期末考題目-Question 3

1 like 0 dislike
2.1k views

(20%)由於經濟不景氣，張三決定改行當個占卜師。但張三對於占卜術還不太上手，非常苦惱。請幫他設計一個程式如下:

請輸入一個日期，然後依照下面的公式：

M=月
D=日
S=(M*2+D)%3

得到 S 的值，再依照 S 的值從 0 到 2 分別給與 小吉(small)、中吉(medium)、大吉(big) 等三種不同的運勢。

input:

1 1

output:

small

 

[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 43449 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30
edited by | 2.1k views

21 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
   int M,D,S;
*     * *****    *** ** ***  *  ** * ** *  ** ** ***      
*   * **   ** ** **  ** *
*  ******       * ***   
**   **     *     **  * *   ***   *   **  ***
*   ** **  *   ** * ****  
 ***  * ***   **  *   * **  *** **  * *******
* * *  **   *  * * * * 
****    *  * ** *  *    *** *  *  *  ** **   ***

 **     *  *    ** * *      0;

}
answered by (162 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m, d, s;
*    ** **    *** ** *  ****  ** **  ***  * *** * ***   ****   
 * *   * *   **  * ******  * *  *   *
 *  * ******  **  *  * *
* ** * * **  * * * ** * ****  ******  *  **** * * *   ***  * *    ** **  *  
  * **    * *      *** *  *   if(s==1)
 *       **** *  * **        *        ***    *  *       *** *   *  **  *
  ** **   * *    ***    *  ** if(s==2)
    *   ** * *** **  **  ***   ** ***  *** ***    ***    *   *  *** ** * *
** **   **     *   * * ** ***  0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89",s);
               ^~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xb0\x8f\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe4\xb8\xad\xe5\x90\x89\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("\xe5\xa4\xa7\xe5\x90\x89\n",s);
               ^~~~~~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("small\n",s);
               ^~~~~~~~~
prog.c:10:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("medium\n",s);
               ^~~~~~~~~~
prog.c:12:15: warning: too many arguments for format [-Wformat-extra-args]
        printf("big\n",s);
               ^~~~~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
***** ** * *  *  *      *  ***  * M,D,S;
    
      * ** ** **  * * * *** *   * ****  %d",&M,&D);
    
** ***    ***   *** *  * ** * ***   *
   *** **   **  **  **   * *** 
* *   ***   *****    **   **   **
* *  *  * *  * * **** ** *
   * *  * * ******** *******  **** *  * ** *    *   * ***         * ** ****  ** * * ****
 *** **   *  **   **** ***  * 
  *  ****** *****    **   ***** if(S==1)
** *** **  *  ***       **
 *  ** *   ***    * ** ** * ***        * * ****** *    *  ****      **   *    * *** **
 ********  **  * * *  **    ****
*     ***   * * **   *****   if(S==2)
  **** ** *  ***   * *  
* ** * *  ** * ** *     *  * * **   * * * * ********* ** **   ** **   * *   ** 
*** ** * *    *   **  *  *** *
*** **  *  *** * *   **********  0;
}
answered by (215 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main()
{
 * *** ****** ** *   *** ******  m,d,s;
 **  ***     *  *** * ** 
*  **   *       ** **** * ** ***  *** *  %d",&m,&d);
    
* ** * * *   **       *   * *  **   + d)%3;
*** *** *****   ***   ** *******
    *   **    * * * ****  * *  
 ** ******  ***  ** *****  
*  * **** *   * ** *   **** ** *  *  ****  ****** * * ** **  
   ***   **** **    **  **   **
*    ** **  *** * *    ** *  if(s==1)
*  * *  **     **    * **** *  
  *   *** ** *      * **  **  ****  * *** ** ******   *  **  **     ***   * ** * ** *** *  
*   * ****  *    *   ****   
* *** * ** *     ** **  *  if(s==2)
  ****       ** *****  *
    * ***** **  * ******** **    ** *  *** *   *  **       *   ** *****   *   * *
 ** * **** **** *****  **** *
** *  *  *     *    ** ***
return 0;
}
answered by (185 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *   **       *********
int main()
{
int M,D,S;
** * * ***** **  **  * *      *** 
scanf("%d   **    * *** **      
S=(M*2+D)%3;
if(S==0)
 ***  *  * *  *** *   *   **   * **    **    
* *     * ** ***  *  ***  ***** ** if(S==1)
* ** *    *  ***    *  ** * ** * * *  *****  *** *    ***     **
  ***  * *** * *** * *   **** ** ***** * **   ***   ***** 
 * * **   * * ** ******    *** *   * **    ** * ****    * **  **** *     *  *****  * *  *    * *    *   *



return 0;
}
answered by (236 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
** *   * *  *   *******   *** m,d,s;
*  ** **   *  ** ** ** **  *****   * *  * *    *   ***      * ** *
 **  *   *   ** ** * * * *  = (m*2+d)%3;
***   *  * * *  ** ** *  ****  (s == 0)
****  ** *    ** ** * ** ***** * **  * ***    * *
****   **   *      ***   *   *  if (s == 1)
* *   **   * ** ***     *   *  *  *   *** *   *  *****   * *
*** *    *   * **  ****  * if (s == 2)
  * * ** *   *   ** *   *** *****   ***  *  *     
* * *  **  *  * * * ** ** *
 ** **  *****    * * *  **  0;
}
answered by (190 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
**  ** *  **   ** *****     ***  M,D,S;
***  * *   *  **    *      * * ******  ** **  %d",&M,&D);
**  ** * *  ** ***   ** * * **    ***  
* * *  ********  * ***  ** ** 
*   **      **      * * ** *  * * **  *   **  * **  * 
* *   *** *  ** ***    ******** 
 * ***  ***  * *   ***  ***  *  *  ** * ** *   * *** 
       **** * ***    ** *       *
* *** *** *** * ** * *  *   *  *   * **   * **  * 
 ** **  ***  *** *  *    **  *   **  0;
}
answered by (228 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main ()
{
* ***     ***     * **  **  ** m,d,s;
* ** ** * *  **  **  ***  ** * *    * *  ** ** ** **   **  ***** 
***** **  ** **  **  *  *   = (m*2+d)%3;
* * *  * **  *** ***    * * * (s == 0)
** *   ***    **** * * *     ** ** *   *   * *   **
   * *** ****     * * * *    *   if (s == 1)
* ** * *** *  *****  *  *   * ** **** * *  ** *    *   *
*  ***   * *       ***  * if (s == 2)
*  **     * * *  **    *****    ***  ***    ** *    
**   ** * ***      **   **  
***    * * *** * *  *  *    *  * 0;
}
answered by (209 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int m,d,s;
*     * * *   ** ****   * *  *****  *   *   * * %d",&m,&d)!=EOF)
    {
  * **  **** **  ****  * *  * *  * * * *   **  * * *  **********
     **   **  **         *    ****  ** **  *  * *   ****   
 ** ** *** * *   * ****** ** *    * **   ** ***  * ** *  **   ** *** **  * ***   ** *** * * *
  *     ***    *  *  ** ** *    **      *** **  *    ** * ** if(s==1)
 * *  ***         ** *  **** **  *** ** *  *  * * ***    **** * ***** ** ** ** ** * * *    *   ***** **
***   *** **   ***** **    * *** ** *** * ** * * * * ** if(s==2)
 *  **  *  * *      *    *  **** * * ****** ** **  *   **     * *  *    *  * **** *    **  ** **    *
*   ***** *  * *   *   * *  ***  ** ** *  *     ****  *  * 
* *   ****** *        **    *** ** *   * ***  ***     *** **  **   *   *  * **  
    }
*    *  **  *  ** * *  * *  * 0;
}
answered by (100 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:19: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                   ^
prog.c:5:22: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'int' [-Wformat=]
     while(scanf("%d %d",m,d)!=EOF)
                      ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  **** *   *     * 

int main()
{
int M,D,S;

** *  *    *  **   * ****** ** *  * *** *
 *  ****
   **  
{
  * * *         ** *  
}
   ** *
{
 * ** *****   *****   *  
}
** * *
{
**** ****  *  *     **** 
}
*** ****   *   * * * ** *

}
answered by (174 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.233
©2016-2024

Related questions

1 like 0 dislike
24 answers
期末考題目-Question 10
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43456 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 888 views
1 like 0 dislike
24 answers
期末考題目-Question 9
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43455 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 826 views
1 like 0 dislike
24 answers
期末考題目-Question 8
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43454 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 862 views
2 like 0 dislike
24 answers
期末考題目-Question 7
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43453 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 776 views
1 like 0 dislike
23 answers
期末考題目-Question 6
[Exam] asked Jan 19, 2018 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 43452 - Available when: 2018-01-19 18:30 - Due to: 2018-01-19 21:30 | 698 views
12,783 questions
183,443 answers
172,219 comments
4,824 users