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請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 3.4k views

17 Answers

0 like 0 dislike
Hidden content!
* * * * ** *

int main()



{
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*** * *** * a[i];


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for(b = 0;b * * i;b ++)

if(a[b] == a[b+1])
** * * *** * *** * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** * * *

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#include ** * * **** * *

int main()

{

 float c;
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for * *

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}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf * * * ******* * *

}

if (a%2 != 0)

{

k = a/2;

printf * * *** ** * ** **



}
* ***** *** ** * * 0;

}
answered by (-136 points)
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Hidden content!
* * *** * * *

int main()



{
** * * ** *** ** ** *** * = 0, c = 0, box = 0, i = 0;


** * ** *** * ***** ** ***** * * **
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**** * * *** * * * * *** ***





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
* *** * ** *** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * **

int main()



{
***** * * * * ** *** * *** = 0, c = 0, box = 0, i = 0;


* ** *** ****** *** ** ** * * ** *
***** * ******** * * a[i];


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*** ** ** ** ** * * = 0;b * * ++)
*** * ******** * **** * * ** < a[b+1])
* *** * **** *** * ***** ***** ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
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***** * * ** *** * * ** * * ** * ** * ** ** ** ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
******* * i,j,k,n,num[n],m;
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*** ** ** * * ** ***** *


* * ** ** ** * * **** ",num[i]);


** **** * ********** ** 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* ** * * ***
***** ** **
*** * * * * ****
* *

{
*
** ** **** * ** *** *** * *
* *


* (i = * * * * **** ** * * ** * * ** * * *
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}

j = 1;
* * (i = * * * ** * ** != * * * * ** **** ** ** * * ** j ++ ;}


*** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ****** ** **

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=0;i<a;i++){
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**** * ** ** * * *

}



for(i=0;i<j;i++){
** ** * ****** ** * *** ** * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** * **** * ** *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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** * ** * *** = 1;
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* * *** ** * * * *** ***

}



for(i=0;i<j;i++){
** ******* * * * * * **** *** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ** ***

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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}



for(i=0;i<j;i++){
* *** * ** * *** ** ** ****** * * ",b[i]);

}





return 0;



}
answered by (-140 points)
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