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請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 2.3k views

17 Answers

0 like 0 dislike
Hidden content!
* * * **** * *

int main()



{
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**** *** * ** * **** *** a[i];


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for(b = 0;b * * * i;b ++)

if(a[b] == a[b+1])
** * * ****** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** * * * **

#include * * * *

#include **** * *** *

int main()

{

 float c;
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}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf * * * *** **

}

if (a%2 != 0)

{

k = a/2;

printf ** ** * * * ** *



}
** * * ** * * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** ** ** * **

int main()



{
* *** * ** ** *** *** = 0, c = 0, box = 0, i = 0;


* * * ** *** *** * ** * ** * * **
** ***** ** a[i];


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* * ** ** ******* * * ** * ** * * * * = box;
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for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
****** *** ** ** ** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include **** *

int main()



{
* *** * * * * ** *** = 0, c = 0, box = 0, i = 0;


* * **** * * ** *** ** ** ***** * * ** * *
** **** * ** a[i];


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*** * * ** * * = 0;b ** * * ++)
* **** * ** * * ** * ** < a[b+1])
* **** *** *** * * **** * ** ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
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* ** ** *** ***** * ** (i=0;i<a;i++)
* * * * ** * * **** * **** * ** * **** * ** ** ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
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*** * * *** ** *** **** * *** **
** ** * *** * **
** ****** ** * ** * ** * **


** * * * ** *** ****** *** ",num[i]);


* * * * *** * *** * 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* * ** ** * * * *
*** * ** *** **** **
**** ** * **
** * ** *

{
**** ****
**** * * * * ** *** * *
* * * *


** (i = * * * * * **** ** * * *** ** * ** * ** *
(j = * *** z - *
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}

j = 1;
(i = * ** * * * ****** != *** * *** ** * ****** * j ++ ;}


** ** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ***** * **

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=0;i<a;i++){
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{
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** ** * ***** * * * ** **

}



for(i=0;i<j;i++){
** * * ** *** * *** * * * *** * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** * *** ** *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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*** * *** * * ** ***** **
*** * ** ***** ** = 1;
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****** * * * * **** * * *

}



for(i=0;i<j;i++){
** *** * **** * * ***** ** * * * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ** ** **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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* ** * **** ***

}



for(i=0;i<j;i++){
* * **** * * *** * * * * * *** ",b[i]);

}





return 0;



}
answered by (-140 points)
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