1-11 Exercise 3: Prefix of a string

0 like 0 dislike
1.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 1.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*****   ***   **   *** *  ******
   *****   *   *   *  * ***  *   *   * ***  *** * * *** **
    {
 *** *    *       *    **** **    *** *** **      ** * * *  (i=0; i<=strlen(string2)-1;i++)
 *  ****    *   *** ** **       **  * *   ***  * 
  *  *  ****  *  * * *   *     *   ** **  ****** *   **      *    *  * ****  * (string2[i]==string1[i])
    *** ***     *   *   *  * **   **** * *** ***** ** ***    * * **  *  *** * ** 
 ****** * **   * * * *  ***   ** * * * * **    ****   * ******** * *  ** **** **  **   ** *   * ** ***********
***  ***    *  ******  **  *  **** ****** ***    *   ** * *  *  **   * ****    
* * **  ** *   * **    ** * **     *  * * * *  *****  *  **
* **** *     *   *      * **  * * **   *  * * ** *  * *  
   *  *  *  **   *** ** *** ***    **** * * ** ** * *  
   **    ****    * ** *   *** ** * *  * **  **  * ***  *** ** **** * * ***  * * *    **** *** * is a prefix of %s", string2, string1);
**  *   ****  * ****** *  ***      * * **    * ****  
*   ** * **     **** ** ** **  **** **  *  *   * *** * *
 * * *  ***** *  *   * *  **** **** * *   ** *  **  
***   ** * **  *****   *   **  *    * ***** *   *** * **  ***  **  * *  *** *   *  **  * **  *** * is not a prefix of %s", string2, string1);
 *    *   ***  *****      * *   **** * * *  ** ** 
    }
**   *    **** * * * ****    * *  *      *   *** * ****
    {
 **** *   **     * *     **** * **** *** ** ***     **     **** (i=0; i<=strlen(string1)-1;i++)
   * ****  * * * * *   *** ** * * *      ***    **   * * *  
****  * **  *  * ****  * * ** *   *      ** ***  **  * *  *** ** *  *  **** (string2[i]==string1[i])
** ** *  * ***   *** ** *  *  * ****  *****      *   **   ** ** *  *     **  **  * 
  **   *  **  ***    *  ** *** *    **  ******* *      * ** *   * *  **   *** ****     *   * *  *  * ** *
* ***   ** **    * ***   *  **   **** *  * ***       *  *   * *   *  ** *   *  *
** ** * *     ** *   **   *  * ****     * * * *** * *** 
** * **   * * **** **  ***  * ***  ***    *  **   *** *     *
 ** *****  *     * * * *   ****    * * ** *    * ***    
** ** * * * ***** * *    * *  *** * *** *  ***** **** *  **  * * *  *  **  ** * *** *  *** is a prefix of %s", string1, string2);
**  ***    ** ***  ******  *  **  ***  ****  ** *  ** *
***   *  *   * *  ******* **   ***  ****  *    * ***  
 **    *** *** * ***   * *  * ***    ** *  ** *** ***  ***  
 ****   **     ******** *** * *  *****        * *  **** *** * **  **  *** *   ******   ****  is not a prefix of %s", string1, string2);
 *******    * * * **  ** *  **   *  *  * *** **   ****   *  
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 * **    *** *** ** ****** *  *  * ** *** %s", chaine1,chaine2);
  **      ** ** **  **   *****  
****    ****  *  **   *  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  **   ** **** * *   *  * *    lenght1,lenght2,c;
**  *    ******* **  *   * * b[100];
  *   *   * *   ** ***  **  ** a[100];
 *   * ** *   *  **** *  ***  **   d[100];
**    * ***** * **  **** * *** **  **   **   ***   
*  * *  ***   *    *  ***       *    **  *  *** ***
** *  *   * ***** * *   ** *** *     **   
  ** *  *     *** **  * * *****   ****
****  *   * *** * ****     * ** ** ** * 
***         * ****** * * * * *
*    *  ** * *  * *  ** ***      **** *** *  ** * **  * is a prefix of %s",a,b);
  * *    **  *      * * ** 
      * ** *  ** * **    *       *
 * **** ******  * ** * ******
 *   *** * * **  * ***** * *     *    *   ** **** * *** ***  *  *  *** is not a prefix of %s",a,b);
*   *** *  * **  ** ** 
 ** ** ******  *   * **   ******  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *****  * **     
#include  * *   ** * **  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
  * *****  *** **  i;
   ** ****   *   * *  ***  
  {
*    *  *   *   ** * ***  *   ** **  **   * ***     A[i]!='\0' && A[i]!=B[i]   )
  ****  **  *  *** *** **         * *   ****  *** *     *  *** ** *  *    ****  0;
*    ** ** * *****  *  *** ** ***   ***       *   
** *  *  ** **     *  *  *** * *   *  *      *  *    *  * *
  }
 **   * ******   1;
}


int main()
{
* * *******  *  ***     *   a[n],b[n],c[n];
 ** *   ***** ** *  ** *****    i;
 * *** *   **    ***  ***  ***   * * ***** ** *** 
* *  ******        ****  ** ***** *   *  ****  
* *** * * *   * *   ****       (aa(a,b)){
* *   *   **  * *   *           * *   **   *    **** *    **  *    *  
**   ****      ****  *   * *    *  * *        *  *  ***   ******* **  * *   * **   * ****   ****
  * * ***  **** ***   ***  ** ****  **   **  ***** *** ***  *   *  **  ***** * ** ***    ***   ****  ** * ** **      *  * ***** 
 * *   ** **   * * *** *     ****  **  ***  * ** *  *  ** * ****   *** **  **    *  *  **

** * *    ****    ** *  **    *    ***********  *    
     **   * *  * ****  ** *     **** * * *  ** *     *    *  * **  ** is a prefix of %s",c,b);
 * *   ***   *  ***   ** 
  *  *** * **** *  *** *  **
  * **     **   ** *   ** * *** * *  ** *****  * ***   * ***  * * *   is not a prefix of %s",a,b);
  *    *******  **  *   *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *******  **  ** 
 ***   ****  *****    *** 
int main (){
char * *   ***
char  * * ***
**** * * * *  string1:   * **  * 
****  *  * * **** *** * *   * *
***  *****    * *** string2: ** **  **
 *      **   * * ****      ****
** **** **** ***
        **     * ***   ********   ***  *  is ***** ** of  * * *  *** * *  
else
***  * **  ** **** *  ** * *  **  * * ** is not prefix of * **  * *    *  **   *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * *   * ** 
#include  * *   * * **  *
#include  **** **** *   *
#include * ****  ***  
int prefix(char p[],char s[])
{
  ***   * *        **    **** ****
* **  *   *   *     * ** ** *  * 0;
* ****  * *    * * if * *** ** *  *    *
* ****  *  * ** *    *  *  * * ** 1;
*  *** * ** **  ** * * 
* *    * *       **   *  *  * ** 0;
}

int main()
{
** * *** *     * *  * *** p[999],s[999];
   * ** ***** *  *****   * ** **   *  **
* * * * *   *  *   *   **  ** * ***     **

  *     * ***  ***    *    * * **
*     *   *   ****  *  *     *       **  is a prefix of %s",p,s);
** *  ** *** *****  **
*     * ** *** ** **  *****   *   * *   is not a prefix of * *** *** **

 * * ** *  *  ** * *** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ** * ***    
int main()
{
    ** *****  * *****    **  length1,length2,c;
 ******** *  * ***   **  * ** a[100];
*   ***** * ***** **  * **  *    * b[100];
** *    * ** *** *** *** *  d[100];
** *  *** *  *** * ******  *  *  ***** *** ****  ** 
* *   *  *** *  *****    * * * *    * *  *
***** **  * ** *  ** **  * *****    * *   *
*   ** * *  * *     ****  *   ** **         *
if (strcmp(a,d)==0)
* **   **  *  *   *  **  
*** ** * * **** *    *  *  **  ****** *  * ***** *  ** ** * * ** **     *  is a prefix of %s",a,b);
**** *    ** **  * ***** ***
**        *     ** ** *  ** 
 ** * **    * **   * ****
 * ***    *   ***  * *** ***          * * **    *  * ***  * **** * *  ** ***  is not a prefix of %s",a,b);
**  * **  *    *  *** **  ** *
 ** ** **  * * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  *  *  **
#include ** * * **  *** *

int prefix (char *  *      str2[])
{
*   ***   * * *****    * * *   * length=0,   * **
* * ***    * *** *
* *  *  ***** *** ***   ** * * = *    ****  * **
*** **    *   *  *  * * 
   ***      ***  *** * *  *  * * **  ***  *   * *
 *****      ** **  *** ** *   ***   * ***   *
** ****** **     **  *     ***  *  if    *  ** *  **
  *  ***    *   * *  ***        ***   * * *   *   * * * *  
   *  * ***** * *  *  ** * *  **    }
** * *  *         ** * **   **  **  * * 
* * **  **     * *    * ***  (count == length)
* ** *  ** *   * ***   *** *** *   ******** 1;
  *    **   * * ***** **   * else   *  ******  0; **** *   ***** *  * *****
   ***  **** **   **    **** * 
}
int main(void)
{
 * *    *****   **   **     **   *  **  **  **
** ***    *****  ** *** ** 
 *  *   *  *   * * *  *   *   * *  * ** ***** *****  *  str1, str2);

 * * ******  *        *** ** * **** *    
  *   *  ****  {
     *     **** * * ***  * *  * **    ****  * *     ** *  *     is a prefix of   **** ** str1, str2);
**   ******   *** *   ***  
  ****      *  **  *  ****  * 
  **  ** * **   **** * **** **  *   ***  **     * * ** * ** * * is not a prefix of ****  ***  str1, str2);

     ***     ********* *    *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ***  *  *    
#include * * * *** ****
#include     * * *****  **

int main()
{
***** * *** *    **    *  *   ** prefix[100];
* **  *   ** ******** ** **** word[100];
*  ** *  **    *** ***  *  **    *   %s", prefix, word);
 ****** * *  *    * *    i;
* * ******** *   *** *  *** *****  = 0; i< strlen(prefix); ++i)
 * **** ***  ** **   **  **    
 ***  * * * *****  **** *** *  ***   *    *   *** * * *** **  * 
**  *  * ** *  * *** *    * *  * *     *** ** **     *
*   **** * *    ** *** * * ** *  *** *  **   * *   ***** *** *** * *  ** ***   *  *** *    ** *  **** is not a prefix of %s", prefix, word);
* **  ***   * **        * **     * ** ** * *** * ****** *** ***   ** * *   *  0;
   **** **    *   **  * * *       * *****  * * *  *
  ******  * * ***** ** * *     *
** * ****  ** **  ***  * * ** *  * * *   * is a prefix of %s", prefix, word);
*** *   * * * *     * *          ** 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ***  ***   
#include * * *   *    ** **  
#include    **   ** *   *  *

int main()
{
    *    **  ** *    ***  * * ** * prefix[100];
 ****    *   ** *   **    ****   word[100];
  ***    **   ***** * ** **   * * **  %s", prefix, word);
   * *   *  **  * ** * * *   i;
*   ** *** *    * *    * **  = 0; i< strlen(prefix); ++i)
 ** *  * *******   *  ***    *
  *  *  * * *  ** ****  * ** ** *  ****** * * **  * *  * *   *  * ****
 *   **   * * * **  *  ***    ****** *   * ****   *    * 
* * * *      *  * * * *  * *  *  *** *   ** ** **       * * *  * ****  **   *  ****  *  *  is not a prefix of %s", prefix, word);
** ******* ** * **** *  * * ** * ** ** ** * ***** *  **    * *  *    **  * ****** *  *  0;
 * ** ** ***** *** *** * *   * ** * **  *  **      **
  **    *  ** * *   
* **   ** *  **   * * *** **    ** ** **  *  is a prefix of %s", prefix, word);
 ** *     * **  **    * **  * **   0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *      *  **    * * 
 ** *   *    * * **** 
** * * *  *  ** *****

int main()
{
   *    *  *   char *** **  **
*  ***    * ** char *    *  
 **      **   *  **** *  * *    * * *      *  *  word);
**   * * ** int i;
* * * *****    for(i = 0;        ***   * * ++i)
 * * * **   {
 **  * ******* * **** *  * *  *   *  ***  ** *
 **   ***  **  **    *      ** {
 * * *** * *  *    *     * ***       * *  **  **** *** is not a   * * of * ** * * ** *** word);
*  *    * *    * ** **     *    * *  *   **     *** 0;
**** * *   *       * *  **  }
***** * *** **  }
**** *   ***  * * **   ** is a prefix of * ****** ** ** word);
*** ***    ***   ** ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.21
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users