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請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 2.6k views

17 Answers

0 like 0 dislike
Hidden content!
** ** * * ** * *

int main()



{
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** ** * * * * ** ******* * * ** * *


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for(b = 0;b * ** * i;b ++)

if(a[b] == a[b+1])
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return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * ** **

#include ** * *** ** **

#include * * * * *

int main()

{

 float c;
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}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf ***** * * *

}

if (a%2 != 0)

{

k = a/2;

printf * ** * * ** ** * **



}
* * ** *** ** * ** * *** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
*** ** * * **

int main()



{
* ***** * * * * ** * = 0, c = 0, box = 0, i = 0;


* * * **** * * * ** *** ** ****
***** ** * *** ** a[i];


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* * *** * ** *** *** *** * ** * **** ** = box;
* *** *** * * * * ** * * * * ***





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
* **** * ** * * *** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ******** * *

int main()



{
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*** *** * ** * ** **** ** ** ****** * * ***
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** ** ** * * = 0;b ****** ++)
* ******* * *** * * * * ** < a[b+1])
**** * * * ** * * *** * ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
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*** * **** * * ** **** (i=0;i<a;i++)
******* ***** * ********* * ****** * * * * * * * ** ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
** * * ** * * ** i,j,k,n,num[n],m;
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** *** ** * * **** * ***** *** *


* * * *** ** * ****** ** * ",num[i]);


* ** ** ** *** *** 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* * * *** * ***
** * ****
** ** * ** *** *
* *

{
**** * *
* ** * * ** * *** **
* ** ****


* (i = ** * * * * *** * ** * * ******
** (j = * z - **
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}

j = 1;
(i = * *** * * * ** * * * != *** * * ** * ***** j ++ ;}


*** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
***** ***** *** *

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=0;i<a;i++){
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* **** * * *

}



for(i=0;i<j;i++){
* ***** * * * ** * *** *** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * * **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* * ** ** * * *

for(i=1;i<a+1;i++){
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* ** * * * = 1;
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**** ** * **** **


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** * * * ** *** **

}



for(i=0;i<j;i++){
* * * * ** * ** ** * ** *** * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * *** *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
**** * * *

for(i=1;i<a+1;i++){
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* ** ** ** * ** *** *** *****
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   i = 0;
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}



for(i=0;i<j;i++){
*** * *** ** * ** * *** *** ",b[i]);

}





return 0;



}
answered by (-140 points)
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