0 like 0 dislike
10.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 10.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * **** *** * x[] = {77,22,88,11,22};
* *** * *** size = 5;
    
*** * * ** * * * * * print the array */
******* * ** *** * ** ** * i = 0; i < size; i++){
**** ** *** ** ** * ** ** * * ** ** ** ", x[i]); **** * ** **** ***** * * * *
** ** *** * *
* ** * ** * * ** *** * **** *
** ** * ****
* * ** **** * ** ** I need this to happen size-times */
* * **** * *** * * * j = 0; j < size; j++){
* ** * *** * * **** **** **** * *** * * * *** from left to right */
****** * ** ** * * *** * ***** * ** * * * * i = 0; i < size-1; i++){
* *** ** ** * ***** ** * * * * ** ** * *** * ** * * * * * * i-th element with its neighbor to check if they are in order */
** ** * *** * ***** ** * * *** ** ** ** ** **** * * ** * ***** ** > x[i+1]){
** * * * **** * * * ** * ***** * ** ** * ****** ** * **** ** * * ****** * ** **** * ** exchange the values of x[i] and x[i+1] */
* *** **** *** ** ****** * * ** *** *** * ** * ** *** * * *** **** * ***** ****** ** * ** temporary; ** * * * ** ***** * * ** **
*** *** * * * **** * * ** * ****** *** **** *** * *** ** *** * ***** * * *** * ** * *** * * * = x[i];
*** * * *** * * * * **** **** ***** * * ** * *** * ** * *** * *** ** * ** ** * * * *** = x[i+1];
* * ** * * * ** **** * **** ** *** * ** *** *** ***** ** ** * ****** **** *** * *** * * = temporary;
** * * *** ** * *** ***** * * **** *** * *** * * *** **** *** *
* * * ** * * * ******* * *** **** ** ** * *
* * * * * *** * ****** **
* ** * ** * *
** ** * * ***** ** * * * print the array */
* * * ** *** * *** * **** * sorting: \n");
** * * *** * * * * *** i = 0; i < size; i++){
* * * * ** ** ** * ** ** **** * * * ** ", x[i]); ** ** * ** * * **** * *** * **
* * * * *** *
** * * * ** * ** ** * * * * * ***** ** **
** ** ** * *** ** * * ****
*** ***** ** * * *
***** * * * * *** * ** *** * *** ** **
** * * *** * * **** * * ** **** ******* * *** *  
* * * **** **** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** ** * * * * x[] = {77,22,88,11,22};
* **** **** ** ***** * size = 5;
    
* * * ** *** ** print the array */
*** * * *** * ** ** *** ** ** i = 0; i < size; i++){
** **** * ** * ** *** * *** *** * * ** * * ** ", x[i]); ** * * **** *** * * * ** *** *** **
*** *** ** ** * ***
** * * * * * * ** * * **** *** * ** *
** * * ***** *** *
* *** *** ** **** * I need this to happen size-times */
*** ***** ** * ** *** j = 0; j < size; j++){
** * * ** ** *** * * * ** *** ** ***** * ** * from left to right */
* ** ** ** * *** ** * **** ** ** * * *** ** * i = 0; i < size-1; i++){
* ** * * * * * * * ** * * ** **** * ** * ** * * * * * i-th element with its neighbor to check if they are in order */
* * ** * * * ********* * *** ** * ** * ***** ** ** * * * **** * ** * > x[i+1]){
****** ** ** ** ** * * *** **** * * *** ** * ** ** * ** * ** * ** * * ** ** * exchange the values of x[i] and x[i+1] */
* ** * ** * * * ** * ** * * * **** * ** * * *** *** * * * * ** * **** **** ** *** * temporary; *** ***** * ** * * **** * * *
** ***** ** * * ** * **** *** *** * * * * * * *** * * ** ********* * * ** = x[i];
* * * * * ** ** * * ** * ** * *** ** ***** * **** * ** * ** * * * * * * ** * **** ***** * = x[i+1];
* * ** * * * * * **** * *** * *** ** ** * * ***** * ** *** * ** **** * * ** * * *** * ** = temporary;
** * *** * * * ** * ** ** * ** *** * * ** *** * **** * ***** *
* ** * * ** * * ** * **** * ****** ** * ** * **
* * * ** **
** * *** * * * ** ***
* *** * * * *** *** * print the array */
* *** * * * * ***** *** *** * * *** * sorting: \n");
* * *** ** * * * * *** *** ** ** i = 0; i < size; i++){
***** * * ** ** ** * ** ****** **** * *** * **** * * * * * ", x[i]); * ** * ** *** ** * * * ** * ** * **
* *** *** * * ** ** **
** * * * * ** * ** * *** * * * * * *
* *** * * * * ****
*** * ** ** ** * *** **
** **** * ** ******** **** *** * *
** * *** * ** ****** ** * * ** * **** ** * * *  
** ** * * * * * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** * *** * * ** x[] = {77,22,88,11,22};
*** *** ** *** *** * size = 5;
    
** * * * * ** ** * ** * * print the array */
*** * ****** ** * ** i = 0; i < size; i++){
** * * * ** * *** * ** ***** ** **** ** * ** ******** ", x[i]); * **** * * * ** ** * * **
* * ** * * * *** *
*** *** ***** ** ** ****** *********** ***
* * ** * ***** * ****
*** ** *** ****** * I need this to happen size-times */
* ** * * *** *** *** j = 0; j < size; j++){
* * *** * ** ***** ** * * ***** * * * ** from left to right */
* * * * ** ** **** ** *** ** * ** *** * * *** i = 0; i < size-1; i++){
** ***** *** *** ** ** *** ** **** * **** ***** * * ******* ** * * ** * i-th element with its neighbor to check if they are in order */
** ** ***** ** ** ** * * **** *** * * **** ******* ** ** * * **** **** ** * > x[i+1]){
* *** ** **** *** * ** * *** *** ****** ** ** * * ** * * **** ***** * * **** * ** *** * ** exchange the values of x[i] and x[i+1] */
* ** ** * *** * **** * ** ** * * * **** *** * *** * ******** * * * *** * * ** * temporary; ** * *** * ** ******* ***** ***
** ** * ** ** ** * ** * *** * *** * **** * ** * ** *** * * * ****** ** * *** ** ** ******* = x[i];
* ** * * * ** ** * * ** * ** * ** * * * ****** * * * * ** *** *** * *** * *** ** * * * = x[i+1];
* * * *** * * * **** * * * * * ** **** * * * *** ** ** ** * ****** *** * * *** * = temporary;
** * * * * * * ****** ****** ******** * *** *** ** * * * ** *** ******* * **
** **** *** ***** * * ** * * * * ** *
* *** ** ** ** * **** *
* ****** *** *** *
* * * * * ** *** ****** print the array */
**** ** * ***** ** ** *** *** ** * sorting: \n");
*** ** * * * ** * * * * * i = 0; i < size; i++){
* **** ***** **** ** * *** * * * ** * * *** * * **** * ", x[i]); *** ** *** * ** *** **** * * * **
* ****** ** * ** *
** * * **** * * * * * ** * ***
* * * ** **** *** *
*** ** **** * * ***
* * * * * ** ** *** * ******
*** * **** *** * ** * *** * ** * * ** ** *** **  
***** * * ** ** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * ** * x[] = {77,22,88,11,22};
* ** *** * *** * * **** * size = 5;
    
**** ** * ** **** * * ** print the array */
* ** ** * ** ** * * * ** i = 0; i < size; i++){
*** * * ******* ** **** * * *** ** * ** * ", x[i]); * * * **** * * * * * ** * *
* **** ** * * **
** * * * * *** *** ** *** *
* * * *** *** *** ** *
*** * *** ** **** *** * I need this to happen size-times */
* ** * * * * ** * *** j = 0; j < size; j++){
* ****** * * ** ** * * **** * ** * ** **** *** from left to right */
* ** * * ** *** ******* * * * * * * * * i = 0; i < size-1; i++){
* * * ** *** * **** * *** * **** **** *** * * ** ** ** * * **** ** **** * i-th element with its neighbor to check if they are in order */
*** *** ** ** *** *** * * **** * * * * * ** * * * * * ****** * * > x[i+1]){
** * *** * * ** ** * ** *** ** * ** ** ** * ** * ****** *** * * * ** *** *** **** * ** * exchange the values of x[i] and x[i+1] */
*** ** * ** * * * ** ** * * ******** * * **** * ** * * * *** * ** * * * temporary; * **** * ** ** * **** * **
* ** ** * * * ** * * ** *** * * ** ** * ** * ** * * * * * * ******* ***** = x[i];
** ** ****** * * *** * **** ** * *** *** **** * ** ** *** ** * **** **** ******* ** * * * ** * = x[i+1];
** **** * ** ***** ** *** * ***** * ** *** ****** * ****** ** ** * *** **** **** = temporary;
* ** * * * * * * *** ** * * ** ** * **** * * ** *
*** * * * * *** * *** *** *** * **
* *** ** * ** ****
*** * *** ***** *
* * *** ** * * **** **** print the array */
* * *** * ** ** * ** * ** * ** sorting: \n");
** * ** ** **** *** * ** i = 0; i < size; i++){
* * * * ****** *** * **** *** ** * ", x[i]); ** * * * ** * * ***** ** * ******
* * ** * * ** **
* ***** *** * ** ** *** * * * ** *
* ** * * * ** ** ** *
***** ** ***** *** * ******
* * ** * * * **** * ** **** *** *** * *
* * ** * ** **** ** ** ***** *** * * * * *  
* ******** * * ***** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * *** *** * *** * * ** x[] = {77,22,88,11,22};
** ** ***** ** * **** ** size = 5;
    
* * * * ** * * ******* print the array */
* ** **** ** ** * *** i = 0; i < size; i++){
*** *** **** * * * * * ** * * ** * ***** * * * ******* ", x[i]); * * * ****** ** *** * *******
* * * * ** ** *** **** *
* ** *** *** * * * * ** *** ****
* * * ** * * ** ** *
** ** **** *** * * I need this to happen size-times */
**** * *** * ** ** ** j = 0; j < size; j++){
** * ** * * ** * *** * ****** * **** *** from left to right */
*** *** * * * ** ** **** ***** **** * * *** ****** i = 0; i < size-1; i++){
**** *** * ** * **** *** *** * **** ** **** * *** ******* ** * i-th element with its neighbor to check if they are in order */
*** ** * * ***** * * * * ** **** * ** **** * *** ** **** ** ***** > x[i+1]){
** * **** * **** ** ** ** * *** * ** * * * * ** ***** * ** * ** ** * ** * * * * *** ** exchange the values of x[i] and x[i+1] */
* * ** * * **** * * * * ** *** ** ****** ** * * * ** * * *** *** **** * ******* ** temporary; ** ** *** * * * * * *
* ** * * * ** * * * * ** **** * ** * ** ** * * ******* ** *** * * ***** * ** * **** **** * *** = x[i];
* * * *** * * * * ** ** * *** * ** * * ** * * ** ** * * * *** ** * ** * ** * * = x[i+1];
***** ** ***** ** ** * ** ** * * * ** ** *** * ** * ** * **** ** ***** ** ***** ** * = temporary;
* * * * * *** ** * * * ** *** *** ** ** * * *** ** * * ***
** ********* * ** ** ***** ** ** ** * * ****
** * ** **** * * ******
* *** * * ** *
* * ** *** * * ***** print the array */
** *** *** * * ** **** ** ** ** ** ** sorting: \n");
*** * ** * * i = 0; i < size; i++){
*** * * *** ** ** * * ** *** * **** * *** *** * * *** ", x[i]); **** ** * * **** ** * ** ***
* * * ** * *** *
**** * **** **** * * * * ** ** * ****
* ** ** * * * *** ***
****** * * * ** **
* * * * * * * *** * * * * ***** ***** **
*** ** ** ** *** * ** ** * * * ***** *** * * ***  
* * * * * *** * * * *** * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** *** ** ** x[] = {77,22,88,11,22};
* *** *** **** *** *** * size = 5;
    
* * * ** **** * * * print the array */
* * *** * ***** * i = 0; i < size; i++){
** * **** * ** * * * *** ******** * * * ******** ", x[i]); * **** *** ** ** ** ** * * **** * *
* *** * * *** **** * *
*** ** ** ** * * * * * ***** * *** * * * * **
* * * * ******** * *
** *** * *** * * * I need this to happen size-times */
* *** * ** * ** * ** * j = 0; j < size; j++){
* ** ** * ** ** *** * *** * * ***** * * *** from left to right */
** **** * * ** ** * ***** * * * * * *** ** ** * i = 0; i < size-1; i++){
* * ****** * * ** ***** *** ** * * *** * **** * * ****** *** ** **** * *** i-th element with its neighbor to check if they are in order */
* ** * ** * * * * * * * * * ** **** * * * * * * * ***** * *** * * *** ** * > x[i+1]){
** * ** * ** ****** * ** * ** * *** *** * * ** * ** **** ** * ** ** **** * ** * *** exchange the values of x[i] and x[i+1] */
** ** * ******* *** * ******* ** * * * * * *** **** ********** * * *** ** * ** ** temporary; *** * *** * * ** ***** ** ** ** * **
* ** * * **** * * *** ** ** ** ******** * **** ** ** ****** * * * ** ** ** * * * * ** = x[i];
* *** **** * * * * * *** ** * ***** ** ** * * *** ** **** * *** ** * * = x[i+1];
* *** *** * * ** *** * ***** * ** *** * * * *** * * * * ****** * * **** *** * * * * * = temporary;
* *** * * * *** ** * * ** ** * * **** ** * * * ** **
* *** * * ***** * ** ** * ** * * * *
* *** * * * ******
*** * *** * ** * * * ****
* *** ** * ** *** print the array */
* **** ***** * ** * * * ** ** sorting: \n");
*** *** * ******* **** ** * i = 0; i < size; i++){
* ** * **** ** ** * ** * ** * * * * * ***** * *** ", x[i]); ** * * ** * * ** ** *
* * * ** * **** *
** *** * ** * ****** *** * * * **
* ** ** ** * * **** * **
*** * * * * **
** * * *** * * ** * *** ** * *** ** *
** * * ** * * * ** ** * * * ** * *** *  
* * ** *** **** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * * *** * **** ** *** x[] = {77,22,88,11,22};
* ** * * * * * ** size = 5;
    
** **** *** ** **** *** print the array */
* * ** ** * * * i = 0; i < size; i++){
* *** *** * * ** **** ****** ***** ** * * * ** * * ", x[i]); ** **** ** * **** ** * * * ** *
* * * ** * * * * *
* * * * ** ** * ** * * ** ******
* *** * ** ** * ******
** ** * * * * * * I need this to happen size-times */
*** * *** * ** *** ** * *** j = 0; j < size; j++){
**** ***** **** * * * * ** *** *** ** ** ** **** from left to right */
* * **** ** * *** *** * *** ** * i = 0; i < size-1; i++){
* * ** * ** *** * ** * * * * * ** ** *** ** **** * * i-th element with its neighbor to check if they are in order */
** ** *** * *** * ** ** * **** ** * * * ** * ** * * ** * * > x[i+1]){
***** **** **** * * ** ** ** * * *** ** ** ** **** **** * ***** * * ** ** * * exchange the values of x[i] and x[i+1] */
** * * * * ** *** * ** ** ** * * * * ****** *** * ** **** ** * * * ** * * **** ** *** ** temporary; **** * ** * * * *** *** * * ** * *****
*** * * * * * * *** * * ** ** ********** ** *** ** ** ** ** * ****** ** **** * ***** * = x[i];
* * * ** *** * *** * * * * ** ** **** * ** **** * **** **** ** * * *** * ** ***** **** * ** = x[i+1];
* * *** * * ** * ** * **** **** ********* ** * * * * **** *** * ** * *** ** * * * * ** * * = temporary;
** * * ***** *** * * *** ****** * ****** ** **** ** * * *** * **
* * * * ** * * ***** * ** * ******** * ***
** ** * ** ** *
* ** ** ** * ** * ***** ** *
***** ** *** * * * **** print the array */
* ** * * *** * * * * ** ** sorting: \n");
* * * * * * * * ** i = 0; i < size; i++){
* * ** * ** ** * ** **** ** * * ** ** ****** ", x[i]); ** *** * ** * * *** * * * ** *
*** * * **** * * * **
* ** * ** **** ***** ** * * *
* ** ** ****** ** ** ****
* * *** ***** ** *** *
* **** * ** * * **** * *** * * *
* * ** * * * * ** **** **** * * * **  
** * * * *** *** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * ** ** ******* x[] = {77,22,88,11,22};
*** * *** *** ** ** size = 5;
    
*** ** * * * **** ** * print the array */
* * * ** ****** ** * * i = 0; i < size; i++){
* * * * *** * * * * * ** *** * ** ** * * ", x[i]); ** * ** **** ** * ***** * ** **** *
** * **** * *** * **
** * *** * * * **** **** *** **
* * *** * * ** * * **
*** * * * * * * * ** I need this to happen size-times */
**** * ** ** * ** j = 0; j < size; j++){
* * * * * * * * ** * ** * * ** * * ** ***** * from left to right */
* * * * ** ** * * *** ***** *** * * *** * ** i = 0; i < size-1; i++){
* *** * *** *** *** * * ** *** * * ** ** * * * * * ******** * * * ** i-th element with its neighbor to check if they are in order */
*** * *** * * * * ** * **** * ** **** * ** * * *** * * * * * * > x[i+1]){
* * * * *** ** *** ** * *** ** ***** * ** *** * * ** ** ******** *** * ***** * * **** exchange the values of x[i] and x[i+1] */
***** ** ** ***** * * ** ** * * **** ** * ** ***** ** * * *** ** * **** ** **** * ** **** temporary; * **** *** *** ** * * ** ** * *
* * ******* **** * * * ***** * ** ** ***** *** * * * * * * * *** ** * * ** ******* *** *** ** * = x[i];
* ** **** * * * ** ** *** *** *** ** * * *** * ** * ** *** *** * ** ** * = x[i+1];
*** *** *** * ** *** ** * * ** * * * * ******** **** ** * ** ** * * ** **** ** * = temporary;
* ******* * * * * * ** * ** ** *** ** ** ***** * * * ** ** **
* **** * * ** *** ******* * **** *** ***
* * ** ** ** * ***
** * ** * * * * *
* ** ******* * * * * * * * print the array */
** ***** ** **** * *** * * * * sorting: \n");
* * ** ** * ** ** *** * i = 0; i < size; i++){
** ********* ** * **** * * * *** ** * * * * * * * * * ", x[i]); * * ** ** * ** **** * * **
* ** **** * ** * * * ***
****** *** * * ** ** * ** * ** ** ***
** * * ** ** * ** **** *
* * * * *** * ** *
** ***** ** * ** * ** ** ******
* **** * * * * ** * ** *** ** * *** * **  
***** **** ***** * ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * * **** ****** ** x[] = {77,22,88,11,22};
* * * ***** * * *** ** * size = 5;
    
* * * **** ***** * * * * * print the array */
* * ** ** ** *** * * * * *** i = 0; i < size; i++){
*** * * ***** * * * * * ***** * * ***** * * * ", x[i]); ** * ** ** * * * ***** ** * * *
* *** * * * *** ******
** *** * **** * *** * * * ** *
******* ** ** * * * ** *
* * * * * * ** *** I need this to happen size-times */
** **** ******* * *** ** j = 0; j < size; j++){
** **** ***** * *** * * ** *** *** ** **** from left to right */
***** ** * * * *** ** ** * ** * * ** i = 0; i < size-1; i++){
** ** ** * * * ** *** * ** ***** *** ** ** **** * ** *** * * * *** i-th element with its neighbor to check if they are in order */
** *** *** * * * * * **** * ** *** * * * *** * * ****** ** * > x[i+1]){
** * * * * ** ** * ** ** * * * * ** * ** * * * * *** * *** * * ***** ** * ***** * * **** exchange the values of x[i] and x[i+1] */
* **** ** ** ** *** **** ** ** **** * * ***** * * * *** * ** ** * ** *** ** **** temporary; ***** ** **** ** * * * * ** * ***** *
** * ***** ** ** * * **** * ** ** * ** ** * * * ** *** ** * ***** *** *** = x[i];
* ** * * * * * * * * ** * * * * *** * ***** * **** * ** *** * ** **** **** ** = x[i+1];
*** * *** * * ***** * * ** ***** ** * *** * * ***** * * * * * * ** * ** * ** * * * = temporary;
****** *** * ******** ** *** * * **** * ** * ** ** * * *
* * * ** **** ** * * * *** *** ** **
* * **** * * ** ** * **
* * * ** * ** ** *
* **** *** ***** * print the array */
* ** * * ** *** * *** ** sorting: \n");
** * * * * * * * * *** i = 0; i < size; i++){
** * * * *** * **** * * * ** * ** ** ** * * * ** ", x[i]); ** ** * ** ** *** * ** **** *
*** *** * * ***
*** * *** * * * **** * * * *
*** * * *** ** * * *
* * * ** ** ***
** * ** * ****** ** * * ** * ****
** * ********* * * * **** *** ***** ****** * * *  
** * *** ***** * * * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * **** * * ** ** x[] = {77,22,88,11,22};
*** * * * * ** * ** * * * size = 5;
    
*** * * ** * * print the array */
* * ***** ******* * *** i = 0; i < size; i++){
* *** * *** ** * ** ** **** * ** * ** *** * ******* * ", x[i]); *** *** ** * ** * ******* * *
** ****** * * **
*** **** * **** **** * **** * ** ** *
***** * ** * ** *
* * *** ** * *** I need this to happen size-times */
* ***** ** * * **** ** j = 0; j < size; j++){
** * * * ** * * * * *** * * * * * ** * * from left to right */
* * * ** *** **** *** * * *** ** ****** * *** * * i = 0; i < size-1; i++){
*** *** * *** *** *** ** * * * * * * ***** **** * * * *** * ****** * ** i-th element with its neighbor to check if they are in order */
* ** *** ** * ** * * * * **** ****** ***** * ** * * * * *** > x[i+1]){
* * **** * * ****** * * ** *** ** ** ** ******* ** * ** * * *** * ** * *** exchange the values of x[i] and x[i+1] */
** *** * ***** * * * * * * ** ******* ** ** ** ** ****** * ** ** * ** * *** ** * ** * temporary; ** * * * ** * * *** * * * ***
* ** ** ****** * *** *** * **** ******** *** * * ****** * ** * ***** * * * * * * ********** ** = x[i];
*** * * *** * ** * *** **** *** * * ** ** * * * * **** **** * * ** * * *** * * * **** ***** ** = x[i+1];
* * * ** * * ** ** * * ***** * * ***** * * ** * * * ** ** ******* ** ** * * * ** ** * = temporary;
* ** * * * *** *** ** * **** * * * ** ** * * *** ** * * * ******* *
*** *** ** * * *** * * * * * * * *** * * * *
** ***** ** ** *** * *
* * * * *** ** ******* * *
* ****** * * ****** print the array */
* * * * ** ** ***** *** * * * *** * sorting: \n");
***** *** * * ****** ** i = 0; i < size; i++){
** * * *** * ** * * * *** ** * * **** ** ** ***** * ", x[i]); * ***** * **** **** * ** * **** * **
* ** * ** *** * * *** *
*** *** * ** * * * * ** ** * * * ******
* * * ** *** * ** * **
** *** *** ********** **
* ** ** * ** *** ** ** ** * * * ** *
** ** ** * **** * ****** ** ** **** * **** *  
**** * * * * ** ***** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.171
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users