1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
** *** **** *    * *     
*    **** *     * *  ***   **   * ** *****  *  *** *   
    {
***   ** * ** * **  ****   * *** ** ****              *  (i=0; i<=strlen(string2)-1;i++)
     *** **      **** *  *  * * *** ****  **** 
 *********** * *    ** ** * *****  ***  *** **        *       * ** ** ***   * * **** (string2[i]==string1[i])
**  *    * **  * ** *  * *  * *       * *  *   * *** **   *   ** *** *****  *    
**  *    ** ** * ** **    ** **     **  * * * *** ** * **   *    * * *      * ** **  ** * ***   *** * ** ***** *
 *  * ***** **  **    * *  * *  *  ** ***  *       **   ** ** * *      **** * *  
 *  *  * ** *   ********   * *  * *  **  *   *****  
       **   **** *  *    ****** * *** *  * * * ***  * ***
     ***  **   *  ** * ***  *****    ****  * **    * *  **
*** ** *****     ** ****      ***  * *  *  **  *  * *****    *    * **    * **       *    is a prefix of %s", string2, string1);
 * *  *  * * **    *** *  * *  * ** * **   ***   
*   ** ** ******  *     **** *** **  ***  *   **** 
     * * * * ****     **  *  * ** **  **  * * ***   
** **  ***  * *     *  ** *   * ** **** **** *  **     **  ****  **   *********    *  *  is not a prefix of %s", string2, string1);
  *  **  ****   **  *   *  * **        **** *  * * ***
    }
**     * *  **   *   ** *  **       *** *  **** * *   **  
    {
**  *   **  *  * ** * **** *** *   * ** ********  *  ***  **   (i=0; i<=strlen(string1)-1;i++)
 *   *  ***  ** ***  **  **  *  **    *   ** * * *   
     ***  *** * * ***       **  *  ** * * *       **  **       ** * *   *  *  ** ** (string2[i]==string1[i])
 ***  ** *       * **  **  ** *  **** *   ** ***  * *** * * *     *** *  ** ***  **** 
 **    * **   **   * *  ** **   *  ** *   ** *  ** * *   ******* ** *** * **  * ****** * * **  ** *   ***   ****  
 * *   ** ** *  * * *   * * **  *   ** ***  ** *     **** **  *  ***  ** *  ** * * 
**** ***  **    * **   ***** *    *    * * * ***   ***** * *
  *    * ** ******  * *      **   *    **** **** *     ** *  
*  * ***  *  **  **  * *  **  ***** *  **** *  *  ***** *
*****    ****  **   **  *  *  ***** * *   * *   ***   *      ***        * **   ***  *   ** is a prefix of %s", string1, string2);
  ** * *** *** *  ** *** *****   **  **  **** * * 
   * * **   *   *** *     *   *** ***  * ** * 
**  **** ***  * *   *   **   *  * ***   *   ** *   * **** 
*  **   *** **  **  **  * ***  **  **     ***  *** * *** ***** * *   *    * *  * **       * **    is not a prefix of %s", string1, string2);
  *  *   *** *  *      ****** **       * *** **** *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *  *   **  *  *  *  *  ** *  *  *** ****  * %s", chaine1,chaine2);
*** * *    *** * * * *  *** ** **  ** * ** *
***  * ****** * *   * *** * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**       ** * **   *      ***** * lenght1,lenght2,c;
* * ***** * ** ***    * * * ** b[100];
  **  *****   *****    *  **  * ** a[100];
*  ** * ** *** **   * ***   ***  *   d[100];
* ** ***** ******** ** **  ** **    * *   * * ** **    
  ***    * * **  ** * * **** *  * ** **** *      
* **** ***** * **  **** *  *  *   **  *
   *  **** ** *   * ***     * **  *    * 
 *** *** * *  *   * *** * *  **  **   
*** ****  * *******   *  
 **  *  * **  * * *    * *   ** *** *  * *     * * * is a prefix of %s",a,b);
* ** ** *** * * ** ****   
** ** *   ***     ** *   *** **
* ***   *** *  **  ** *  * **
 *   **** * *    ** ****    *** ** **********   *  ** **   *  **  * is not a prefix of %s",a,b);
* *    * ** *  ***  * ** **
    *  * * **  * *   * * ** **** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *    *  ** ** **
#include  *****  *  *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* **  * *         i;
***** *    * *    *     * *
  {
 *   *  *     ** *   ** *****   ** * *   *   A[i]!='\0' && A[i]!=B[i]   )
*** ** * ** ** ***         *    ** ** * ** ****** ***  *  ** *    0;
** * *  * * * ****   *  *  * *** * * * *   * ** **   
* ***    *  *** ** **** * * *      ******   ** ****   * * *  **  ** * * *    
  }
******  *   **   *  1;
}


int main()
{
** ** **   **********  *** ** a[n],b[n],c[n];
 ****      ***** **    ** i;
* ***** *** * * **** ** * *    *  *   **   * ** * 
 **   * *   * * **    ***  **  *  *  *****  * *
**   *  ****** **  ****** * *** (aa(a,b)){
*   *   ** ***  *   *   **  *****  * * *** * **  * **          ***   * 
 **  *  *     * ***** *  **     **    * ****  **   * ** ****  *   *** * * **  * **   **  
*** *    *    * *** *  * ***   *  * * * **    ** * * *  * * *  ****   ** *  * **   *  *   * * *  ****  ***     
* **    ***     *** *** * *  *** * *    * * *  ***   ******   ** * ****    * * * *  *

  * *** *   ** *   * *   ******* * * *  * *** **
  * *   ** *  **** ** **   **** *  *  **  *  * * **  * * ***  **** *   is a prefix of %s",c,b);
 * **  ** ****  ****** *  *
 *** *   **  **** *** * ** *  * *
   **    ** ** *   **        *  ** * ****** ***          ** * is not a prefix of %s",a,b);
* **      ***  *****   * *   ***   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * *   **  *
   **  *  *** *****  * * 
int main (){
char   *** * 
char   *** *** 
* * *  *   *   string1: ****** **
* **   * **  *     ****     *  ** * **
    ***  **  * string2: *  ****
* **   * ** ** * ** *  * ** * *
* ** ***   *******  
  *  **  *  ***** *  ** ***  ***  *   ******  is * *   ****  of     ** *  ** ** *  
else
*  * ****    **  ******* ** *   * ***  ***  is not prefix of * ***** *** ****  ** *  

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *     * *   
#include  ***** ****   * *
#include * ** ** **  * *  *
#include ** *    *** *
int prefix(char p[],char s[])
{
* ***  ***  **  * *** *** *   *   ****
*  *  * **  *    *  *  **   *** 0;
* ** *** * *     * * ***  if       ** *   *   *
     **  *  * * ****  * ** * ** 1;
 *** * ***    ***  * **
  ***  * ******** ****** *** 0;
}

int main()
{
**  *   * ** ****  * * ** p[999],s[999];
* *    ***   *   **  *** *****  ***   * ***  
******** * *         **    *     ***  *

** ** * *         * ***  **  **   **
**         *** ** * * **    * *** *** **** is a prefix of %s",p,s);
       * *    *  **   *
 *  * * ***    **** **  ****   *   is not a prefix of    ****   **

*** *  *  **    **** **     0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  ** **   **
int main()
{
 *  **   ** * *      *   length1,length2,c;
* *   * *    **  ** *   **   a[100];
***  *   * *   ** *  *****  ** b[100];
 **   *** *     **** *  *     d[100];
    * *** *** *** * **   *   * *     *****   *
*   **  *  * *    ** ** ** *  ***** *** *   *
** *** ****    *******   * *  **  ****  
 **    *  *  *     * ** ***** * **   * ** *
if (strcmp(a,d)==0)
      * *** *  * *  *   **
*  *    *   **  *  ** ***  ** *  ** * *  ***  *  *    *  ****   is a prefix of %s",a,b);
 *   *  **  *  ****** * **
*   *   * *   *  **** *  ******
   *  **       ***** **** *
 **    * *** ** *    ** *      ****  *    * * *** * **  ** *      is not a prefix of %s",a,b);
** ** * * ***   * * **    *  
** * *  * ******* 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ****    *****
#include    ** *   *  

int prefix (char  ***   str2[])
{
**     *  *  ** *     * *  length=0,  ***   
* ***   *   * *  * * *
*** **       **********  *** * =   * * **** **
**  **  ** **  *****    **   
  * *****  *  * *** ****  * ** *** * ** *** * 
*       ** ***  * *   *  *** *  * * *  * **  * 
  * ** **       **** **  *    **** if  *  * *  * **
  **      *   ** ***                 ** *  *** *  * ***   
   * *  **   * * *** * ** ** *   * *   }
 ****   *         *   *     ** ****   
   **   **  ** *  *  (count == length)
**  *   * ****  *** *    *   * * *  * ** 1;
*** **  *     * *   ***  *   else **  ** *   *  * 0; ** * * * **  ***  
  * **   * ***           * **** 
}
int main(void)
{
  ** * *  **  * ** * **    *   *** **  ** * *
  ****** * ***   **    * 
   ***  *  *   * *  *   * * *  *   *  ***   **  ** *   str1, str2);

  **  **** **** * *** *** *  **   ** *   
*  ***  *  *   {
*** * **   *** *    *****     * ****  **    *  *** ****      * * * is a prefix of ** * * *  str1, str2);
  **   * *  * **  *  * **  
*  *   **  **  * *   ** * * *
 **  *       * *   **   * * * *  * ** * **     *** * * **** **  * * *** * is not a prefix of *  *** str1, str2);

     *** **  * * ****** ** *  *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * ****    * 
#include  * **    *  *  *
#include * ** **  **

int main()
{
  *     * ** ** * ***  ** prefix[100];
** *  **   ****  * *****      word[100];
* ****  * *      ***    ***  * ** *** %s", prefix, word);
*  * * ***    * *  * **** *  i;
 **  ***  **   *     ***  ** * = 0; i< strlen(prefix); ++i)
 ***  *        * * **  ***  
**  * **** * * *  * ** *  ** *    ** ****   * ** **    ***  ** *  *
* ****** *****   *      * ** * *       *  * * *  *
*  **   *****      ** *  ****  *** ** **   *   *** **   * *  *  * ***** *   ** *** * *** ** ** is not a prefix of %s", prefix, word);
*** *******  *  * * *  *  * * *      *  * *  ***  * * *  **   * ** *   * *****   0;
  *  *   * ** * **  ** *  **  * ***  ****  *   *
 * *   ******* ******  ** **
****** **     ** ***  ***** **** **   is a prefix of %s", prefix, word);
 *** ***   * ****      *** ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *   * **** *
#include  *    *  ** ** * 
#include *  **  ***  * ****

int main()
{
***** * ** ** *  **    * **** * prefix[100];
      ***     ** **    **** word[100];
  * ** *     *** ***  **      ******* %s", prefix, word);
* ** *   *  ** *  **** * *** ** i;
*  **** * *    ** * ****     * ** = 0; i< strlen(prefix); ++i)
  ***    ****  * *   ** *** **
*** * *  ** *    * * ** * * * **** ** * ******  **      ** * ***  * 
 ** ***  ***  * *     ** ** **** *      ** *  *  ***** 
* * *   *  *     * ***    *    * *   *  *   * **** *  *****  **   * ****   * **   ** *   is not a prefix of %s", prefix, word);
 *   ***  *****  **       *  *  ****   ** ****   ** *  * *  *** **  ***** * ****  *** ** * ******  0;
   * * **** **   *        *  ** *****  * **  ***   ** *
*** * *   **  **  *   **** *** **
   ***   *  **         * **  * *** ***  is a prefix of %s", prefix, word);
*   ****  * **   ** * **   *  *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** *    **    ** *
* * *   * *** *   *** *
 * * ** * ***   **        * 

int main()
{
   * *  ****** * char ***  * *
****        ****  char **  *
  **  *   **  * ****  *****   *** *   ****  word);
  ***** * *   * *  int i;
* *  *  ** * **  for(i = 0;   * ***  ** * *   ++i)
**  *      {
    * ** *   *  * *   * * ****   * ******  * * *
* * *  * ** *** * **    *  ** {
**   *       *  ** *  * ** *     *         **  ** *     *  is not a *  * of *  ****       word);
 *   * *****  * ***   ** * * *** * *** * *****  0;
**     *  * ** *****  *** **  }
*  *    *   ** **  }
 ** ** *  **     ***    ***  is a prefix of  *   * ** ** word);
*  *  **       **   ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.139
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.5k views
12,783 questions
183,443 answers
172,219 comments
4,824 users