[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
*** * * * *
*** * ** ** ** **
** **** * * * ** {
* a, b, c;
* *
* * * * */
*** ** *** * * * ** by *** * *
* ** * *** * * * * ***
***** * *

c = a + b;
** * **
** * * + %d = * * * * *
** *
*
*******
** 6
***

6
10

Comments

Great

Answer 2

Hidden content!
** * ** * *

* * **** *** ***

** * **** * *


* * *


* * * *


* * * * ***


** * * * ** *** ** * * *


* * * **** * * * * ** **


* * * *


* = a +


* * * **


**** * * * + = * ** * * ***


* *


*


* *
*

*

*


* 5
*

Comments

Good job

Answer 3

Hidden content!
** * ** ** ** * * *
* * ** * ** * ** %d * * ** ** *** ** * * ** = a * b + * * ****** ****
** ** *
***
1 * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * * ** * ** * * * * * ** **** * the * * or add ** own * * *** * * ** * * or * * * ** * * * *** * * a, b, * ** the * ** * * ** * * * * * * two * ** * by * * *** * ** * ** * * * ** **** * = a + ** ** ** * ** + %d = *** a, b, **** * * * ***** **

Comments

Good job

Answer 5

Hidden content!
** * * *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}