[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.6k views

22 Answers

0 like 0 dislike 
Hidden content!
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***   *  * **** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  * * * * *** *** 
#include  * *  *  *   **   

/* run this program using the console pauser or add your own getch, ** ******     **  *      *  or input loop */

int main(int argc, char *argv[]) {
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*     *****  ***  **    ** * * ***  b;
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***  ** * * * * **  ** ** * * = d+3;
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*  ***** ** * *    ***    = e+3;
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** *  **** **  ** * * *
  * * *  ***   ** * ***

int * * **  **  char   *  * {
/*
*      *** * */

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a = a+3;
b = * *
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** *   *   **  *    *  ** *  **     0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *   * *** *  *** **
      * **   * *    

/* run this ***** * * the *  *  *  or add your own *  *  *****         **  * * or **     */

int  ***  ** char  * ****  {
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}
* * *  ***      * ** *    * **  **  ****
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *     * * *   * **

* **   ***  *  ***  *
*
*     *   * *       *** *  ** *  * **    * *  **  * *** ********   *  ** *   *  *   

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*  * * **    *        * * *   *   **   **    *  *  *****  * ** * ** *    **
 
*  =  * *
 
**   b +  *

*  = c + *

*   = d +  
 
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*
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*  **  
 
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
     ***** ******* 
****** * *    **** * *

int ***   argc, char  **  {
** *** ** **** char ***
  *   ** * * char *   
**  ***  *** char **  *
**** **   *  char  **
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* * *  *    *     ***  *   ** *** input the letter to *  ** *****
*  ****  ***   
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* **     * * * *   * = *  * * + 3;
*    *     **  **  =   * * + 3;
** ** ***    ** **     **  = * *   + 3;
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    * ** ***  
* **   *** * *      ** *  * * *  ** * **          *     *   *   *  **
*** **** ** * ** 
 *****      *   * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *** *** * **   ***
* **** *  ****** **

int  ** argc, char *argv[]) {
* * *   ****   char *  
*  *****     ** char letteri;
  * ***    * *  char    **
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********* ** *   *  char  *** 
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*    *   **  **   *       * ** input the letter to encode: *   *     * 
* ** *  *** *    * 
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 * *** ***  **    * * * * ** * +3;
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***  *  *   **   ******* +3;
***     *****  
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* **        *  ****** **  *      **   * ** **** ***         *  *    **** 
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 * *  *   *  return 0;
}


INPUT
*  *** ** *** * 
*** * **  ** **
OUTPUT
 *****  *  ******
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**     ** * ** * * **  * 
    **     *  *     

int  ***** argc, char * ** * {
 * * *   *    char **  *
 ****   *   **  * char * * **
**          * char ** **
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***   *   **** *  char     
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* **   *  *    ***** ****  * input the  ****** to    ** * ***    ** *    
 * *  ***  * ***  
    *   ***      * ** ***  ***   *  * **  **    * ** ******  *    ** * *** * * *****  *** ** ***
         ** 
  *      *   *** letter = letter + 3;
 *** * * ** *  * ** =  *   + 3;
*** ***    ** * *  **** = *     + 3;
 ** ** *  *      * * =  **   + 3;
****** *   **   * *** * = ****  + 3;
 ** ****   * * 
* **   ** *  *   * ** ** * **  * **  letter is **    *  **** *     ****  *  **     ** *** *
***  *    * ** 
  *   **   *  * return 0;
}

INPUT
 ** *  **  * * ***
    * *    
***** 
*** ** * *** ** ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **   * **  

int main(int argc, char *argv[]) {
***  ******   * *  **    ***** * * lettera;
 * **** *  * *    ****       letterb;
   ** **    ****  *  * *  letterc;
  *     *  *   ****** **   letterd;
  *   *    ****     **   *  * lettere;
***** *** *** *   * *    **
  *  ** * ***** ***  *       *   *** %c %c %c * ** *   **** **  *     *  * **   * *  ** *  *  *** *** **** *  **  * 
* * * ** *   * ***  *  **  **  = lettera + 3;
*** **   ** **  *** *****  *   * = letterb + 3;
***     * ** *  *    **   ******* = letterc + 3;
***  * *    ***    *  *   * **  * = letterd + 3;
 ***** * ** **  **    ***     ** = lettere + 3;
 * ***** ** *  *  * * **  * * * * **    ***  *     *
***  ** ***   ** ** * **    ****      %c %c %c *  ** *  * * *  letterb, * *  *  *   *  * *
  *  *  *   **     **** *  *
  *    * **  **** * ** *** *    *  ***   * 0;
}

 **  *
*  *
*  **  ****  *
*** ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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