[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

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** * * ** ** {
*** a, b, c;
* *
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c = a + b;
* * * * *
** * ** + %d = **** * *
* **
*
** * **
* 6
* ** *
*
* 6
10

Comments

Great

Answer 2

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* * *** * **** *

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* * * *


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*** * * ** *


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****** * *


* = a +


* ** ** ***


** ** + = * * * * *


***





** *
*

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***


5
*

Comments

Good job

Answer 3

Hidden content!
* *** * *** * ***
** ** ** * ** * ** ** %d * ** *** * * *** = a * b + * ** ** ** * **** *** * *
* *
* *
** * 1 *** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * *** * *** * * * ** ** ** *** * * * **** ** the * * * or add * * own ** *** * ** ** or * ** * * * ** * * ** a, b, ** the * *** * * * * * ** * two * * * ** by ** * * ***** * * * ** *** ** = a + ** *** * * * **** * + %d = * a, b, * * ** * * * *

Comments

Good job

Answer 5

Hidden content!
* * * **** *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}