[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
* * * * ** * **
**** * * ** *
* * * * * ** {
* a, b, c;
* * ** * **
* ** * * * */
* * * *** * * **** ***** by * *** *
* *** ** * * ** **** * **
** * * ***

c = a + b;
* ** **
* ** * * + %d = * *** * *
**** *
*
** * *
* 6
* * **
*
* 6
10

Comments

Great

Answer 2

Hidden content!
* * * *** **
*
* * * * ** * * * * *

* * *** * *


*** ** *


* *** **


** * *** *


** * * * * ** * * ** **** * * * **** *


*** ** ** *** ***** * * * * * ***


* ** * * * *


= a + **


* ***** ** *** *


***** ******* + * = * ** * *


* *


*


*


*** ** *
*
* **


5
**

Comments

Good job

Answer 3

Hidden content!
** * ** * ** *
* * * ** **** * ** %d ** * ***** * * ***** = a * b + ** * ***** * * ****
* **
** * *
* 1 **** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* ** ** * * * * * * ***** * * * ** * ** * * * ** the * ** * or add own * * * * * * ** ** or * *** * ** ** * * **** * ** a, b, *** ** the * ** * * * * * two *** * ** by ** * * **** ** *** *** * * * ***** * * = a + * * * * ** * ** * + %d = * ** ** a, b, ** *** * ** * * *

Comments

Good job

Answer 5

Hidden content!
* ** *** *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}