期末考題目-Question 3

1 like 0 dislike
2k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 2k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
* *****  *       * *  **   ***  ***  * * **** ***   ****  * ** **
  * ****  **** * *   **  *** 
**  ***   * *** ***  *    *  
*   *** *  *  ** **   **  **** * ***  ** ****
 ** * * **** *  ****** ** * 
 * *   ***     * * ** **  ***   *  * * *    * 
 ** * **** *****   **  **
 * * *  *           **  ***     ** *  * ***  ***   

   * **     *****  *    0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*  **      **** *** ****** *  ** **  ***** *   ***  **   *    *  * *** 
 *******  ** *  *** *  * *     * ** *
***** *  * * *  * * **     ***   
    **  **  **  **  * * *    *   *       * ***   * ***   **** *   **  *******
 ** **   *  *   ***  *** *** if(s==1)
  *    *   **   *** **  *** **** *  *   *  **    *** *** * **  *** * **  * ***   *
  * **  * * **  * *****  * * *  * *   if(s==2)
 ** * * ** **      * **     ****   **** * **  * *   *  *  *** **    * 
*****   *  *  * **  **   ****** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * *    *    ***    ** *  *  M,D,S;
    
   *  **  **** ** * **  **  ** *** *  * %d",&M,&D);
    
 * *** * * ***  ***  *  *** * *   * *
 ***  ** **   *   ******         
***      *** **** *          * **
  *** **  * * **     * ** * * 
*   ** * *  **  * ***  ****** *   **    ***** * ** ** * *   * *      ** *** ** **   *
  *   *     *  **** ****
   *      *  * ** ** *      *   if(S==1)
* * *  *****    * ******  ** 
* ** ** *  ** ***   * ** * * *  *    ** * *    ***** ** ***** * * *  **  *** * **** * * *      *
** ***** ***   * ** ****  **** 
     **  *       * *  *** ** ***  if(S==2)
 **  *  * ***** *   *  *
 * * **        *  * *  *  * *  ** **  *    **  * **     ****  *****  
*** ** * ***  ********* *    * ** 
**  *** *   **  ****  * * **** 0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* *  *   * ** * *   ** ****   *** * m,d,s;
*     * * ** **      ***  *   **  
* *  *  ***   *   *** * *** *  * **  *** * %d",&m,&d);
    
 ***     * *  * ***    + d)%3;
*** ***  ******  * *  **  *** 
*** *  ****  * * *  ** *   *  **
*  ** *   ***  ** *** ** *
*   * ***** *** ** * * ****** *        **  *** **** *** **    * * ***
*** ***   *  *  * *   *  ***  *
****** * ******  *** *  *  ** **** **** if(s==1)
  **  * **     **  **  * **
 * * **    ** * * * ***** * *  **  ******    * ****  * *    * *  *** * *** *    
 *  * * **** *   * ***    *******
 * ***** * * *  **** ****** ***  if(s==2)
* ** *  ***     ****  *  *   *
  *******    *** **  *** * **   ** * * ** * ****   *****  * **    **     * **   **     
*   ********* *  **** 
*  *   * **  *  **  * *   *** * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ** * * *******   ****
int main()
{
int M,D,S;
  ** * *    **** * ******   *** *
scanf("%d  * *  ** * * ****  * **   *
S=(M*2+D)%3;
if(S==0)
** * * *  *** * * * ** *  *      *** *      ** 
      ** ****    ** **  ****  if(S==1)
*      ***** * *** * *   ** *      * **      **   ** ** **  
* * **  ** * *  *  *  *  * *    ****  **  *   * *  
** * ** ** *     ** *   * *   *   * * *  ****  **  ** *  ** *  * **** *          * * *     ***    ** ** 



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*******  ***** *    *  **** * m,d,s;
 ** **** ***** ***     ***    *** * * **    *** * * **   **   * 
*** * * * * ******* *** * = (m*2+d)%3;
   * * *** *     *   * *  (s == 0)
  ** **   * **** *   * *   *  *    ******* * *** *****
  **   ***   **   *  ***     if (s == 1)
 ****  ** **** **** *       * *  * *   * *   
*****   *** ****  * *  *           if (s == 2)
****** *   *  ***   **   *** * * ****    * *  **   
  ** ****    * * *** *** 
 *  *** * **  **  *  ******   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  * * ***      ** ***** * ** M,D,S;
* **** ***  *  ***** ****     ***  **  * %d",&M,&D);
  *  ** ***   *  ***** ** * * *  
 **** *   * * *  ********  ***  * 
** *** *   *   ** **    *  * * ***  *** *   *  *  *
**      *********    ***     ** 
 *  *  *   **  *  ****  * *  ***  **** * ***** *  * **
  *    *  **   ** *  **   **
*     **** * ** ** *   **  * **      ***     
 ** *    *    ** *** *          0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
*    **    *  *  ****    m,d,s;
* * **   *****  * *** *** ***  *** * *   *   ***** **        * 
*   * **        * ****** = (m*2+d)%3;
**** ***        *** **  *    *  (s == 0)
 *   ***** **   *      * ** **  **  ** * ****  
 *  ****    ***  * **  ****  if (s == 1)
    * *    ** **  *   * * ** * *  *******  ** *   
** *****  * * * ***  ** *     * if (s == 2)
  **  **     **   **   * * *      *    **  * *   * *
* * ***   *  ****    *  ** * * * 
 * *  *     * ** *** *   *** *  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
 *   * *    * ***  ********* * ** *  %d",&m,&d)!=EOF)
    {
   **   *     ****    * *   *  ** *  *   * * *      *    ***  
* ** *   *** ******** *    *   *    ** **   ** * * * *  * *****
***  *    **  * * *  **   * * **  * ** * ****   ** * **   * ** ******* **** **    * *   ****    *  **** *  
**  *  * ****   **  *    **      *    *  **   *** ****** *  if(s==1)
***** * *  ******* ***** *** ****   * ** *    **  *  * *  *** **** *  * ** **  ** *   ****   *   * *      ***  ***
* *     *    *** *  *  ****  *   ** * ** *******  *  * ** if(s==2)
* *  * *  **** *    * * ** *   ** **** * *  *  *   **  ***    *  * *** *** **  *  ** **  * **  *  
****  * * **  *  ** * * *** *** *  ** *  * *** **   *  
***  * ** **    *   ******* ***     ***   ** **   *  **    ** *  ****  *** ***  *  
    }
 * *    * **   *  * * * *****   *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***        *** 

int main()
{
int M,D,S;

* * *** *** *    ***** **  **   *   ***  *
 ****   **
**     
{
 * *  *  ** *  *    *** *
}
*  ****
{
 **   *  **** *** *    *
}
 *     
{
  ***  * *  ***  * * 
}
    *  **    *  **  *  * **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.180
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 888 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 826 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 862 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 776 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 698 views
12,783 questions
183,443 answers
172,219 comments
4,824 users