[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
* * ** *******
* ** * ********* * *
** * * * ** * * {
* a, b, c;
*
* * */
***** ***** * * **** * by ** * *
* *** * * ** ** *****
** * * ** * *

c = a + b;
** * * **
*** ** ** + %d = * * *
*** *
*
* **** *
6
* ***
**
* 6
10

Comments

Great

Answer 2

Hidden content!
* * *** **

** * ** ***

**** * *** *


* **


* ** ** **


* * * ** *


* * ** * * ** * * * * **


* * *** ** ** * * ***


* * * ** *


= a + *


* * * *


** * * *** + = * * *


*


*


* *

* *
***

* *


* 5
**

Comments

Good job

Answer 3

Hidden content!
** ** ***** *** *
* * *** ** ** ** * *** %d * *** *** * * ** * ** * = a * b + ***** ** * *** * * *
**
** *
* * * 1 ** * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* *** * * ** ** ** *** *** *** * * ** the * *** or add own ** ****** ** **** or * * * ** **** * * * * ** a, b, * * ** the * * ** ** ** * ***** ** two * *** * * by *** * *** * ** * * ** ** ** * = a + ****** * *** ** * * * + %d = ** ** a, b, * * * * *

Comments

Good job

Answer 5

Hidden content!
* * * ** *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}