0 like 0 dislike
9.1k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.1k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** * * ** *** x[] = {77,22,88,11,22};
* * *** ****** ** size = 5;
    
**** * * *** * print the array */
* * * * **** * ** ** * i = 0; i < size; i++){
** ** * * **** * ** ** **** ** * * * ** * ", x[i]); ** ***** ** *** ** **** **** ***
*** *** ** ******* * **
* * *** * ** *** ***** *
** * * * * * ** * * ***
* * * ****** *** * * * I need this to happen size-times */
** ** ** * * * *** * * * j = 0; j < size; j++){
* **** ** ** * ** *** *** ** **** * *** from left to right */
* * * * ** *** * * ** *** * ** * * * * **** i = 0; i < size-1; i++){
* ** ** * * ***** * * * *** * *** *** ** * * * * *** * i-th element with its neighbor to check if they are in order */
* * * * * * ** ** ** *** *** ** * * * **** ** *** * **** ******* > x[i+1]){
** * * * *** ** * ** ** ** * ** ** ***** ** * * * * * ** * * * *** *** exchange the values of x[i] and x[i+1] */
* ** * * * * * ** * * * * *** * ** * **** *** * *** * ** * * * **** temporary; * * ***** * * * *** ** *
** * * ** ** *** * * * *** *** **** * * **** * * * * * ** * **** *** **** * * *** = x[i];
* **** * *** ** * * * * ** * * * *** *** * **** ** ** *** * ** * * * ** *** ** ****** * ** ** = x[i+1];
* *** * ****** * ** * ** ** * ******* * *** ** * ** ** **** ** * *** * *** * **** * ** * *** = temporary;
**** ** ** * * * **** ** * ** * ***** *** * * * * * * ** ** ** * *
*** *** ** * **** ** * * * **** * * * * *
* * * * ** ** * * **
* * * * * ** *** ** *
* ** **** ** ***** print the array */
* ** **** ******* ** * * * ***** * **** * sorting: \n");
* * ***** *** * ** * * * i = 0; i < size; i++){
* ** ** * * ** ******* ** * **** *** ** ** ** * * ", x[i]); * * *** * *** * * * ****** * ***
** ** * * * * *
********* * ** ** * * * * ** ** ***** *
* ** ** * ** * * * * *
***** * * ** * **
* * *** *** ** * ** ** ** ** ** ***
* * ** **** ****** ** ** * * * *** ** * *  
* ** * * ***** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * *** ** ** x[] = {77,22,88,11,22};
* **** * * * ***** * size = 5;
    
*** * * * ***** **** *** print the array */
**** *** * * **** * ** ** * i = 0; i < size; i++){
**** **** ************* * *** * * * ** ** ** *** **** **** * * ", x[i]); * ** ** ** * ** * *** *
** ****** * *** ** *
* ** * ** * * * * ** * * *** * * *
* *** ** * ** *
* * *** ** ** ** I need this to happen size-times */
**** *** * ** * * j = 0; j < size; j++){
**** *** *** * * ** *** ** * * ***** * from left to right */
** * * *** * *** ** * *** *** * ** * ** * * **** * i = 0; i < size-1; i++){
**** ** ** * ** ** * *** * * * * ** *** ** * *** ***** *** * ** * i-th element with its neighbor to check if they are in order */
**** ******** * ** * ** * * * * * *** * *** **** ** *** ** ** * * > x[i+1]){
** ** * * *** * * * ** ** * * * ** ***** ** * **** ** * * * ** ** * * ** * exchange the values of x[i] and x[i+1] */
** * * * **** ***** ***** ** ** * ** * *** * * * **** ** ** ** * *** * * ** ****** * * temporary; * ** ** * * * ** **** **** * *
** * ** **** ***** ** * * * * ************ **** * ** ** ** * *** * * *** * ** ** * * = x[i];
** * * * ** ** ** ** *** ** ***** * *** * ***** * * * ** * ** ** * * **** ** **** ** = x[i+1];
*** *** ** * * * * * *** * *** ***** **** ***** ** ** * ** ** * ** ** * * ** **** = temporary;
***** * ** *** * * ** * * ** ** ** *** *** ** *** * * * ** ******
** * ******* **** * ** * * *** * * **** * **
** * * * * * ** *
*** ** ** *** ****
* * *** **** * * ** print the array */
*** * * ** * * ** * * *** * * sorting: \n");
**** * * ** *** * **** * i = 0; i < size; i++){
* ***** ** ** ** ** * ***** ******** ** ** ** *** ** ** * ", x[i]); * *** * * * ** * * *** * ** **
** **** ** *** * *********
** * * * * * * **** **** ** ** * * **
* ** ** **** ******
* **** * * ****** *
* *** ** ** ****** ** *** ** *** *******
*** *** ** ****** ** ******** ** * * * *  
** ** * *** * ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * *** ** ** *** x[] = {77,22,88,11,22};
* * * ******* * ****** ** size = 5;
    
*** ** * * ** * * ** ** print the array */
*** **** *** * * * ** i = 0; i < size; i++){
* * * * * **** * *** ** * ** * * ** * * *** * * ", x[i]); ** * *** * ***** * * * * * * *
*** *** ** ** * ** * ***
* * **** *** * * * * * *
* ** **** **** *** * * *
*** ****** * * * * **** I need this to happen size-times */
* * *** * ** * * * ** * * j = 0; j < size; j++){
* * * * * ** * *** * * **** * * ****** from left to right */
** * * * *** * **** *** * ** *** *** * ** * * ** i = 0; i < size-1; i++){
*** * *** * ***** * *** *** ** ** *** ***** ***** * * *** * * * * * * ** *** i-th element with its neighbor to check if they are in order */
** **** ** * * *** * ** ** * ** ** * * ** * * * ** * ** * * > x[i+1]){
*** ** * * *** * *** **** **** * * ** ***** *** * ** *** *** * * ** *** * * ** * * * exchange the values of x[i] and x[i+1] */
** *** * * * **** * * * * * * *** *** * * *** ** * * **** * ** *** * temporary; **** ** * ** ** **** *** * ** *****
* *** * ****** * ** **** *** * ****** * ** ** * * ** * ** * * * * * * * **** ** * * * ** * = x[i];
**** ******* *** * * * * ** *** **** *** **** * **** * ** * ** * * * *** ** * * * * * *** = x[i+1];
* * * * ** * ** **** * **** *** **** ** * *** * ** ** * ** *** * * * ** * ** * * = temporary;
**** * ****** ** ** **** ** ** ** * * * * * ** *** ***** *
** * ** ******* * * * ** ** * **
* ** * ***** * *
* **** *** *** ** *
***** * ******* ** print the array */
* * **** * * ** * ** * * * ** * **** * sorting: \n");
** ** ** ** * ** ** i = 0; i < size; i++){
** *** * ** * ** **** * *** * * * ** * * ** ** * *** *** ** ", x[i]); ** * * ** ** *** * **
* * * * * * * ** *
**** ** * * * * * * ** *
* * * **** * *
** *** *** ** * *
* * * ** * * * *** * **** * * * ** * *
** *** **** ****** ****** * ********* * ***  
*** *** * **** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * ****** ** * * ** * x[] = {77,22,88,11,22};
* * * ** * * *** * size = 5;
    
* ** **** * * * * * print the array */
* * * * ** ** ***** i = 0; i < size; i++){
**** ******* * * ***** * ** * * ** * *** *** * ** ", x[i]); ** * * ** ** * * * ***** * * * *
**** * * * ** ***
** * ***** ** * * ***** * * **** ****
** * **** * *** * **
* ** * * **** *** * * I need this to happen size-times */
*** *** * * ** * * *** * j = 0; j < size; j++){
* * ** * ** *** * * * *** ** *** from left to right */
* *** **** * ** * ** * * * ** * ** ** i = 0; i < size-1; i++){
* * * * * ****** ** ** **** ** ******* * * * ** * * **** **** * * * i-th element with its neighbor to check if they are in order */
* **** * * * * **** * * * *** * * * * * ** * * * * * ** ** * ** * * > x[i+1]){
* *** * * * **** * ** **** * ** *** ** * ****** *** * ** *** * **** ** exchange the values of x[i] and x[i+1] */
* ** * *** * *** * *** * * * * * * * ** *** * ** * * * * * * ** temporary; ** *** *** * ****** *** ** * *****
* * ** ** * **** * * *** * **** *** * * ** ** * * *** * ****** * * * *** * * *** ** * ** ** ** = x[i];
* * * **** * ** * * *** * ** * * ** * * *** ** * **** ** * * * ** **** * ** * *** ** **** * = x[i+1];
** **** * * * * ** ** *** ** *** ** ** * * ** *** * * ** ** * ** * * ** ** * **** * * = temporary;
** ****** ** * ***** *** * * ** ** ** * ** * * * * * * ** * * *
* **** ** * ****** ** *** *** ****
* * * * * ** **** **
* * ** *** ** * * *
* ** ** * *** print the array */
* * * ** *** *** ** * * *** sorting: \n");
* **** *** * ** **** *** i = 0; i < size; i++){
* * *** * * * * *** * * * * ** * * * **** * ** ", x[i]); * * * * *** * **** * * ***
** * ** * *** * * **
*** *** * * ** ***** * **
**** ** * ** ** **** * *
*** * * ** ** * *** * ***
** * * **** * * ** *** * * * * * **
*** * * * * ** ** **** * * * **** *** * ** ***  
* ** * ** ** ** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * ** * *** x[] = {77,22,88,11,22};
** * * ** *** ** * size = 5;
    
* * * *** * * ** print the array */
* * **** ***** *** * * * i = 0; i < size; i++){
* ** * *** * * ** ** * ** *** ******** * * * ** *** **** ", x[i]); *** * ** * *** * * ** * ***
** ** ***** ***** * * *
** * *** * * * * * ************* ** *
* * ** * * * ***** *
* * ** * ** * * ** I need this to happen size-times */
* ** * * ******* * *** * * j = 0; j < size; j++){
* * ** ** ** *** ** *** **** ***** *** from left to right */
* * * * * * * ***** * ** * ** ** * i = 0; i < size-1; i++){
******** *** * * * ****** *** ** * * *** *** * * ** ***** ** ** i-th element with its neighbor to check if they are in order */
* ** * ** * * **** * ***** * ****** ** * *** ***** * *** * *** * ***** > x[i+1]){
* * *** * * ** ******* * * **** * **** * ** ** ** * ******** * *** * ***** ***** exchange the values of x[i] and x[i+1] */
* * * * *** * ** ** ** ****** ** * * *** * *** *** ** * ** ** * ** temporary; * *** * ** ***** * * * ** * * *** *
* ** *** * * * * ** * * ** ** ** * *** * *** * ** * * *** ************ * * * *** *** = x[i];
* ******* * *** *** ** **** * ** ** ** ** ** *** * ****** * *** * ** ****** = x[i+1];
* * *** * ** * *** * ** * * * * * ***** * * **** * * *** ** *** * * * * ** * * ** = temporary;
* *** * * ****** * **** * ***** ** ** * *** * * **** ** * * ***
* * ******* ** *** * *** * *** * * ** ** **
* ** * **** * * * ** **
******* ** ***** **
* ** * ****** * * * * * print the array */
******* ** * * * ** ****** sorting: \n");
* ** * *** ** * * *** * i = 0; i < size; i++){
***** * * ** ** ** * ** ** * ** * * * ** * * * * * * ", x[i]); ** ** ** * **** *** ** * **** *
** *** * ** * * *
* ****** * ** ********* ** *** **** ***
**** **** * * **
* * * ** * ** *** **
* ** **** ** * ** * * * * *
****** * ** **** ******* *** * ***** * * ** **  
*** *** ****** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * ** ********* *** x[] = {77,22,88,11,22};
** ** * ** *** * **** size = 5;
    
* ** * * * * * print the array */
*** * ******* * ** i = 0; i < size; i++){
** * * * * * * * ** * * ***** * ** * * * ** *** ", x[i]); * ** *** * * * **** *** ** ***
***** *** **** ** *** * **
** ***** * * * ******** *** * ** *
* *** ** *** **** *
* ** *** *** * * ** *** I need this to happen size-times */
* ** * * * * ****** ** ** * ** *** j = 0; j < size; j++){
* * *** * * * *** * * **** * **** *** * from left to right */
** ** ** *** * **** * * * * **** ** * ** i = 0; i < size-1; i++){
** * * *** * *** * ** **** * ** * ** *** ** * * *** * * * * * * ***** i-th element with its neighbor to check if they are in order */
** * ******* ** * *** *** ** * ** ** * ** * ** ***** *** * **** > x[i+1]){
* ** ** **** ** * * ** *** * * * ** * ***** ** ***** ** * * * *** ** **** ** exchange the values of x[i] and x[i+1] */
* * * ** * ******* ** * **** * *** * * * * **** *** * * * *** * * * **** * *** * *** ***** * temporary; ** *** * * * * * * *** * *
** *** ** * ** *** * * *** ** * ** * ** ** ** * **** * ** *** * ** * ** * *** ** * * = x[i];
** * ** ** * * *** * *** ** * *** ****** *** ** ** ****** *** ** ** * *** ** * * * * ** = x[i+1];
* * **** ***** * ** * *** * ** **** ** *** **** ***** * * ** * * **** * * * * ***** * * * = temporary;
* *** ***** * * ** * * * * *** **** * * * ** ***** *** *** * * ***
** * * * ** * ** ** * ** * * * * * * * ** **** * *
** * * * **** * * ** ******
* * * * * * ** * * * *
** * ** * ** * * * print the array */
* ** ** **** ** * ** ** * sorting: \n");
* * *** * * * *** * i = 0; i < size; i++){
***** *** * **** ******* ** * * * ** * ** *** * * * ****** * ** ", x[i]); *** ** * * ** * ** * *** * * ** *
* ** *** * * * **** * *
*** * * * * * ** ** ** * ** **** ** **
** * * *** * ** ** ***
* ** * * ** * * **
*** ****** * * ** * ** ** *** *
* * * * * *** * * ** * * * ** * **  
*** ** * ** * * ** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * ** * * * * x[] = {77,22,88,11,22};
* ** *** ** ** * size = 5;
    
* * *** * ** **** print the array */
* **** *** * * *** * * * ** i = 0; i < size; i++){
* ** ** ** ** * * ** ****** **** *** *** * ** * * ", x[i]); ** * * *** **** **** **
*** *** ** * **
* * ********** ** ** *** * ** **
***** * ** * **
** *** **** * * * *** ** I need this to happen size-times */
* ******** * * * *** * j = 0; j < size; j++){
*** * **** ** * ** ** * ** * ** * from left to right */
* * *** *** * * * * ** **** * * *** * i = 0; i < size-1; i++){
** **** ** * * **** ** ** * ** ** ** ** * * ******* * **** i-th element with its neighbor to check if they are in order */
** ** * ** * * ** * * **** ** * ** ** ***** *** * * ** * > x[i+1]){
********* *** ** ** **** * ***** * * * *** ***** * ****** * *** ** * * ** ** * * ** exchange the values of x[i] and x[i+1] */
* ** * ** * * ***** **** *** * * ** * *** ****** ** *** **** *** ** * * *** temporary; * * * * * * ** * ** ** ***
* *** * * * ** * ** *** * ***** *** ****** * * *** **** * ** ** * ** *** * *** ** ** * * *** ** = x[i];
* * * ** *** ****** * **** *** **** * * * * ** *** ** * * ** ** * **** * * **** ** = x[i+1];
*** ** ** * *** * * * * * ** ** ** * * **** ** * * * **** *** * * ** * * ** * * = temporary;
* ** * * ** * **** * * ** **** * * ** * * * ** *** * *** *
* * * * ** ** * * * * * *** * ** * *
* *** * ** ** **** * **
***** ****
*** * * * * ** *** * ******** print the array */
* ** ** * * ** * * **** * *** sorting: \n");
*** * ***** * *** ** ** ** *** i = 0; i < size; i++){
** * * * ** * ** * * ** * **** ******* * * * ** ** ", x[i]); ***** * ****** * * * **** * *
*** * *** * * * *** **
* * ** **** * ** ** *** * ** * **
* *** ****** ** ***** * *
* ** * * ** * ****
** ***** *** ** * ** **** ** * ** * ** * *
** ** *** *** ******* * * * * * ** * **  
** * ****** **** * * ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ******* **** * * x[] = {77,22,88,11,22};
** * * * ** **** * size = 5;
    
* * ********* * ** * * * * * print the array */
* * ***** * ** * ** i = 0; i < size; i++){
* * ** * * * ** ** * * * * * ** * ** ** * ", x[i]); * * * * ** * ** ***
* * * ** * * ****
* ** * ** * * * * * * ** * ******* * * *
* ** * *** * *** *
* *** ** * * ** ** I need this to happen size-times */
** * **** * **** *** * j = 0; j < size; j++){
** ** *** *** * * * ** * * * * * *** from left to right */
* ** * **** ** * **** ** ** *** * **** i = 0; i < size-1; i++){
***** * *** *** * * ** ** ** ** * * * *** * ***** * * * ***** *** ** * * ** i-th element with its neighbor to check if they are in order */
* * ** * * * * ** * * * * * * *** ** * * * ***** ** ** > x[i+1]){
* **** *** * * * * * * * ** ** * ** ** ** * * *** * ** * * * * *** ** * ** ** *** exchange the values of x[i] and x[i+1] */
* * *** * ** ** * * * *** **** * * **** ** * * * ** ** **** ** ** ** * ** * ** temporary; * *** * ** * ** ** ** * ** ** * *
** ** ** * * * * ** * *** * * * * * * * ** * ** **** * * *** * * ** ** * ** ** * *** ** * **** ****** = x[i];
** * ** * * * * * * * ***** ** ** *** * ** * ******* ** **** * * * **** **** ** **** * = x[i+1];
* *** ** *** * * ** ** * ** ** * **** ** ** *** * * **** * * * * * *** ** * *** * ** = temporary;
* * ** ** **** *** * * * * ******* * * * * * * * ***
** * * **** * * * * * * * * ** **** * * * * **
**** ** ** *** ***** * *
* ** ** ** * ** * * *
* * * * ** *** * *** ** *** print the array */
* ** ** * * * ****** * *** * ** * sorting: \n");
** * ***** ** ** ** * i = 0; i < size; i++){
* *** ** **** *** * * ** ******** ** ***** * ** ** ** * ", x[i]); * * * * * * ** ** ** * * **
* ** * * * ** * * * * *
* * * *** ** * ** * ** * **** ** *
* * *** ***
* * *** * ** * *
*** ***** ** * ** * * *** **** **
* ** **** * * ****** *** * * * * ***  
** ** *** * ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** * * *** ***** * ** x[] = {77,22,88,11,22};
** *** * * ** **** * size = 5;
    
** ** * ** *** ** * * print the array */
** *** * *** * * * * ** *** i = 0; i < size; i++){
** * *** * * ** *** ** * ** * **** * * ******* **** * ", x[i]); * *** * *** * * ** * * * ** * * *
***** * * ******
** ** * * ** ** * * * * ***** ** *
*** *** **** ** ****
* ** * * *** * *** * I need this to happen size-times */
** * * ***** *** *** * * * j = 0; j < size; j++){
* * ** **** ******** * * * *** * * * ** * ** * from left to right */
**** ** * ** *** * ** * **** ****** ** ** * i = 0; i < size-1; i++){
** ** **** * * * ** *** * ** * * * * * ** ***** * ** * **** * * ** i-th element with its neighbor to check if they are in order */
* ** ** * **** * ** * **** * ** * * ** ** **** * **** ***** * * > x[i+1]){
** *** * ** * ***** ** ** ** **** * ***** * ** ***** * ** ** ** * * ** * ** *** **** * * * **** exchange the values of x[i] and x[i+1] */
** * ******* **** * **** * * * * * ** * * * * ** * ***** * * * ** * * * *** * **** ** temporary; * * * *** * ** *** ** * * **
***** ***** **** * * * * ** ***** ** * * * ** ** *** *** * *** ** * ** * * ** *** ** * = x[i];
* ** * ** ** * ** * ** * * ** **** * **** *** *** * ** *** * ** ******** * * * * * *** * = x[i+1];
*** ******* * * ** * * * ** ***** * ** ** **** ** ** * ** * * * *** **** * ****** * * ** = temporary;
* * * * * ****** * *** * *** ** * * * * ** *** * * ** ** ***
* *** * **** *** * * * *** ** * * ***
*** **** * * *** **
* ** * * ****** ***
* **** * ** ** * * * print the array */
*** * * * * ****** ** * * * * sorting: \n");
* *** **** * * * ** i = 0; i < size; i++){
* ** * ** ** ** ** * ***** ***** * ** * * ** * ", x[i]); * ** * * * * *** *** *
* **** * ** ** * ** *
* **** * * *** ** ** ** * **
*** *** *** * **** ***
** ** * *** * ** **
* * * *** * * * * **** *** *** * * * *
**** **** * ** **** * * ** *** ** * **  
* * * * * ** * ** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** ** * * * * x[] = {77,22,88,11,22};
* ** ** * * * *** * *** size = 5;
    
* ** ***** * ** * *** print the array */
* * ***** ** **** *** * *** i = 0; i < size; i++){
* *** * * * *** * * *** ** * * * * * ** ******* ***** * ", x[i]); *** ** *** **** ******** *** * * ***
* ** * * * ** * * ******
* * *** * ** * ** *** * * *** * ******
* * * ** * ** * * * *** *
** * * * * *** *** ** I need this to happen size-times */
** * * * **** *** ***** * j = 0; j < size; j++){
** * * ******* * ** ******* ** * * * * *** from left to right */
* ** ***** * * *** * * ******* ** ** ** * * i = 0; i < size-1; i++){
** ******** ****** * ** * * * * * * * **** * ** * ** ** * i-th element with its neighbor to check if they are in order */
*** ** ** **** ** *** * **** *** * * *** ** ** ** *** * ** * * * * > x[i+1]){
** * **** ** ** ** *** ** *** ** * ** ** ** * **** * * ** ** **** **** exchange the values of x[i] and x[i+1] */
*** **** * ** ****** * ** * * ****** **** ** * *** * *** * * * * * ** * *** * ********** * temporary; * ** * * ** * ***** * * ** * * **
* ** ** * * * * ****** * * ** * * * * * * ** ** * * ** ***** ** *** * * * * **** * * = x[i];
* * ** ***** ***** * ** * *** ** *** * *** *** * * ** * * ** * *** * * * * **** * * * * * = x[i+1];
**** * ** * ** ** * ** * *** * * ** * * * * * ** * *** * * * * * * ** *** * * = temporary;
** *** * * ** * **** **** * ** ******* **** **** * * * * * *** * **
** ** *** * ** ** ** *** * * ** **** *** *** * * *
* * *** * ** *** ***
********* * * * * * **
** * **** * * *** **** print the array */
* ** * * ** * * * * ** * ** ** *** sorting: \n");
** * ** ** * * *** *** i = 0; i < size; i++){
**** *** * **** * * ** * ** ** *** * ******* ** * * ", x[i]); ** * ****** * ** * ** * *
* * *** *** * *
* **** ***** ** * * ** **
******* * **** * *
** ** ** ** * * ** **
* ** * ** * * * ** * * ** * * ** *
* * * * * ** * * * **** ** ** * * *** * ** *  
*** * * **** * ******** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.110
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.9k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.8k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users