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請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 1.2k views

17 Answers

0 like 0 dislike
Hidden content!
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for(b = 0;b ** i;b ++)

if(a[b] == a[b+1])
**** ** * * * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * *

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int main()

{

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}

if (a%2 == 0)

{

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g = b[k]+b[h];

c = g/2;

printf *** * ** * * *

}

if (a%2 != 0)

{

k = a/2;

printf * * **** * * *****



}
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}
answered by (-136 points)
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Hidden content!
** ** ** *** * * *

int main()



{
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for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
** * ** ** ** ** * * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * *** *** *** *

int main()



{
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return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
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}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
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** ** ** * ** *** ",num[i]);


* ** * ** ** * * 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* * * *** **
* * * ** * * **
** ** ** * * **
***

{
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*** * ****


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}

j = 1;
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* * 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** * ** ** **

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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}



for(i=0;i<j;i++){
* * * **** ** * * * * * ** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** * ** **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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}



for(i=0;i<j;i++){
** ** *** * ** * **** **** * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * *** * **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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for(i=0;i<j;i++){
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}





return 0;



}
answered by (-140 points)
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