[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.3k views

22 Answers

0 like 0 dislike 
Hidden content!
***  * * ** **** ** **

int *  * argc, char **** * {
  ***   ** * *    *   *     ***  */

*****  ****  ** **** int number;
* *     ****** char a;
  ***  ***   ******  ** *** *  ** b;
  * ** ***   * ****  * **    c;
**   * *** ******  ***      ****     d;
**  **  *      *    *  *   * e;
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***   *  * *   ** *   ***** **  *    *    *  *  **    **
*** *  *   *  
  *    *      *  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*** *  * ********** * 
 
* *   * ** ** * * **    {

* **   *   *
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**  *** *  
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* =   *   
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 ***   *   *****  **** *
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **   *******   
#include *   * ** ***  

/* run this program using the console pauser or add your own getch,   **  **  **  *****  or input loop */

int main(int argc, char *argv[]) {
***  * *    ** * **   * ** ****  a;
****             *  * **       ***  b;
 **  *** ***  ** * *    *   * c;
      ** *   *   ***  **   *   d;
*******  **   *  *  **  *  *  * e;
   ** *     **** ******     
     **** *  *** **  **** ***  *   * * * the words you want to * *   * **
     ** ***  * *     ****
*** ** **    * **  * **** **  = getchar();
  **   *    * ***    ** = a+3;
 *    **  *   **  * ****     **   
**** * ***    * *     **  * = getchar();
******   ** * * *   *** = b+3;
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***** **   ****  ***  ****     * = c+3;
  *  * *** ** *   *     * * * **
***     ** ***   * *     * = getchar();
*** *  **  * * * *   * * = d+3;
 **** **  ** * **  *  *  ******* 
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** *  ** *  ****  * ******        **  = e+3;
*   **  **  *** * ******  ***   **
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 **      * * ** *  *  **** *  **   * *  *  * ** *      &a, &b, &c, &d, * *   
*  **    * *  * * *    
***  *   ** ******* * ***  **  the message how??
  * * **  ***  **  *     ** 
*****      *  * *   *        ** *  **  * * * *  * *   *  a, b, c, d, e);
 ***  *  * ** * **  * ***   *
*           ** ***        ***   ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *** *  **    *  *** 
*  *     ***  *** * 

int   **  **  char  **   {
/*
**     *** * */

***  *    

*      *   * *       *  * *** * *   ** *   *   * *   *  *** ** 
a = a+3;
b = ** 
c = * *
d = d+3;
e =    

 * *****  the * * * **
 * *** ******    *  * 
 * **  ***   *  * ****          * *  *

* *  *        *        
  * **   *** *    ** *** ****  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *  *** *     **      ** 
  *  *    * * **  ***

/* run this  *  *  ** the  **   *  or add your own **  ** * *  *  *     * or   *  ***  */

int    **    *  char ** **  {
* ****  *  ***   int num, ** * 
    **   ****    *  ****  
    *    **   
***  **  * *    **  *      ***     
***  ***    ** **  for *  * = **  *    *** 
{
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  ** * *** ** ***** if **        * * 
** *   *     ** *   **   = * * *** 
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}
** *   *   * ***   **** *  *  * *    ** 
*  * ** **  *   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *** *   * * **     **
 
****   *       *  *  *** 

  * **   *        *       *****         * *  * * *   *   *  ** **** *   *** *  * ***          
*
    * ** *        **   

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*   * ** **  *** * *

 *** ***       *   * **  * * ***    *    *    *   *     *  ******    *    
 
* = * *  

     b +  

    = c + *

 ** = d +   
*
  * *    
 
*      *  ** *****   *   ***      *  *   
*
* *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***** *  * * *   **** 
 ***    *  **      ** * *

int * *    argc, char  ***** {
      **    * *  char   *   
   ***** * *** char **  * 
**  ***   *      ** char ** * 
  *       *     char     **
 ** ***     * ***  char ** **
* * ***  ** * *  
 * * * *** *      ***  ** **  input the letter to  * **   ** 
**** *  ** ** 
  * ** * *    * * **    * *  *  * ** * *    *  ***   ****   **  *** ****   ** **      *  * **** **
** * ****    * *     = ** ** + 3;
 *  ****** *   * **  *** =     + 3;
 *  *** * * *       = ***** + 3;
 ** **   *  *  letterc =  * * + 3;
* **  **  **           *   = * **   + 3;
 ** ***  *     
 * ***    ***    * ** **     *** * ** *   * * *  **** * *   **  * * *** **
* ** * ** ** 
 *       *** ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * *    ***   ***  *
  ** *   * ***    * *  *   

int *** ** argc, char *argv[]) {
***  **   **   char  * *  *
*    **** * * *    char letteri;
 * * * * *     char  * *  * 
     * **    *    ** char *    
* * ****    **   * char   **
* ******   ***  
*  *    *     ** * ** * ** ** input the letter to encode: * *** **   *  *
*  *** *  ***** 
** *     ** * * **   ***   * *  ** ** * *** *  *** *   **  *  *   * *  ** * ** **  **   *    *  ***   * * * * *** *
  **  *   *** *    ** ****** +3;
** ** *** * * * **  *   **   +3;
 *** *** ***  * **** * +3;
    *   ** **  **    ***  +3;
          *  *   ***   +3;
*  ***  *  ** 
***  **   * ***  
   * * * *   ***  *  ****   **  *** ** *   *  *      * *       *    *
 * *   * *  
 **  * *** *   return 0;
}


INPUT
 **  *  ******   
 * ***  *
OUTPUT
**     ****** * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***    **  *   *   **
*   ** * *  *** ***  

int   * *  argc, char *    * * {
*** *  *   ***   char * * *
***    *      ** char  * *
 *****  *  * **  char **  *
*** *   * *** char  *    
 **  ****   ** *** char *******
     *  * *    
 * *  *    * * **  ** * *** *   input the  *** to  ** * * *****  *  * 
* * **   *  ***  
**** *          *   *  ***  **  *   ****    **** **  * * *  ** * *  * ***  * *  * ***** ** * **   * ***
 *** * ** * *  
 ***  * * *  ** letter = letter + 3;
*** *      * * **** =   * * + 3;
 ****  **     *   =   ** + 3;
* * * *    *  * ****  =  *  * * + 3;
 ****   *  *** *  ** ** = *** + 3;
 * *    **      
** *   *    * **  ***   *   *   **  letter is     *** ****** *   *    **   **      **** ** *
* *  *   ***  
**  *  * * *    *  return 0;
}

INPUT
 ** *  ***  ***  **
* **  **   *  *
** ** 
    *****   * **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   *****    **  * 

int main(int argc, char *argv[]) {
 ** * ***  ****    ** ** ** ** lettera;
*  ***     *** *  * ***** ** * letterb;
 * *   * ***  * * ***    *   * letterc;
*  * * * ** *    * *  *****  *** letterd;
 *  *   *        ** **  * *   lettere;
* ***** * *     ** **  ** * 
* *      ***** **  *     **            ** ***   *** %c %c %c *  * ** * * ***** **    *   *   *  *** **  * * * * ***    ***  ***   
 *   ** ** ** * * *   *  *****  ** = lettera + 3;
 **  *** * * **   * *   ** ** ***   = letterb + 3;
** * *   *****  ** * *     *  * * **** = letterc + 3;
****** *   * * ***      * ***  ** = letterd + 3;
****  **    **   *** * * * ***  **   = lettere + 3;
********** * ** * * *  ** *** ** * *  * *    ** *
  * ** *  *   *** ** *** * **   *  %c %c %c **** * * **    letterb, * **   ** * *    * *
*  * **  ***  **  ** ** 
****   *** * * ***    * **     0;
}

  * *
* *
*  * *    **
  ** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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