[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

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* * a, b, c;
** ** *
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* ** *

c = a + b;
* ** *** *
** * * + %d = * * *
** **

* ** * *
6
**
**** *
* 6
10

Comments

Great

Answer 2

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* * * ** * **


*


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** ** * *


*** * * *** ** * ** *** ** * * * * ** **


* ** ** * * ** * *** *** * *** *


*** * * *


* = a +


* * *


* *** ** + ** = * **


*** *


**


**
*
*
* *

* ***


5
**

Comments

Good job

Answer 3

Hidden content!
* ****
* * * * ** ** %d *** * ** *** ** ** * *** = a * b + ** * * * * * **
* **
*
* 1 * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
*** ** * * *** ** ** * ** * * ** **** the ** * *** or add ** own ** * ** * * ** * ** or * * * * *** * * ** ** * a, b, * the * * ** ** * ** ** * two ** ** *** by *** ** ** * * * ** * * * * = a + * * ** * ***** + %d = ** a, b, * ** * ******

Comments

Good job

Answer 5

Hidden content!
* * *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}