1-11 Exercise 3: Prefix of a string

0 like 0 dislike
11.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 11.3k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 **  ** * * *** *   * *  
 **** *** **   *******  ****      *** *     ** ****
    {
  * *  * * * **  *******   ***** **   *   ** ** ** ** **** ** *  (i=0; i<=strlen(string2)-1;i++)
 ** *    ** ***** * *** * * * * *** **   ****** *   *
         *  * * *  * *** ** ** * * * * * * **  *** * * * ****    ***       *  *   (string2[i]==string1[i])
* *     **** **  **      *  **  *   *** ***   *****  *  *    ** * **********   
 *  * ** * ** * ***  *   ****    * ***  ******  * *   ** ***    ** ***  ****  *** *  *  * * **    *  *  *      **   ***** *  *
   *   *    ** *********   **     **  * **     * ** ** *     **  **  ** *** *
* *   * * * *   *     *** * *  *** * **   ** ** **** * **** * 
 ***    * *  *** *  *       *    ** *  **   ****  * ***** **   
****  ** ** * **    *  ***  **       ***   *    * *
    ***  * *   *  *  * * * *   * ****     *  **  ** *     *   ***   * * ***   ***   * ** is a prefix of %s", string2, string1);
****  *  ** ** **    ** ***** ** ***    ****  *** * * * * *
    *  ***  *   **  *  * **   *  *  **  ** ** ** *  *  *   *
  ***    ***  *  **** ***   *  **  *** *  *    * ** **
  * *****  **  **** * * **** **** **    ***   ****  * ****  *****  *** *   *       ***  is not a prefix of %s", string2, string1);
 ****  * *** * ***    *  *  * *** * *  *   *   **** ** * *
    }
* ** ** * * ***   *   * ***   ** *  **** * ****   *** ** **** * 
    {
   * ******   ** * * **    ***** *  ******  ********  * **  * (i=0; i<=strlen(string1)-1;i++)
  *  **    ******    ***  * *   ***  *     **    *  *   ****
**  *** ****  *   * * ***   ** **      ** ** ****    *  **   *   *  *****          (string2[i]==string1[i])
*  * *  **** ** * **   **    * * *  * ** **** **   ****       *   * *  **     ***
*  **       **  * *   ***  ** **  **     *   * * ** ***    ** **** *  ** *      *** **  ** ***  * ** * * 
** *  * **** ***  *   *  * *  *     ****** ** **** *** **** *  ** ** ***  * 
    * ** *  ***** *     *   *** *    *** ** **** *
 *** **     ** * **** * * *  ** *  * *  *    * *** ****  **
* **** *  ** ******* ***   *    * *  *          *     * * 
*     ******    ** * ******  ** *  ***      * ******   ** *  ***    ***      ****   *  is a prefix of %s", string1, string2);
 **  **  **** ** *** * *  ****  *   ** *     * *
* *  ****  * **  * * *  *      *      ** ******    *  **    ** 
          **** *  * *  *** **  *  *  *    *   
  * * **  ** ** * * * ** * * ***  * ******** ** *  **** *       ** *  *   ** *** * *** *   is not a prefix of %s", string1, string2);
**    *    *   *** * * * * ** **   *  * ** **      
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 *      *****  * ** ***  *  **** ***  * %s", chaine1,chaine2);
** **   ***   ** * * *   * **        ** *  * *
** ** ***     * * ***   **      * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
**   * ** *  *   **   ****  lenght1,lenght2,c;
** **  *  **** *   * *** *    b[100];
*   *** * ** *** *** *    *  ** a[100];
*  * *  * * **  * *****    ** d[100];
* * * * * *  * *  ****  * ****  ****  **   ** *
***  * *  ***** **** *  *  ******  ** *  ** ** *   
    *** * * * *     *  ** *   *   ** **** ** * *
 ** ****    * *****  * *********  *  ** 
* ******  **** **  *** *** **** * ***  *** *
    ** *  ** *** ***** **
 **** *  **    **  **     * * ****  ****  **  **  is a prefix of %s",a,b);
 * *       ***** ***  *   
* ***   * *** *** ***** *   * ***
* * ***     **** * ******   
  ** **** * * *   ** * * ***   *    * ** ******** *     *** * **   is not a prefix of %s",a,b);
  ** * **  *    **** ** *
 * *** * **  *  **  **  * * * *  ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ***  *     *     * 
#include    *   *   * * *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 * **** *  *   i;
********** * *** * ** * * **
  {
 ******** ***** *****  *  *  **** *  *****  A[i]!='\0' && A[i]!=B[i]   )
       *   **** * ** * ***** **   * ** ***  ** *****  *******   *****  0;
  ***   *  * ***** **   * **   *  *  **    *****     * * *  
     *   *** *   *  **  **   ** * * ** ** ** ** **  * ****    *  *  *    * **
  }
 **   * ****  1;
}


int main()
{
*** *    *** *  ** * ** * *  *  a[n],b[n],c[n];
 * * **  ** **     **      *  * i;
 **  **     ***** ***   *   * ** ****   ** *  *
*  **** ** * * **  * *    *  *    * **   ***
 * ****   ***** ** **  ** *     (aa(a,b)){
* *  *****    * *       ** *****  ***    ******** *   ** *   ** **  * * * **
  *     ** * **  *** * *  ** *****    * **  * ** *****       **** *   ** *    ***  ***** **
 **** * **  *  * **  * * *** * ******* ** * **   * *  ****** **    *   *   **     ***  *****    ** * **   
 * **  *** *  * ** **** *** *       *    * * * *   *   **  **   ** * ** ** *   **

*  **   ****  *  *****  **  *   **** * ***** **  * ***   
 *   **  *     *  ***  *** ** * ***     ** **  *   **    * *****    **** *  ** is a prefix of %s",c,b);
** * * ** **     * **  **  **  
 **** ** ** *   ***     **
*  *  * *  * **  *     **** * *  **  ****** *   *   **  ** *     * ** is not a prefix of %s",a,b);
* ** ***  *  *  ***  **  ***   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **     *  *
* **** *   * ***   **     
int main (){
char  **
char  ***
 ***  *   ** ** *   string1: ***  * *
 * *    *   *  *   *  ** *  *  
 * ** **   string2: **   **  
* *  * ********  * ***  *
 *  **    *  **  ** 
**  *****  **   * *   *** *   ***  *** * * is  ***      *  of   * *  * *** * *    
else
 *   *  *  ***   * *****       *****   * is not prefix of * * * *    ** * * * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *  *  *   
#include    ** *   ** * **
#include **     ***  ** ** 
#include  ** **    * * 
int prefix(char p[],char s[])
{
** *******   *   *  **** * * ** *  * * **
 *  **** ** **    **** **       0;
*** ** * ***  ** *** ** if   *  *     * **  *
     *   *** * **** ** ** 1;
* ******* ** ***  ***    *  
*****     **** *  * * *    *** 0;
}

int main()
{
   **  *  *** * ** *** p[999],s[999];
 **** ****  *  ******   * ******    ***** ***   
*   **    *  ***** * ****  ** ******* 

   ** * ** ****   **        **  
****  **  *  ** ***** ** ******* *** ** * **  * is a prefix of %s",p,s);
** ******       *  ***
****  ** ***   **   ** * *   *   ** * ****  is not a prefix of  *   * **   

  * * ** **   ** ** **   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** *  * * * ** **
int main()
{
 *  **    ***** ***     *     ** length1,length2,c;
   ****   *   *** *   **  * **  a[100];
     ** *** ***  **** * * b[100];
******   *  **  * ** * *** d[100];
    * **  ** *  * ** *** *** *******       *** * 
**  *** *  *** * *  *   *  **   ******    *    *
 ***   ** * * *** **  ***    **  **
* * *   *  ****** *  * * ******  **  ****  *
if (strcmp(a,d)==0)
* *  * **   *      *   **** *
* *  * *  ***  * *  *  ** * **   ****  *     *    *  **    *     **  * is a prefix of %s",a,b);
   ****  * **  *  *    
 ***   * *****     **  * * *   
  **  *     * ***      **    * *  *
  **  ** *** ****  **  * ** * *   **  * * ***    * *  *** * **** is not a prefix of %s",a,b);
***** ****** ****** *   ***    
 ***      ** * **** * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * **       ** **
#include * * *       **

int prefix (char **   * str2[])
{
* ** **  * * ** ****  *** * *  length=0, ***  ****
*  *******     **  **
    *****  *  *** *  **  ** ** *   * * = ******  ****   * ****
 ******   *  *   * * * *   
 * *  ** ** ** *    *     **  * *  * *** **   *   
*  **     *       *   *****  *  * * **
**       *  * *   ***** *** * * * *** if **** ***  
*** * *    ** *  ****          * ***  * *** * **        
*    *  *    *    *   ****    *     }
** *  *             ** *    * **** 
***  * *** ****  * **      (count == length)
    * **  *     ***      * *  *****  * *  1;
**  *  *  ******  *     * ***   else * **  ** ** 0; **** ** **** * **
 ***** * * **      *** ******  
}
int main(void)
{
  **  * *    ***** **   **  *  **   * ** **
**  ** *    *  **     *   *
***  * **  ****  * ** **  ** * * *** * **   **    * str1, str2);

*  *** *  * ** *     ** *  *  **** * 
 * *** ** **   {
**    * *****  **       **** *  * *** **      **      * ***    **   is a prefix of ***  ****** str1, str2);
** ** **  ***    ****  ** 
*  * ** **  ***** *     **   *
* * ****  ** *    ***   ****   * *     *  ****  * *  ** *** * *  is not a prefix of    ** * str1, str2);

*** ****** **  ***    *  **   ** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *     *** * *
#include **** * * *      
#include       * * *    

int main()
{
 * *   *  ***  *  ** * * * **    prefix[100];
*** * ****   ****  *** *    * word[100];
*  *   **       **  * ** **** * *  *    %s", prefix, word);
**** ** * *** * * * *      i;
*  * **    *  ** *** *     *** = 0; i< strlen(prefix); ++i)
*   ****   * * ***   *** * ******  
    *  **** *   *     ***** * ****  ** * *       *  *       ** *****
 * ** *    * ** **** **  **** *  *    * ** * *  ***  ** * 
*    * ***   ** * *    *   ***   ** * *  ***   **** * * *****  **  ** *** ****       * * ** * * *   *    is not a prefix of %s", prefix, word);
*  *  **   * * * * ***  ** *  **  ** ****  *    **  ***** * * ** ********* **  * * ****  *  0;
 ***** * **    * * ****        ** *      *** * *  **  * *
*  ** * * **    *  *** * **  
* *   ** * ******  ** * * *** *  *** *  ** is a prefix of %s", prefix, word);
*** *  *  *** **** **   *    ** *   *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***** **  * *
#include **  **  ** ****
#include  * *   ***      

int main()
{
    * * ** **    * * * * ***** **  *   prefix[100];
   ****   *   * *  ** ** **   word[100];
 *   ** ** * ** ***      *   **  * * *   %s", prefix, word);
 ** * ***   *    **  ** ***  *  i;
*** * * ***** ** **** *   *    = 0; i< strlen(prefix); ++i)
  **   *  *** *   * * ** **
** *** *** *  *   * ***  ***   * ** ** * *** *** ***  ***   **  * ***
 *****  * *   * *  * **   *  *     ** ** ** *  **
 **  *    *  * *******  ***   ** *   *      ** * ** **    ***   **   ** * * *** ** *** ** **** * is not a prefix of %s", prefix, word);
 ** **    **   ***  * ***  *   ***** * **     * *  * *    *  * ***** * **   *** *** 0;
****   * *** ** *  ***  *   **** **** ****  **      *   
  **  * ** * ** *********   
 *   *** ****     *  * * ** * * * ***     * *  is a prefix of %s", prefix, word);
*   **  *** * ** ** *   *  *    ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**   * *****  **   **
 ** **    *  ** * **** 
* * ***  * *  *** *  

int main()
{
 * **   * * char * **   *
  * ** **   ***   char ** * *
 ** *     *** *** ** *** * * * ******  *    * * word);
 * ** *     *  * int i;
  ***  *  *    for(i = 0; **       ******* *** ++i)
  ** *** *  *     {
***    * *  *  *     *     * ***  **  ***** *
 * * *   *    *  *    ***  {
* ***** *   * **** *    *  *   **  * ** *   * *****   * * is not a **   of  *  ***  *****  word);
  **  *     *   ***** * *  ** * *        *** * ***** 0;
  ****   * ***    **   **** **  }
     **   *  * *  }
**** ** *** * *  **    *  *** is a prefix of    * *        word);
    * **  ****   *   * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.67
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 16.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users