[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

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* ** * ** *

Answer 2

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Answer 3

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* = * * * + *


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}

Answer 4

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*


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***** *

Answer 5

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* ** ** * **
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* c, *
* ** %d ***** * * * *** ** *
* = a * c +
* * *
* **
}

Answer 6

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** * ** * * * *
* * ** *** * *


** ** b, c, d;


* ** * ** * * 3 * * * ** *** *** ** ** **


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= a + b + *


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*
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Answer 7

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int


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opp = a + b * c;


** * * * * * * * is = **** * **


** 0;

}

Answer 8

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* * ** * * * a, b, c, d;
* * * *** ** * *** * * the user and read * * *** **** * * * *
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** ** ** * * * ** the **
** * ** ** ** ** ** * * * * + %d * %d = *** ** a, b, c, d);
**** *** * * * *** * 0;
* * 4 ** * * 4 2 10

Comments

Good job

Answer 9

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*** * * * * * * **
* * *** **** **


* **** * * ** * {
* * *** a, b, c, d;
*** * * * the **
***** * ** * **** */
* * * * * *** *** * * * * by * * *** * **
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d = a - b / c;
* ****** the * **
* * * * * * ** ***
*** * * * 0;

}





* 8 2


***


8 2



10

Comments

Nicely done, keep up.

Answer 10

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* * *** ****
** *** * ******** **
** * ** * * * {
*** a, b, c;
* * ** *
* ** * */
* ** * ** ** by ** *
*** ** ** ** * * * *
*** * * ***

c = a + b;
*** * **
** ** * + %d = ** *
* **
*
* * * ** *
* 7
*
*
** 7
10

Comments

Nicely done