[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.9k views

22 Answers

0 like 0 dislike 
Hidden content!
**      * *  * ***** 

int *** ** argc, char ***** {
    *** *    * *   *  ** ** */

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**    * **  
* *    *** * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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**** ***  *
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***    ***  
#include  * * * * *  *  *

/* run this program using the console pauser or add your own getch, * *** **  **  *  *****   or input loop */

int main(int argc, char *argv[]) {
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*     *** *   ** *** *  *  = d+3;
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * *  *** **   ***  
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int **    *  char  *  * {
/*
***   *    */

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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***  ** * * *****   
 **    * **   * *   

/* run this *** *  *   the   *  *     or add your own  * *  * *   *   *    *** **   or   *     */

int ** *  *  *  char  ****  {
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}
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  *  **     *     0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *    * *  *      **  

* ** *         **  *  
 
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*
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* * = c + 

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*       
 
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*     * * ***** ** * ***
* ****   * ***** * 

int ******   argc, char **    * {
  **    **  * char  * *
*  * ** * *   char  * ***
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** * **  ****  char ** ** 
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* *  *  *** **    **   = **   + 3;
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** **  ** *    = *     + 3;
**   * *  *  * * letterc = **** + 3;
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*   * * *  ** 
 **  **   ** * * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***   ***  **** *  **
 *  * *** *  ****     

int ** * argc, char *argv[]) {
* * ** ** *     char  ***  *
 * *    *     * char letteri;
   ****   *  * char  ** ** 
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*  *    *  * ** * * *** *** *  * **** **   ** ***   * ** *   * * *    *  ** *  **    ***     **     *
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**  * *  ** *   *** ** *  +3;
* *** ***  **      *  ** * +3;
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*  *  *  ***   
**** **  * ***  
*  *  *      * *  *   * **  * *****   *  ** ***     ***    * *  ** *  * 
 **  *  * *    
 **    * **  return 0;
}


INPUT
 ***** * * * ** * 
**       *** 
OUTPUT
*   *****    **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * *    * * *  *      
   * * * **  *   **   

int *** argc, char *   *** {
   ****    ****  char *   *
    *    * *   * char *  * 
* *   **  * * *  char  *    
** *  * *  **** char  *   
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*   ***   * **  * * 
*** ****     ** *     ******   ****** *** *      *   *     *  ** *   *   ****   **  **  ** ** *      * * 
 * *     *   
 **** *  * ** letter = letter + 3;
 *    *   ******    *  = * * ** + 3;
 *****  **** **** = **  ** + 3;
*    *   * *  *  ** *  =  *** + 3;
   *  *    *** *    ** =  ** * + 3;
* **  * *** ** * 
* ***** * *   *****  ****   * ** letter is ****       * * ** * **  *  ***  * * **   
 **    * *  *  
 * **** **   ** * return 0;
}

INPUT
   *  ** *** * 
*      ** **** 
*   *
***  *****         **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** * ***     *

int main(int argc, char *argv[]) {
 * ***    **** * ** ** ***  * ** lettera;
* **    * ** ****  * ***  ** *  * letterb;
** ** *** *   *   * * ****** **   letterc;
** **  * ** **  * *** *   * * letterd;
* *  ** * * **        * *  *  lettere;
**** *****  ***** **   *  
****    * **  *  **   ******  **   *** ** %c %c %c * ** *** *  *  * * *   * *  ****  * * *  *  *  ** * ***       **   *   
*   *******  **   **  **  *   * * **  = lettera + 3;
* ***  * *    *  * *  *** ** ** = letterb + 3;
******** ***** **  *  ** *   = letterc + 3;
* **  * **** * * ** *  *     * * *     = letterd + 3;
* *  * **** **  * ****   **  *** *  = lettere + 3;
** * *  *  ***  * **** * **  **  *****      *   * * * * **
**     *    * ** **** *** *    **** %c %c %c * *     * **** letterb,  * **   *  *  *** *****
  *** *       *  *        * 
**  **   * *******    ** **** *    * 0;
}

*  **
 ***
 **      **   
*  *  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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