[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

內容已隱藏
** *** ** **** ***
** *
** * b, c, **
* ** %d ** ** * * * **** * *
* = * + b * *
*** * * * * * **

Answer 2

內容已隱藏
* * ** * **
** *

* *


* ** * * ** * ** * * **** ** *** * * *** **


= ( a + b ) *

** ** * ** * *

** *
**

Answer 3

內容已隱藏
*** ** ** *** **
* *


** * *


* * * * * * ** * * * ** ** * * * ** *


= * ** + **


** * ** ** * **


* *

}

Answer 4

內容已隱藏
* * * * *** * **


* * ******** ** *


* * ** * ** ** * ** or *** * * * * ** *** * ***** * or ** ** * *


** * * * * * {


* c, d, *


** **** * * * *** * * * *


* * * **** * * %d %d * * *** * * * * * * *** * * ** *


** = a + b - c * d;


* ** *** ***** * * *


* * ** * * * ** ** **** * **** *** ***** * *** * *



** *





** * * ** 9 2


* * ** *

Answer 5

內容已隱藏
* * ** * * *** *
**** *
* * ** c,
** * * %d *** * * ** ** * ** * *
** = a * c + **
* ** ** *** * *
* *
}

Answer 6

內容已隱藏
* ** * ** * ** **
* ** ** * * **** *


** b, c, d;


* ***** * * 3 * * * * * ** *


* ** * * * * * * * * * * ***


= a + b +


***** *** *** * * * ** *


***
**

Answer 7

內容已隱藏
* * * * *

int ** *


* * a, b, c;


* *** ** * * * * * * the *** * * ** *** * ** ***** * **
** * ** * * ** **** *** *
** * * ** *** the ** ** * ** * * * **
* ** * *** * * * *** *** *
**** * *** * the * * * ** *** * ***
* * ** * ** *** ** ** * ***



opp = a + b * c;


***** * is = * * *


* ** 0;

}

Answer 8

內容已隱藏
* * * *** *
* * ** ** * ******* *** ** argc, char * ** {
** **** * * **** * a, b, c, d;
* ** **** ** ** ** the user and read * * * *** ** * * * *
* * * ** * ***** * ** ** three * ** * by * * *** * *
* * * ** * **** ** ** * * * * **** ** **
*** ** *** * ** ** * ** * *
* *** * *** * ** ** = a + b * c;
* ** * ** ***** the **
*** ** * * * * * * + %d * %d = * * a, b, c, d);
* ** * ** ** * * * 0;
** 4 ** * 4 2 10

Comments

Good job

Answer 9

內容已隱藏
* * ** ** * *
** * * * * * **


* ** ** ** * {
* *** * a, b, c, d;
*** * * * the
* * * *** ** */
***** **** ** * * **** ** * *** ** by ** ** *
** * * ** ** * * ********* * * ** *** *** * **
* * ***** * * ** *

d = a - b / c;
*** * *** ** the ****
* * ** * ***
* * ** **** 0;

}


**


* 8 2


*** *


8 2



10

Comments

Nicely done, keep up.

Answer 10

內容已隱藏
* * * * * ***** * *
* * * * ** *
* *** *** {
* * a, b, c;
* ** **
* * * * ** *** */
* * * * * *** * by *** * ***
* * * * *** * *** *
* ** * **** *

c = a + b;
* * ** * *
***** *** + %d = * * *
**** *
*
** *
** 7
*
*
7
10

Comments

Nicely done