0 like 0 dislike
12k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *********** ** *** ** * x[] = {77,22,88,11,22};
* *** *** *** ** * ** ** size = 5;
    
* * * ** ** *** *** *** print the array */
* ** * * ** ** *** * * i = 0; i < size; i++){
* ** * ******* * ** * *** * * * * * * * ******** ", x[i]); **** * * * *** * * ***** * *
* * *** * * ***
** ** ** * * * * *** *** ** * **
* ******* ******* **** ******
* * * * * * *** ** **** ** I need this to happen size-times */
* * * * * ** * *** ** * * j = 0; j < size; j++){
* ** * *** * * ******** ** * * ** *** from left to right */
* * ** * ** *** * * * * ***** **** * *** * *** * * i = 0; i < size-1; i++){
* ********* * ** * ** ** ** ** * *** * **** ** ************* * *** * *** i-th element with its neighbor to check if they are in order */
**** * ** ** ** **** * **** * *** **** * * * * * * * * *** * **** > x[i+1]){
* ** * * * ** * ** * * * *** ** * ** *** * *** *** * * *** * * **** **** * ** * exchange the values of x[i] and x[i+1] */
***** * ** * **** * * ** **** ** * *** ** *** ****** ** *** * * ***** * * *** * * *** temporary; **** *** * * ** ** ** ** * *** ** **
* * ** *** * * ** * * ** *** ** ** * ** **** ** ********* ** ** * ***** ** ** * * = x[i];
* * *** * * *** *** *** ** ** * ** ******* * * * ** * ***** ** * * ** ** * * * * = x[i+1];
*** *** ** ***** ** ** ****** * ** ****** ** * ****** ** **** * * * **** * * ***** ** = temporary;
** **** * * * ** * * ** ****** * ** ** ******* * ** * **** *** *
**** * ***** * ** *** * ** ***** ** **
* * ** **** **** *
******* * * ** * **
** *** * * * * print the array */
** * * *** **** * **** * ** *** sorting: \n");
*** * ** ** * * * * * *** * i = 0; i < size; i++){
* ** *** * ** * * * ***** * *** * ** *** ** *** * * * ", x[i]); *** ** * * * **** ****
**** * ** * *** ** * **
** *** * * ***** * * ** ** * ** * *
**** * * * *****
* * ** * * ***** **
* ** *** * ***** * ** * * * * * * ** *
* * ** ** * *** *** * * ** ****** * ***  
* * ** ** * ****** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * * * * x[] = {77,22,88,11,22};
* ** * *** * * * ** *** * size = 5;
    
* * ** ******* * * print the array */
** ** *** * *** * ** i = 0; i < size; i++){
* ** *** * * * * * * * * * * *** * * ** ** ** ** ** * * *** ", x[i]); * ***** ** ** * ** * * *** ** * *
** * ** * * * ** *
** ** * * * * ** * ** *******
* *** * ** * *** *
** * * * ** ** * **** ** I need this to happen size-times */
*** ** * * * * * * *** j = 0; j < size; j++){
* ** *** * * * * * * *** *** * **** * * * from left to right */
** * **** * * ***** ** * *** ** ** * * ** * i = 0; i < size-1; i++){
** * * ** * * ** *** * ** ** * *** * * ** ** * * * * *** * * ** i-th element with its neighbor to check if they are in order */
**** ** ***** ** *** *** * *** * * * *** * ** ** ** * * ** *** *** * * * > x[i+1]){
* * *** ** *** *** ** * **** ** * ** ** * **** * ** * ** * **** *** ** ** **** ** exchange the values of x[i] and x[i+1] */
* * * ** ** * ** * * * * ** ** * * ** * * * * * * ** * * * * *** * ** * ***** temporary; * * * *** *** ** ****** ***
******* ******** ** * ** ****** * * * *** * ***** ****** *** ** *** ** * * * * ******* *** ** *** ** * ** = x[i];
**** * * **** * *** * * ** * *** * * *** * **** * * * * * * * * * ** ** * ***** = x[i+1];
* * ** ** *** * **** * **** ** ******* * **** * * *** ** *** ********* ** ** ** *** * = temporary;
**** ** * * ***** **** * ** * ** ** * **** * * ** *** *** * * ** *
*** * ** * ** ** * * **** ** * * * *
** * ** ** ** * * *
****** *** ** * *** *
**** *** ********* ** print the array */
** * * * ** ** ** * *** * sorting: \n");
* ****** * ** ** * * * * * i = 0; i < size; i++){
*** * * * *** * ** ** *** ** ** * ******* * * ** * * ", x[i]); * * * * * ***** * *** *
******* * **** * * *
** ** * *** * *** * * * * *
* ** ** *** * * **
* ** * *** ** * ** ** * ** *
* ********** * ** **** **** **** **
* *** * * * * ** ** * ***** * * *****  
** ****** * ** **** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ** * * x[] = {77,22,88,11,22};
* * ** * * *** ** size = 5;
    
* *** * * *** * print the array */
* * ***** * ****** * ** ** i = 0; i < size; i++){
**** * ** *** * **** * * ** ** * * * * ** ", x[i]); * ** * ** * * * ** * * * *
** * * ** * *****
* ** * * * * ** * ** **** * * * * * * *
** ** * ** ** * * ***
* * * ** * **** ***** I need this to happen size-times */
***** *** ** *** ** *** ** *** j = 0; j < size; j++){
* ** ** *** ********** ** *** * ***** *** * *** from left to right */
* ** * * ******** * ******* *** * * * ** * * * i = 0; i < size-1; i++){
* * * * ** * *** * * * ** *** ** * **** * * *** ** **** * ** * i-th element with its neighbor to check if they are in order */
* *** ****** ** ** ** * * * * * ** * * * * * *** ** ** **** ** * * > x[i+1]){
* * ** * * * * * ** ** ****** * * ** * * **** *** * * * * ***** * * * * * ** exchange the values of x[i] and x[i+1] */
* ** * * ** * *** * *** * ** ** * ** * * * ***** * * ** ** * * * * * ** temporary; *** ** *** * ***** * * ** * ** ****
***** * *** * * ** * * *** ** ** ** ** * * ** *** * *** *** ** *** ** * * ** **** * ** * = x[i];
* * * * **** * * * **** * * *** * * *** * ****** *** *** * *** *** * * * * * *** * * * = x[i+1];
** * ** * ***** * * *** ** ** *** * * * * ** ** ** * * * ******** ***** ** ***** *** = temporary;
*** ** ****** *** *** * *** * * **** * *** * **** * * ** **** **
***** *** * ** * * *** ** * ***** * ***
* *** * *** *** ** ** **
** * * *** * ** *****
*** * * ** * * * * * print the array */
** * *** * ** ** * ***** * ** sorting: \n");
* *** *** * * ** * * i = 0; i < size; i++){
*** ****** *** * *** ** * *** **** *** ** **** *** * ", x[i]); ** * * ** * * * * * ***
*** ** * * * * * ** *
** * * ****** * ** ** * *** *
** * ***** * * ** *
**** * ****** **** *
** * ******** * *** * ** * ** * * * *
* ** * ** * * ** *** ****** *** ***** * ** ** *  
* *** **** * ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * * ** * * x[] = {77,22,88,11,22};
* * * ** *** * size = 5;
    
* * *** * **** *** ** ** * * print the array */
* ** * * *** **** ** * i = 0; i < size; i++){
*** ** ** ** * ***** * ** ** ** * * * ** * ** *** * ", x[i]); ** * * ** **** * *** **** * **
** **** *** * * ***** *
* * ** *** * * * ****** ** * ** * * ** *
* *** * * ** ** ** *
** ** ** * ** * * * I need this to happen size-times */
***** ** * ** * ******* j = 0; j < size; j++){
* * * * *** * * * * * * * ** **** ** * ** from left to right */
* * ** * * ***** * ** * * * **** * *** ** ** * i = 0; i < size-1; i++){
**** ** ** *** ** * ** * **** *** * ** ** ** *** *** * * * **** *** * * i-th element with its neighbor to check if they are in order */
*** ****** ** * ** * * * * * * **** ** * * ** * ******** * * *** ** * > x[i+1]){
****** ***** * * * * **** * ****** * * ** * * * **** ** ** * * ****** exchange the values of x[i] and x[i+1] */
*** ** ** * * ** * * *** **** ****** ** ** ** ** *** ** ******* * * * * ** * * **** * temporary; ** **** * * *** * ** ***** ** * **
**** * ***** *** *** *** * ** * * *** * * * * ** * ***** * ** * * * * ** *** * * * * = x[i];
* ** * ** * * * * *** *** ** **** ** ** *** * **** * * * * * * * **** * ** = x[i+1];
** ** ***** * ** * * ** * ******* *** ** * * ***** ** * * *** * *** * * ** **** * * ** ** = temporary;
* * *** ******** * ** *** * ** ** ** * * * *** ** *** ** *** ** ** **
* *** ** * * * ** * * ** * * *** * **
* * * ** **** ** ** * **
* * * ** *** *** *
**** * * * * * print the array */
****** ** **** * * ***** * ** * sorting: \n");
* ** **** * * * * * i = 0; i < size; i++){
* ** * ** * * ** * * *** ** * * * * ***** ** * ", x[i]); **** * * ** ** *** ** ** * ** * *
* ** * * * *** ****
** ** ** ** * * * ** ** ** **** ******
*** *** *****
* * * ****** *** * * *
** * * * *** *** * ** *** * * *
* ** * * * * * ** * * *** *** ** *  
* ** * * * * * **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** *** * **** * ** x[] = {77,22,88,11,22};
* * * * * ** * * ** *** ** size = 5;
    
**** ** * *** * ** ** print the array */
******* ***** * * * i = 0; i < size; i++){
*** * * ****** ** *** ** * ** ** * *** ** ** * **** ", x[i]); * * * * ********* *** * ** *****
* * *** ** **** ** ** **
* ** * **** * ** ** ** *** *
* * * *** *** ** * *
** * * * ** ** *** I need this to happen size-times */
* ** **** ** * ******* *** j = 0; j < size; j++){
** ***** * **** ** * *** ******** * ** * * ** from left to right */
** *** * * **** ** ****** * *** * *** ** * *** i = 0; i < size-1; i++){
*** * *** ***** * *** *** * * * * * * * * *** * * * ** ** * * i-th element with its neighbor to check if they are in order */
* *** * * ** * * * *** * ** **** ** *** * * * * ***** * ** > x[i+1]){
* ** ** * *** ** * ** *** ****** *** *** **** * * * *** * * * * * * * * *** * exchange the values of x[i] and x[i+1] */
**** * ***** ** * ***** * * * * * * ** * * * *** *** *** * **** ** * *** * temporary; ** ******* * ** * * ** ** * * * ***
* **** * ** * ** **** ** * * * * ** *** * * ** *** ****** ** * ** *** ** * *** ** = x[i];
** * ** * ***** ** ***** ** * *** * *** ****** **** * ** * ** * * * * * * ** * * ******* = x[i+1];
* ** * ** ** * ** *** * *** * *** ** ** * ** * * * * * * ** * * **** * * * ** ** = temporary;
* ** * * * ** * *** ** ***** * ********** * ***** *** * **
* *** ****** * * ** ** ** *** ** * * ** * *
* * ** *
* ***** ****
***** *** * * ** ** *** ** * print the array */
* ** **** * * * **** ** * * sorting: \n");
** * * * *** ***** * ** i = 0; i < size; i++){
* ***** * *** * * * *** * ** * * *** * ** * * ** * ** * ", x[i]); * ****** * * ***** ** * *** * **
****** * * ** *** *
** * * ***** *** * * * * ** *** *
* ** * * ** *** * * *
* ** ** * * *** ***
* ***** * **** * *** * ** ** ** *
*** *** *** * ** * * * * ** ****  
*** ** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** *** ** ** * x[] = {77,22,88,11,22};
* ** ******* * ** ** *** size = 5;
    
* ** ** * *** * * print the array */
* * ** *** ** * *** * i = 0; i < size; i++){
*** ****** * * ** * * *** ** * **** *** * * * * ", x[i]); *** * ** * * ** **** * * * *** ** * **
*** ** * *** * ** * * *
* * * * **** *** ** ******** ** ** ***
* *** * ** ** * *** * * **
* * * * * **** I need this to happen size-times */
****** *** *** **** * *** *** j = 0; j < size; j++){
* * * * *** **** * * * * ** * * **** ***** from left to right */
*** * * ** ***** * * ** * ***** *** * ** ** i = 0; i < size-1; i++){
* * * * ** * * ** * * *** * *** ******* * * * * * *** ** ** *** i-th element with its neighbor to check if they are in order */
* ** * * * * * ** * * * ** * ** * ** * **** * * * * *** > x[i+1]){
* *** * * ** **** ** ** *** **** ** ** ** * ** * * * * * ** * * * * * exchange the values of x[i] and x[i+1] */
* ** * * ** ** **** ***** * * *** * ******* *** * ** * *** **** * ** * * * **** ** * temporary; * * * ** * ** *** *** **
* * ***** * * * * * ** * ***** ***** * * ** * ** ****** * * * **** *** ** * * ***** * ** *** = x[i];
** * ** * ** *** * ** **** ** * * ** * * ** * ** *** ** *** ***** ** * * * ** * * * * = x[i+1];
**** * * **** * *** ** * ** * * * * ** * * * *** * * **** * ** * * **** = temporary;
*** * * * * * ** *** **** * ** ** ** * * ** ******** * *
*** *** *** *** * * *** ** ** * * * ****** *
* ***** *** ******** ** *
* * * ** * * *** * * *
** ****** *** ** **** print the array */
* ** * ** *** ** ******** * ** * sorting: \n");
* **** * ** ** * ** * i = 0; i < size; i++){
** * *** * ** ** ** * *** **** * * ** *** * ** * *** *** ", x[i]); ********* ** * * * ** * * **** ****
* *** * * *** *
* *** *** ** * * ** ** * ** * ** * * ***
** * * ** * ***** *
*** ****** * * *** ** *** *
* ** * *** * * * *** * * * * *
** *** ** ** * * * *** * * * *** ** ** * **** *  
* **** ** ***** *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * **** * *** x[] = {77,22,88,11,22};
* ** ** * *** * size = 5;
    
* * * **** * * * ** * print the array */
* * *** * *** * * * * * i = 0; i < size; i++){
* * **** **** ** * ** * * * ** ** * * * ** ** *** * ", x[i]); ** * * * *** *** * ** ** ** *** *
* *** * * **** * ** **
* *** * ** * *** * * ***** * **
* * *** ** * * **
* * * ** * * ** ** * ** I need this to happen size-times */
* * * * ** * ** **** *** j = 0; j < size; j++){
* * * *** *** * *** ** * ** **** *** ***** *** from left to right */
** *** * * *** * **** ** * * * * *** * * * ****** i = 0; i < size-1; i++){
* * ** * ** * **** *** * * * * * ** ** * ** ** * ** ** * * * ** i-th element with its neighbor to check if they are in order */
* * * ** * *** * * * * ** * * ** * * * * * * *** ***** **** * > x[i+1]){
* ** ** *** **** * * ** *** * * ** *** *** * **** *** *** ** ** ** * ** ** * ** ** *** exchange the values of x[i] and x[i+1] */
* ***** * **** **** * * *** ** * ** *** ***** * *** ** ** * ** * ** ** * * temporary; * * *** * ** ** ** * ** ***
* * ** * ** ** ***** * *** ** ** * * * ****** * ** * *********** * * ******** * = x[i];
* * * ** * ** *** * * **** *** * *** * * * ** * * * * ***** * *** * ** * * * = x[i+1];
* ** * * *** * *** * * ** ****** ** **** * * * ** * * ********** ** ** ** ***** * ***** * * = temporary;
* ** * ** * ** ** * * * * ** * ** ** **** * * **** * *
* ****** * * * ** ** * * * * * *** ***** *
* * ****** ***
** * ** **** * ** **** *
* ** * * ******* **** *** print the array */
** ** *** *** ** ** * ** * * * sorting: \n");
*** ** ** *** * * ** ** i = 0; i < size; i++){
* * *** * ** **** *** ** *** * ** * * * * ** ", x[i]); * *** * * * * * ** * ****** * * ** ** *
* **** * * * ****
* *** * ** ** * *** * **** ** * **
* * ** *** * **
* ** ********* ** *
* * ** ** ***** * *** * *** ** **
** ** *** ** *** *** **** *** * * * * * ** *** **  
* *** * * ** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** ************* **** x[] = {77,22,88,11,22};
* *** ** * *** ** * ** * size = 5;
    
* ** * * * **** * ** print the array */
** * ** **** ** * *** i = 0; i < size; i++){
* * * *** **** ** * ** ** ** ** ** * * ** **** ** ", x[i]); * ** * ***** * **** ** * ** * * * *
* * *** * * ***** ***
**** *** * ** *** ** * *** *
* * * ****** * ** **
* * **** * ** *** I need this to happen size-times */
*** *** * ** * *** * * j = 0; j < size; j++){
* * *** *** *** *** * ** *** * * * * * *** * from left to right */
* **** *** *** * * ** *** **** ** * ** *** *** i = 0; i < size-1; i++){
* * **** *** ** * * * **** ** ** ************* * * ** * * * ** * ***** i-th element with its neighbor to check if they are in order */
* * *** * * * * ** * ** * *** * ** * ** * ** * * * * * * * ** * * * > x[i+1]){
* ** ** *** ** * ******* **** ** * * **** * * * * ** * ******* * * ****** * **** *** *** exchange the values of x[i] and x[i+1] */
* * * ** *** * * ** ***** * * **** ** *** ***** * * **** * * ***** * * * * * *** *** * * **** temporary; * ** ** *** **** *** ****
* ** * * * * * * ** * * * *** ** ** * *** *** ** * ** ********* * * ** * ** ***** ** * ** = x[i];
**** ** * * ** **** * * ** ** * ** ** *** * * * * * * * * ** ***** * = x[i+1];
* ** * * *** ** ** * * * * ** * * * *** * ** ** * * * * * * *** * * * * * * * * ** * ** * ** ** = temporary;
* * * * * * * ** * * * **** * **** * ** * * * ** ***
***** * **** * **** **** * ** ** *
** * * * * * * ** *
* *** ** * ** *
* * ** * * ** *** print the array */
** ** **** ****** * * * ** * sorting: \n");
* ** * * * * * ** * *** i = 0; i < size; i++){
** * **** *** * ******** ** * *** * * * ** * ** ", x[i]); *** * * * ** ** * * * *****
** * *** *** **** **
* **** * ** * * * ** ** * * * ** * **
* ** ** *** **** * ***
** * ** ** ** ** *
* **** * * * * * *** ** * ** * * ***
* * * ** * ** ** * **** ****** * * *** * * **** *  
** * **** ** * *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** ** ** **** x[] = {77,22,88,11,22};
* ** **** * ** * * **** size = 5;
    
* * * * * * ***** * * * print the array */
* * ** *** * ** * * *** *** i = 0; i < size; i++){
** ** *** * * * **** ** ****** * * ** * *** *** ** * ", x[i]); * * ** * *** * * * **** *
* *** ** *** ***** * *
* * ** ******** *** * * ** **
* ** **** ** ****** **
** * *** * ** * ** * I need this to happen size-times */
* * *** ** ** * *** *** * j = 0; j < size; j++){
*** ** ** **** * * ** *** * *** *** * from left to right */
**** * * * * * * ** ** ** * * ** *** * * ** i = 0; i < size-1; i++){
* * ** * ** ** * * *** *** * * **** *** ** * ***** * * i-th element with its neighbor to check if they are in order */
** ***** * * **** ** * * * * * * * * * ** * * **** *** * ** ***** * > x[i+1]){
* * ** * ** * * * * * * ** * *** * * ** ** * *** * * * ** ** ** *** *** **** * exchange the values of x[i] and x[i+1] */
* *** * * **** ***** ** ***** * **** **** ** * ** * * ** * ******* ** ** ** ** temporary; * * ** * * * * ** * * *
**** * ****** * * * * * ** * **** * * * * * **** * * *** * ****** * ** ** ** ** * *** *** * ** *** *** = x[i];
* ** * ***** ** * * ** * * *** ** *** * ** * **** * *** **** ** *** *** **** ** = x[i+1];
* * * *** * ** *** ** * **** *** ***** * **** * * ****** * * * ** ** ** * * ** *** = temporary;
* **** * * * * ** * **** **** ** * ** * * ** *** *
*** * ** **** * * * * ** *** * ** ** ** *****
** * * ** * * * ** ** ***
*** * * ** * **** ********
** *** * ** *** ** *** print the array */
* **** * * **** * *** *** * sorting: \n");
** * * ** ** ****** ** *** ** * i = 0; i < size; i++){
***** ** ** * ** * * * ** *** **** * * ** *** * * ", x[i]); * *** * ** * ** * ** ** * * *
** * *** ** ** *** *
* **** ****** ** ** * * *** ** **
* * * * *** *** * *****
* ** * ** * ***
** ***** ** ** * ** * *** * * * * *
* * * ** * * * * * ******* * ** ** *  
** * ** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * ****** * * * x[] = {77,22,88,11,22};
*** ** **** * * * * * * * size = 5;
    
* *** * ******* *** * print the array */
* * * * * * ** * * ***** i = 0; i < size; i++){
** * *** * * ** * ** *** ** **** ** * ** **** * *** ** ", x[i]); *** * * ** * *** * * * ** * *
* ** ** * * * ** ****
****** * **** ** ** * ** ** * * *
**** *** ** * * ****
* * * *** * * * *** I need this to happen size-times */
** **** * ** * **** j = 0; j < size; j++){
* *** * **** * * * * * * * * * from left to right */
* **** *** *** * ** * ** * ******* * ** * ** i = 0; i < size-1; i++){
* * * ** * * ** * ** ** **** ** **** * ** ****** ** ** * i-th element with its neighbor to check if they are in order */
** * * * * * * * **** ** * *** ** ** ** *** * > x[i+1]){
* * ***** ** * **** * ** * *** ***** * * * * * ** ** * ***** ** **** * * * ** **** * * * exchange the values of x[i] and x[i+1] */
*** * *** **** *** ** ** * * *** *** ** **** ** * * ** *** **** * ** ** * * * ** **** * temporary; * * **** **** * * ** *** *** ** * *
** ** ** * ** *** * * * ** * ** ** ** ** * *** * * ** * ** **** * ** * ** ** = x[i];
* *** **** ********** * *** * * * ***** * * *** * ** * * ** **** ** ***** ** * ** * = x[i+1];
* ** ** **** ** ** * * ***** * *** *** * * *** * * * * ** * ********* * *** * * * ** ** = temporary;
*** ** * **** ** * * ** * * ** * ** ** ** * ** ** * * * * *
**** ** **** * * ** * ** ** * * ***** ****** *
** ***** * ** * **
* ** * * ** * * *
* * **** * * * ** print the array */
**** * * **** *** ** ** *** ** * sorting: \n");
* * *** *** * ***** i = 0; i < size; i++){
* * *** * ** * ***** ** * ** * * ** **** * ** * * ", x[i]); * ** * ** * ** * **
*** * * *** **
* **** * ** * * ***** *** *** *** *** * *
** * * ** * ** * **** *
* ** * * *** * ** ** *
* ** * * * * * ******* ** * ** * **
*** * * ******* * * * ****** **** ** * * * *  
* ** *** ** ** * * ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users