期末考題目-Question 3

1 like 0 dislike
2k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 2k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
***  **   ***   **    **     **    * ***** ** ** *  ** ** 
  *   * * **    ****   **  
 ****   **  * **    **  * 
 *    **  ** * **   * ** * *  ** *** * *    
** ** **    * **  *   **  **   **
**  ** ****   *** ** *  ***     **   **
  *   **  *    *  ** **  *   *
**** *** *** *  *  ***** ** **  **** *    

 * *      *   ** ***  * 0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 *****  * **  ***  *****  ***  ****    * ******* ** ** **  **   
* ***    *   * **  **   **     *  * 
**  * *  **    *         *     * 
 *** *   *****  *       *  *   *   *    **      * *  *  *  * ***    ***  ****
***  *** **    *** *  **  * if(s==1)
 ***   *  *  ****  * *  ***   **** **   *   ******   * ****  *** *   
  *  * * *    * ***    **   * *  if(s==2)
*** **  *   *  ****  *  *  ***      *********** **  ** * ** *
**** *** ***** *      *   0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* * *  *  * *  **  *  *** M,D,S;
    
*** *  * * *    *** **      ***** * **     * %d",&M,&D);
    
 *** ***** ** ** *  *    ** * *****  *
*****   *  ***  ****  
*   *** *    ****   ***** *** *   * *  
 * **     *** *** ** *  
 *   ** **  **    *  * *   *** ***     ***** * *** *    *** **  ** *******   *
**  *  * *  * *   *  *
 *   **** * * **  *** *    if(S==1)
** *  **** **** *     ***
** * *    *** *   ***           * * *** * ********  **   ***  *  * *   * * * *** * ** 
 *** **  ********* ** * *  ** 
 *    *   *   **   * *  *  if(S==2)
******    *** * **     **    **
****   * * *  ********** *** ***  * * ***    *   * * * * *****   *  *     * *   **  *    
 ** **** *       ** *  **     **
*   * * ***  *   * * * ***   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
  ********  **** ***  **** ** * * m,d,s;
  * *  ** *  *  * *  * * *
*** * * * **  **  *   * *  * *     **    ** %d",&m,&d);
    
  * **** * **** *   *   *  **** + d)%3;
 ****  * *  *** **  *  * * *
 * ***    ****      *       **
 *    *  **   *** * *  *** 
** *  *  *   ****  *  *  **  ** *** *     ******* *  *   *      * ***
* *  ** * *    ** *** * **** 
**  ***** ***  **  *****  *  if(s==1)
* **   *  ***  **  * *  * * 
**    * *  **  * **   ***** **   *   *    * * *  * *****  *  * *** *********  *  ** * 
*  * *  **  * *** * ***  *
**  *****     *  **  *  ** *  if(s==2)
*  **  ****    **  **   *
  ***   *  *** * *  ** *  **   *    * ** ** * ** ***** ** *  ***** ** *  *  * * * *  **  *
*** *     *  ***  ** **  **  
*  ***   *    * ****** **  ** 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   *** *  * * *  
int main()
{
int M,D,S;
    **** * *  *  * * **  *   *
scanf("%d * *** *  *****    ***
S=(M*2+D)%3;
if(S==0)
 ***  **  **** * ** ** * *  ***   ***  **
**  **** *  ****  ** ** * *    if(S==1)
  ***      ** **     **   *  ****** ** *   ** *         *   **    *
* **  ***  * * ** * * *   ** ** ** ** * ***  *  ** * * * ****
 **** * ***      * *   *    * ** **** * * *  ****   **  * ***   ** *** ** ***** *****  *  **   *     **** ** *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *  *** **     ****   *  * ** *  m,d,s;
  **  *****   ***    * *  *** **  *  **** * **      *  * 
 **  *     *    * ***** *** *  = (m*2+d)%3;
*    **** * **  **   *    ****  (s == 0)
 *** **  **  *  * *** *** * ****  ****    ***   * **  
* ** *  * *** * *   * ***** * if (s == 1)
  * * * ****** **    * ****  *  *   *    * * ** *   
 * ***   ** *   ***    ****** if (s == 2)
** *  * ** ***** * ** **** *****  * ** *  *    * **
  **  *   *   **** *** * *
 * * **** **  *** *   * ***  *      0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
     ***  **   *** * ******   M,D,S;
 ***       *   **    *** * *  ****** %d",&M,&D);
***   * *   *** **    * **    ** * * * 
   *** * **  * ****** * * ** *  
 * *   ** *** *  ** * *     **    ** ****  * * *   *** 
 ******* * **** ****   ***  ** * 
** * **  ***** *** *   *** *     *** * *  **    **** *   **
*****  *  *** *   *      **  * 
 * *  *  **** *** ****  ****  * *    * *  
 * ****  * * * * ** *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *  *    ***** *  *  ** * *** m,d,s;
*  ***   * **       **** ***    **** * **  * * *  * ***  * * * * * ** * 
 *  **     ** *  *  *****  = (m*2+d)%3;
  ****** ** *** ** ** ** * ** (s == 0)
*  ** * ** *    ** *  *   * *  **    *  * *** **
* * * ****       **  * ***    if (s == 1)
 *  * **  **** * *    *** **** *****  *      ** 
******  *   ***   * ******  *  *   if (s == 2)
 ***  * *    * *   * *     *  * * *** * ** * * *** 
*** ****  ** ***   ** *  * 
* *** *  *  ***   *  *    **    * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* ****   **  * *** * ***  * * *         **    %d",&m,&d)!=EOF)
    {
*   ***** *   *****  ****   *   *  ***    ** * *   *    *  ** *
** *  ** **  *    ** ***** *  **  *** *  ***  *  ** *   * *  * 
 *  * *********  **   **         *  ** ***** ** * **    * * * *** **** **  *    *     *   * *** * ** * ***   
  *    ** **** *** *  **  ****    *****     *   * * *  if(s==1)
**    ***  **      *    ****        ** * *  **  *** ***   **  *  *** *         *   * *     *** ** **
***   ** *    ***   * *     * *****  **  ***  ***  *  if(s==2)
**  *  **  *** ****    ********      **  ** **     *  * * ***  *** *  * ****** *** **  ***  * * * **** *   
*      * ** ** ****   * *  *** **  *** * ** ** * ** *   *
*  * *  *      ***** **     ** * *   * *** **   *   ********   * **   *
    }
**  ***   **** * *   *  * ** *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *  ****  *** ****  ** * 

int main()
{
int M,D,S;

   * ********   ***  ** * *  ****  * 
 ** ***  * 
 * *  
{
*     * *  ** ***   * **  * **
}
* *** 
{
   ****** * **  ***** 
}
   ***
{
*     *  ****   *    **
}
  * **    * *** ** ** *  *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.45
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 888 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 826 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 862 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 776 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 698 views
12,783 questions
183,443 answers
172,219 comments
4,824 users