[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
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** ** * ** ** *
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* a, b, c;
** *** *
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* * ** *

c = a + b;
** * * * *
** * ** + %d = *** ** * *
* *

** *****
6
* * **
**
** 6
10

Comments

Great

Answer 2

Hidden content!
** * * * * **

* *** * * * * * *

* * ** ***


*** * *


* * **


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**** * ** * *** * * **


*** ****** ** * * ** ** *****


**** * ** *


** = a + **


* * * *


****** ** * * + * = **** *


* * *


*


** *
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* * **
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* 5
**

Comments

Good job

Answer 3

Hidden content!
** * ** *** * *
* * * ******** %d ** * ** = a * b + *** * ** * *** * * * * **
** *
*
* * 1 *** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * * * * *** ** **** ** ** ** *** ** ** the ** * * or add * * own ** *** ** * ** or *** * **** * ** * * *** * * * ** a, b, ** ***** the * * * *** * * * two ** * * by *** ***** ** * * * *** ** **** ** = a + * * ** * *** ** *** + %d = * ** a, b, * ** * * *** *

Comments

Good job

Answer 5

Hidden content!
* * * * ****

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}