[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.4k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  * * **  *** 
#include   *  **    * * *

/* run this program using the console pauser or add your own getch, ***  * ***   *   *** or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
******      * *  *****  
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int * ***  *  *  * char  ** {
/*
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b = * *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
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* **  * **  ****  * 

/* run this *** ** *** the  ***  *    *  or add your own **            * ***      **   or  * **  */

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  *   **   *** *  * ***
 
** *  *** * *** *  **   
 
*  ** * *  ** **    ** * *    *    * * * *    *      ** * ** *** **  *** **  *  *  *  *   
 
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*
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *   * *  *** *    *
      *  ****** ***  * 

int **  *** argc, char  * *  {
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*  **  ** *** char *** *
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***** * * * **  letterc = ** *   + 3;
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      * ***** *  ** *** ***** **  * **     ***     *   * **  * **** 
*** **  * *   
  ** * **    return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   **    * *** *   *     
*   **  * * **   ***  ** *

int  *  **   argc, char *argv[]) {
* *      **    **** char  *  
 * **    *** char letteri;
* * **  * ***  char    *** 
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* ** *** ***** *   
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**  **  * ** **  
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* *  * * * *** 
** **   *** return 0;
}


INPUT
******      * * * 
 *  **  * *
OUTPUT
 **  **    ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * **  * * *  **** *  
* * *     * ****    * **

int       argc, char  *** * {
 *   ***   ***** *  char  *  *
    *  *  * * * char   *  
**    **  *   *    char *     *
   *   * *  *** char *   * 
 * **   **** char     **
**    *      **  * 
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 *   ** *    
 *    **   * *** ***  ** *******   **    **  * *    **   *  **  ** **  *   **  * *    *  ** *   ** 
**  ***    *    
*** *  *   *  letter = letter + 3;
*  ** * **  ** ****  =   ** + 3;
 * * **   ***  *  *** =  * * *  + 3;
 * ***   *  ****  = **  + 3;
 *   * * ** * *  * * = ** + 3;
 * **  * *  *  *  
 * *   ** *  ***  *** ***  **     ***     letter is  **  *  *   *  * *  **  ***    **    *  *
   **    *  *  
* *  **    *  *  return 0;
}

INPUT
** *  *     **
*  ***  **
*    
*** * ** *  **  **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ***  *    ***** * 

int main(int argc, char *argv[]) {
  *  * * ***  ******* **  lettera;
 * *      ***** * ***** **   letterb;
*  * * **  *      **** ** *  letterc;
    *    * *** * *** **  *** letterd;
*   *  *****   *****    * lettere;
****     **** **  * * ***  * *  
 ********  **** **    *  ***    *** %c %c %c  **    **    *   **  * * * * * **   * **** **** *   *     ** **** **  *  * 
  * * ** * *  * *   *  *****  = lettera + 3;
*   * * ***  *****  *** **   = letterb + 3;
 * * * * *   * * * * *   **   = letterc + 3;
 ***   ****  ** * **  *** ** = letterd + 3;
  ****** * ***  * * *   ******  = lettere + 3;
   *    *  * ** *      ****** * *  *  ********* *  ** 
 ***   *  ** **    *   * * *** **  *            %c %c %c *  *   ***** letterb, *     **** * * *  * 
 ***  * * * **   * *  *** *
**  *    **  *  *** * ***  ** * 0;
}

**   
** **
  * * **
* *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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