1-11 Exercise 3: Prefix of a string

0 like 0 dislike
1.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 1.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
****  *       **** * ** *  **
 ****      *   ** *  *   ** ** * ***  *         **  *  *  
    {
** * ** *** *    *     * **  * **  ***  *  **   **   (i=0; i<=strlen(string2)-1;i++)
    ***    *  *******  * *  ** *** ***  **  * ****   * 
 * *****        ***   *** **  * *** *  *   * * **** **         **    **  *  (string2[i]==string1[i])
** ***** ** **   **** * *  * **** **   * * ***  **  ****   **** *  ** **** * ***** ** *
  ** *   *** * **  *    *   *  *   *  *  ***    *    *    *    **    ** ******* *  *  **  * ***   ** **     ** **    
  ** *** * *   ** *     ** ** ** *** ** *   *   ** * ***     ******* **    * *  ******
* *   * ** *  * ***  * * ** ** * * ***      ** **       * **
   *   **  ***  ** * * ********  * **   ***   *   * *** * *  *  
* * *******   * ** ***  ** * * ***    **    *  **
** ** **     ***** * *  *** **   **  * * *  * ***   *  *     **  ****     ***** *** * * is a prefix of %s", string2, string1);
 * *  * **  * *   **  ***** *  * * ****  *     
 * * *     *  *  * * * ***    ** * *  **       *** *
**    * *         ****  * *  **  *  *  *   *** *    ** *
 * * **   *********** **    ** **   * * **   * ***    * * *  ***   **  **    ***  ** **  * * **  is not a prefix of %s", string2, string1);
 **** **  ***    *****     *  *  * ****    **** * ** *  
    }
    **    ******  ******** ******** **  * **** *******
    {
*    *  * * ***** **  * ***    ** ** *       * *  (i=0; i<=strlen(string1)-1;i++)
* ** *  *  * *  *  *    *** *   **  *    * *   * **  *
****  * *****  * ** **   * ** ** *    *** *     *** * *        *****  * **    * * (string2[i]==string1[i])
*  * *********  **  ** * *** * * * * * * * **** *    *  *****  **   * **      ** *
 * *  * ** *******  *** * *******   ** * ***  * * *  *   *****  *  ***        *** ********   * ** *   *  **
 ***** *      *  ***     **** ***  ***      ********* *      ***  ** * * * * * ** ** *
* ** * ***  * * **    ******          *  ** ** ******
  * *     * **   ***    * * ****     ***   * * **** * **** *
******* *  *   * * ****   * ** ***   ** **  **   * *  *
* ***       **  * * ** * ** *******     ***  ******  *** *   ***  * *   *** *** **  ***  **  * is a prefix of %s", string1, string2);
  ***    **  ** ***  *****  * *  *     ***   ** ***** * *  ** 
 * * *  ** *       *   ****   ***   *      ***** * * *     **
 ** *  **** * ***** *** ***** * *** **  ***  * *** *   
*** **  * *  **  *   **** ******    **** **    ** ***   ******  * ***  ***   **   ** **  * ** *   is not a prefix of %s", string1, string2);
    **   * *  ** * *      ** *** **     *  ****** *  * *  **      * 
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
   * ***  ***  *  **  ** * * **   ** *** *  %s", chaine1,chaine2);
***  ******  ** *** ****      * ** **  * **
**** * ***  *** ****  *     *** 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*  ** *** ** *  *  * ***** ** lenght1,lenght2,c;
 **  ** ***   **** ***   b[100];
 ** *********  * * *** * * a[100];
* ** **** * * *  * * ** * d[100];
* *    ***  * ****** * ****   ** ** **  ****    
   * * * * * *  *  ** *    *   ***    * ** **  ** **
 *******       * * *   ** **
*  *  ** * *** * *  **   * ***  ** *  *   * *
* *** * ** *  *****  * ** *  **
* ****     ***  * *  ***   
***  ***      *  *** *  ***  * * *   *   **  ****  *    is a prefix of %s",a,b);
 **  **** * *  *   *      ** 
 *   *   **** *  **  *****
 ** *****  **  * *  **** **   *
 ** * *****    *** ** **    *  ****    *  **  * **** ** * *** * *  *** * is not a prefix of %s",a,b);
*  * *  ***  *  *  **  ** 
  **  *** * * * * ****   **   ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  * *  *   * 
#include **      ** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 ** *      *       i;
**  *  ****   * * ***  ** **
  {
 *   *    * **  **   * *  *  **   *  *    * ***  A[i]!='\0' && A[i]!=B[i]   )
****** *    *** *     **  *** ****  * *   *  **    * ** *  *  ****  0;
  ***** ***  ***  **  * * *  ***** * * * *   * * * ****
*   **   *******  * *  *  * ***** *     ***** * * ***   **  ** * 
  }
***** *      **   * 1;
}


int main()
{
    ***     ** *   ***** a[n],b[n],c[n];
 *    ** **** ** *       *   * i;
  **   **** * *   * *       *** * *   **  ** ** * 
*   ****  ** *   *  **  *   ****    *      ** * ** 
**** **  * ** *** **  * *** (aa(a,b)){
 ****  **  *****  * *  ***** * ****   **   *   ** * *** * *   ** ** 
*     ***     * *   ** ** ****  * * *  **  ** *  ***  * ***     *  *     *  ** *    *  **  *** * 
* *  ***** ****  *     **** ***  *  **   ****    * ***  **  * **    ****   ****  ***   *     * *  *  ****    *****  * *
   ** *  * **  ****    *  *   * **      *  *** ***** ** *** **  * ** * * ** ****

 * * *** **      * *** ***  *** * * ****  *  ** *  * *****  *** 
 ** ****  * * **  * **   **  * *  *      **   *    ** * *   *  ***   is a prefix of %s",c,b);
** * ******   * *  *    * *
*   * *  * *****    *  ** * ** 
  ** *  ***     ***     *  *   **    *     *   *  *   **** ** is not a prefix of %s",a,b);
 * **** * * *** ** **** * ******** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ****  * **    
   ** * ****** *  ** *
int main (){
char * *** * *
char   ****** * 
** *       string1:  * ***
*   ******** *  ***  **  * * 
  * ** ** *    * string2:  * *** 
  ******  *  * ** *  * ***
**  *  *** ** *** ***
*   * ** ****  *     *    *  ******  is * * **  * * of   ***** ** ** 
else
*  *  * *   ***  * ** *  *  * * *  * *   * * is not prefix of ***   **     ******  * *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  * *  *     
#include  *****  ***   *
#include ** * * *** **  *** 
#include ********** **  
int prefix(char p[],char s[])
{
 ** ****** ***   *****  *     *** * **  * ** 
*   *   * ***       *  * *  0;
**   ****  ** * * * if * ** ** **   * * 
* * *** * * *   **  * *  *  *** *** 1;
*****  **** *  *    *  **
**    *  *     * **     ****   0;
}

int main()
{
** *** *  ***   * *   *   p[999],s[999];
    ** *** **   ****   * ***    ***** 
 *  **  * ** *  ****  ** ** **** ***  *****

 ** *       *** ***  * ***** * 
*    * *** *** ****** **   **     *   *  is a prefix of %s",p,s);
  *  **   *  * ****  * 
*   *     *** **    **   *  *      * *      is not a prefix of *  * * ****   

*** * * *   *  * **  * 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *  ***   *  *****
int main()
{
**  * ****  * ** ***** **  *  length1,length2,c;
  ****     * **  **   *** ***  * a[100];
 *** **   ** **   * * *  ***  ** b[100];
*****    * *  **** * * *  ** d[100];
 **   ***     **  *** * * *   ******  *   * *  *   ** **
**   * ** **  * ** *  ***      *    *     * *    *  ****
  **** *  * * *  *   ** ***  **  * *     
* * * *** ** *   ** *** *  ******* * 
if (strcmp(a,d)==0)
*****  *** * ** *  ***** ***
*    **  * * * *** ******  *** * ** ** **  ***  *** **   * ***   is a prefix of %s",a,b);
*  *   * * *   *  ******  *
***** * * * ***  **   ***  **
*****   * ***     ***  ***  
  *******  ***  **   **  *  *  *** ** ***  ** ** *  ** ** * ****** ** **  *   is not a prefix of %s",a,b);
* **  * ** *   **        **  *  **
 * * * * **  * * 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **    * ** *
#include   * *   *  ** 

int prefix (char **       str2[])
{
 * ** * ** **     *  * *    * * **  length=0,    *** 
    **   **    **
   *****   **  *  **   **  =  *  **** ***** *
    *   * *** ***  **   * ** 
***  *****   *       ** **    ** ***   **  
 ***  **  * *  * ** * *  *   * * ****  *  *  * *
 *  *     *    ** *  *    ***   if **  * ***   * 
 *** *   ** *   * *          ** *  *****   ** * *** *  
*** *  ** *  **  *   * **  * **   **    }
   * *             *  **** *   *
*  * **  * ** *    * *  ** (count == length)
    ** * *      *     *  *  * * **   *    1;
*  *  * *   ** *  **    * else  *  * ***** * 0; *  *** ** **
* *  *  **  * * *    ** *   
}
int main(void)
{
****   * * * ****  *  ****      ** *   * 
  * **  * *   **    ** ***  *** 
* ******    ***  *  *  *** *  * *  *  *** *   *  *  str1, str2);

* ** **  ***    *    *   *       * *   ******
* *     * **  {
 *** ** **  *** * ** *** * *  * * *    ***** *  **   *  **** is a prefix of    * *     str1, str2);
**  ****      *  * *  * * ***
  * *** **** ****  ***   ***
      * ***** *  *   *****   * * *       ** ***   * ***  * * **  **  *  is not a prefix of  *** * ** str1, str2);

* *  * * ****     ** *       0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   **   ***
#include     *      ***
#include **  * **** *  *

int main()
{
 ** ******* **  ****** * ***    prefix[100];
 * ********     ***** ****  word[100];
 ***    **** * *  **  ***** ****  *** *  %s", prefix, word);
 * * *   *     ***  *  ***  *  i;
 **  *      ** *** ** * * ** *** * = 0; i< strlen(prefix); ++i)
**  ** * *  ** ***   *  **   
 ***  ***** * ***   * * ***  * *   **  ** **    **   * **    * *   
*     **  ** ***  * *   ** **  * * *  ** *  **   
**  **  * * ***     * * *  *   ****  * *  * **  **   **** ****  **    ***    *  *  *** * *****   * *  *** is not a prefix of %s", prefix, word);
*  **     *****  *    ** ***   ** *  ***    ****   *   ***  **** * *  *   **   0;
  **   **  ** ***** ***** *   ** *  * ***** **  * *  ** *     *
* * * *** *  ***** ** ** ***
 *  *  * * ** *     *  * * ** **** ** * is a prefix of %s", prefix, word);
   **** *  **    *  **** *  * **  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  **** ***   **
#include ** * * **   ****
#include * **    *** ** *

int main()
{
* **  ***       * * *   * * ** prefix[100];
 **** ** *   *** **** * ** word[100];
***** * **  * **** * **   **** **  *   %s", prefix, word);
*  *     *   *  ** * * **** * i;
 ** *  *  *** *  *    *  *  * * = 0; i< strlen(prefix); ++i)
 * **  * ***  * **   *
*  **   **    *  *     **   ** * * *  **** *** * * ** **  ***** * * * 
** ** * **  *   **  **  ******  **  **  ** *   ***  *
         * ****  ****  * * *   *   ***  **  *   ** *** *****  * *********** *  *    *** *  *  is not a prefix of %s", prefix, word);
 * * * ** **    ** ***   ***    **  *     ****     **** ***** * *    ** ***     *      ** *   0;
***  ** ******* *    * **** **   ** * * ***** * ** ***
*** * ** *    *    ** **  
  *   **    *** * **  ***   **   *  ** is a prefix of %s", prefix, word);
 * *** ** *    *********   **     * ***  0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *** * **  *** ** **
**   *** ***   **  * 
*   ** *     *** ** 

int main()
{
**  *  **       char *  ***
**  *   ***  char  * **** 
 *** *     **  * * *** * *    * *  *  * *   word);
 *   ** ***    * int i;
****   * *     * for(i = 0;  * *  *   * * *** ++i)
 * * ***   **  * {
 ** *   * *  * *   *  * ****   ** *  *
   **** *  ** * **    *   *** {
**  *  *   ** *   *     **** ***** ** **  ** *    **  **  * is not a *** of  * * ****   *  word);
      * *  *   *   * *** ***  *   *** **  * **  ***** 0;
*****  *    **       ** *   * }
        *  }
** *    *  * **** * *       is a prefix of  ***  * *  **** word);
 ****  *** *** * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.82
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.5k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users