[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
** * * * * **
* *** *** **** * ***
* * * ** * * ** * {
** a, b, c;
** ** * * ***
* * * * * */
* * * * ** * * ** * * by ** * ***
** ** ** **** * *
** * * * *

c = a + b;
* * * * *
*** ** + %d = *
* **

****
* 6
***
****
6
10

Comments

Great

Answer 2

Hidden content!
* * * **** ***
*
** * **** * *
*
* * **** ***** *


* **


* * ** ***


* * ** ***


* * *** ** * ** * *** ** ***


***** * ** * * ** * ** **


** * * *


* = a + *


*** * *


**** * + ** = *** * ** * *


* *





** * *

*
*

***


* 5
*

Comments

Good job

Answer 3

Hidden content!
* * * **** * **
* * * * * ** %d ***** * * * *** * * *** = a * b + *** * * ** *
* **
* *
* 1 * ** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * ** ** ** * * * ******* * * * ** * ** the ** * *** or add own ** * or ** ** * ** * ** * ** a, b, * * the **** * ** ** * ******* * * two ** * * * by * * *** * ****** * * * * * ** *** = a + ** * * * *** * + %d = *** a, b, **** *** * ** * *

Comments

Good job

Answer 5

Hidden content!
** * * * **

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}