1-11 Exercise 3: Prefix of a string

0 like 0 dislike
1.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 1.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*    **** *** **** * *** *     
**  * *  ****   *   **   **   ******* *  ** ***** *** * ** *   **
    {
  ****** **   ** * *** ******  ** * **  * * **  *** *** (i=0; i<=strlen(string2)-1;i++)
   **  ****      ** ****  **   ***** ***** * * *    **  * * **  *
*  *  * ** ***  ** *  * * * **   * * *****   **   * * *** **  * ** **  **  *  *    ** (string2[i]==string1[i])
 **  * * *   ***  * * ****  ***** * * * **** * **  *** ***  *   *    ** ** * *** 
***    *    *  *  ****   * **** * ***   ** * * * ****     **  *** *  *  ** * **  *** *   **  ****** * *     ***  *
*    * * ***   ** * *    * * ** ******   * * **   *  * *  * ***  ****    *
  * **********  ** *    *    * * *   ******  ** * *
  * ** ***   ** * *   *    *** ** * *    **  *   * *** *
 ** ** *** ***    **** ** * **    *  *  * *    ** **  * 
  * ***** **  **  * **  *** *  ** *  * * *  ** *    **** ** ***  * *   ****** ****** *  *  is a prefix of %s", string2, string1);
 * *  ***   * * **** * ***  ***    *** * *  ***** **  *
 *  *    * * **     **  *    * * * * **     * ** **  
*** *  *  **** * **** **** ***  * *      *   **  ***
 **  *******  ***  ** *  *   *     ********  ** *  **  ******  *  *   ***  **** ****    * ** is not a prefix of %s", string2, string1);
** * ***      * *     * **  * **  ** ** * **     *  ***
    }
 **** ** * * ********   *  *    **** ** * *   *** *** *
    {
*   *   *** * *  *  ** ** *** * *    ** ***** *   ***  **   * (i=0; i<=strlen(string1)-1;i++)
 *        *    * ****  **  ***  *** ****** * * 
** *  **  ***** *  * *   **** *** *  * ****** **    *********   **** ****  * ** (string2[i]==string1[i])
     *   *     *       * *** **  * *     * **** * *  **** *   ** * * *** * ** **
  ** * * ***   * **   ***  * **   **    *       * ****  * **  **** *  * *** * *      *  *    **  **  *  * **   
     ** *  *  *  * *   ** *   **    * *** *   *  * * *** *   * *** * *** * **   * *  
 *   * *** * **   *****  *  ***  * * *  **   ** ***  * ** *
*** *  ***** ***  *   ** ***   ** ** * ** *   *** **  **  *  *
* *** * *   **********       **** *** * **  *  *    *****
   *  ***  *   * * * ** * *    *   **     * *******  *     **   * * ***     ***   ** *    is a prefix of %s", string1, string2);
 ***       *** ****   * * * ****  **  * **  *    
   ******* * *  **** *** **** ** * * *  *****      ** 
** **  **  * *    ***  ****  * ***  * * *  **   ***  
 *   **    ** **       ********   *  ***  * * *  *** **  **  * *    **    * ******* **  * ***    *   is not a prefix of %s", string1, string2);
*    * **   ***********  * *   ***  *** ***  *   * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* **     **** *   ***** *   ***  ** * **     ** %s", chaine1,chaine2);
* ** * **    *  ** *    ***     *   **** ** * 
  * ****  **  ***  ****   *    **  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 * ** *  *   ***  * ** **  lenght1,lenght2,c;
* * *     *   *   **** **   *  b[100];
*  *** ** **  * **  *   **** *  a[100];
* *     ** * ** **  ** **** *** d[100];
   **   **  *   * ***** * * * *   ***     *      *  *
 *   * * ** * *    **  * *** *    ** *  ** *
       * *  *  ****  **  **   * * *  
 * ** **   * *       ** * *  *  ***  **
**  ***** * *  **  *  * * *    *  * *  
  *     *           *  ******* 
  ***  *** ** *   ** * *** ***** ***   * *** * ** is a prefix of %s",a,b);
  **  * **  *****  *   ***  
** *** * ** * ****      *  ** 
 * * ****** ** *       *** *
 **** **   *   *     *** * **   **    *   ** * ** **   * *******  ***  *  * is not a prefix of %s",a,b);
* ****  ********  * ****  * 
*  * **** * *          *   *** *** * 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  ***   *   *   
#include *    *  ** *   * 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
    ****  **    *  i;
 **  *   * *  ** *  * *   * 
  {
  ** *** * *     *  * ** *** ** *  *   *   A[i]!='\0' && A[i]!=B[i]   )
*****  * **      ** *   **  ** ** ****  * * * ***    *     *  ** ***    * * 0;
*** **  *  *** **  ****  *  *   **   *  *  ***      *  
*****      ****  *      * *   *    * * * * *** * *** * **    ** *****   *
  }
  ***  *  *    *  1;
}


int main()
{
****  ** ** *  * *  ****  **  a[n],b[n],c[n];
* * *  *****  * *  ** *   * i;
****** * *** *  ****  *** * * **   **   **** * 
 * *  * * * *   * *     ** **  *       *
     ** * *   ******   * ** **    (aa(a,b)){
* * *** ** ** *     * *** ** ** ** *   *   *  * * * * **** **** 
   * *  *** **   *** ***   *  **  *****   * ***        ** *  **   *    *** ** *** ****
    *   *** *** ***   ** ** * ***   *****  *  *  * ** * ***     ** * * *   * *  *     * *      *  * * ** * * * 
*  *   *  **       * * ** **** * ****  *** ** * ** *** *  **** * *    *** * ***   *

      * *   *  **   * *     *  ** ***  *** ******  * *  * *
 ***   * **    * *  *  * *** ** *     ** **   *      *    *   ***  is a prefix of %s",c,b);
* **** *** *  *   *   
** *****             * *   *
     ****  * ** * ** * *** * ****** * **** ***  * ** **** ** *   **** is not a prefix of %s",a,b);
*  * *  * * *  *  * ** ** **  *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * *** ********
* ***** **** **   **   
int main (){
char    * **
char  * ****
 *    * * ** ***  string1: * ***   
* *  **   *     **  ***   ** ** ** 
  * * **** **  ** string2: * **  * 
* *  *  *** *   ****  **  ** 
 **** **  * **** **
  **   **    * ******   *  * *  *** ** is * *** * **  of * * **  ** *  * **  *
else
* **   ** *  *** *  * *       *** ***   ** *  is not prefix of  **  *   *   *  ** 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *  ****        
#include  *  * * *   * ***
#include  * *  **** **
#include    **** * **** **** 
int prefix(char p[],char s[])
{
 ** *    *  **** **   **       ***   *****
**  **  ***** * **    *** *  **** 0;
** * **  ***** **  *  if  *   ***** ** *** 
    *  * * * * *  **** ****    ** *  1;
* **  *     * **  *
  *** **  **  ***  *  *    ** * *   0;
}

int main()
{
  **     ** **** ***   p[999],s[999];
***   ***  ** * * ** *  * **  ******* 
*  * *   *  **     * ***  ******     *    * *

******  * *****  *     *  *****
 ** * * **   *   * *  * ****     * ***  is a prefix of %s",p,s);
* ***  **** ** **  ** * **
    **  *   * *  ***  *   * *** * * **  is not a prefix of ** *   *  

    * *   **** **** *   * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   **   * * **** 
int main()
{
 **     **   *  **     *  *** *  * length1,length2,c;
 ******  **   * * * *  ***   * a[100];
**   ** *  * *** **** b[100];
*********  **  ******* * *   * d[100];
   **   *** *  *** **   * ** *** *  **** ** * **
****  ******     * * ***   *******     *   *   *
 **  *** ** ****     **    ***       ** **
 *  *****  **   * ******  **** *    *
if (strcmp(a,d)==0)
****  *   *******   **
   * **           *    * ** *   ****   **    ***   **  * **  * is a prefix of %s",a,b);
 *    **  *  * * **  *   *
***   * *******  ** * *       *
     ** ********   * **  *
 * *** ***** ****       **   *  **** **    * **  * *** *  *  * *  *    **  is not a prefix of %s",a,b);
*** ** **   * * *       **** 
 *   *           **** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *****  ** 
#include * ******* ****  * **

int prefix (char *** *** str2[])
{
   *   *   * * * * *  *** **   length=0,  *****
*** ****    ****   ** 
 ***    * *** *  *     ***** =   **  * **   * 
*   * * ****  **   * *** *
 ** **    **  *****     ****   ****  *  *   *    * ** 
* **        * * * **   *** ***  *  * *** **** 
 ** ** * *  * *  * ***  *** ** * if  ***  ***** 
** *  ****  * *      **             *  * *   *       *     **   
** ** * *    *      **** *   *      *   }
** **            *    * **    **  **  
 ******** * **** * *      (count == length)
**** *  *  ***    ***** *  **  * ****** 1;
 * *    ** **    *** *   * * else  ***  * ** * 0;  *     ** * *********   
*  *** * * * *     **  *  **  *   
}
int main(void)
{
**   ** * * * * * *   *    *  *  * *  ****
 * * *  *** ***  * ***** 
  * *       *  **   **   ** **  *  *  *   str1, str2);

      **  * **  * ** ** * *** *
 *** **** *  *  {
   *** ****** * * ** ** ** *   *  * *** *** * ***** **  ***    * is a prefix of  *  * * **  str1, str2);
 *  ** ** ** *** **  *      
* ** *   ******  *** *   * 
*** ***    ** * *    * ** * *   *   *  ** *   * *** *******  **  *  is not a prefix of ***  * * str1, str2);

***** * **  * **  **   **     0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  ** *** * ** *
#include **** *** * * * **
#include * * **   *   **

int main()
{
***  **  ***     *  ***  * **   ***   prefix[100];
 * ******      ********  ** *  word[100];
*     ***    ***********   *   *    ** %s", prefix, word);
* ** *    **  *     * **  *  i;
***  *  **   *  * *   *   ** = 0; i< strlen(prefix); ++i)
**   *    * *   **    *  
**     * ** * * **    *    ****   **  ***  ** **  *   * ******  **
 ** *    **  *         **    **  **   **** ******* ****
 * * * *   * * ***  *      * * *     * *  * * **   * *  ***  *  * ** ** ******* **   ***** * * is not a prefix of %s", prefix, word);
*    * *   *          * * ** *  * *  * *   ** **    *  *  **  ***** *  *  *** *      *   * ** 0;
**   *  * ********  * ** * * *    *** *** *  ** *  **
   **  *    *** *       
***** *   *   *     **  *** *** * **   *  is a prefix of %s", prefix, word);
 * *  *  * *    * ** *  **  * ***  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   **  * *****
#include       ** * *   *
#include  * * *     * *  

int main()
{
*    * **   * *  **     *   prefix[100];
****** ***    * * *     **  **  word[100];
*  **     **   * *     *** * ***     * **  %s", prefix, word);
 ***    *  * ****   ** *      i;
 * ** ** *  * ***  ***   * ** *  = 0; i< strlen(prefix); ++i)
 *    *    *   * * ******  *
  ** **  *   * *    *   *    * *   * * *** * ***    **   * ** * * *  * ***   
*  * *   * ** ** ** * *   ***      ** *
*** *    ** *  *  *  **    ****  **  *  ** * * * ** * * *  * ** *  * *  *** *       ** *   **   ** is not a prefix of %s", prefix, word);
 **** * *  *   * * *  * *       * ******* ********   *** **   *  *  *     *  * *  ****  0;
   ** ** **** ** *** ** *  * ***  ***  *   *          **   *  
 ****   *       ** * ****   *  
   *  *** * ** * *    * **  ** **  * * is a prefix of %s", prefix, word);
 * ** * *  *******  *   * *   * *  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***   ** ** * *    ****
 *      *    *  ** *** ***
 * *    ** *   *   ***

int main()
{
 * *  **  * *   * char  *** *    
**  **     *** * char ****   
*  *   ** *      * **** *     * **   **  word);
            * * * int i;
  ** *    * ***  for(i = 0;    *   * **   **** ++i)
** * * *   ***  {
   **    **  **    *  *    ** *     ** *** **
 ** *  *   * *  *   **  * *  ** {
****** * * **   *  * **   *   ** * ** *  *  * *  *  * *  * ** * * is not a  * ** of *** *******   * word);
  **    *   * *   * ** *  *    *  *        *  *** ** 0;
**** ** ** *  ** * *  **  ***  }
*  * * ***  *  }
 *** * * ****     * * * **** * * is a prefix of * * ****   * * word);
           ** 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.123
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users