1 like 0 dislike
398 views
請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 398 views

17 Answers

0 like 0 dislike
Hidden content!
** * ** * **** **

int main()



{
***** * * *** ** * * = 0, c = 0, box = 0, i = 0;


* * * **** * ** ** *** * ***** * ***
********* **** ** * a[i];


* ** * ** ** * ** * * * = 0;b *** i;b ++)
* *** * * * * * ******* * ** * * *


*** * * **** * * = 0;c * (i-1);c ++)
* ** **** * * ** ** *** *** **** **** * = c + 1;b **** i;b ++)
* ** **** * * * * * * * **** *** * * a[b])
* * * ** **** *** *** * **
*** ** * * * ***** * * ** * *** * ** ** ***** = a[c];
** * *** * ** * * * ** *** * ** **** * * * ** ** *** *** = a[b];
* ** * * *** **** ***** * * * ** * * * * * ** *** * * = box;
****** * ** ***** * ** ******* **





for(b = 0;b ** * ** i;b ++)

if(a[b] == a[b+1])
**** ** * * *** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** ** * *

#include * * * *

#include * * **** *

int main()

{

 float c;
** * ** ** * ** * * ** a;
** * * ** * **** * * * * * * * * *** ** *
* ****** * * * **** ** * * * ***




* ** **** ** * * * * * * *
** ** ** ** **** * * * * * *** * * * **





for ** *****

{
* ** ** * **** ** * * * *** * * ***
* *** * * ** **** *** ****** ******** *** * *** * ** **
** ** * ***** * ** ** ***** *
* * * * * * *** * * * *** * * **** * * * = b[j];
** ** * * * * * **** * **** * *** * * = b[i];
***** * **** ** **** ******* *** * * * = d;
* * * ** *** *

}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf *** * *

}

if (a%2 != 0)

{

k = a/2;

printf * * *** * * *



}
*** ** ** * *** ** * * ** *** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
*** * * *** *

int main()



{
* * ** * ** * ** = 0, c = 0, box = 0, i = 0;


*** *** **** * *** ***** * * ** * ****
* **** **** * ** a[i];


** ********** * = 0;b ** * i;b ++)
** ** * * * *** ** * ** ** * * * ***


**** **** ** ** * * = 0;c * ** (i-1);c ++)
* **** ** * * * ** * * * * = c + 1;b < i;b ++)
* ** ** * ******** **** * * * * * * ** == a[b])
* * *** * *********** *


** * * ***** * * * **** ****** ** *




* **** * * * * * * * * *** * *** a[b])
* **** * * * *** * **** * **
**** * * * ** * *** * * * ** *** * * * * * ** ** = a[c];
***** * *** * *** *** * * **** * ** * * ** ***** ** * * * = a[b];
* ** *** * ** * * ***** * ** * ** * * = box;
* * * * ** ** ** * ******** *





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
** * * ** ** * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** *****

int main()



{
** *** * * * * * * * = 0, c = 0, box = 0, i = 0;


***** * ******* ** * * *** * *** *** * *
** ** * * * a[i];


* * ***** * * = 0;b < i;b ++)
**** *** *** *** *** * * ** * * ** * *


* * ** * * ** * = 0;c < i-1;c ++)
* * ** * ** ** ** * * * * ****** = c + 1;b < i;b ++)
*** *** * ** * * * ** *** ******* == a[b])
** **** ** * ** *** * * **** *


**** * * * *** * * * * *




* ***** ** *** ** * * * * * ** ** > a[b])
* * ******* ***** *** * ** ***
* ** ** *** * ** ** * *** * ***** * ** = a[c];
* *** ***** ** * *** ** * ** ** * * ***** **** * ****** = a[b];
* * * *** * ** * ***** **** * * *** *** *** *** * = box;
** * * * ******* ** * * **** ** ** * *




* * * * * ** ** = 0;b ** * ++)
*** *** ** * ** * * *** ** * < a[b+1])
* ** ** ** ** ***** ** ** * **** ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
** ** ** * **** ** * ** *** ****** * *
* **** ******* num[a],i;
* * * * ** * * * ***
**** * * * * * * * * ** ** **** * * * * * ** * ** *


* ** * * **** * ** ** (i=0;i<a;i++)
* * * ** ****** ** * *** * ***** ** *****
* ***** * **** * ** **
* ** *** * ** * * ** **** * * ** * * * (num[i]>num[j])
** * ** ** *** * * ** ** *** ** *****
** *** ** * * * * ** ** * **** **** * * * * * *** * **** *
** * ** * * * * ** *** * * ** * * **** * * *
* ** ****** ** **** * **** *** ** ** *** * *** * *
******* * ****** *
* * ** **** * ** *** * (i=0;i<a;i++)
* * ** ** * * * ** ** * * ** * ** * ************* ***** ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
*** ** *** * * ** * i,j,k,n,num[n],m;
* ** * * * **** ******** * ** * &n);
* * * **


* * * * *** ** * *** ***** ****
** *** *************** * * ** * * * &num[n]);


**** ** **** * * *** * * * ******


* * *** ** * **** *** * * ** *


* * * * * * ** * * * * *** * *

   {
**** * * * * ** * ** ******
**** * ***** * ** * * ** * *
** * * ***** ** ** * *** ***
****** *** *****
** * * *** * ******* ***


* * * ** * *** * ** * * ",num[i]);


* ** * * ** ** * *** * 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
**** * ** **
** * * *** ** ****
*** ** * ** * *
* *****

{
* * **
** * *** ** *** * **
* *** *


* * (i = **** *** * *** * * * * * * **** * *
(j = * ** z - *
** (i = j + * ** * * ** *** **** *** = ** * * = * *** = **

}

j = 1;
* (i = *** ** * * ** ** != **** * ** * **** * ** * * j ++ ;}


* ** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** *** * * **

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* * *** ** *** *

for(i=0;i<a;i++){
* ** **** * ** **** ** *


* ** ***** ***** ** * * * * * *
***** **** * *** * ***
**** * * ***** ** *** = 1;
*** * * * ***
** ** **** * * * *


* * **** ** * * * **
* ** * ** * *** *
* ** * ** * * **** *
* ** *** ***


** * * *** * * * ** = 0;
* ** **** ** ****

   i = 0;
**** ** *** ***** * * ** ***

{
* * ** ***** * * ***** * *
** ** * * ** *** *** **** * * *** *** ***** * * * * *** * *** *
* ** * * * * * *** **** * **** * * * * ** ***** * *** * = b[l];
* *** ** * ***** ** ** * * * * ** *** * *** * ** ***** = b[i];
*** ****** **** * * * ***** * * *** * * * ** * * * ** = k;
* * * * ** * *** * * * *** ** **** ** * * *** * = 0;
* ** ** ** ** * * * * * * * ***** * **


** *** * ********* ****

}



for(i=0;i<j;i++){
* *** * ** ** * ** * * * ** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * * ** * ** * *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
*** ** ** *

for(i=1;i<a+1;i++){
* *** ** * * ***


** ** * ** * * ***
* * *** * ** *** * *
* ** *** *** = 1;
* ** ** ** * **
**** *


* * * * **** * ** **
****** * ***** * *
* * * * * * *
*** * * * ****** * **


*** * ** * *** * * = 0;
* ***** ** *** **

   i = 0;
* * * ** * * * ** * * *****

{
**** *** * ** * ** * ***** ** * * **
** ** ****** * ** * * * * * * * * * **** * **** * *
*** * ** ** * ** ** ** ** ** *** * * * * * ****** * = b[l];
* **** * * * * * * * * *** * ** *** * * *** ****** ** = b[i];
** *** *** * **** * ** * * ** * *** **** * * ** *** ** ** = k;
* ** * * * ***** * ** * * * ** * * ** * ***** = 0;
******* ** ** ** * *** ** * * ** *


* ** * *** * * * *

}



for(i=0;i<j;i++){
* * * *** ** **** ** **** **** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** * ** *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
*** **** * * * **

for(i=1;i<a+1;i++){
*** ** * * * ** *


** * * * * * * *
*** * * ** ** **** * ** ***** ***
** * *** * ** * = 1;
*** ** * * * * ** **
* ** * * *


**** ** * *** ** * ***
***** ** * **
* *** * **
* ** ** ****


* * * *** *** = 0;
** *** *** **

   i = 0;
** *** *** * ** * * ** *** ***

{
***** * ** ** * ** * * * **** ** *
* * ** * ** * *** * ** ** * ** ** * * ***
* ** ** * ** * * * *** * **** ** * **** ** * *** = b[l];
*** * * *** ** * ********* ***** * * ** *** * * * *** ** * * = b[i];
* * * * *** * * ** *** ** * ** *** * *** *** *** * = k;
** * ******* * * * ** * **** * * *** ** * * = 0;
** * * * *** **** * * * * * **** * **


* * ** *** * * * * * **

}



for(i=0;i<j;i++){
***** *** * * * ** ** ** * ** * ",b[i]);

}





return 0;



}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.72
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 232 views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 619 views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 403 views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users