期末考題目-Question 3

1 like 0 dislike
19.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 19.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*  ****   *** *  **  *   * * * **  ** ** ** ****** * ** 
*    **  * *  **  ** ******** **
*  ***    **    ** *** **
***     * **  ***  * *  * ****** * ** *  *** *** 
**       ** *  *** * *  
 * **    * ******  *** ****   ** ***  ** ** **  ***
 *  ***    ** ** *** **  ** * 
 * * *      * *  *** *  * * **  *  *  ***  * **

*      * * **   ******   0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
 * *******   **  **** * * *** ****     *       *  ** *****  ** 
* *  *** ** **   * *   * ** *
   *  *   **   ****** **   *
* * ****   **  **   *   *** **  **   *   *   *    *    *      * ** *
*****     *  ******  * *  *** if(s==1)
* * **   ** *   ** *    ***      ** **    * * * * *****  ** *** *** 
*   **  *  ** ** **  ** if(s==2)
  * *** ** ***    *   * *  *  *   *  *  **  *    ** ** *  * **  * * 
**** *  * ***   * ***   *  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *   * * **     **   * ** **  M,D,S;
    
   *** **    * ** *  ***  * ***  * *  * %d",&M,&D);
    
  *** ***** **     **   *   *  *   
**   *   * **  ***** *** 
******   ** *   **** ***   * ****
***   ** ****     * **  *** 
      * ** * **  * **   *** ***   * * ***  * **  ***   **  *** ***     *   * *
* ****   * * ***  *  *
 ** ** **   **    **** * if(S==1)
 *  **   *** * *** ***** * **   
*** **** ***** ** ***  *   * ** *    ******  ***** * * *       *   *****   * ** *  * * 
  * **  * * *  * * ** *  * **
 *    * *  *  **     ******  **** if(S==2)
 *** ***  *   **     **
*  **    *** *  *  *           * * *   **** ***** * ****  **** *   * *** * *** ****
   ***   *      *    *    * *
 ***   *   *  **     * *****   0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 * ***** ** *** *  * ***  ** * m,d,s;
 ** * * * ** **  *     **  
***  * **   *   ** *****  *******  ****  * %d",&m,&d);
    
      **    *   *** ***  * *** + d)%3;
   * * * *** **   * * ** **   
  *  ** * ***  * *   * *** *  **
*** *** **  *  * **** **  * * 
 * ** *** *   * *   ** *  *       *  *    ***   ****** * **  *  ** 
*  *        **   *  *    *   
 * * ** * ** ** **  *  ** *** * if(s==1)
*  ** ***  *  ****    ** *  *
  ** * * ****  *  *      ** * * * * * * *    **     * * **** *** *    ** *    ***  **   ** 
 ** ****  **** * * * *  ****
*  * *** ** ***   *           if(s==2)
***** *****   **** **  *   * *  
 * *  *** * *  * *  * ** ***  **    *    *    **   * **     * **      **   *** *   
 **  ** ***  ** ****** ***   **
** **  * *  ***  *  * *  * 
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *  * *** **   *  * * 
int main()
{
int M,D,S;
 *   **** ** *** ** * **** ***     
scanf("%d *****  **** * **  
S=(M*2+D)%3;
if(S==0)
 **  * *  **    **** *    ********  ** ***
   **  ***    ** * *  * * ***** *** if(S==1)
   **     *  * * ** *  *     *  *  *    *  * **  ** *** *  * *  
 ***  *  * *****  ** *  * *****  **** * *       
*   * * *   ***    * **   *  **      **     * ** *   * * *   * ***      *  **  **   *   * * ***  



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
 *** *  * *   *   * * ** *  ** m,d,s;
**  ** * ****** *  **  * *   * * * ***  * *     ***  *  **    ** **  *
 ***  *  ** *  **** ****    = (m*2+d)%3;
****    * ****  ** *** * ** (s == 0)
**  ** *  **  ** **** * *     **   **   ** ***  **** **
**** *** * *****  * * *****      if (s == 1)
*  *  **   **** *** *  * * * *  ***  *  * **  **** ***
 * *****   * *  *  *****   if (s == 2)
 ****** *  **   *  *  ** *     ***  **  * ***  * ****
  *     * *   * **  * *
  **  * *    * * *** * ** *** *   0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
  **  * *** *** * *    *  M,D,S;
***  ****  ** * *   *   **** *  ** ** %d",&M,&D);
** ***   *  ** ***  **   ***    
* **  *  *      *** *   ** ****  ** 
 *  ******   ***  ****  *** ***      ****  **   
 **  *   *   * * * * *** *   
* * **  ****    ***   **    * ** *      * ***  *   **
** * ** **       ** ** * *
      * *  * *    *  * *     ******   *   * **   *   
****   *  ***  *  *    ** **    0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
     * **  **  ***     ** **  m,d,s;
*  *       *    * *** ** **   ******    * ***  ************ **  ** ** 
 * * ******  *   * * * * *  * = (m*2+d)%3;
  ** ***  **     **    *   ** (s == 0)
 ****   **     ** *****   *     ** * * ** *    **
  *   * *     ***** * *   ***  if (s == 1)
  * * * *      ** *     * ****   ***   ** ****  *      
  *  *     * *  **   * *   if (s == 2)
 * *       **  ** **   * *** ***   ** ** *   * **
* * *   *   * * **** **  *  
  *  * *  * ** *    *  ** * * * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
* *   ******* *  ******    *    *      *    %d",&m,&d)!=EOF)
    {
*   ****   **   *****  * *   *** *  *  * ** **    **** ***** *  *
   *****  * * ***     * ** * ** * **** * * *** * *  * ** 
 ** **   * ***** *  *  **  *   ***  *    ***  * *****  *   * * *  **  *   *  **   ** ****** **   ****    
*    ** * *    *  * *** ** ****   ** ******* **  * *   *** ** if(s==1)
 *  ** *** ** ***** * *  **  ****** *   **  ** * ***      **   *  **  *    **    * *** ****  ** 
* *    *     **** *       * ***       * ** * * ** *    *  if(s==2)
 *   **** *** *  * **  * *** ** *    * *     **   * **** *  * *  *  **  ****  ***  ***  * ** *  * 
* *   **  *    ** ***        *** ** ** *   ****   **  * 
*  * *  *    *   *     ** ***     ** *  *    *     ***  ** ****  ****  ***  * **  
    }
* ** * * *  *****  * * **   * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*****  *  ******** *

int main()
{
int M,D,S;

 ** * ** ***  **  * *    *    ***
*        
***   
{
  * *** *** ******    ** *  *
}
  *  *
{
**** *** **** * ***** * *
}
* *  * *
{
** *   ** **** ***    * 
}
* ***** **   **    ** **

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 5.1k views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.7k views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 7k views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.9k views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 4.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users