1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.6k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 **  ***   *     * **  * ***
***** *** *** *  ****  * * *** ** ***     **    * ****   
    {
*  * * **  *  ****  ********* *  ***  *****      *** *  **  (i=0; i<=strlen(string2)-1;i++)
*** * * **** * * **   * *****  **** *  *** * *   * 
 ***** *** *    **   *    * * **   **   * **   * *** **** *  ***   ** * ** *  **     **     (string2[i]==string1[i])
* *  *** * *   ***     **  ***  *   *  * **  *   *       ****   ** *  *****   *    ****
 **   * *** ** *  *    *** ** *   * *  *  *  ** *** * **** *** **   ** * ** *      *** *  * * **   ** **   * * ****
 ** ******    * *   *  ***  *   *   *  * *    **  *   ** **  **        **   
 * * *    ** *    *  * *   * *     ** * ***  ****      *******  **** 
  * *** * ***  **   ** ***** * ** ** ** * *** * * *      
 **    ** ****    ***  *   ** * *  *   * * **  ** 
 *   *   * *****  ** ** *** *  **     **  * **  * * **  ***  ****  ****** *   *** ***** ** *  is a prefix of %s", string2, string1);
  ****** *  *  ***    * **** *  **** * **  *** *    * ***
 ** *    * *****      * *  *   ***  **      *  * *
* **** * ****  *   *   * *      ***  ** * *** **   * * 
* ****** *  **** * ** * *** * ** * * * ******   **** *  ** **** **   **  **  *   *  **** * *   is not a prefix of %s", string2, string1);
*   **  *  ** **  *** *** * *   * * ***  **   *** **
    }
  * **** **   * ** * ***      * **  *** *  *   *    * **
    {
*  **** *** ****   **  *** * *  *  * ********  * * * * (i=0; i<=strlen(string1)-1;i++)
  *    **** * **  * ****   *******       *  * * *  *  
   **   * * ** *   * ** *  * ** ***     **  *   * ****** * *  **  ** ** * *  *    * (string2[i]==string1[i])
 * ** **       *****       *  ** * ** ** *** *   * *  * **   *  ** *       * * *  
   ** *** * ** ** *  **  **** ** **    ** *** *   **   *  ** ****** ** *  *** *     *  **   *** ******* * *****    
*   ***   * ****    ***  **  *   **   **  **    ** * *** * *  * *     *  *  *** **     
* * ******   ** ******* *  ** *  *        ** **  ** *
 *  * ****  ******** ***      ******  ** ** * * **  * ****  **
  * * * **  **  * * *** ** *   * **  *      *
* * *     ** * ** ** ****   ****** *   ****** * **  *** ** *** **  *  ***  * ********* is a prefix of %s", string1, string2);
     ****   ***** * *** *****       ***** * *  ** ** 
***  *  *  **   *** ** *****  *  *   ***    *  ****** * ****
*  * **   ** *  *    * * * ** *** **   * **      ***   ** 
 ** * ** * *******  * * ** *  * ***** ****** **   * * *** *****  *  ****  ** * *****    ** *   is not a prefix of %s", string1, string2);
   *** *      ** *    **   ***  *   *   *** *  **    
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* **   * **** *  *    ** ** ** *  *** *  * %s", chaine1,chaine2);
 **   *  ***    *  * *  ** ** * *    ** ***
    * *  **** **  **** *** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  ** ***  **   ** ** * *** * * lenght1,lenght2,c;
 ***** ***    *     *** ** **  ** b[100];
   *** **** *        *  * * *    a[100];
 **** **    **  ******* d[100];
 * *  * *   * *** **      * * ** *          * **
       ****  ** *     * * **       **
   **  * **  ** **  *  *  **  ***  *  
*  *    ***  **  *  ********** ** 
* *  ***  *  **  *********    **  * **
  * *     * * * ***  ** * * **
    *** * * ** ***  * ***   *****  *      * ***      is a prefix of %s",a,b);
   * * * * ***    *  ***** 
 *    * * ** *  * * ** *    *** 
   *  *      ****** *   ** **
   *   **  ***   ** *   *** *  **    **  *   * ***  *   ****  ***  is not a prefix of %s",a,b);
 **** *  ** ****** **   *
**** * ** * *  ** ** *  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   * ****** ** *
#include * * *** ** **  *
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
***  * ******* * i;
  ***    *   *  * *******  
  {
*     *       *  ***    *  *    * *   *  ***   A[i]!='\0' && A[i]!=B[i]   )
  ****   ***    ***  * ** *  **    * * * *   **   **  *   * **** *         0;
 ***  *     ** *****  *   *  ***   ** ***   *  ** ***
 **  *  *  *    *      **   * * **  *      **  *** **  * ** * *   ** ******
  }
*  *** *  *       * 1;
}


int main()
{
     * ** * *   *  ***** a[n],b[n],c[n];
 **   *    ** *  *   ****    i;
*  ** *   * ***  * *              **  * **  
 **** ***  *     *    *   * ** ***  **   * ** ****   * * 
 *   *** ***  *** ****   ***  (aa(a,b)){
 * ** * *   **   *****  * *  **** *  * ****   ** * **    * *****  *  
 **  * *   * ** *    *           *      * * **    * *** *  *   *  ** ** ** ****  *    ** ***** **  *** 
*   ** *      * *** ** ***  *  *    **  * * **  **  ** * * ***  **  *  ** *            ***** **  *  * ***  * ** ** * *** 
   **    ** ****** * * *** *  **  * * * * * * *   ** ****  * *       * ** ** 

*  * *  *  * *  * * * * *  **  *  * * *      * **  ** *
* * *** ****  ******** ********    *** * ****  *  *** *   *****  *  is a prefix of %s",c,b);
 * ** * **   ** **** * ***
**  * *   *  **  *    **  
* *    ***     * ***  **  *** * ***  ** ***     ****    *        is not a prefix of %s",a,b);
 * ** *****     **     *     *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     * ** *  
* *    * * *  *  **
int main (){
char * *  *
char * *** * 
*  ***** **   string1:    *    *
 * *** * *  *    ** *  * *  *** ** ****
*        * * *  * string2:  **  *  
 * *** ** **** ****   **** 
  *** * * *   * ** **
  ** *    * **    *   * ** *     *** * is *  *  *    of  * ** ***  *** ** 
else
* **** *** **  *** *** *     * * ** * is not prefix of **  * *** ** *** *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *  *** * * * ** 
#include  **   *** *   * *
#include ** *      *
#include *  *  * ** ** *** *
int prefix(char p[],char s[])
{
*** *   **   *  *    *** * ***** ***  *    *
*    ** **** *  *  **   *    0;
  **  ****  *   * ** * * if ***     **  * * *  
*  * **  ** *  ***  *****  *  *  1;
*  **  *   *  ** *  * 
 *  **   * * *  **    ***    *  *  0;
}

int main()
{
 **  ***   *****  * * ** * p[999],s[999];
**  * *  ***** ***   **** * ** * **     *   *
    * *  **  ***    *****   ***** **    **

*  *  **  *  * *** ****  *  
** * *  *    *      * *    * *   is a prefix of %s",p,s);
 ** *** *   * *** *  
 * *  *    *    *  *   * *****   *   * *   is not a prefix of    *  *****

  * * * ****  **  *  * * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * * *****  *
int main()
{
***** * *  * ***  *  * * length1,length2,c;
  *   *** *   ** * *  *  * ** ** a[100];
*********  **** **    * *   * *  b[100];
 ** ** * ** ******* ***    d[100];
**  **  **  *   **   *** *** * ******** *   ** ** ** 
     ** *    * **   **  ***** *** **   * * * * *
 * *   * *  *  ****  * * * * *      * **
* ** *  *     *  ****     *   **      *
if (strcmp(a,d)==0)
  *  * *  ** *  *   * * **
 **  * * * *   * *  **  * *******   *   **     ** *****    is a prefix of %s",a,b);
 *   * *    ** *      * 
   ** **  *   ***  *** ****    * * 
  * * ***  **  **  ** *  *
 * **   * *     *  *   *  **  *  ******* **  *      **** *  ***  ** is not a prefix of %s",a,b);
 * ****  * * * *    **** 
  * * *   ***  ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * * ** * *
#include  * ****  ***** 

int prefix (char  **    ** str2[])
{
*  *    *** ** *** ***   *     length=0,   * *
* **      **  **   ****
* * * ** **** * *     ** * *    * =     *       * **
 **     ** *  *    * **  ** ** 
 *    *** *  ***   * * * * *   ** * * * ******
* *    *** ****   ** *  ******* ***
 *      * *  ***    *  *  *** * * if *** **   *
  *** * *   * *  * *       ****    *   ***  * **     **  
     *    **   **  * ** *  * *       }
 *** *           ****    *   * * **  
 * ***  *  *   ** * *  (count == length)
 *  *  ****    ** **   * * **     *  **  ** 1;
* *** ** *  **** * *** * *** *    else   *  * ** 0; ****  **    ***  ** **
 * *  *   **    ** **   * * * 
}
int main(void)
{
    * *** * ***** *** **  *   *     * ***  *
*     ***** *** **   **** *
***   ** *    **   ** * * * * ****     * ** * * str1, str2);

****  **   ** * ** ** ***** ** ***** *  *
***   * * * {
  *             * * *   ** *******   **  *****  ** **            is a prefix of   * *  *   str1, str2);
 **   *    * **** * *    **
 **  **   * ****  ***   * **
* * ***  **  **** ***    * *** ** **  * *   ***    * *****  **** *      is not a prefix of  ***  * *   * str1, str2);

  * *   ****  *  * ** *   ** * ** *  *  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   ** *****  *
#include  **   **  *  
#include   **  * *   *

int main()
{
 *  ***   **  * ** **  ***   *  prefix[100];
 *****   * *** * ***   *****  word[100];
*   ** * *   *  * * **    * * *** **** * %s", prefix, word);
 *  **** * ** * **  *    i;
*** **  * **  *  * *  *  = 0; i< strlen(prefix); ++i)
*  *  ****   *** **** *  * * **  *
*     **  * *  * **  **** ***** *  **      *  *   ** **     *  *  *
    **  **    **  *  ****   *   ***     **** ** ** **** 
*  ** **    *** *     * *** * ** * *    * * * ****   ******* ****     * ** * *   **     *   is not a prefix of %s", prefix, word);
 ** *   ****    ** **      ** ***   ** *   *   ** **  *     *  ** *** *  **   ** ** * ** * ** * 0;
 ** ** * * *  * * ***  ***  *  **  * ***** ***  **
   *** *  *  * ****  * **   **
**  ****  **    * ******* * ***** * *  ** * is a prefix of %s", prefix, word);
 *    *  **    *  * ** *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  * ******
#include  *  ** ***  * ***
#include *****  * **  *

int main()
{
 *  *  *** *   **     * ** *** * prefix[100];
*  ***  * ***** ****    ***  * word[100];
* **        * * * ** *** *    *** ** *** **** * %s", prefix, word);
**** *  *  *  * ** *** *  ** i;
  ** ** * ***   * *  **  *** = 0; i< strlen(prefix); ++i)
 *******     * * **  * 
  *      * *  *       ** *  *   **   ** * ******* *   * *   *** 
 * **  ** * * **   * **  *  * ****** *    ****   * *  *
*  * * *  **   *  ***   *****  * *    * ******** ** ***** ******    ** * ***** *  * *     is not a prefix of %s", prefix, word);
 *  ***     *  ***    ** ***  *** ** * * ***   ***** * ** ** *  * * *   ** *  *  * 0;
 *****  *** *   *  ** ***  *  ** * *** * *  * ** *     * * 
* *** ** * *   *       ** * 
* *  * * ****     **    * *   *    *    is a prefix of %s", prefix, word);
* * * * ***** ** * *** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ***  *   *** *** * * *  
*  **  ** **  **  *  *
*  *   *  *    ***   **

int main()
{
*  ***     *  char   * **
* **   *  * **  * char * *  * ***
 **  * *** *  **   *****  **  *  * *    * word);
  *    *  *  * * int i;
* **  ***    for(i = 0; ** ****   ** * ** *  ++i)
*       **     {
   * * ** ** * *  **   **  * * *   ** *   ** 
***  *   ** * *  ** **  **   {
 * ***   * *     ** *  *  ****  * * *** ** **   **      is not a  *** of     ** *   ** *  word);
* ****** *    *  *** * *     ** *  *  *******  *   0;
*    ***      *      *   **  }
***     ** *** *   }
**    *  * *   *   ** **  ** * * is a prefix of    *  *   *  word);
 *   ** ***  * **  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.234
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 11.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.3k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users