期末考題目-Question 3

1 like 0 dislike
2.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 2.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* *******   **  ***  ***  *  * **    * *   *  * * * *  * 
**  ** *    ***   ***** ****
   *** * * *** *  *    *
 ** * **  * *  **** **  *  ******      
 *  ***** **    * ***  **
* * * * *** * * ** ** **  *****   ** *** * ***
 *  * * ** ** *  ** * **
*  *  *** ** * *     *  **   * *  *   *******  * 

***  **  * * **   *** *** 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* *    ****** *  * ******** *   ***  * *  ****   ******** * 
**** *  *  **  *   **** *  * *** ** 
    ** * * *    *** *   *  **   **  
   *** *** * **      *   ** *    **     **** ** *  *** ** *    *  * *    
* * *   *  * *  *  *** *   **  ** if(s==1)
*  * *  *   ** * *  ** * **  ** ** ** **      *** * * *    **    *  ** *
 *    ** ** *****  *   * * ** if(s==2)
 * ***   ** *  ** ** * *  *  * ****  *  *    **** *** ** *   ***  *** 
** * *  *    *    *  * *   ***   **  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ******** * *  *  ****  ** * M,D,S;
    
  ** * *  **  * ** * *    *   * *****   **  %d",&M,&D);
    
**  *  * * **     *   *    *** 
***  * ***     **** * *   
*   ** **    * *   * ***   ** *  *
  *  *   *  * ***** ******
 ***** *  ***    **   *   * * * ** ***  **   *  ***   *  *** * *    *   *   * *
*** * * * ***  ***    
 **      ***   *   **   * *** **  if(S==1)
  ** *  ** ** * *      *
  *  ***  *  ****  * ****     * ***  *** **** ** ** * ****  *  **  ***** ********* * * *
* **  ***** *    ** **   **
****   *     *** *  * *  **** if(S==2)
 * **  ****** *   * ** 
  **** ** * ** *****   * * ***    ** * **   *   *  ****  *  **  *  **  * *   *   ***  
* ** * * ***    ***  **
  ***  ***   ** *******   * * ***    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
   ***   *   * **  ***    * ** m,d,s;
 ** *** **  *   *     ** 
* ** **    * *  * * **    **  *   * ** %d",&m,&d);
    
*** *** * *     **   *   * *  * *   + d)%3;
 **  * ** **  ***    *  **
*  **  *  * *  * * ***** ****
* *       *  ****  ***  *  ** 
**  *** **    **   *** **** *   *  ** *   *****  ***   * * * *  * 
*** *  ** ** * ** ** **     
**  *  * *     ***  **   *      if(s==1)
***    **  * ****   *  ** 
*  **  **** **  *  * *** ** *** * ***** ***** *** *****    * ******   ** *** *  ** * 
 **  ****  * ******* **  **  
   *** *  *** ** ****  *  ***** if(s==2)
 ********  **   * *  *** ** **
*** ****       * * * *   **   * ** ***  ** ****  ****  *  *   *** * ***** * * ******
* *  *** *** ***  * ** ***   
** *    *    *   ***  * ***  
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  * * **  **** **   
int main()
{
int M,D,S;
**   *  *** * * *    * *  ****   *
scanf("%d **   ** *  *   * * 
S=(M*2+D)%3;
if(S==0)
*   *****  ** *   ** * ** * ** * *  **  **  *  
 * * *   * ***  * *  *    * *     ** if(S==1)
 * **   *  **   *    ** * * *  *      *   * **** * ** **********   *  
*  * *** * **   **    * **    *  **   *********   * *       * 
**     *** * **            * * **  *  ** *** *  **   *   **  *    ** *****   **   **  * *  *** ** *   



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *** **  *  *   * *    *  * m,d,s;
  *  *  **    ***  **  *** ** ** *     *  **  ** ** ***     
 *  ****     *****    ** = (m*2+d)%3;
 * ** * * *** * ** *  ** * **  (s == 0)
* **   **  *      *  ** *  *  **  * **** ****** *** 
 * *  ** *****     * *   if (s == 1)
   * *  *    *  ** **  ****  * **          * *  ** *
****  *** **  *** *      * * if (s == 2)
 **  ** ***  **   *** ** **    *  * *   *  ***   *
* ***   ******  *  *  * *  ***
*   ** **  **  *   * * *****   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
** ** *  * **   *** *  *  ***  * M,D,S;
 ** **  * *    *    *** * **   *** * ** * *  %d",&M,&D);
  *  ********* ** ** **  ** *  
       *** ***   ** ******   ***  * * *
*  *      ****  *     ****  * *   * ** **  **  * *
*** *** * *  ** * ** ** *** *** **  **
*   *   ******  *****    ** * *  * *  ***    ** ***   * *
  ***        *    *  * *** **
 * **  *  * *  *** ***  **   ** *  *  ***   
* * *   ***      * ** * * ** *  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 **  *   ** *** ****  ** *    m,d,s;
  ***   ***  *   ***** * ***   *  *  *  * ** *           *
  **   * *  ** *  * * * *   = (m*2+d)%3;
 ****** *** * *  ****** *  (s == 0)
 ****   ****** **** * *  *  **    *   ** ***** *   
*  ****   ****  * * * **** if (s == 1)
* *****  * * *  *    **  ** ***  *** ****    ** **** *** *
  * **  **  ****  *  * **  if (s == 2)
*** * ** ****    *   ** * * **   *** ***  * **
*  **   **  * *  **  *  ** *
**    * * * ****** **     *  ** 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
   ***  *** ** ********  **  ** ***** %d",&m,&d)!=EOF)
    {
*  *  *  **** ** **   * **** * *** ** * **** ******* *  ***
  *   * **      *********** **  *  ****** **   * **** * 
 * **** *   ** *** ** ** *  ***   * ** * * *   ****   ****  * * ****      * ***  **** * *  * ** * * *    * ** *******
**** * **   ***  * *   * ** *   *   ***  ******** *    ** ** *   if(s==1)
  **   *  * * * *  *        ***** *** *  * * * *  * *  **  * * * *****   *   ***  * *     * * **  * ****    *** *
*  **  *   ** * ******  * * *** * ******** * *  ******  * if(s==2)
*****  **  * *  ** * ** ** * *** *****   * ** * ***   * * * *  **    * * * * * *** *    *  *** *  *
* **** * *  *** *  **  *  *   * ** * *   *  *  *** * *
 *       * **   ****** ** * * * **    *    *  ******* *  **   * * * **   *  ***** **  
    }
    ***** ****  ** *  * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * ** ** *** *****  **

int main()
{
int M,D,S;

   ******  * ***        ** **  *  ***** *
 * * 
  ** 
{
*** ***  ***      ***
}
 *   *
{
 **  * ** * ***   *  *** ** 
}
 *   *   
{
* ****    * * * *  * ***
}
 *** *    * **  *  *  **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.45
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 888 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 826 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 862 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 776 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 698 views
12,783 questions
183,443 answers
172,219 comments
4,824 users