0 like 0 dislike
10.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 10.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** **** * * x[] = {77,22,88,11,22};
***** *** **** size = 5;
    
** * ** ** * * print the array */
* ** * ** * *** * * i = 0; i < size; i++){
* * * ** *** ** *** ** * * * ** * * ***** * ***** * * *** * ", x[i]); *** **** ** * * * * ** * **
** ** * * * *** ***
** *** ******** ****** ** * * * ******
* * ****** * * **
* *** ****** * ** **** *** * I need this to happen size-times */
* ****** * ** *** * j = 0; j < size; j++){
**** * * * **** ** ** * **** **** * *** * * from left to right */
* * ** * * *** *** * ** * ** *** * ***** * i = 0; i < size-1; i++){
*** *** * * * * * * *** ** *** * * *** * ** * **** ** ***** i-th element with its neighbor to check if they are in order */
* ** * **** * ***** ** ** * * * * **** * ** ** * * *** ** * > x[i+1]){
***** * ** *** * * ** ** ***** * *** *** **** * ** ** * ****** ** *** * ****** ***** *** * exchange the values of x[i] and x[i+1] */
* * * ** ** ** * *** ** **** * * * *** * **** * * ** * ** * * ******* * * *** temporary; ** * ** **** ** * * ******
* * ** * * *** *** *** ** ***** **** * ***** * * *** * ** ** ** * ** * ** * *** ** **** * *** * ** * ** = x[i];
* *** * *** * ** * *** ** * ** **** ** ** * ****** ***** ** * **** * * * **** * * **** * * *** * = x[i+1];
*** ** ** * ** **** ****** *** * *** * ** ** * ** * * ** * **** * * * *** * ** * = temporary;
* * **** **** * ********* * * *** ** *** ***** * * * ** * *
* * *** ** ***** ***** * * ***** * ** **
* * ****** * * *
** *** ** *** ** **
** * * * ** * ** **** * print the array */
** * ***** ** * * * * ** ** * ** sorting: \n");
* ** ** *** * * * i = 0; i < size; i++){
**** * ** **** ***** * *** ** * * * * ** * ***** * ", x[i]); ** * * * *** ** *** * **
*** ** ** * *** * *
** * *** * * * * * * * *
* ** ** *** * *
*** * ** * **** **
* * * * * ******* * **** * * *
** ***** ** * *** ****** ** ** *** **  
* *** ***** ** ** * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** ** ** **** * x[] = {77,22,88,11,22};
* * **** *** ****** *** size = 5;
    
* * ***** ** * print the array */
* **** *** *** * * i = 0; i < size; i++){
* ** *** * *** * * * * * ** ** ** ** ** ** *** **** ", x[i]); * ** ** * *** * ****** * *** * * ****
** * * * * ** *
** * ******* * * * **** * * ** * * *** ***
*** * *** *** * ***
*** * *** * ** * * *** I need this to happen size-times */
** * ** * *** ** ** ** * * * * j = 0; j < size; j++){
** **** * * * * * * * * **** *** * * * from left to right */
** * **** * * * *** * * * ***** ** * ** * i = 0; i < size-1; i++){
** ****** * **** * **** ** **** * ** * * * * ** * * * * ** ** i-th element with its neighbor to check if they are in order */
****** *** ** ***** *** *** ** * ** ** ** * * ** * ** * * ** *** * > x[i+1]){
** ***** **** * *** ** ** **** ** *** ** * * * ** ** * * * ** * ** ** * * exchange the values of x[i] and x[i+1] */
** ** * * * * * *** * * * ** * ********** * ** ****** ** * ** * * * ** * * ** ** **** ** ** * temporary; * * ***** **** * * ****** * * *
** *** ** ** * *** * * ** * * * ** *** * ** ** ** * *** ****** * * ** *** * ** = x[i];
* *** * ** * * * * **** * * * ** ** * * ** *** * * * *** *** * ** * * ** * * *** = x[i+1];
* ** ** *** ** *** * ** *** ** ***** * * * * ***** * ** * **** ** ** *** *** ** * *** * = temporary;
** ** ** *** ** ** * * * ** * * * * * * *** * * ** * ******
******* * *** * * * *** * * * * ** *** ** * ** **
* ** * ******
* **********
*** ***** * * ***** * * ** print the array */
* * * *** * * * * ** * * * * * *** * sorting: \n");
** * ** * *** * * ** * ** i = 0; i < size; i++){
** ***** *** ** * * * **** * * * *** * *** ", x[i]); * * * * * ** *** * * **
***** **** *** *** * *
* * * ** * *** * * ** ** * ***
*** * *** **********
* **** *** * **
** * ** * * * * * **** * * ** **** **
** * * * *** * * ** * ***** * * * * **** *  
* ** ** *** *** * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** * * x[] = {77,22,88,11,22};
* * *** ***** * ** ** size = 5;
    
** * *** * * * * print the array */
* * * ***** ** * * * i = 0; i < size; i++){
* *** * * * * * * ***** * **** * ***** * **** ", x[i]); * * * * * * ** * ** ** *
*** * ** * ** *** *** ***
** ** * * * ** * ** ** * ***
*********** ** * ***** * **
* *** * ***** I need this to happen size-times */
* * * * ** *** ** * * j = 0; j < size; j++){
* ** ** * *** ** * *** * ** ****** ****** ** from left to right */
* *** * * * * * * ** ** * * ** *** ** ** ** ** * i = 0; i < size-1; i++){
** * * ** * ** * ** *** * * * ** * ** * * ***** * **** * * ****** * * * i-th element with its neighbor to check if they are in order */
** * ***** ** ** *** ***** * * * *** * ** ***** * * ***** ** > x[i+1]){
* ** * *** * * * **** * * ** * * * ***** ** ***** ** * * ******* **** ** exchange the values of x[i] and x[i+1] */
** ** * *** * * ******* * *** * * * *** * * * * * * * ** * * * * * ** * * * * * temporary; ** ** * * ** * * * * * ******
** ** *** * * * * * * ** *** ** * * * * ** ** ** **** ** **************** ** ** ******** **** * = x[i];
* ** ***** * * *** *** * **** * * * ** * *** * * * * ** * ** **** * ***** * ** ** ** * * * = x[i+1];
** * * *** **** * * * ** * **** ** *** * * * * * * * * *** * * * ** ** * * ** ***** = temporary;
*** ** * **** ** ** * *** * * * ******** ** *** **** * ** * * * ***
******** ** * * * * ** * * * * *** * *
* * ** * ** *** ** * ***
* **** * * * * *
*** * * ** * *** * ** print the array */
** * ** ** ** * * * **** ** ** * * ** sorting: \n");
**** ** ** * * ** * i = 0; i < size; i++){
***** * * * * * ** * * * ***** ** * ** *** * * ", x[i]); ** ** ** ** ** *** ** * *
* ** ** * * * ** *
** * * * ** * * ** * *** * * * ***
** **** *** ** *
* **** **** * ** * * * *** *
** ** * *** ** *** **** *** ** *** ** ** *
** ** ** * * * ***** ** * *** ***** * ** **  
**** ** ** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * *** *** *** ** * * * x[] = {77,22,88,11,22};
* ** ** ** **** ** * size = 5;
    
** ** ** * * print the array */
* * **** * * ** * * * i = 0; i < size; i++){
* * * * ** * ** * ** ***** *** ***** * * * ", x[i]); *** * * * * * * * ** *
* * ** ** * ****
* ** *** ** * * ** * * ** * *
* * * * *** * **
* ****** * * * * **** *** I need this to happen size-times */
* * * * ** *** * ****** ** j = 0; j < size; j++){
** * * ** *** * *** * *** *** * **** from left to right */
* * * ** *** * ** **** * *** * * * i = 0; i < size-1; i++){
*** *** *** * *** * ***** * *** ** * * * *** * ** * ** * * i-th element with its neighbor to check if they are in order */
** * * *** * ***** *** * ** * * * ** * ***** *** * ** * * > x[i+1]){
* ** ** * * * *** *** *** ** * * ** ***** ** * ** * ** * ** ** * ** ** ****** * * exchange the values of x[i] and x[i+1] */
** * * ** *** * ******* * * ** ** ** * *** * * **** * * *** * ** * * * ** * ** temporary; ** * ** *** ** * ** *** **** * *
* * ****** ** ***** ** * * * ***** * * ** *** *** **** * ** * **** * ** * ***** * * ** ** = x[i];
* * * ** * ****** * ***** * * ******* ** **** **** * * * ******* ** **** ** * * * ** ** * *** ** = x[i+1];
* * *** ***** ******* *** *** * *** ** * ***** *** * *** **** * ** * * **** * *** *** ** ** * = temporary;
* * * * * * **** * * ***** * *** *** ** * ** ***** * ***
* ** ** * * **** ** ** * * * ****** ***** **
** * * ** ******* *
* * ***** ** * * * **
** * *** *** * ** * * **** print the array */
* * * * ** * * ** * ** ** * * * sorting: \n");
*** *** ** ** * * * i = 0; i < size; i++){
*** *** * * * * * * * * * * ** ***** ** * * * * * * ", x[i]); * * ******* * * ** * * *** * ** *
** * *** * **
** * * **** *** ** *** ** * ** *
** ******* * * * ****
** *** ** *** ** * **
* ****** ** * * ****** *** * ** * *
*** ** *** * *** * * ** ** ***** ***  
* * * * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ** x[] = {77,22,88,11,22};
**** * ** ** ** *** * * * size = 5;
    
* ** * ** *** * * * * print the array */
* * * * * ** * * ** i = 0; i < size; i++){
** ** * ***** *** ** **** *** * * ** **** * * ", x[i]); ** ** ** *** * ****** * * * ***
** * *** * **
**** * ** ******* * * * ** * ** * * *
*** * ** * *** **
* **** ** ** * *** ** I need this to happen size-times */
** *** **** * * * * *** j = 0; j < size; j++){
* ** ***** * * ** * * * * ** ***** * **** from left to right */
** *** * * * * * * ** * ** ** * * * ****** * i = 0; i < size-1; i++){
* ** *** * * ***** ** * * ******** ** ** * ********* *** ** i-th element with its neighbor to check if they are in order */
* ***** *** * * * * * * *** ***** * * * ** *** **** ** ** * > x[i+1]){
* ** ** * ** *** ** * * **** * * * * ** ** * * * * ** * ** * * ** * *** exchange the values of x[i] and x[i+1] */
**** * * * * * * ** * * * * * *** * ** ** * *** ** * **** **** *** *** * * * ****** temporary; ** ** * ** * ** ** * * * *****
** ************* * * **** * ** * ***** * * ** * * * **** * ** *** * ** * * ** ** = x[i];
* *** ** ** **** ***** * ** **** * ** *** *** ** * **** *** ***** * ** ** **** * ********** * = x[i+1];
* **** * ** * ** * * * * * * * * *** * * * ** * * ** *** ***** *** ** *** * ** = temporary;
* *** * * ***** ***** ** * * *** * * * **** * * *** * ***** *** * ***
* * ***** * *** * *** **** * * * ** *** * ** **** *
* * * * * *** *******
* ******* ** ** * *** ***
* ** ** * * ** * print the array */
* * * * * * ** **** * ** ***** ** * sorting: \n");
* * ** * *** * * ****** i = 0; i < size; i++){
* ** * *** * ** * **** * ** *** * ** * * * ** ", x[i]); * * * * * ** * ** * * * * *****
** ** * * * ** *** * ***
*** ** * ******* * ** ** * *** ** * *
* * * * ** ** ** * ***
* * ** *** * * **
*** * ** * *** * * ***** * *** *
* * * ****** ***** ***** **** **** **** *** ***  
* ** * * * *** * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * ** *** x[] = {77,22,88,11,22};
** * * * * * *** * size = 5;
    
* * * *** ** * * *** ** print the array */
*** * * ** * ** **** i = 0; i < size; i++){
* * *** * ** ** *** * **** * * * ** * * * ** *** * * ", x[i]); * * ** * * **** * **** ** *** **** *
* ******* * ** *
* ** * ******* * ***** * * * ** ** *
* * *** ** ** * ** ** *
** ** * *** ***** *** * I need this to happen size-times */
** * * * ******* *** * *** j = 0; j < size; j++){
** * * * * **** * * * * *** * ***** * * * from left to right */
* ***** * *** * ******* * **** * *** ** * * * * i = 0; i < size-1; i++){
** * ******** *** *** ******** * * ***** * *** * ****** * *** ** *** * * *** i-th element with its neighbor to check if they are in order */
*** ** ** * *** * * * * *** **** ** * * ** * * * * **** > x[i+1]){
** * * * * * ** * * * * * ***** *** * * * * * ** * *** * ** ** ** * * *** * * * * * ** ** * exchange the values of x[i] and x[i+1] */
****** * ** ** * *** * * * ** ** *** * *** * * * * * ** *** *** * ** ** ** temporary; **** ** ******* * * * *** ** * *** *
* ** * * ** ** ***** ** * * * * * ** ** ***** **** * ** * * **** * **** ** * * *** = x[i];
**** * * ** ******** ** ** ****** * **** ***** ** ** * ** * * * ** ** ***** ** ** * * = x[i+1];
** * ** * * * ** * * * * **** * ** ** * *** ** * ** * * ** ** * **** *** * ** ***** * * * = temporary;
* * * *** *** *** **** *** * *** * ** ** * * *** * * * **
* * * * ** * * * ******** * ** * * * ***
** * * * * ** * *
*** * ** * * * *** *
* *** *** * *** ** print the array */
* *** ** * *** ** ******* ** sorting: \n");
****** * ** ** * ** i = 0; i < size; i++){
* * ** * ** ** *** * * *** ** * ** * ******* ** * ** ** ", x[i]); ** ** ***** * **** * * * ***
*** * * * ** * ** * * *
***** ** * ** ** * * * * *** ** **
* *** * ** *** *******
* ** ***** ** *** *
* ** * * * ***** ***** ** ** *
* * ** ** * * * ** ** **** ***** **** ** *  
**** ** * * * **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * **** * ** * x[] = {77,22,88,11,22};
** *** ***** * * * * size = 5;
    
**** **** ** *** * *** * print the array */
** * ** * * **** *** ** * * ** i = 0; i < size; i++){
* ** ** *** * ** * * * * * ** * * * * ** *** ", x[i]); ** *** *** * ** * *** ** ** * * **
***** * **** *** *
* *** *** * * *** ** ** ** * ** **
** * * * ** * **
** * * *** **** * * ** I need this to happen size-times */
** ** ***** * ** * j = 0; j < size; j++){
****** * ** * * ** * ** * * ** *** from left to right */
* * ** * ** ** * ** ** ** ** * ** ***** * * ** * * ** i = 0; i < size-1; i++){
* * * **** * ***** ** ** ** *** * * * * * * ** * *** * ** * ** * **** i-th element with its neighbor to check if they are in order */
* ** * *** * ** * * *** **** * * * * * **** *** * * **** * * * ** > x[i+1]){
*** * *** ** * ** ** *** ** ***** ** *** * * * *** * * * **** * ******** ** ** exchange the values of x[i] and x[i+1] */
* * * * *** * * * * * ** ** * * **** * *** ** **** * ** ****** * *** temporary; * * **** **** * * * ** * * ***
** * ** ** *** * *** * * ** ***** * * ** * * ** * * * * * ** ** ** *** *** ** * * ** = x[i];
*** ** ** *** *** ** ** ***** * **** * * * *** *** ** **** * ** *** * *** * ** ** *** = x[i+1];
** ** * ** * * * * *** * * ** ** ** ** * * * * * **** * * ** * * * ** ** ** * ** = temporary;
***** * *** * * *** * ** * * ** * * **** *** **** *** * * ** **** * *
* * ** * ******** ** * * * ** ****** * ** *
* *** * ** **** * * *
* *** ** * *** **** *
* ** ** * ** * * ** print the array */
* *** ** * * * ** * * * **** * * sorting: \n");
***** *** * * * ***** *** i = 0; i < size; i++){
* *** ** *** * * * * *** * * ***** * * *** * ", x[i]); * * ** * *** ** * * * * *** *
** * * * *** * *
* * **** *** * ** * ** * * * * *****
* * * ** ** ** ** * * *
* * * *** * *** * *
* * ** * *** * * * * * * ** *
** ** * * * ** ** ** * *** * * *** **  
** *** * * ** ** ***** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ********* ** * ** x[] = {77,22,88,11,22};
**** * ** ** ** * ** * *** * size = 5;
    
* * * * ** ** *** print the array */
** ** * ** * ** * * * *** i = 0; i < size; i++){
*** *** * * * * ****** * * * ** * * ** * * **** ", x[i]); * ** * * * *** * * * **** **
****** ** * **
* * **** * ** *** ** ** * * * **** ** **
***** **** ****
**** ** * * *** ** I need this to happen size-times */
*** *** ** * * * ***** * j = 0; j < size; j++){
* * * * * ** ****** ** *** **** * *** ***** from left to right */
* * * * ******* * * **** * * * ** ** *** i = 0; i < size-1; i++){
*** *** * **** * * ** **** * * *** ** **** **** * * * ** **** * * i-th element with its neighbor to check if they are in order */
** * ** ** * * *** * * ** * * * ** ***** * ** ** > x[i+1]){
** ****** ** ** * ** *** * * * * ** * *** *** *** * * * ** * *** **** *** * ** *** * * exchange the values of x[i] and x[i+1] */
** * * * * * ** * ** *** * * ** * * ** ** ********* * * * ***** * *** * * ** * temporary; ** ** ** * ** *** ***** * ** * *
* *** * * ** ** **** * * * * * ** ****** * * *** *** ** * ** * *** * * * ** ****** * * = x[i];
* * * *** * * *** * * ** *** * * * * ***** * ***** ** **** * ** * ** * * ** = x[i+1];
* **** ** ** * * * * ** * **** * *** ** * * * ** ****** * **** ***** * ***** ** = temporary;
*** * ** ** * * * * ** **** ** * ** ** ** * *
**** * * ** * *** * ******* * ** ** *** * * * ***
* * * * * * ********
** *** *** ***** **
** ** * * **** * print the array */
* ** * * * * ** **** * * * sorting: \n");
* *** * ** *** **** *** * ** * i = 0; i < size; i++){
** * * **** ** * *** * * * * ** * * *** **** * * ", x[i]); ** * * * * *** * * ** * *****
* *** * * * ***
* * *** ** *** * * * * ***** ***
* ** ** ** * ** ***** ** *
** * * * * * ***
* ***** * * ** *** ****** *** * * *
*** ****** *** * * * * * * * ** ** * * **  
******** * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** ** * **** *** ** x[] = {77,22,88,11,22};
****** ** * ** * * * * size = 5;
    
* * * ** * **** print the array */
* **** * *** * * * ** i = 0; i < size; i++){
* * * * * ** * * * * * * * * * * * **** *** ** * * * ", x[i]); * * * * *** ** * ** ** * * * * *** *
** ******* * * * *
* **** ** ** * * * ** * * *
* * * * * ** ** *
* **** * * **** *** * *** * I need this to happen size-times */
* * *** ** ******** j = 0; j < size; j++){
* * ** ** * * * ** * ***** * ** ** ** ** from left to right */
* * * * * * ** * * * ** ** * * ** i = 0; i < size-1; i++){
*** *** * * * * * * * ** * * * * * * ** * *** **** * * **** * **** ** * * i-th element with its neighbor to check if they are in order */
* ** ** ** ** ********** * ** ** * * *** ** **** * **** * **** ***** *** * ** ** * * ** > x[i+1]){
* * * * * ***** ** ** *** *** * ** * * ** * ** ** * * ****** * * ** * exchange the values of x[i] and x[i+1] */
* * * * * * ** * *** ** * * * * * *** * * * ******* ****** *** * ** ** **** temporary; *** * * ** *** * * ******* *
*** * *** * * **** * * * * *** *** * ** * ** * * ** * * * * * * *** * ** ** = x[i];
* * * * * **** * * * *** *** ****** * *** * * **** ** **** ** ** * * * *** * ** * * * *** ** * = x[i+1];
* ** * * * ** ** *** * ** * ** ** * ** * * * * * *** * * ** *** * **** ** * = temporary;
* * * * **** * * *** ** * ** *** ** ** ** * * * ** ****
**** * * * * *** * ***** ** * ****** ** *
** * * * ** *** ** *
* *** ** *** * *** *
* * * ** * **** * print the array */
* ******** * ** * * * * ** *** sorting: \n");
* * * ** ** ** ******** * i = 0; i < size; i++){
*** ** *** * * * ** * * ** ** ** * ** ** * ** * * *** ", x[i]); * * * ****** * * * * * ****** *
* ***** ** ** ***
* ** * * * * * *** * ** * * *** * *
* ** * ** *** ****
** *** * *** **
** * * * * * ** * * * **** * * **
** * ** ** * * ****** * * ** * * ** * **  
** ** * * *** * ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * ** ***** ** * x[] = {77,22,88,11,22};
**** * * *** ***** * *** * size = 5;
    
* * * *** ** **** print the array */
* ** * * * ******** *** i = 0; i < size; i++){
**** **** ****** ** * *** *** *** * ** *** ** * ** **** ", x[i]); ** * ** *** *** * * **** * *
* * * * * * ** ** * ** *
** ** * ** * ** ** * ** * * **
*** **** ****** ** * *
*** * * **** *** ** ***** I need this to happen size-times */
****** ** ** *** *** *** j = 0; j < size; j++){
** ** ****** **** ****** *** * ** ** *** * from left to right */
* * ** * *** * ******* * * * ** * * * ** * *** i = 0; i < size-1; i++){
*** * * ***** ** ***** ** *** ** ** * * * * * ** * * ** * * ** i-th element with its neighbor to check if they are in order */
* * * ** ***** ** ***** ******* * * ****** * ** * ** * *** * * ** ** *** > x[i+1]){
* * * ** *** ** ****** * ** **** * * ** ** * * ** * * ** ** ** * * **** exchange the values of x[i] and x[i+1] */
**** ** * * ** *** * ** ****** **** * * ** *** *** * * *** ** ** * * ** * ** * * temporary; * * * * ****** ** *** * * ** ****
** * * * * * * * * * * * * ** * ** ** ***** *** **** ** *** ** * * ** * * * * * = x[i];
* * * ** * * *** * * * * * ** ** ***** **** * ** ** ** * * *** *** ***** * ** *** * = x[i+1];
* ***** * * ** * * * * *** ** *** *** ******* **** *** * ** ** ** * * ** * * **** * *** * ****** *** = temporary;
* * * * *** * * * * *** ** ** ** ** * *** * ***** * **** ** * * *
* * ** ** ***** * ** **** * * ** * *
* * *** * *** * * * * ***
* * * * ** * *** **
* * *** ** ** ** *** * print the array */
** *** ** ** ** ****** * * * * sorting: \n");
* ** ***** * * ** ** ** i = 0; i < size; i++){
***** * ** ** * * * * * ** * ** * * ", x[i]); * ** * * ** * * *** ****** *
** * * ***** * **** * **
** * * **** ** ** *** ** *
* * ** ** * ***** *
* ******* *** ** * * *
* *** ***** * * **** * * **** ** * * * ** *
* * * **** ** * ** * * * * * * **** ** ****  
***** *** * * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.171
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users