期末考題目-Question 3

1 like 0 dislike
1.9k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 1.9k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
  ** ** * *   * ****** **  * * ***  * *   ** * * * ** **  ** ****  
******    * ****** **  
  * **   ******** ** ** 
** *  *  **  ****   **  ******* **  **  * * **
   * * ***  *      *  
*   ** ****   *****   **   *    ****    *** **
*****  ***  **  * **** *   
***  *    ** ** ********* * * *** *****    

   **   *** **  **     *  0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* **  **** **  * * * *   ***      ***** *    **** **  ****   
* **  ****  **   *  ** *    ******
** *  *  * *** *   ****   * *  * 
 * *   * *******  *    * *  ***  *** * ******       *       **          *
*   *   * * * *  *   * * ** *  if(s==1)
*** ** ** **   * * *** **** * ** * *   ** *** *       * ** *     *    ***
*  *          **** *      *  ***** if(s==2)
** *  *** *   ***  **  ** ** ** **  ***  * *  **     * *** ***    ***   ** 
**   ******  **      *  *   *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* ** *  *   **  *  *** **   * M,D,S;
    
 * ** * * ****      *  ** * *  ***  *  %d",&M,&D);
    
 ***    *     ** **** **** ***** *  
  **** * *** * *  * ***  ***
** ** ********* *    ** *  *  ** *
 * **  ** ***  ***   ** **   *  *
*** *    ** *  * *   * * * ***** ** **     *** * *  *** *   **     *** *  **      * **  **  ** 
* * ***  *** ****** **   **** ** *
* ** * **   **  **    ** ****  * if(S==1)
**  * *****  ******* *  
 ***** ***    * *  ******   *  **** * ** * *  * **   *** **  *         *** ****   *
* *    **  ** ** ** ****   * *
**  * *     *          *    *    *  if(S==2)
  * **  **  ***  * ** * ****    
*  *  *  ** * *  * * *  * * * ** * *  * *  * *  * ***  ** * * * ** **     ** *   
** * **   *****  *  ***
***** * * * **    * *  ** * * *  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** ** * * ** **  ***** * m,d,s;
* * *  * * *  *  *    **  
***     ***  *        **** * * ****   *    *   %d",&m,&d);
    
**   *****  * **** * * *****  *    ** + d)%3;
* **  * * *  ****   * **** 
 * ****  *  *****  * **   * 
* *** **  *  *** ** *****
****     ****    * ** **** ***  * *  *  *****  *     *     *
  ****  * ** *   **** *  **
 * * *  * *   *   ** *  ** * *   if(s==1)
*  *     * *  ** *   **      * 
*** *  * ** * * ****  * **    **  * *     * ****  **  * **** * *  ***  * ** *   ***  
** * * ***     *  ***   *
** **** **  *         ** * * **   if(s==2)
    ***** ****     *** *  ** *
  * **  ****  ****  ** ***      *  * * * ** ** * * ***   *****  * * * ****  *
* **    *   *        * * *  ** *
   ***    **** **  *  **     
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *** *       *** 
int main()
{
int M,D,S;
*  **** **      * *  ***     
scanf("%d  **  * * ** * ***  ***  *
S=(M*2+D)%3;
if(S==0)
   *    *  **** **      *     * *      * *      
**   * **  ** **  ******* ** * *** if(S==1)
 ** * ***   ** *  ** *      **  **** * *  *       **  * * **   
** *  ** * * *     **** * **    *  ** * * *          **
** * ***** **** *  * * **   *** ***   *** *  ***   **** * ***   * *** *** *   * *** * * ** * **  **



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 ** **  *  **   *     * *  m,d,s;
*** * * *  * *** **** *  **  *  **   *** **  * **    *  * *** 
****  *   * ***     *      = (m*2+d)%3;
***   * ***   *  **  *    **   (s == 0)
** * *  ***        * * * * * *  *** **     **   **
**  ** ** *  ****** **  *  **   if (s == 1)
**     *** * * * ***   ** **    ***   * ***
*   *** * ***** *    ****** * ** if (s == 2)
  **   *  * **  * ** *  ***  *** **** ** * *** *  * **
  ***  *   *   * *     ***   *
*    *****     *   *  *     **  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
 * *** **         * ****  **  M,D,S;
* *** * ** **** **   **** ** *    ****  %d",&M,&D);
*******    *** * * ** *** * **  *   *
  * * * **  ***  ** ** ***  ***
*****  ** ***** ****  *  * *         *** **   * **  * 
* * *   **   ***** *  * ***     **
*     ***  * *  ****  *   ***   * * *  *     *    **** 
     * ** ** **  * ** ** *** ***
**    *** * **    **      * *   *  *** ** *      
** *  *** *    ****** ** *    * *** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** **   *** *  ** *** * * * ****** m,d,s;
  ***  *  * * *  *    * * *****  *  ** *     ***  *  * *** *** 
*** ** * ** *** ****  * = (m*2+d)%3;
*   *  ** * **** *  **     * (s == 0)
*   * **** *  ***** *  *     *****  *     ** *    * **
 ** **** **** *** * * * ** *    if (s == 1)
** **  ****  ***** **   *  *****   ** * ****   *   
* **     **  *  * * **  **   * if (s == 2)
 *** **    **  **  ** ** ** ***** **  **      **   *
 *   ** *  * * **     * *
 **  *  ** *     ** * **   *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 * **** * **  * ** * **   **  * ** **    * %d",&m,&d)!=EOF)
    {
  ********      * *****  * * ******  * *** **   * * *** **
*  * *   *   ***       *  ** **  **  * * *   **** ***  * 
*   ***  *      * ** * ***  * ** *   **  **  ** * * *** ** *   * *  ***   **** **   *** ** ***   ***
**** *** ***  ** *  *   *   *    ***   *   *  *             **** if(s==1)
*** * **   **  * *  *     **** *** ****      *  *** *    ** *** *  * * * * * ** ** *****   * 
* **   ** * ** * **       * *** **** * *   *  * *** ****  *  if(s==2)
 *  * * ***** * *  **   **   *    ** *  *   **** *** **  * *  *   *  **    ****** * **** **
****     *   *     *  **  ***   *** **   *  ** *****     
 * * ** **  * *** * **   * **********  ** **  *  * * *  * * *     ****  **** *  ** *    * 
    }
 ***  *  ***   *   **  **   0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *****   * * *      

int main()
{
int M,D,S;

* ***  * ** *   **** *   ******* *  
 *   *   ****
 *  *
{
    *  *  *  *  * **  * *
}
 **   *  
{
**  **   *  **  *****   *** 
}
* ** *
{
****    ******     
}
**    ** * ****      * ***

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.47
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 868 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 814 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 841 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 753 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 684 views
12,783 questions
183,443 answers
172,219 comments
4,824 users