1-11 Exercise 3: Prefix of a string

0 like 0 dislike
1.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 1.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
*  * *    ** *******  *  ** **
 * *    *   *** *    *****    * *** * *   * *  *     * * **  ** **  
    {
* ***  ** **   * *  * **  * * *     * *     * *  *  *  (i=0; i<=strlen(string2)-1;i++)
  * ** *  * ***********  *  ***    **** *  ***  **    ** * **
  * ***  * * ** * ** ******* *  *  *  * ****  * *   *  ** ** *  *    * **  * * (string2[i]==string1[i])
*  ** *   *   * *  ** **  * * * * ** * ***  ** ***    **  ***** * ***    ** **    
 *  ***   **   *****   * ** * *  * * ** ***  *  *  *  **  **     * ***   ** * ****   ***  ***     * *** ***
**** ******** ***    *  * ******  * *** *   ***   **  ***   *    * ** *  *****   
* * *     **  *    **  ** * *****   ****  *** *
*   * *   *     *  *  **   *** **********  * **  ***  *   * 
 **   * *    **   *  *   ** *  *** *** *   **       *
 ** *****      *  *      ***    **  **   **  * * *****  * *** ** *** ***** *   * ***** *    * * is a prefix of %s", string2, string1);
****  ** ** * *   *   **  **    *  ***  **  **  *  * **
**    ** **** *** **** * **  ****      ***    ** ***** **** ***   *
 ****** * *   *    *  *  * *   **   **      * *     
 * * **  **** **  * **  ***** ** ** *  **        * * ** **  *  ** ** *    *     ****  *  ** *** is not a prefix of %s", string2, string1);
 ** ****  *** *****  **  ** *  **** ***     ***** *    *  
    }
 ** *  * *  * ****  *    ** *    *  * * * *    *  ** ** * ** ** 
    {
****** *  **  * * * *  *      *** *    *** ** **  ** (i=0; i<=strlen(string1)-1;i++)
*** ** *** ** ***** ****        **    **** *** *      ** 
**    ** ** * ** *  *  * * * ** ** * **    *  ****     **       *   *     *  *  ** * ** (string2[i]==string1[i])
 *  *  **  *** *****  *  *  *   ***** *  ***   * *****   **  * *    **  *  ** 
**  * **  *  ** * *   * **  * *  *  *  *** **   * ***     *  * *  *  **  ***  ****   *   ****     *      *  ** ** 
 *  * **    * ** **  ** *****  ** **   *     * *  *      **  *  ** *** **** *** **
* * ** ** **** ***       *** ** *  * **      ****** 
   * ******* * ****  **        *      ******    **** *   *
**   * *  * * ****  *** *** ** *** *  *   *  * ** 
**   *   *** ** *   * **   *  * * *  *  **      ** *****   ** * * *       * *  ***  *  * * *  *****  ** is a prefix of %s", string1, string2);
 * *  ** ** * ** *** *   *** * ** *  **   **  ******* *
     * ***      *** * * * *        *  * *  *   *    *** 
 *  * ** * * *** * **  ***** ** ****   *  ***
**    *  **   *** ***  **  ***   **    * **        ** * *  ***    *  *      ** *** ** ** *   *  is not a prefix of %s", string1, string2);
 *  **     *  *     * ****    *     *  *** **  *    
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* **  *   ** * *    *** ****    * ****** *****  %s", chaine1,chaine2);
*    * *  * ***  ** * *** * *  * *   *  * *** *  
  **  *    * * * *  * * ******  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*    *    ** *   **    lenght1,lenght2,c;
 ** **  * **** *    *  **  b[100];
  * ** *  **   *** ***   ** ** * a[100];
*******  ****    **  *  *  *** d[100];
   *     ** *  ** ***    *  **** * *    * ***   ** 
 * ***    * *** *  * ** *  *  * * * * * 
 *  *     * ** * ******* **     *     *  * 
**** ** *      **    **** **  *     *  *  *
  ******   **  ** ***       ***
**   * * * * *  ***  **  ** ***
**    ****** *      ** *    ** *    ** *  ****  *    is a prefix of %s",a,b);
    * * * ***** **  *    * **** * 
*** ***  *     *  * * * **     * 
**  * *  * **   **   *  *** *
  ** **  ** *** *  * *        *  ***   * *** **   **  * * *   *  ** * is not a prefix of %s",a,b);
*   **  *  **    **  *   ** **
 ***      **   *  *** ***  0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *   *  * *  *  
#include        *    ***  
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
  * ** **   * * i;
 ********    * **  *  ** **  **** 
  {
 *  **   *  ** **    ***      *  **  * **   A[i]!='\0' && A[i]!=B[i]   )
   **** **   *  **   ** **  *   ** * ***  *  ******* ***  ** * ** *  *  *     ** 0;
* **** *     * **  ** ** * ****  **  * **** * **  *    **   
       **  * *   **    *** *  *   *   ** * **** * * * * *  **  *  ** *  
  }
 * *  *  *** *****  1;
}


int main()
{
*  * *  *** * * *** *   *      * ** a[n],b[n],c[n];
***    **** ****     *      **   i;
 * ***  **   *  *  * *    ***  ** *   * * **** 
  *  * * *   ******    **   * **   ** ****   ** ** 
  *  ** *********** * * * *  (aa(a,b)){
* * *    * ***  **   * *    *******   *  *  ** ** * ***       ** * *  * *  * * 
  *** **   ***  **  * * *  *** ** * **  *  **  * *     *** ** *  ***** *  *  * *   * * *** 
 **    * * ****** *   * **   ********** ***** *      ** *   *  *** **    **  ***  **** ** **    **   *** ** *** *   
* ***    ** * *  * * ** ***  * *    *   **** **    *  *  ***   **   * ** * *   *

*   * * *         * *  *    *   *** ***     *****      
 * **** * ** * *  *         * ** ***  * *    *  *   *  *  * ** *** is a prefix of %s",c,b);
  * **          **    ***   **
**   *   * ** ***  *****  * ******* 
 * *    ****   ** **  *  **    ** ****** *  ** * ** **   **    is not a prefix of %s",a,b);
** *  *  *  * *** *  * *   *   *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ******  ** **
* ****   **   *   *   ****
int main (){
char  *  ***   
char   **  *
  **   *  **  * string1:  * *   
 *    * ***  * **  * *   *  **  
*  * * *  *   string2: *  *    
  ***** * ***  * * * * *  ** ** 
   *** ** *  * * 
 ***    ***     **** ****  ** * *    is *  *  ***  of   *  ***  ***** ****  
else
 * * * *  * ** * **** *   *** *   *** *  ** is not prefix of **  * ****  ***  **** * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *  **   **      
#include   ** * ** **  
#include   * *** * * **
#include    *****  ***  **
int prefix(char p[],char s[])
{
*   * *  *       *  **    *    *****  *****  
  * ** ** ***** * * *  *** * ** 0;
* * * **  * **  if    ****         * *
**  **** * *    ***    * * 1;
***  **** **  ***** *  
*  **    ***  ***     ** * *    *   0;
}

int main()
{
*  *   *****  * *** **   p[999],s[999];
* ***   * *** ** ***** ** *  *  ** **
  * ***    *   *** ** **  ** *** * **   ** * 

** **  *  ** **    * * **      
* *     * *** *  *   *  ** ******   ***       *  is a prefix of %s",p,s);
  *  **     *  ***  **   
  *****      *******   ******     ** *   is not a prefix of * *   *   

*   **        ***  ** *** *  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *     *  **  *
int main()
{
 ** * ****     *       * * **  length1,length2,c;
   **  *  *** ** ** *  ** * a[100];
* *  ***  **  *   **  **  ** b[100];
 *    ** **    *****  *  * **   * d[100];
*    ***  * *******  * *   **     *** *  * * *
** *  ** * * * *  ****    *  **   **  * **   * **
* *** * *    *  *      * *  ** *    *
* ***** **  * *  * *   **    ** **    * **  * **
if (strcmp(a,d)==0)
 **  * ** *******  **** ** 
  **    *   **   *  * *** ** * * ***       *** **** *  **** *  **  * *  is a prefix of %s",a,b);
 *    **   *** **    * *
 ** *  *  ********** *    *    
**** *   *  ***    * *  * 
** ***** *  *** * *       ** *  *     **** *** **    *** ** ** * is not a prefix of %s",a,b);
 *  ***  ***  *    *  **   * *  
** **     ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * * *    * * 
#include  * * *   * * **  * 

int prefix (char *** * * str2[])
{
 * **********  *   ** ** * * *   length=0,    *  
*   *******   * **     *
**     * ****  * ** **** *  * =  *** * ** **  *
 *** ***     ** * ** *** **** *
**  * **   **   * ** **    *** * **  
  *   ** *  ** * * * *  *   * *    **** ** * *** *
*   ** *   *  * **  *** *  * if           *
 *   *   *  *  * * ** ***       **   * *   *   *    * *   
 *  *   ***      **  ******* *   }
   *** **         * *   *   *** **     *
 * *** * *        *  *  (count == length)
* *     *  *****  **     *    *    ***      * 1;
* ** *  * ***  *** *   * * *  else  **  ***     0; * * * * * * * * * 
* *   * * **  *     **  *   
}
int main(void)
{
 *  *   *  ***** *   * *  **        *    
* *  * *****     *  * ****  
    * *  * **  *  ****    * * *    ***    str1, str2);

 *   *** *** * **  ****    *     *    *
***    ***   *  {
    *** * ** * * *** * **    *** ******     * *  * **   * * * **  *   is a prefix of    ***  str1, str2);
*** ***   * ** ***  ** *  **    
  ** *    *  *** ** **  * *  
**** * ****  * **  ***** *  * *  *   * ** ** ****** **  *   **     is not a prefix of    * ***  str1, str2);

   ****  * *  **   ***** *  ** 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** * **    
#include ** *****  *** *
#include   * * *  * *   

int main()
{
  *** **** *   ******* * **    prefix[100];
**** ** * *** ****    *  ***  *  word[100];
  *     *   ***** ***  ** * *  *** *** * * %s", prefix, word);
** *  **  *  ******** **   ** i;
 * ** *   ** ***  *   **  *  **    * = 0; i< strlen(prefix); ++i)
 *    **  *****  * *    *
  *  *** *  * ** *  * *****  *** ** **  *** ***** ** ****   * *   * 
***       **** *   ***** * **** ** **  ***  *** **
 *** * **** * ***  ** ** *    ***   **     *** ** * * ** *   ***  ****** * ***  ** * **     is not a prefix of %s", prefix, word);
 * *   *        * *    **   *** * ** **   * **     **      **  ***    **  * * 0;
*   * *     ***  ** * * * ** ** *  *   * *     ** * *** 
**     *  * ***       ** * *  *
** ** *  ** * ** ****  *****    ** is a prefix of %s", prefix, word);
   ****    *   *   ***** * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *       ***** * 
#include    ** ****     
#include ***   **** ** * 

int main()
{
**  *  ****** *** * *** *     *  prefix[100];
  *  * **  **  **** ** **** word[100];
*    **   ** *    ****  **** ****   * * %s", prefix, word);
* * ****   * * ** *** **   *** * i;
 *** **  *  *    * * ******* = 0; i< strlen(prefix); ++i)
    ***  *   * *   *    **
*** *        * ** *  *     **    * *     ****    * *****  * *  *  *  
*    * * *      * * *  *** *   * * *** *   * *  * *   
*     ***      *   *    *  ****  *  * * * *  ** * **  ****** ***  *   * **   * ** *  ****  **   **  * is not a prefix of %s", prefix, word);
**   * *   *    *     * * * *  *   *   *    * ** * ** ****  ** ******** *** ** *****  *  0;
** *    * **  *      **     ***  * ** ** *   ***  * * *
 ** * *** *** *** * ****  **
 **** **      **  *   **   * *  **   ******  is a prefix of %s", prefix, word);
**    ** ** ** **  **  * *    * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   * * * *  **** *  * 
 ** **   **    ***** *
 **   ****  * ** ***  *

int main()
{
 * * **     * * char   *** *** 
 *  * ** *  *  char * *  * 
* *   *** **  **          **  *  *  *  * * ** *** word);
  * * * *   *  * int i;
 *  *  *    **  * for(i = 0; * * **   **    ++i)
 ** **  *   **** {
 **   *  **   ***   *      *   *   ** ** **
* ******   **** ** * *  * {
** **   *** * **   * ** **    *   *   * *      *   ** ****   * is not a   **   of  * *  ** *     *  word);
 * * ***  ****   **  ** * * *   *    * *  *    *  *** 0;
 * *    **      **     * * *** }
**  *  *  * * }
  ** * *   * * *   * ** *  * *  * * is a prefix of    **  * *   ** word);
 * ** *        ** *     0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.196
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 2.4k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 1.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users