[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
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* * * ** * ** *
** ** * * * * {
*** a, b, c;
*** * ***
** ** *** ** */
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* * ** *

c = a + b;
* ** * *
** * * + %d = ***** * *
** **

** ** *
6
* * * **
***
6
10

Comments

Great

Answer 2

Hidden content!
* * ******* ****
*
* *** * * * * ** ***

* *** * * ** **** * * ***


** *


* * * *


** * *


* ** * * *** ** * ** * *


* **** ****** *** * * ** * ** *


** *** * * *


* = a +


* * ***


** * * ** + = ** * * **


* * **





* *


* *

****


5
**

Comments

Good job

Answer 3

Hidden content!
* * * ****** * *
** * * * *** ** * %d * *** * * ** *** * * *** = a * b + ** * ** * * **** *
** **
*
** 1 * * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
** *** * ** * * ***** * * ** ** * ** * * *** the *** * ** or add own * * *** * * * * * or * *** * * ** * * * * ** ** * a, b, *** * ** the * ** * ** ** * * *** two * * * ** * by ** * * ** ** ** * *** *** ** * = a + ** ** * * * * ** + %d = * a, b, *** * ** * ** **

Comments

Good job

Answer 5

Hidden content!
***** * *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}