[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
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a, b, c;
* ** **
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* * * ** * *

c = a + b;
** * *
* + %d = * *
** *

* * **** *
** 6
**
***
** 6
10

Comments

Great

Answer 2

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* * * ** * *

**** ****** ****
*
* *** * ** * * *** *


* * * *


*** * * *


* * * * * *


** * ***** ** *** * ** ** * ***


* ** ** **** * * ** * * *** * **


** * ** * *


** = a + *


* * ** * *


****** ** * + * = ** *** **


* * *





* * *


*** *** *
*
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5
**

Comments

Good job

Answer 3

Hidden content!
** * ****
* **** *** * * ** * * %d *** * * * * * *** * * = a * b + **** ** * *** * * * * *
* ** *
** * **
* * 1 * * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * * *** * **** ** ** * * ** * * ** ** * * ** *** the * * ** or add * own *** *** * ** * * * or *** * * * * * * * * *** * a, b, * * the *** ** * ** * * * ** * * ***** ** two * * *** ** by * ***** ** * * * * * * * * ** = a + * ** * ** *** *** + %d = ** * a, b, **** * *** *** *

Comments

Good job

Answer 5

Hidden content!
**** *** * * ***

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}