0 like 0 dislike
9.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * ** * *** x[] = {77,22,88,11,22};
*** * **** ***** * * size = 5;
    
* * * ** * ***** *** * ** ** print the array */
** **** * *** * * ** * **** ** i = 0; i < size; i++){
** ***** ** * * * **** * * * ** * * ***** ***** ", x[i]); * * ** ** ******* * ** *** * * ***
** **** * * * ** **
** *** * * *** *** * * ** ******** *
* **** ** ** ****** **
****** ** ***** * ****** I need this to happen size-times */
* ******* ** * ** * * j = 0; j < size; j++){
* *** ** ** ** ** ** **** *** * * ** ******** ***** from left to right */
* * ***** * * ** *** * ** * ** * * * ** i = 0; i < size-1; i++){
* ** *** ** ***** *** ****** ** * **** * * * ** * * * * i-th element with its neighbor to check if they are in order */
* * ** **** ***** ***** ** * **** * * * * * * *** ***** * * * > x[i+1]){
* * * *** *** * *** * ** * * * * * ** *** ** * ** * *** * * * * ***** * ** * * *** * ** ** exchange the values of x[i] and x[i+1] */
** ** ** *** * * ** ** *** * * *** ** * ** * * * * * ** * * ** * ** *** * * ** temporary; * ** * *** * *** ** * * **
** * **** * * * * * * * * ****** * **** ** * **** * * **** * ** ** * ** *** * = x[i];
* ** *** * * * ** *** * * * * * * **** * **** ** ** ***** **** ******* ** ** * *** = x[i+1];
* * ** ** * *** ** * * ** *** * ** ** ******** * *** * **** ** ******* * ** = temporary;
* *** **** * *** * ** ** * ** ** * ** * ** *** * ** *** ** * *
* ** * ** * * * * ** * *** * * ** **** *** ** * **** *** * *
* * * * *** ** *
**** ** **** * * * * *****
** * * * * ******* print the array */
** * * * ** * ** ** * sorting: \n");
* *** ** * * ** *** * *** i = 0; i < size; i++){
*** ** *** ** ***** * ******** * * * * * ", x[i]); * * *** ** ** ** * *** *
** *** * * * * * *
** ** * ** * ****** ** * ** ** * **
** * * * ** *** *** * ****
****** * *** * *
* **** **** *** ** ** ** * * *** * * *
* ** *** * * ** *** * ***** * * * *** ****  
* ** **** * ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * ** *** * ** x[] = {77,22,88,11,22};
** * ** *** * ** * * * size = 5;
    
* * * **** * ** * * * *** * print the array */
***** * * * * * * ***** i = 0; i < size; i++){
* * *** * **** ** * * * * * * * ***** *** ***** ", x[i]); *** * * * * * ** * ***** ****
** ** * *** *** * *
** * ** * * * * *** * ***** * ****
* *** * ** * ** * *
*** ** ** * * I need this to happen size-times */
** * *** * * * * * ***** ** j = 0; j < size; j++){
** * ** * * * ** * * * ** *** * ******* * * from left to right */
* * * * * * * * ** * * *** * ** * * * i = 0; i < size-1; i++){
** ** *** * *** * * * **** * * ** * * *** *** ** * ** *** i-th element with its neighbor to check if they are in order */
* ** * ***** *** * * * ** * ** * ** * * ** * ** * * *** > x[i+1]){
*** * * * * *** * * ** * ** *** ** * * * ** **** * **** ** * * ** * ** * * ** * exchange the values of x[i] and x[i+1] */
** * ** * * **** * * * ***** * * **** ** * ** * ** * * ** * **** * * ** **** * * * * * **** temporary; ** * * * * **** * * **** * *** * *
**** ***** *** ** ****** * ** ** ** ** * * ** ** ** **** * **** **** * ** * ** *** ** * ** = x[i];
** ** ** ** ** * ****** *** *** * **** ****** ** * ** * ****** ** * *** ** = x[i+1];
* ** * * ** * ***** ** ****** ** ** * *** ***** * ** * ** ** * *** * * * ** **** ** * **** * * = temporary;
* * **** * *** ** * ****** * * *** * * ** * * ** * ** * ** * * * ****
* ***** * * * ** * ** ** ** * ** * * *** ** *
*** * ** **** * *
*** * * * ** * **
* ** ** * * * * * ** * * ** * * print the array */
* * * * *** ** * ***** * * ** ** *** sorting: \n");
*** * * *** ** ** * ** ** i = 0; i < size; i++){
** ******* **** ** ** ** ****** * * *** * * *** ** * **** ", x[i]); * * *** ** * * * ***** ** *
* **** * *** * ****
**** * **** *** * * * * * ******* ***** ** **
** * * * * **
**** * *** ****** * *
*** *** * * ** *** ** ******* * *
* **** ** ** ***** * * ** * * *****  
* ***** **** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** * * *** **** ** x[] = {77,22,88,11,22};
* * * * *** * * ** **** * size = 5;
    
* * * * ** * ** * * **** print the array */
***** ** ** *** *** ******** i = 0; i < size; i++){
**** ** * ** *** * * * ** * *** ** * ** * * ", x[i]); ** *** * * *** * ** * ** **** * **
* * * * ** * * ** * *
* * ** * ** * * * * ** * *** ** **
* **** **** * * ** * *
** * * ******* *** * I need this to happen size-times */
* ****** * * **** ** j = 0; j < size; j++){
*** ***** * ** ** *** * *** ** ** * * * from left to right */
* ** ** * * * **** ** * *** ** * ** * ** * * * ** i = 0; i < size-1; i++){
* * *** ** ***** ** * * **** ** ** * * ** * * ** ** * *** ** * * *** i-th element with its neighbor to check if they are in order */
* ** * * * * ***** * ******* * * ** *** * *** * * ** *** * *** ** * * *** > x[i+1]){
* **** * ** ** ** * * * * *** ** ** * **** ** ** * * *** ** * * ** * *** * ** ** ** * exchange the values of x[i] and x[i+1] */
* * * * *** *** *** ** *** * ** * * * ** **** **** * * * **** ** *** *** * temporary; * * ** * * ** * * **** ** **
* ** ** **** * * ****** ** * * ** * ** * * * *** * * ** * ******** * ** * ** ***** *** = x[i];
** ** *** * * ** * * ** *** ** ****** * **** ** **** **** * ** * * * *** * **** * * * ** * = x[i+1];
***** ** * ** ** * * ** * **** * ** *** * * * * ** * **** ** * * *** * * = temporary;
* ***** ****** * ** * *** ** ** ***** **** * * ** **** * * **
**** * ** * * * ***** * * * * *** ** ** *** **
* ** *** * **** * * *
* * * ** * * * *
* * * * * ** * *** print the array */
** * ** **** **** ** ** * * sorting: \n");
* * * ** * ** *** ** *** i = 0; i < size; i++){
** ****** ** * *** ***** ** * * *** * ** * ", x[i]); ** ** *** ** * * ** ** ** *****
* * *** ** * * ** *
** ** * ** ** * *** ** ** ****** ** *
* ******* **** ** ****
**** * * ** * * ****
***** * * * ** ** ** * *** * * ***
* *** * * * ** * * **** ******** * *** ** ***  
** * * * ***** **** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** *** ** * ** x[] = {77,22,88,11,22};
******* * * * **** * ** size = 5;
    
** ** * *** ** * * * ** * print the array */
* * **** ** * * * * ***** i = 0; i < size; i++){
* * * * * * * *** * * * *** ** **** **** * ** *** * ", x[i]); *** * * ** ****** ****** ** * *
*** ** ** * *
* * * * * ***** * ** **** * *** ****
* * *** * * **** ** * *** *
** * ********* *** **** ** I need this to happen size-times */
* **** * * * * *** * j = 0; j < size; j++){
* ** *** * *** ** ** * ** * * ** *** ** from left to right */
* ** *** * * * * ***** * * * * **** * ** ** i = 0; i < size-1; i++){
** **** * * * * * * ****** * * ** * * * * * * * * * * * ** * **** ** ** i-th element with its neighbor to check if they are in order */
* *** *** * * ** ** ** ** ****** * * ** * * * * * * ** * ****** > x[i+1]){
** ** *** * *** * * **** *** * * * ** ** * ** * ** * * **** **** * * * ** ***** *** exchange the values of x[i] and x[i+1] */
* * ** * * ** *** *** *** * * * *** **** ***** * * * ** * *** * ** *** * ** ** ** temporary; ** * * * * **** * ******** * **
* ** ** ** ** * ******* ** * ** * ** ** * *** * *** * * * * ** ** ********* **** * * *** = x[i];
* ** * **** ******* *** * * * * **** * * * * * *** *** * ** * * * ** *** = x[i+1];
* * ** ** *** * * * * * *** *** *** *** *** * * ** * * ** *** *** * * * *** ** * *** = temporary;
* * * *** * * * * ** ** * * * * * ** * * ** ***** ** ***
* ***** ** ** ** ****** * ** *** **** **** *** **
*** * * ** ** *** * ** *
* ** * * * * ** ** * ** *
* ** * * *** **** **** ** print the array */
** * **** * ** * ** * * sorting: \n");
** * * * *** * i = 0; i < size; i++){
*** * * * * ** ***** * * ** * * ******* * *** *** * ** ", x[i]); * * *** * **** * * ** *****
***** ****** ** * * * * *
** *** * ***** * * * * ******* * ** ** *
** * ** * ** ** ** ***
* * * ** ******** ** *** *
* * ** ** * * *** * * ** ** * *******
* * *** * * * * ** * ****** * ***  
******** * **** ** ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * * ** ** ****** x[] = {77,22,88,11,22};
* * ** ****** * * * * * size = 5;
    
** ****** ******* * print the array */
* ** ** *** * ** **** ** * i = 0; i < size; i++){
** * ** * *** * * **** * *** *** *** ** *** * * * * ** ", x[i]); * * *** * * * ** ** ******* **
* ******* * *** * *
* * ** * *** * * * *** * * ****** * * ****
* * **** * * *** *** ** *
* ****** **** * *** *** I need this to happen size-times */
*** * ** *** * ** * *** j = 0; j < size; j++){
* * * *** * ** *** ** **** * * * ** ** * from left to right */
**** * * * **** *** *** * * **** * ** ***** * * i = 0; i < size-1; i++){
*** *** ** * *** ** *** * ** ** * ** * * * ** * * *** **** * * ** i-th element with its neighbor to check if they are in order */
** **** ** **** ** * **** ******** * ** **** * *** * * ** * ** * ***** * > x[i+1]){
** *** ************ *** * ** * ** * * **** ** *** * **** ** ** * * * ** * *** * **** * ** * * * ** * exchange the values of x[i] and x[i+1] */
*** ** * **** *** ** * *** * ** * * **** * ** ***** * * ** * * *** * **** **** ** ** ** temporary; **** **** *** *** * * * * * * **
* * * * * * ***** ** * * **** * * *** * ** * ** * * ** * * * ** * * * = x[i];
* * * *** * **** * * *** * * ******* ** **** * * ** ** * * * ** * * ** ** = x[i+1];
*** *** * * * * ** ** * ** * * * * ** * ** ** ** * ** * *** * ** ** ** ** ** **** * * = temporary;
*** * * * *** **** * * ** ** * **** * * * * *** *** ** * ** ****** ***
* * * * ** * * *** * * * * *** *** *
* * ***** *** * *
** * ** ** ** **** * *
** * * *** * **** print the array */
* * *** * * * * * * * * ** *** * * * sorting: \n");
** ***** * * ** ** * **** i = 0; i < size; i++){
***** ** ** * **** ** * **** * * ** *** * * *** ** * ", x[i]); * * * * ** **** * ***** *
* ** ** ***** ** * * **
*** ** * ** *** *** * ** * *** ** ***
*** ** * * * ** ** * *
** * ** * ** * * **
* *** * * ** * ** * * ** ** *** *
**** * ** * * * ** * **** ***** * * * * ****  
* ** *** * * * ** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * * * ****** * x[] = {77,22,88,11,22};
* * ** ** **** *** size = 5;
    
*** * ** * * * * ***** * * print the array */
* * ** * * *** *** * i = 0; i < size; i++){
* * * ** ** * * * *** * * * * * ** * * * ** * ** *** ", x[i]); ** *** **** * * ** ** ***** **
* * * * *** * ** * ** **
*** ** * * ** *** * ** * *** ** ***
* ****** ******** ******* * *
* * * *** * **** * ** * I need this to happen size-times */
* * *** * * ** ** ** j = 0; j < size; j++){
* ** ** * ** * ** ** ** **** **** * *** *** * * from left to right */
** **** * * ** * ** ** * ***** * ** * ** i = 0; i < size-1; i++){
** * * **** * ** * * *** * * *** ** ** * **** *** * **** i-th element with its neighbor to check if they are in order */
* * ***** * * * *** ** * **** ******* ** * ** * * * ** * * * > x[i+1]){
* ** ** ** * * ** ** * *** ***** ** * * * * ** *** **** *** ** * ** * ** ** * * * ** ** exchange the values of x[i] and x[i+1] */
*** *** * * * * ** ** * *** * ** *** ** * * * **** * ***** ** * *** * *** * *** temporary; * * * ** **** **** * * ** ***** *
* * * * * ***** * * * * ** ** ** ** * * * * * ** *** * ** ** *** * *** * * **** * = x[i];
* ** *** **** * **** ** * ** **** ***** * * * ***** * * **** * ** * *** * * * *** * ** * * * *** = x[i+1];
**** ** ** ** * * *** ** * ** * ** * * **** ***** * * **** ** * ** ** *** ** * *** ** ** * * * ** = temporary;
**** ** *** ***** ** * * * * **** * * *** * ** **** ** ** ** ***
*** * **** * * * ** * * ** ******* *** * ****
* ** * ***** *
* ** * ** * ** **
***** ** ** * ** * print the array */
* *** * * * * ** * * ***** sorting: \n");
* *** * ** ***** *** * * i = 0; i < size; i++){
* ** ** **** * ** * *** * * * * ** **** ", x[i]); ** * ** * **** *** * *** ** **
* *** ** * * * * * ** *
* ** * *** * * *** * ** * * ** *
** * ** * * **** ** **
** ** **** * * *** *
* * ***** * * * * ** ** ** ** ********
** ** * * * ** * * ** ** * * * * ***** ***  
* *** * ** * * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * *** ** * ** * x[] = {77,22,88,11,22};
* * * * * ** * * **** size = 5;
    
*** * ** * **** ** ** ** ** print the array */
** * * * ** * ** i = 0; i < size; i++){
*** **** * ***** * * ** ** * ***** *** * * ** ", x[i]); ** * *** ****** ** **** * * * * *
* * * *** ******* *
** *** ** *** * * ** *** * * * ***
****** ** * * ******
** **** *** **** * * * *** I need this to happen size-times */
* ** ** * * * * * ** **** j = 0; j < size; j++){
** **** ** * *** * * ****** * * * from left to right */
** * ***** * ** * *** ** ** * * ********* ** i = 0; i < size-1; i++){
* * * * * * * **** * * * * * ** ** **** * ** ***** * ** * * ** * i-th element with its neighbor to check if they are in order */
*** **** * ** *** * ** * ** * * * * * *** * **** * * **** *** * * > x[i+1]){
** ****** * ** * ** * * ** * **** * * *** ** * ** * * *** *** ** * * * * * * * * exchange the values of x[i] and x[i+1] */
* * ** * * * ** * *** *** **** ** ** ****** ** * **** ***** * *** * ** * * * temporary; * * ** ***** *** ** * * * * ** * * * ** **
* ****** **** ***** * * ** * ** ** ** * *** * * ** * * *** *** *** * ****** * = x[i];
** ***** * **** ** ** *** ** * * ** * * *** *** ** * *** ***** * ** * **** * ** ***** * * * = x[i+1];
*** * *** * * ** * * ************* *** ***** * *** * ** ** ***** * ** * ** * * ***** = temporary;
* ** **** ****** * * *** ** * ** *** ***** * ** * *** * *** ** *
* ** * * * *** *** **** * *** * ** *** * ***
* * ** ** * * * *
** * **** *** *** ** * * **
* * *** * ** * ** * * print the array */
* ** **** * * * ** * * * * ** sorting: \n");
** ** **** * ** * * * ** i = 0; i < size; i++){
* ** * **** *** * * * ***** * * *** ****** ", x[i]); * * * *** ** * * **
*** * ** * * * * *** * *
** * * * **** * ** **
** * ** * **
*** * * * ** *** *
*** * * *** * **** ** * * ** * * *
** *** **** * * * ** * * * * * ******  
* **** **** * * * * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * **** * * ** x[] = {77,22,88,11,22};
** * **** ** * * * * ***** size = 5;
    
*** **** * * ** ***** * print the array */
** *** *** * **** * ** ** i = 0; i < size; i++){
* *** * * ** * * ****** * * * * **** ** * * * ", x[i]); *** ** **** * ** *** *** * ** * *
******* * ***** * *
* * * * * ** * *** *** * *** * *
*** * **** *
* * * * *** ** * I need this to happen size-times */
* * ** * ** * * ******** * j = 0; j < size; j++){
* *** * ** ***** * *** ** * ** * *** ** from left to right */
*** * ** * **** * ** * * **** * ** * i = 0; i < size-1; i++){
** * ** * *** ** *** *** *** * *** * * ***** * * **** * * **** * **** **** ** i-th element with its neighbor to check if they are in order */
*** ** ******* * * ** * * *** *** * * * ** * *** *** * * ** ** ** > x[i+1]){
* ** * ** * *** * * * * * ** ** * * * * * * ** ****** **** * * * * * ******* ****** *** * exchange the values of x[i] and x[i+1] */
** * * * * * ** *** *** * *** ***** ***** ** ** ** * *** * ** ** * *** * temporary; ** * * * ** ** * ** * **** * *
*** * * ** *** ******* * ** ** * * * * * *** * ** ** ** * ** * * * * ***** ** * **** ** = x[i];
* * * ****** *** * * * ** *** * * * ** * *** * * ***** * *** * * * * ** * ** * * = x[i+1];
* ***** * ** ** **** * * * ** * * * * ** ** * * **** * ** ** * ***** * ** *** * = temporary;
* **** * * * * * *** ** * ** ***** *** * ** * * * * * * *** ** ** * * *
**** ** * * * ** **** * * ****** *
* ********* * *** *
**** * **** *** *
* * ** * ******* * * * * * print the array */
* ** *** * ** * * ****** * **** ** * sorting: \n");
***** ** ***** *** ** i = 0; i < size; i++){
* * ** ** * * * * * *** ** * ** * ** *** * * * * * ", x[i]); * ** **** ** *** **** ** *
** * * * * ***** * *
* *** ** * ***** **** * * *** **** *
* * * * ** *
* * * **** **** * *******
** * **** ** * * * * **** *** * **
** * * * ** * ** * **** ** * ******  
*** * * * ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * ** * x[] = {77,22,88,11,22};
* *** * * ** * ** * * size = 5;
    
* ** * * * *** ** print the array */
** * ******* * *** ** * i = 0; i < size; i++){
** * *** *** * * *** ** *** *** * * * * * * ", x[i]); * ** * *** ** * * *** ***** * *
** ** *** ******
***** ** *** *** *** * * * * ***
** ** * **** * *
* ** * * ** * **** * * I need this to happen size-times */
** ***** * * *** * ** **** j = 0; j < size; j++){
* ** *** * ** * * * ***** **** * * ** * *** from left to right */
* * * ** * ** ** * * ** * * * * ** * ** ** i = 0; i < size-1; i++){
* ** * ** * ** ***** * *** *** ** * * ** * ** * ** *** * i-th element with its neighbor to check if they are in order */
** * **** * ** *** * *** * * ** **** *** * * * ** ***** ** * * > x[i+1]){
** * ** *** * ** *** ****** ** * *** * * ** * * * ***** **** *** **** * * * * * * exchange the values of x[i] and x[i+1] */
* * * *** * **** * * ** * * *** *** * **** ** *** * * **** * * * ** *** * * * temporary; * * ** * * * ** * * * *** * * *
* * ** * ** ** ** * ** * * * ** * ***** *** *** *** ** * **** ** ****** *** * * * = x[i];
* ** * * * * ** * * **** * *** ** * * ** ****** * * * ** * *** * ** * * ** ***** = x[i+1];
* *** ** ** * * * * ** ** * *** * ** * *** * * * * * * ** ** * * ** = temporary;
** *** * * ***** * * * *** * * ** * *** **** * * *** * **** * ** **
* * * **** * * ** * *** * ** * * **
* *** * ** ** **** ** *****
** **** * * * * * **
** ***** ****** ******** print the array */
* **** ** * ** ** * ** * * ** sorting: \n");
* *** ** * * * ** *** ** * ** i = 0; i < size; i++){
* *** * ** ******** * * ** ** * ******* * ** ** * ", x[i]); * ** ** * * **** ***** *** ****
** ** * ** ****** **
* * * **** ** **** ** ** ** * * ***** ***
**** * *** ** ** *
** * *** * *** ** **
******* *** *** ** * * ** *
* ** ** ** ** * * ** * * ** * ** * *****  
** * ** * ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** **** *** * *** x[] = {77,22,88,11,22};
** * ** * ***** *** *** * ** size = 5;
    
**** ** ** ** *** * * print the array */
** * **** ***** ** i = 0; i < size; i++){
**** * * * * ** * * * * ***** * ** * **** * * ", x[i]); * *** * * * **** *** * * * **
** * ** * ** * * ** *
* * * * ****** * *** * *** **** ******
*** * * ****** *****
*** * ***** * *** * ** I need this to happen size-times */
** * ** ** ***** * *** j = 0; j < size; j++){
* **** * *** ** * *** * ** * *** * *** *** from left to right */
* * ** *** ** **** ** ***** * *** * *** * * i = 0; i < size-1; i++){
* ******* ********* ** **** * *** ** * * *** ***** ***** * ** * * ** i-th element with its neighbor to check if they are in order */
******** * *** ** * * ** * * * * * **** * * ******* ** *************** *** > x[i+1]){
** * * ** * * * * *** *** * * ** ** *** *** * * * *** * ** ** * ** ***** ** * *** ****** * * exchange the values of x[i] and x[i+1] */
* * * ** ** * **** * * ** *** * ****** **** * *** *** *** **** ***** * * ** * *** *** ** temporary; * ** * ** ** *** * * * *** * * * ** *
* * * *** ** * *** ** * *** *** * * * * ** * ** * *** ** ** * * * * ** * * ** * * = x[i];
* * *** * *** * * ***** * * * * * ** ** * * ** *** * ** * ** * ** ** *** **** = x[i+1];
* * ** ** ** ** ** ** * * ** * * ** ** **** *** ** * ** * * * *** = temporary;
* * ** ** ** **** **** *** * ** ** ****** * **** ** *** *
*** ** ** ** * * *** * * ****** * **** ****
** * ** * ****** ***
** * * ** * ** *
**** * * * ** ***** print the array */
* ** ** ** * * *** * * * sorting: \n");
* *** ** **** * ** * * * i = 0; i < size; i++){
* * * * ** * * ** ** * ** ** ** **** * * * * * ** ", x[i]); **** ** * * ** * * * * ** ** *
* ***** ** * * * ** * * ***
***** ** ** **** * * **** *** *** *** **
* ** **** ** * ** **
* *** **** * ****** * ***** *
* * ** ** * * *** *** * * * * ** * *
** * * ****** * * *** ** * ******* *  
* *** ** * * * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.190.141
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users