期末考題目-Question 3

1 like 0 dislike
2k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 2k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
 ***       ***  *** **** **** *     * **** * * ***   * ***
*         *   *    *  ***
    ****   * *   *  *     ** 
 * **  ** * **  *  ** **** * *   ***   **   * 
* * *  **    **        **
***  *****  **   * ***** * * *   *  * ***
  **  *       * * *    ** 
 ***     *   *   *  ** **        ***  **   * *

** * * *  *** *   ****    0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
* **     **      * * * ** **   *  ***** *  *** ** *  **  **   
  * * *** *  ***    * * * * * *    **  
** * *   ** ******  **    *   *
*   *   * **  ** ****  *    * *   *******   ****        * *   *   ***   *
**   * *** ****   * * *** **** if(s==1)
   * ** **  *** *** *   ** ****  ** **   *  *  * * **  *    *****      
    *  ** **  * ****     if(s==2)
  *  * *  **  * *    * *   *** * * * *  * * ** * * * * **** **  * * *
 * *    **** **   * *  **    * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *     * *  ****   ***** *  M,D,S;
    
* * *  *    *****    * * *   ***  ** * * %d",&M,&D);
    
  **** ** **  *   **    * ** *** *
 **  *  * *  **   **  * 
* ** **  ** **** * *  ***   *** *  
* ** ******   *    * *  *  *
  * ** *     **     **** ********     *   * ***     ** **  * * *    ***  ** **
   *   *     ** * * 
* *  *   **** ****  * * ** if(S==1)
  * *   ****** ** *     *
 *** * *   ** *  **  ***  ***   *   **   *   **    *  *  * * ***     *  ***   *** *   *
 **  ****  ** * * **  ** * ***
**   **    **   *  *  *  ***  *  if(S==2)
 *** * *  * *  * *   * **
  ***** **  ****       **   **             *** **        ** **    *   *  *** * * ***
   *  ** *** **    * 
 * * **   ** *** *    **  * **  *    0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
* ***   * *  **** ******* m,d,s;
* * *    * * *** *******   * 
  * *  * * *   * *   **  **  **  **  *  %d",&m,&d);
    
  *   * *****  *** *  *   * *  *  + d)%3;
** *     **** **  *******   * **
   * *  *  ****    **  ** ** *  ******
*   * *  ***   * * *** *****
* *** *         *   * *    * *  * *******  ***  * * * * ****  *  
   *  ** *** **   ****   *
 * *  ** ** **    **   * * * * * * if(s==1)
  * ***  * **  * ***  * ***  ***
*   * ****     *  ** *   * ***  ** * * * **    *   * *   *   ** ** *  * ****  ***    *  **
****** *    *  *  *  *  *** *
  * *** * * ***      * **** ** if(s==2)
* * *** *** ***  **  * **
  ***   ** *   * * ****** *  ****** ***   *         **   *   *  * * **  * 
*****   *** * ***** ** * 
 *  * **  ***  ***     ***    * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**       *** * * * * 
int main()
{
int M,D,S;
* *** *  *  * **  *** *  **** **** *
scanf("%d *  *   ** * **** **** 
S=(M*2+D)%3;
if(S==0)
  ** *  *    * ** *  * ** ***  **  * *    * * 
*    **   *** **   **  **** *  * if(S==1)
 *    * **   ** **  *  * *  *     * ** *  ***   * * *  *   *  ***
*     *****     **** ** ** **  ***  *   ****   ** 
   *  * ** ***  * * *    ** ***   **  *  ** ****  *     *   **   * *   * *   *    ***** ****



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
**    ****  *  *    * *  ** **** m,d,s;
****   * * **      ***   *** ** ***   *   **  **  ***  *** * *** **   
*    * ** *  *  *  ** = (m*2+d)%3;
 *** ****  *  *    ***  **    (s == 0)
****** ** ** **  ** * ***    * **    **  *  * 
  * * ***  *   * * *** ** * if (s == 1)
**** **   * * *      * **   *    *** *  * ** *** **  *   * *** 
  ** ***  *  *** * ** **  ** if (s == 2)
  * ** *   ****  **  **   ***        ****  **  *       
 *     *  ****  ******* *    
  ** ** * ****  *  **       * ** 0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  * *   ** * * * ** ***  ** *     M,D,S;
** **  ***** *   * * *** *     ** %d",&M,&D);
 *******  * ***  * * ** * *******
*  *  *  **  **** ** *   ** ** ***** 
**  * * *    ** *    *    ***  * *        **   *
******* * * ***  * **** **   *** 
****    ** ********* **   * *    ****  * *   *  ***** *
 *       * *** ***  ** *     *   ** ***
  * ** *        *  ** ** ** ***** *** * * ***** * 
*****   * ** *  ***  * * * ***** 0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
  **        * *   ***  *** *  m,d,s;
*     ***      **** *  ** * ** *  **  **  *  * ***** **   * ***** *** 
*** ***      * **** *** *   *  = (m*2+d)%3;
* *  ***    *** ** *  * (s == 0)
 *  *** ** *****    **  ***** * *  * *    **** ****   * 
** *** **  * * ***  *    *** if (s == 1)
* *  *** **  **     **** ****   ** *    * ***
*  ** * **  **  ** *** * *   *** *  if (s == 2)
   ** * * *  *  ** *  * ** ***     **  **  *** 
* ** **** ***  *  ** *  *  
    **     ***  * ** *  **  0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
   * * * *   *   *  ** *** * *      ** *  ******  %d",&m,&d)!=EOF)
    {
 **   ** *** *   *** **     * * * *  * * **  ** * ******
        * *** ** **** *  **   * * **  *       **  *  **
 ** * *  *    *  ** *** **   *   * **  **  **      *  ** **  *  *  ******  ** **   *   **   *  **  **
  ** *  * **    * *  *     **   *****  **  * * *     *  * ***    if(s==1)
 ***  **  *****      ** *  * *  * *     **** ** ** ***      **     *   ************     *  * **   ** *    **   
  *** * * ** *       **** *   ** **  ********    * *   *   * if(s==2)
*** ** **  ** **  * * ** *  * * ** **  * ***  * ***  *    ***  *** ***   * *  **  *** ***    **  ***  **  
*  ******** *  ** * ** ** *   ** **  ** **   **    **** * * * *  * 
  **** * * *  ***   ** * ***  ***  **  *      ***  *** *** **** *  * ** **  * * **   *** ***
    }
*  * **** ***** ** *  * * ** **  *  0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *    *  *  ****** ** 

int main()
{
int M,D,S;

*  *   * **** * * ***  *   ** ** ** **  
* *    ***
  *** 
{
  ****  * * *** **  * 
}
***  
{
 * ***  * ****     *** 
}
** **  
{
* * **   ** * * * **  
}
 *  * *    ******   **   

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.198
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 888 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 826 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 862 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 776 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 698 views
12,783 questions
183,443 answers
172,219 comments
4,824 users