1-11 Exercise 3: Prefix of a string

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
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#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
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}
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Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>
#include    * * ** ** *
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}
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Hidden content!
#include  * * *** *** 
* ***     **** ** **
int main (){
char      ** *
char  **  * **  
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else
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return 0;
}
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prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
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Hidden content!
#include ****** *  * 
#include    *  * **   *   
#include      * ******
#include *  *  ** *   * 
int prefix(char p[],char s[])
{
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}
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Hidden content!
#include <stdio.h>
#include  ***** *   **   
int main()
{
******* ***    *  ** *  **  length1,length2,c;
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}
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Hidden content!
#include   * *  *** ** **
#include  ** ** ***   * 

int prefix (char *  * *   str2[])
{
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{
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****  **  *** ****   *  *        ****    ***   *   **   *   ** **** *  is not a prefix of  * * * **  str1, str2);

******** **    * * * *** *** *   0;
}
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#include **   **** *  
#include **    **** *
#include      ** *** *

int main()
{
 **** **  **   * * *  **   **    prefix[100];
  *** *  *  ** * *    * * * *** word[100];
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 *        *  **  *****  *  ***** ****   **   *  * **
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   *   ***     ****  *  ***  *  * * *    is a prefix of %s", prefix, word);
* ***** **    **  *  ***** * **    * 0;
}
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Hidden content!
#include       *  *  * *   
#include *  *  *    * *  *
#include  *********    

int main()
{
* ** **  * **** **   *** ** **** prefix[100];
 **    *** **  *   *  **    * word[100];
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 *  *   *** **** * ***   ***  * *
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***   **  * * ***  * *  * * ****  * *  **  is a prefix of %s", prefix, word);
**  * * **     *    * **** **   *    0;
}
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Hidden content!
 **    * *** * * *    **
********  * * ** **    
 *  * * ******    * **  * *  

int main()
{
 *  ** ** ** char  ** *    
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 **   * * *    * *   ** ** }
 *** *       }
 **  **  * **  **  * ******** is a prefix of **  ** * * * word);
* **    *   *  *  ** 0;
}
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