[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

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* a, b, c;
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c = a + b;
* *
* * + %d = * * * *
*
**
* * * * *
* 6
** **
****
6
10

Comments

Great

Answer 2

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*
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= a +


* ** **


** ** * + * = ******* * *


*****





* *


* *
*
* * **


* 5
**

Comments

Good job

Answer 3

Hidden content!
** * ** ** ** * *
** * *** ** *** *** * * %d **** * *** *** ** * * **** = a * b + **** * * ** * * ****
** *
**
* ** 1 ** * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* ** *** * ***** * * * *** ***** ** ** *** * * * the ** * *** or add * own * ** * * ** * *** ** or ** ** *** * * * *** * * a, b, ** the * * * * ** * *** * *** two **** * * by *** ** * *** * * * * = a + ** * * * * * ** + %d = * * a, b, ** * * ** ***

Comments

Good job

Answer 5

Hidden content!
** ** *** **

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}