[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

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** a, b, c;
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* ** ** */
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*** * * **** ** **

c = a + b;
* ** * * * **
****** + %d = * *** *
**

* ** ***
* 6
*
**
* 6
10

Comments

Great

Answer 2

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* *** ** ** * ***
*
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* * * * *


** = a +


* * *** * *


*** *** * + = ** * * * **


* * *


**




* *
* * *
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*


* 5
*

Comments

Good job

Answer 3

Hidden content!
* * * * ** * * *
* * * * ** ** ** ** * * * %d * * * * ** * * * * * * = a * b + ** * ****** ** ***
* * * *
**
* 1 * *** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * ******* *** ** ** **** ** *** * * the ** * * or add * own * ** * * or * ** * * ** * * * ** a, b, *** the **** ** * * ***** * *** * two * * * **** * by * * *** **** ** **** * * **** = a + * * * * **** * + %d = * ** * a, b, * **** * * *** **** *

Comments

Good job

Answer 5

Hidden content!
** *** *****

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}