[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
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**** ******* ** *
**** ** * * * ** ** {
a, b, c;
** * *
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* **** ** * * *** by ***** * **
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*** * * * *

c = a + b;
* * *
* * ** ** + %d = *** * *
* **

*** ***** *
6
* ****
*
* 6
10

Comments

Great

Answer 2

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*** * * * * * *

*** *** * * * ** ***

* * * **


**


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* ** * * **


* * ** * * * **** * * *******


** * * * **** ** ** **** * ** **


* * *


* = a +


*** * * *


****** * + * = *** * * * *


* *





** *

*
*
*
***


5
**

Comments

Good job

Answer 3

Hidden content!
*** * * ** * ** * *
* * * * * ** %d ** * * * * ** * *** ** * * * = a * b + * ** ** ** * *
* *
****
* 1 * ** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* ** * ** ** * * * ** **** * *** ** * * * *** the *** ** or add * ** own ** ** * * * ** or * * * * ** *** * * ** * * a, b, * *** the * * *** * * ** * * * two ** ** * by * * * * * ** ** ** *** *** * * ** = a + * * * * * ** + %d = a, b, ***** ** * * * * **

Comments

Good job

Answer 5

Hidden content!
* ** ** * **

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}