** * *** **** * ** *** *** * ***** ** * * ** * ** exchange the values of x[i] and x[i+1] */
*** **** * * * * * ****** ** * ***** * * ** ** ****** ****** ** ** * *** * *** ******* temporary; **** * *** ** * *** **** ** **** *
********** *** * *** *** * ***** ********* *** * ****** * * ** * ******** ** ** * * * * * ** *** = x[i];
* * * **** * * ** * ** * **** * * **** * * * * * * * ** * * ** * ** * * **** ** ***** = x[i+1];
*** * *** * * *** * * *** * **** ****** ** * * **** ******* ** * * * ** * ** **** * *** ** * ** = temporary;
* ***** * ** ** ** *** * * * ***** * ** ** ** * ** **** *** *
* ** * * * *** * **** **** * **
** ********* * * ***
** ***** ** *** * ** **
* ****** * *** * print the array */
* * ** * * ** * ** * * *** * ** * * sorting: \n");
**** ** * * * ** * * ** * i = 0; i < size; i++){
*** **** * ** ** *** * *** *** * * ** * * * * *** ", x[i]); * ** * * * * * * ** * ** * *
***** *** * * **** *
** * *** **** ***** ** **** *********
**** * * * * * * ** ** **** *
* * * * * * ***
** *** ***** * *********** * * * * ** *
* *** ** * * * * * ************ * ** *** ***  
* * *** *** * *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * ** ** *** * * * *** x[] = {77,22,88,11,22};
**** ** **** ** * ** * size = 5;
    
** **** * * * * print the array */
*** *** * ****** ** ** * * * * i = 0; i < size; i++){
* ****** *** ** * * ** * * ** ** * * **** ***** ** ", x[i]); * * * *** ** * ** ***** *** *** **
* * **** **** ****** ****
* ** * *** **** *** * * * *** * * * ***
* *** * * * ** ** * * * *
** *** * * * ** I need this to happen size-times */
** ****** ** ***** ** ** *** j = 0; j < size; j++){
*** *** * **** ** *** * * ** * *** ** from left to right */
*** *** ** * ** ** *** * ******* * ** ***** ** ** i = 0; i < size-1; i++){
* * * * *** * *** ** *** **** ** * * * *** * ** ** ** ******* ** *** i-th element with its neighbor to check if they are in order */
* *** * ** **** * **** * *** *** ** ******* *** ** * * * * * * * **** > x[i+1]){
* ** * ** ** *** *** ***** * * * * ** * **** ** **** ** * ** *** * *** * ** exchange the values of x[i] and x[i+1] */
*** * * * ** * *** * * * *** *** * *** ** *** ** ****** ** ** ** * ** * ***** * **** * temporary; * **** * ** *** *** * **
***** * * ** ** * * *** * *** ***** * * * * * * * ** * * * * *** * ** **** **** * = x[i];
* * * * ** ** * ** ********* * ***** * ******* * * * ** ** * ****** * = x[i+1];
**** * * * ****** **** * * * ** * * * ** ** * ** * **** *** * * ** ** * * * * ** = temporary;
* ***** * * ** * * * * * * * * *** * ** ** * * * **
* *** **** * *** ** * * ** * ** ** * ** *
* **** * * *
*** * * ** *** *
* * * ** * ** ** * ****** print the array */
** * *** *** ** ******** ** * ***** * * * *** sorting: \n");
* *** * *** ** * * i = 0; i < size; i++){
** * * ** *** * * ** * * ** ** **** ** * ** ** ", x[i]); * ** * * ** ** *** * **** *
* ** *** * * **** **
* * * ** ** * ***** ****** *
*** *** * ** *
* ** ** * ** * *
* ** ** *** * * *** * ** * * * * * **
* * * * ** ** ** *** * ** * *** * * * ***  
* * * ** ** * **** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ************* *** x[] = {77,22,88,11,22};
* *********** ** * * * * * size = 5;
    
******* *** ** *** * ** * print the array */
*** ** * * ** * ** ** * i = 0; i < size; i++){
** * *** **** ** * * * * * * ****** * ***** * **** ** *** **** ", x[i]); * * * ** ** ** * * *** *** * *
* * *** **** * * * * * *
* *** *** **** *** * * *** * * * * * *
* **** * * * **** **
** * * * *** ** * I need this to happen size-times */
* * *** ** *** * ** ** j = 0; j < size; j++){
* ** * * * ** * ***** * * ** ** ** * *** * from left to right */
* * * * ******** * * ***** * * ** * * ** i = 0; i < size-1; i++){
******** * ** * * * ** * * * * * ** ** *** * ****** ** ** * * * * * *** i-th element with its neighbor to check if they are in order */
* *** * * * *** ***** ** ** * ** *** ** * * * ** * * * * ** ** * * > x[i+1]){
*** * * *** * ** ** ** * * * * * **** * *** * ***** ***** ** * * **** * * * exchange the values of x[i] and x[i+1] */
* ** *** *** * * * * * *** * **** * * * ** * **** *** * * * * * * * ** temporary; * * ** * * ** * ** * * * * ***** **
**** * ** ***** * * ********* * ** **** *** *********** * **** *** * * ** ***** ** * ** * * * * = x[i];
* *** *** * * *** ** * * * * ** ********** ** ** ** **** * * **** ** **** ** ******* ** ** ******* = x[i+1];
*** * * * * ** *** * *** * * ***** ******* * * ** ** *** ** *** * * *** ** ** *** * * = temporary;
*** * * * * * *** **** ** * ******** **** ** * * ** *
* *** ***** * ** ****** * * ** *** * ******
* ** ******* *
** * * * * * * **** * * *
** ** ** ** print the array */
*** ** *** * * * * * * ** * * ** ** sorting: \n");
** ** * * ** ** *** * *** * i = 0; i < size; i++){
* ** * ** ******* **** * ** *** * *** * ", x[i]); *** * ** * * **** * * *
* * * ** *
* ** **** * *** * **** ** **** * *** ***
* ** ** **** ** * ** * *
** * ***** ******* **
*** * ** ** * **** * * **** ****** *
* * ** ** ** * *** * ***** ** * * * *  
** * *** * ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * ** **** ** * ** * x[] = {77,22,88,11,22};
* * *** **** **** * * * size = 5;
    
*** * * * * ** ** print the array */
*** * ** * * * * * * * * i = 0; i < size; i++){
* ***** ** ** **** ** * * ** * ** ***** * **** * ** * ", x[i]); **** * * * * ***** * **** *
* * *** ** * * ***
* * * * * * ** ** * * * ** ** * **
* ** ***** * ******
**** * * * * ** * ** * *** I need this to happen size-times */
** ** * *** * ** ** * * j = 0; j < size; j++){
* * *** ** ** * * * ****** *** ** * ** from left to right */
**** **** **** * ***** * * * **** ** * * * ***** i = 0; i < size-1; i++){
* ** * * ** * *** * * *** *** ** ** ** ** *** ** ** * *** * * i-th element with its neighbor to check if they are in order */
* *** ** **** * * **** * * * * * * ** * ** **** * * ***** *** * * > x[i+1]){
** * * * ******* *** ** * * ** * * ** * * **** * ** ** * * *** * ****** *** *** ** * * * exchange the values of x[i] and x[i+1] */
** ** ** ** * * ** * ** ****** * ** ** ***** **** * * ** * * ** * * ***** ** temporary; * ** ** **** ******** * *** * ** *
** ** * * * * * * *** *** * ** ** ** * ** * ** ** ****** ** * * *** ** ** ** * ***** * * * * *** = x[i];
* * * * ** ** ** ** * * *** * * *** ** ** * ** * * ** * * ***** * * ** * * *** * *** = x[i+1];
* * * * * * ** *** ** ** * * ** * ** ** * ** * ** ** ** * * * * = temporary;
** ** ** ** * *** ** ** ** * * * *** * **** * * * *** *
** ** * * * **** *** * * * * ** **
**** ** * ** ** * *** ***
* ** ******* * **** *
**** ***** * * print the array */
** * ********* * *** * sorting: \n");
** * * * ***** * * ** ** * i = 0; i < size; i++){
*** * * * ***** * * * * ** ** *** ** ***** * ** ", x[i]); * * ** **** ** * *** * * * **
**** * * * ** ** ** ***
** * * * * * ** *** * * ** ** *
* * *** ** ** ** ** **
** * ** * *** * *** * **
**** * *** * *** * *** ***** **
* ** * ****** ** * *** * *** ** * * ** ***  
* * *** * * * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** * * ** * * * * x[] = {77,22,88,11,22};
** * ** ** * **** size = 5;
    
* ** * ***** **** ** print the array */
* *** * * *** * ** * * * i = 0; i < size; i++){
*** **** * * ** ** ** * * * ** * * * * **** * ** * * ", x[i]); *** * ** ******* * ** ****** ****
*** * * ** * * * ** * * *
* * * ******* ** * ** * ** * *
* * *** *** *** * ** *
***** * * *** ** I need this to happen size-times */
* ** ** * * * * * * * j = 0; j < size; j++){
* * ***** * * ** **** ** * ** * * ** * * *** * * * from left to right */
** * ** ** **** * * * * *** * **** * ** * * * i = 0; i < size-1; i++){
* * * * * * * ** * ***** * * **** * * ** * **** *** * ********* i-th element with its neighbor to check if they are in order */
** **** * ** *** *** * ** ** * * * * * **** ** ** * ** * > x[i+1]){
*** *** ****** * * * * *** * * * * * * *** * * * * * * ****** ****** *** * *** ********* * exchange the values of x[i] and x[i+1] */
* * * ** * **** * * ****** * ** * ** **** ** * * * * ** * **** ** * ***** ** **** * * temporary; * * * * ** * * **** * ** **
* * ********** * ************** * * * * * ** ** ** *** ** * * **** * * * * ** *** ** * * * *** ** * *** = x[i];
* *** **** ****** * * * ** ** ** * **** * *** * ** * * **** ** ** ******** ** ** **** * ** * *** = x[i+1];
* ** *** ** *** ** * * * **** ** ** * * ** * * * * * * ************ * ****** *** * ** = temporary;
** ** *** ** * ** ** * * * *** *** * * ** ** * ** * * *
** * *** * * * * * ** * * ** * ** *******
********* * ** * ** ** ***
* * * ** * *** * ***
* ** * **** **** print the array */
* * * ** *** * **** * * ** ** * * ** sorting: \n");
* ** ** * * *** * * i = 0; i < size; i++){
* * * ** ** *** *** *** * **** * ** *** * ** * ", x[i]); ******** ** ** ****** *
**** ** **** ** * *
* ** *** ** ** * * * * * *
*** *** **** *** ***
* ** ****** *** **** * **
** * * * *** * ** * **** * * **** *** *
** * *** ** *** * *** **** * *** ** *** *  
** ** *** ** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * * * * **** * * ** x[] = {77,22,88,11,22};
* * ** *** **** * **** * size = 5;
    
*** *** * * *** * * * print the array */
** * * ******* * * ***** ** i = 0; i < size; i++){
*** *** * ** * **** * * *** * **** *** ***** * * * ", x[i]); *** * * ***** * **** * *** *
* * * *** * * **** * *
*** * ** ** ** * ******* * ** * *
*** * ** ** ** * ** * * * *
*** *** *** * **** * * ** I need this to happen size-times */
** * * * * * * ***** j = 0; j < size; j++){
* * * ** * ** * *** * ** ***** * * * from left to right */
** * * * *** *** ** ******* * **** *** ** ** * ** i = 0; i < size-1; i++){
** * **** * ** * * * ******** ****** ** **** * **** * ** * ** ** * i-th element with its neighbor to check if they are in order */
* ** ** *** ** ** *** * *** * * * ** **** * *** * ** ****** *** > x[i+1]){
* * *** ** **** *** * * * * * ** ***** ** * *** ** * *** ** * * * * * ***** ** exchange the values of x[i] and x[i+1] */
*** **** *** ** * * * * ** * **** ** ** ** * ** * **** ** * * ** * ***** ** temporary; * * * *** ** * *** *** *** * ** **
* *** * * * * **** ****** * ** *** ** ** ** * * ** ** *** *** * ** ** ***** ** ** = x[i];
* * ***** ** **** ** ** * **** * ******** * * ** ** * * ** ** * *** ** * * *** = x[i+1];
* *** *** * *** *** ** * *** ** ** * * *** * * ** * * * * **** ** *** * ** * ****** ** * * ** = temporary;
** * **** ** * * *** ** * ***** * * * ** * * * **
** * ** ***** ** * * ****** * ** ** *** * ** * *
* ** *** * ** ***
** * ** ** * ** ***
* ** ** * * ******* *** ****** print the array */
***** ** ** * *** * * * sorting: \n");
** ** ** * * * * * * i = 0; i < size; i++){
* * ** * * ** * * * * * * ** * *** * ** * * ** * ", x[i]); ** * * * ***** ** ** * ** **** * ***
* **** * * * * * ** * *
* * ** * ** * * * ****** * ** ** * *** * **
* * *** ** ***** ** ** * ****
* * ** *** * * ***
* * * * ** **** * ** *** * ** * **
* * * * * * * * ***** ** ** * * * ** * **** **  
* * * *** ** ***** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * *** *** * *** ** * x[] = {77,22,88,11,22};
* * * * * * * * size = 5;
    
** * * * **** * * ** print the array */
** ** * ***** * ** * * i = 0; i < size; i++){
** ** * * ** * * ** *** ** * *** * ** * * *** ** *** * ", x[i]); *** ***** * * *** **** *** *
** * * * ***** ** * ** *
**** * **** ** ** ** *** * * * * ** * *
**** ** * * * *
*** * ** * * ** * * * * *** I need this to happen size-times */
* ***** * *** ** * * * * j = 0; j < size; j++){
*** ** * ***** ***** * ** *** * * *** * from left to right */
** ** **** ** ** * ** * **** ***** * ** * *** * i = 0; i < size-1; i++){
** *** * ** * * *** * ******* * ** *** ***** * ** ** * * * ** ** * ** * * i-th element with its neighbor to check if they are in order */
* ************ *** * * **** ** * ** ***** ** ** * * *** **** * * * > x[i+1]){
* * * ** * * ** * **** *** * ** ** ** ** *** ** * * *** * **** * *** * * * * **** ** exchange the values of x[i] and x[i+1] */
*** *** * **** * ***** ****** * * * **** * *** **** ****** ** * * **** ** * * ** temporary; * * *** * ** * *** * ** * **
*** * * ** * * ** ** * * ******* * * * ** * *** ** ** ***** ** * ** * = x[i];
* **** * *** * * *** * ** * ** * * * * **** * *** ** * ** ** **** * * ** * ** * = x[i+1];
* * ****** ** * * * * * ** **** *** ** *** * *** *** ** * ** * * ******** ** ** * ** * ** ** = temporary;
* * * ** * ** ** * * * * ** * * * ** * *** **** *** *** * * ** *** ** *
* * *** **** * * ***** * ** *** *** *** *
* *** ** ** *** * **
** *** * * *****
* * ** ***** **** print the array */
* *** * * * * **** ***** *** sorting: \n");
* ** ** ** * ** * ******* i = 0; i < size; i++){
** ** * * *** *** * * * ****** * * * * **** **** * ", x[i]); **** * ** * * **** ** * ** **
* ** * *** **
*** * *** ** * * *** **** * *** *
* * * ** ** ** **
*** ** *** ******** *
******* * ** ** * * * * * **** * ** * * *
*** * * ** ** **** ** * * *** * * *** * *  
****** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.164
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users