1 like 0 dislike
1.5k views
請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 1.5k views

17 Answers

0 like 0 dislike
Hidden content!
* * *** * *** **

int main()



{
* * ** * ** ** * * = 0, c = 0, box = 0, i = 0;


**** ** ** * ** * * * * *** *** * ***** *
** *** **** *** ** a[i];


* ***** * * * = 0;b i;b ++)
* * ** ** * * ******* *** * * ***


* ** * * ** * * ** = 0;c * * * (i-1);c ++)
**** * * * * ** *** ** * ** * ** * ** = c + 1;b i;b ++)
****** *** * * * ** **** ** * ** * ** ** a[b])
* * *** * ******** * * *** * *
* *** * *** ****** * * * ** * * * *** * * * * ** = a[c];
* *** * * ******* *** ** * * * * **** ***** * = a[b];
******* *** * ** * * * ***** ** ******* * * * * * = box;
* * ** * * ** ** ** *





for(b = 0;b ** * i;b ++)

if(a[b] == a[b+1])
**** ******* ** * * * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ** *

#include *** ** * *

#include **

int main()

{

 float c;
* * ** *** ***** *** a;
* ** *** * * * * * **** * ** *
* * ** ** ** * * * * ** *** *




** * * ********* ***** ******* *
* * * * ** ** *** ** ***** * * *** * ** **





for * *

{
** ** ** * **** ** * ** * * *
** * *** ****** ** * * ** * ** * ** ** ** ** ***** ***
**** * ** * **
*** *** *** * * **** * * ** ** * *** = b[j];
*** ** * ** **** * **** * * * * * *** ** = b[i];
* *** *** ** ** ** * ** ** * * * ** = d;
**** * ** *** **** **

}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf * * ****** *

}

if (a%2 != 0)

{

k = a/2;

printf ** * *** * ** **



}
** ** * *** * ** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** *****

int main()



{
* ******* * ** ** * ** * = 0, c = 0, box = 0, i = 0;


* * * * ** ** * * ********* ** * * * * ** **
* ** *** *** ** * * a[i];


* * * * ***** = 0;b ** i;b ++)
******* ** * * ***** * * ** * **


* * ** * **** * = 0;c ** (i-1);c ++)
*** * * * ** **** **** * * * * ** = c + 1;b < i;b ++)
* ** * * * * * * * * ** ** ** ** == a[b])
* * * *** * * **** * ** ***


** * ************* * * ** *** *******




* * * ** * * * * ** *** **** * ** * * * a[b])
** * * *** * *** **** ******** * *
** * ** ******* * * * * * * ***** ** * ** = a[c];
* * *** * * ** *** *** ** * * ** ** ** * * ** = a[b];
** * *** * **** * * * ** ***** * ** * ** = box;
*** *** *** * ** ** * *





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
******** * * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** *

int main()



{
* ****** * *** * **** * * * * *** = 0, c = 0, box = 0, i = 0;


* ** * ** ** *** ** * * * * * *** * *
* ** ** * * * ***** a[i];


* ** * ** * ** ** = 0;b < i;b ++)
** ** * ** *** *** ******** * * * *


* * * ** ** *** ** = 0;c < i-1;c ++)
* **** * * **** * *** ** * **** * * * = c + 1;b < i;b ++)
* ***** * ** **** ** * * ** * * ** == a[b])
**** * * ************** ** *** **


* * * * * *** ** *** * ** **** * *




** ** * ** ** * * ******* *** * * * * * ** > a[b])
** ** ** * *** * * * *** ** *
* ** ** ** * *** * * * * * * * **** * * * ** *** * = a[c];
* * ** *** ** *** * ** * * * ** * ** * * *** = a[b];
** * * * **** * **** * ** * * ******* = box;
*** * * ***** ** ****** **** **




*** * ** = 0;b * * ++)
* ** ** * *** * * ** ** * < a[b+1])
*** ****** ** * * * * *** ****** * * ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
** *** ** *** * **** ** * * *** ** *
* ** ******* ** * num[a],i;
*** * ** * * * * *** ***** * **** * * * *
* * ** ** ***** * ** ******* * * ** * * ***


* * * * ** * *** * (i=0;i<a;i++)
* ** * * * * ** * ** * *** * *
* * ** * * ** * ** * ****
* * *** * * **** ** ** * * * * *** * * (num[i]>num[j])
*** ** * ** ** ***** * * *** ** ** * *** * ** * * *** * * *
* * * ****** * ** * ** * *** ** **** ** *** ***** ** * * *
** ** * * ******* * *** * ** *** ** ** * **** * ****** * *** **** * **
* ******* **** * ** *** * * * ******* ** *
* *** ****** * * * *** *
*** * * * * * *** * (i=0;i<a;i++)
** * * ** * *** * * * * ** * ** *** * * * ** *** * ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
** ** * * * ** i,j,k,n,num[n],m;
** *** * ** * * ** ** ** ** * *** &n);
* ** * ** *** ****


** *** * *** * * * * **
* ***** ***** * ******** * ** * * &num[n]);


**** * * ** * * ** * *


* ** * **** ***** * * *


** *** * ***** **** *

   {
** ******* * **** *** * * ** ** * * * * * ** * *
** * ***** ***** * * ** * * ** *** ** * **
* * * * ** *** * ** ****** * ****
* * ** ****
** ** * ** * * * ** * * ****


* * * * * * ** ",num[i]);


* *** *** ******* *** 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* * * * * * ** **
** * ** * **
* * *** * **
* **

{
** ****
* * *** ****** ****
* *** **


(i = *** * *** ** **** * ** * * * **** *
*** (j = * * z - * ****
** (i = j + * *** ** * * * ** * ** = * **** * = ** *** = *

}

j = 1;
* (i = * * ** **** ** * * * *** * != **** * * * * * *** ** j ++ ;}


** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * * **

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
** *** * * ** *

for(i=0;i<a;i++){
* * ** * * * ** ** * *


*** ***** * * * * * ****
*** *** ** * * * *** * * * * *
* ** * ** * ** * = 1;
**** * *****
** *** *** **


** ** * ****** ** **
**** ** * * * * *
* ** *** * * * * * * **
* * *** * **


*** ** * * * ** * * = 0;
* * *** **** **

   i = 0;
******** ** ** *** * * *

{
** *** ** * * *** * ** * **
** * * ** ** ** * ** * ** ******* ** ** * ** ** **
* * * * * ** * * * ***** * * * * * ** * * ** ** * ** ** = b[l];
* ** ** **** * **** ** ** **** ** ***** * ** * * = b[i];
* * * ******* **** * * * *** ***** * * ** * * * *** * * = k;
********** ** ****** *** * ** ***** * ** * ** * ** ***** = 0;
** * * *** *** * * * * *** ** *** * *** ****


**** ** ** * ** *

}



for(i=0;i<j;i++){
** * ****** * *** ** ** ** ** * * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** *** ***

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* *** **** * *** * ****

for(i=1;i<a+1;i++){
* * *** **** *** ** *** ***


* ** * ** * * * ** ** * ** * *
***** *** * * * ***
* ** **** = 1;
* * * * ** * *
** * *** * * * *


* * *** ** ** *
** *** * ** * * *
** **** * *** **** *
**** * * ** *** *


* ** ******* ** *** = 0;
*** ** * *

   i = 0;
***** * ** *** * ** **

{
** ** * * **** ** *** ** *** ***
* * * * ** * ** * ** ** **** * ******* * * * * **** *
*** ** *** ** * * * * * ** ** ** * * * * * * = b[l];
*** *** * ** * * ** * * * ** *** ** * * ** ** * = b[i];
** * ** ** * *** ** ** **** * ** * * **** * *** *** = k;
* ** ***** * * **** * ** * **** ****** * ** ** = 0;
** ***** * ***** ** *** * ** ** ** * ****


*** *** * * * * *** *

}



for(i=0;i<j;i++){
** * ***** * * * * *** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * * * *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* * * * * ** * ** *

for(i=1;i<a+1;i++){
** ** * **** *****


*** * ** *** **** * * * * *** *
* **** * ** * *** *
** *** *** * * = 1;
**** ** * * * **
*** *** *** * *


** **** ***** *** ** *
** **** * *** ***
* * ***** *** ** *
** * * * *** ***


** ** ***** * * * ** = 0;
***** * * ** * ** *

   i = 0;
* ** ** * *** * * * * **

{
*** * *** ********** ** ** * *
* * *** ** *** ***** * * ***** * * * *** ** * ** ** * *
* ** ** * * *** * * * * * ** * * * **** * *** = b[l];
* **** * * * *** * * ** ******* *** ** * *** ** ** = b[i];
* ** * * *** **** *** * *** ** * * ** ** ** *** ** * * = k;
* ** * ** ** ** * * ** **** **** * * ******* = 0;
**** *** * ******* ** * *** *** * *** **


* * * ** * * * ** * **

}



for(i=0;i<j;i++){
****** * *** * * *** ** * * * ** ",b[i]);

}





return 0;



}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.85
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 847 views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.8k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.5k views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 6.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users