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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 943 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
*** * ** *** **** * b;
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*** ** **** ** * * e;

* ** ******** * *** ** *** *** ** * * ** * **** ** ** * * *** * *

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* ** ** ***** * *

***** * ***** ** * ****** ** *** * **** * ***
* ** * * * * ** * * 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include * *** * ***
int main(int argc, char *argv[]) {


** ***** * char a;
** **** * * ** * * ** b;
* ******* * * *** ** * c;
* * ** ***** *** * * d;
* ** * *** ***** * * * ** e;
* * * *** * * *** * ** * * *
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* * *** * ** the message how??
* * *
** * *** ** ** ** ** * * * ** * * * **
* ** *** * *
** * ** * return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
int main(int argc, char *argv[]) {


**   char a;
** ** ****** * ***** b;
*** * * ** * char c;
* * * * * * ** ** ** d;
** * ** ***** * ** e;
**** ** * *** * ***** * **** ***** *  
    ** ** *** %c %c %c %c * * **** ** ** * * ** *** * * **
** * *  
    * ****** *** ** **** *** * ** ** * *** * ** * **** * ******* ****** *
** ** * ** ** * * *** **
* ****   * *** * * * * * *
****** * * * ******
***** **** ** ** * * *** *
* * ** * ** * * * ***
* *** ******** *** * *** *** *** * **** * *
*** * *** * **********
* * ** * ** ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
* ** * * * ** **

**** **** * * * * {

* * **
= ** ****
* = ***
* = * *
* = * *** *
* = * **

e = *
= ****
=
* = *

***
**** **
*** *
* ****
* **

** * * ** ** * * * * *
*
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** ** * * **

* * * * * * * {

* ** *
= * ***
* = *** **
* = ** *
* = ** * *
= * * * *

e =
** = *
** = **
= **

* *

** * **
** *
** * *

* * * ** *** * * * ***** ***
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * * ****
#include ** ** ** *** * *

int main(int argc, char *argv[]) {
** ******* *** * ** letterj;
* * * * letteri;
** *** * ** * *** * * letterm;
* * *** ** * ** **** lettere;
* ** ** ** * * * *** lettern;
*** *** * **
** ** * * * * *** * * * ** **** * input the letter to encode: ");  
* ** ** * ***** ** *
**** * * **** *** * * ** * * * ** * * *** * * **** &letterj, * ** &letterm, *** * ** * ***
* ** * * *** * ** * +3;
** * ** * **** ** * ***** * *** * * +3;
** * ** ** * * * ** +3;
* * ** * * * *** * * * ** +3;
** * ** * * ** ** * ** ***** * +3;
*********** * *** * * **
* ** *** * * ** ** ** *
****** * * * * * ****** * * ******* **** * *** * * * ** * *** ** lettere, lettern);
** * ** ** * * *** *
** ** * * * *** * * * 0;
}


INPUT
********* * * *
* ** *
OUTPUT
* * * ** **
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
*** * ******* *

int ** ** argc, char ** {


*** ** * ** ** char a;
* ** *** * ** ****** * * * * * * * * * char b;
* * * * * * * * ** * ** ***
* **** ***** *** * * ***** **** * * **** **
** * ** * ** **
* * *** *** the * how??
***** **** **
* * * *** ***** ******** * a,b);
* ** ***
* * * * * ** * 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * ****** * ** ***

int main(int argc, char *argv[])
{
* ** **** letterj;
*** ** *** * ** ** * letteri;
** * ** **** * * ** letterm;
* ****** * **** lettere;
* * * * ** * ** * * ***** lettern;
** * * ** * * ** **** *
* * ****** * * * ** ** * * *** input the letter to encode: * * *
** *** * * * * *** ***** *** *** *** *** * ** * ** *** * * * ** * * ** * * * * * *** *
** * * ** * * * * * *
* * * ** * ****** * = letterj +3;
** *** *** * * *** * ** * * *** = letteri +3;
*** * * *** * *** ** *** * * = letterm +3;
* * * *** ***** * ** * = lettere +3;
* ** * * * ** ***** * ** = lettern +3;
* ** ** *** *******
* * ** ** * * **** ** **** ** * *** * *** * *** * * ** *** lettere, lettern);
* **** *****

* **** *** **** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* *** ** * *****

* ***** * * ** *** {

** ***
= * *
= *
i = * *
* = ** *
* = *** *
e = *
= *
** =
= * *


* * * * *
* *** *
**
* ***

* ** ** ** * *** * * *** *** ***
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ****** **
#include **** *

int main(int argc, char *argv[]) {
** * ** ** ** *** ***** * letterj;
* * * * ******** *** **** letteri;
* * * ** **** * * * * * letterm;
* ** * *** ** ** * lettere;
* *** * * *** * * **** lettern;
* ** * ** * * *******
** * * *** * * * * ** **** ***** input the letter to encode: ** **  
* * * ** * * * **** *** ****** * ** * * * * ***** * *** *** * ********* * * * * ** ** ** ** * ** ** *
**** * ** ** * ****** *
* ** * *** * letterj = letterj +3;
*** * * * * ** ** *** = letteri +3;
* **** ****** ** **** * ** **** = letterm +3;
*** *** **** * *** * * = lettere +3;
* ***** * * * * * ** * = lettern +3;
* ** ***** * **** *** *
* * * * ** ** * * ** **** **** ** *** ** * ** ** * ** * ** lettere, lettern);
***** * *** **** **
* ***** *** * ** * * ***** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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