1-11 Exercise 3: Prefix of a string

0 like 0 dislike
1.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 1.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 *   *  * ** ** *** **  **  
**    * *         *     **** *  *****    * * **   * *** *
    {
* ** **** * * *   *  * * ** * *** * * ***** ******  (i=0; i<=strlen(string2)-1;i++)
  * *   ** *  ** * ***   *   *  *  *  * ***      * ** 
  * **** **** *   ******* *     *  *   **  *  *   ** * ** **  ****** *** ***  ***  (string2[i]==string1[i])
  * *  **** ****   * * ** *    ***  * * * *****    ***** * ** ****   *  ** 
**** ***  **  *    * ********    ***  * *** ** *  *   ***  **  * ****** *  * **    ** ** ***** * * *  ***     
 ****** ** **  ** ***      *  ***  ** *    * * * * ***            *     * * * 
 *   ***** *******  ** *** * * * *        **** ***
 *   * ***   * *      * *  * *  **  * * ***  *     *    * 
* *****      ** *  * ****    * *  *  ** ****     *** **
 **    ***  * *  ****    **      *  ***  **  **   **  * *****  **  *** *    **  * * **  is a prefix of %s", string2, string1);
 * * *  * ***  *  * *    ** **  ** *  **   **  * * ** *
**   ** ** *  **   ** * *  ****** **    ****   **  * ***   ***  
 *   ****   * **** *** * * ***** *      *  *   *     
**** * * * *  *   **   **  *     *     *   ** ** *** ***  **  **  * * **** **** ****  *   * is not a prefix of %s", string2, string1);
* **   ***  ** **    *     *   *  *   **  ***   * **
    }
*   ****   ***  ****    **    **   * *  **   ***   **    ***
    {
       *      * *   *** *   **   **  * * * **    ** **  (i=0; i<=strlen(string1)-1;i++)
 *      * *    *** *  **  **** **  *  ***     * *  ***     *** 
  * ** *    * * **   *****  *  **   * *   *  * *** *  * *****  ****   *   * *  (string2[i]==string1[i])
*  *    * *  **  * ** * ** ** *   ** ** * **   ******  * ****     ***   * *   *
 *  **  *     **  * *  *** *  *    ** ***   ** ***  * *    * * *** *** *** **    ****   * ** *****  ***  *  **   *
  *  *********** * * * **    * * * * **   ***  *  * ***  *  ***** *   ********
* **  * *** *   * *  *      *   ** * ** **     *** * 
*** ** *    * * *  *     *** *     **** *   ** *   *** ** * *
*   ***** *   * * * * * *    * *******  * * *   **
*    *          ***  *  * **   *  *  *  *    ** *  ****   * ** ** *  *   * ***  ***     * is a prefix of %s", string1, string2);
  *   *  * * * *   * ** ***      ****     **   **** *  ** 
**  * *  * *   ***  *     *  * ***        *** * ****  * ** *
* **   *** * ****** ** **   ** **    **   * * * ** **  * 
** ** *  * *      * ** ***** ** *   ****    *** ** * **    ***    * *  *   ***    * **** * * ** is not a prefix of %s", string1, string2);
  **   ** ***   ***      *    ** * *   * *     * *** ** *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
*  *    **     **    ***  * *** * **** **** %s", chaine1,chaine2);
  *  ** * ***    ** *  ***  ****** **  *  
 *  **   *    *  **      * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
   **** * * ***    ** * ***** * lenght1,lenght2,c;
***  * ***  ** * * *    * *** *** *** b[100];
*   **  *  * *     ***  a[100];
* ***   * ******* ****  ***    ** d[100];
***  *    * * *  * ** *** * *** ** *    *   *
 **      ** * * ****   *   **   * * **  **  *    * **
**   *****   *  *** **   **  * * **** *
**     * *   * *     * * *  *    ****
  *     ***  * * *      ** ** **   
  ***  * ***   * ***   * 
 *  *  *** **  * * *** ** * **** **  *** ** *** *  *    is a prefix of %s",a,b);
** ** * * * * **** ****  ****
*  * * **  * * ** * **       *
   *  * *  ** * ******  **
** *    ****  **  ******  *******  ***** **   **** *** ** * *    *      is not a prefix of %s",a,b);
* *   ** * **     *    **  **   
   * ****  ***** *  * ******   0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **   *    **
#include **     * **** ****
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ** ** *  *    i;
***  ***   * * *   * ****   ****** * 
  {
** * * ********     * * **  *  * ***** *  A[i]!='\0' && A[i]!=B[i]   )
*   ** **  *   *  * **** *  **** *    *** **    **   * ***  * ****   * 0;
 *   ** **  *     ****  * ***  *** * ******* *
******** **   *  * * **   *    *** * *   ** ***   **  *  * *   * *** * ** * 
  }
  *** *  ***     1;
}


int main()
{
* ****  **  * ** *    ***  * a[n],b[n],c[n];
    ** * *   **** ******* ** *  * i;
**  * * * ****   * * **   **   *  * *   ****** 
* * ** * *** ** **  * * * ***   *    * *  ** ***  *   **
 * *   ** ****** *    **** (aa(a,b)){
*** *** *   **********   * **   * *  **    ** ** * ****  * ****** ***
   **   ** * ****  *  * * *  *  *      ****** ** * **    * ** *   **    ** **** * ***  * *  *
** ****   * * ** **  * ***** * *   *  *   * * * *    *****   ** *  * **** ***  ** ** * * * *    * **  *
 *** ** **** *** * *    ****  *   *  * * ** ** **  * *  * ** *  **** ** * *

 ******* * * * **       *  *** **  ******    *** ** * 
 ***  * *  * ** *   *   ** *     ** *  ** *   **  ** *    **** is a prefix of %s",c,b);
*  ** **  * * ***   *  ******* 
*    *** * ***** *   ***  *    * 
* ** *  ****  ******* * * *   **  ** ******* ** **** * ** ***     *  is not a prefix of %s",a,b);
 *   *    *** **   **  * *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * *  * *   *
 *  *  **   *   **** *
int main (){
char  **** ** 
char **  **  ****
 ****** * * *    string1: *   *  
 **  *  **   **  * *******    *
*  *  *  *    string2:  *    **
* *** * *   ** *  **    ** **
* * ****  * * *      *
  * *   ****  * **  **       ** ******* *  is *****  ** * of  *  * *     *     * 
else
* *  * *   *  ******* * ***  ***  * is not prefix of  * * *****   ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **********   *
#include ** *   ** **
#include      * ***   *  
#include * * *** ** *   * **
int prefix(char p[],char s[])
{
**  **  *  ** **** *  **  *** *****   * * ***
 *** **** * * *** **  ****** 0;
   ** * * * * * *** *** if * **  **    ** 
* * * *  * * * **** * *** *  * 1;
********  **** * *** **
  * *** ****  **    *** ** *  ** 0;
}

int main()
{
***      **  *** **     p[999],s[999];
 ** * *    *  ***   *******     *  * *** *  
   * * *  ** ** *** * ***  * **  * ******* * **  

 * *    *****    *   *** *  * 
* * * * ** *   *   **    **   * *  * is a prefix of %s",p,s);
 ** *   * * ***  *     *
*****   * ****** *     ****    ****  is not a prefix of      *** ***

* ****** * ** ***    **   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *   *    * ** **
int main()
{
*   * * ** * *  **  *     length1,length2,c;
* *       * * ** **       * a[100];
 * *  ** * ** ****** * *   * ** b[100];
***  ***   ***  **  ** * * *  ***** d[100];
 **  *  **   * *** *   *  * ** **  * ***** *   * 
* *   ****    * *         ** *** ******
*****    ***    *  * **** * ** 
* **** *  * * *   ***    *  *    ** **** 
if (strcmp(a,d)==0)
* * ***  *   **** * *  * *  * 
 *  *   ****  * **    **** **   ******    *  *   * * **  *     **  is a prefix of %s",a,b);
** ********   * **       * 
 **    ***  ****  **    *   *
** **    **** *  * *   **   **
 *   *  ***  *  * *     ****   ****** ******* * *  *  * ** **  *** * **  is not a prefix of %s",a,b);
    ** *  **   ***      *  
  ** * *   * ***** ** * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **** *   * 
#include ** *   *  ***    * 

int prefix (char *** * str2[])
{
 ** ** * * **     * **  * * *  * length=0, ** * *
 * *   **** *   * * 
 ***** * * *  *  *** **   *     * =  *    **** ** ****
* **  * * * *   *   * *
 ** *      **** * ** * **  ****   * *  *
  ***       ** *      *** *   * ***** ** *** * 
* **    * * ***  **** *       if **    * *  
* ***  * **    * * ****         **  *  * * ** ** * *** **  
*    ***   ** * **** **  ******* **    }
*   *         *    **  **   * **  * *
* ***   **   * *  * (count == length)
   **  ** * *  *   *    *  *  * *   ** * ** 1;
**  * **   *  ** *        *   else ** *****  0;   **** **  *    **  * 
   * ******  *    **** **      
}
int main(void)
{
 *******  * *   *   * *   *  *     * * 
   ** **** * ***  ** **   *
  ** **  * **   * *  *   **   ***    *** ** **  * str1, str2);

*      **  * * **  * ***  *       ***  * *  
***  * *   * *  {
*  * *  *  ***    **** * ***  ***  **  *** **   * *  *     **  *** is a prefix of   **** str1, str2);
*** **  *  * *  *  *   *  
**     * * * **    ***  *   *
*  *  * ***   * * * *******   ** ****  * * *** ** ** * ***  *  *  is not a prefix of  **  ** str1, str2);

  ***      *   *******  ** ***  **  0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *****  * *   *  
#include *****  ** ***** **
#include     ** ***** *   **

int main()
{
  * ***   **   * * **  ** *       prefix[100];
* * * ** *  ** ******  ***   word[100];
* **** *  **   * *  ** *  * *    * **** *   %s", prefix, word);
  *   * ****     *  *  i;
* **   *   ******    *  *  **    = 0; i< strlen(prefix); ++i)
* *****  ** *     * *    ** *** 
  **   *  * **   *****      ***  * ****      * * **   * * *** 
*  **  *   * **  *** *   **** ***   ** ***  ***** * * **** 
* *   **    *****   * ****      *** ***** *  **  *   **  *  * *  * ** *  **  * * * ****   is not a prefix of %s", prefix, word);
  ** *  ** * *  * *    ** ********   **  ***  *  *       **  **** * ***** * *  *      0;
*****   * ** ***   * *   *    *** **  *   *** * * *    ******
 *  *** *   *   *   ***** **    
***  *   * * * **  * * **  * *  * * * * is a prefix of %s", prefix, word);
    *** * **        ****** *    *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     ** *  *  ***
#include ****   *  *** *
#include  *** *     *  

int main()
{
* **       * ** ** *  * **  prefix[100];
** *********    * *   * * ** * *  word[100];
* *   **   ***  **** ** *** * **   %s", prefix, word);
*  ** *   ** ***    *  * * *** i;
* *   *    **   *****   ** ** * = 0; i< strlen(prefix); ++i)
   *    *   *  ** ** ******
  ****** * * ***** **  * **  *   ** * *    ** ***   * * ***** * ** ** 
** ***** * ** ** **   *      **   * ** **  *** **   
 *  *   ***** *** ** *   ****   **   **    * * * *  ** *  * *  **      **** ** ** **  *  * * ** * is not a prefix of %s", prefix, word);
* ** *  ***   * ****     ** *  ** *** * * *** * *** * *  *   *   ****  ** ***  * * * 0;
**   * * ***** **  *  **  **** ***    ** ** *
** ***  **   ** ***  * *
***  * ****  ** * * **** * *   *** * is a prefix of %s", prefix, word);
***  ** *   ** ** **   * **       0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***** ** ** ******** **  
* **     **   ***   * *  
**   *  ***       ** * ***

int main()
{
* ****** **     * char ***  ** *
    ***   **** * * char ** **** 
***  **  *         ***  *  **** *  *   * **  word);
*      *****  int i;
***** * *** *  for(i = 0; ***  *** *  ** ++i)
*    ** *   ****   {
** *   *        **** *   *  *   * * *   * **
 ** ** **  ** * *   ** * ***     {
* * ** *    ** *  ***     *    **  *  **** *    *    *  **  is not a ** *  of *  ****  **  word);
*   *   * * * **      * *  ***** *  **   ****  ***  * 0;
 * ** * *     * ***  *   * }
 **     * ***  ** }
 **  ** **   *    **     * *** is a prefix of  *  *   * ****  word);
 **   * * *    **    0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.187
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users