3 like 0 dislike
1k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 1k views

22 Answers

0 like 0 dislike
Hidden content!
* ** * *** ** * ** **

int *** * argc, char * {
***** * ** * * ** */

* **** * *** int number;
* * * * * ** char a;
* **** *** * * *** * * * * * b;
* * * ******* * * * **** c;
******** * ** * ** * d;
** ** * * *** * e;
* * ** * ** ** *
* * ** *** ** * forgert how to shift word ** **** * *** *
*** * ** ** * ** *** ** *** * * *** ** * * ** * * ** ** *
*** * * **
* * ** * * * ** *** the message how??
*** **** *
*** * * * * ** *** ** * * * * * ** * *
* * * *
**** *** *** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* * *** ******
*
* *** * * {

*
= * *
* **
= * * ***
= * * **
* = * *

* = *
* =
** = **
= *

* **
* * **
* ** * *
** **
* * * *
*
**** ** ** * ** *
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include * ** * * ***
#include ** ** * * ****

/* run this program using the console pauser or add your own getch, * **** * *** or input loop */

int main(int argc, char *argv[]) {
** ***** * * * ** * *** * a;
* ** *** ******* ******* * b;
* ** * * *** *** * c;
* * * ******* * ** * ** d;
** **** * *** ** ** e;
* *** *** * **** *
****** ** * * ** * * * * *** the words you want to * * *
* ** ** *** * * ** ***
** ** ** * ** **** * **** = getchar();
** * *** ****** * * = a+3;
** * * * * * *** * *** *
**** * * *** * ** *** = getchar();
* ** * ** ** * * * * = b+3;
**** ** ** ** ** * *** *
** **** * ** * *** = getchar();
* ** ** ** * * * ** *** = c+3;
*** *** *** * * * *** *
* ** * * ** ****** * ** = getchar();
**** ******** ** ** ** * * = d+3;
*** * * **** ***** *** ** * * * **
**** ** * * * ** * * = getchar();
* *** * * * *** ** = e+3;
******** * * ** * * * *
** ** * ** **** ***** * **** *** * ** ** * *****
******* *** ** ** * *** ****** **** ** * &a, &b, &c, &d, * **** *
* ** ** ** * * * **
* ** * * * *** * *** the message how??
* * * ** * ** *
* **** **** * ** * **** ** * * * *** *** a, b, c, d, e);
***** ** * * *** ** **** * *
** * **** * *** * * * * * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* * *** * *
**** * * * *****

int * * * char * * {
/*
*** * * ** */

* ** *

* *** *** * ***** * *** * *** * * * * ** * * * ** * * *
a = a+3;
b = * *
c = *
d = d+3;
e = *

* ** the * * * * *
** ** * *
** ** *** ** *** ******** * * ***

* ** *** * * ****
* *** * * ****** * * * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
** * * *** * * ** * *
* ** * *****

/* run this * *** *** the * * *** or add your own * *** ** *** *** or *** * * */

int *** * char * {
* ** * * * * * int num, * *
*** *** * * **** ** * ***
* * ****
* ** ** ** * ** * ***
** ****** for * * = *** * *** **
{
* * ** * **** ** = ** **
** **** * if * * * ***
*** ** * * **** = ********
* **** ** **** * *
}
** * * * * ** * **** *** * *
* * ***** ** ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
* * ****** ** * *

* * * * * **

* * **** ** * * * * ** * * * * * * ** * * ** * * * ** *
*
** * ** * * *

* ** * * * **

** * * *

* ** ***** * * **** ** * * * ** ** * ** *** **

= *
*
* b +

* = c + **

= d +

* *

* * * ** *** * ** * * **
*
** * *

100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
*** **** * **
** ** *

int * * argc, char *** {
* * ** * ** * char * *
* * **** char ****
* ** ** char ** *
** * ***** char ***
* * * * * char * *
** * * ***
** * *** ** * *** * input the letter to ** *** ****
* ** ** *
** * **** * ** ** ** ** * * * **** * **** * ** ***** * * * * * **
**** **** ** * ** = **** + 3;
** * ** * *** = ** + 3;
** * * * = * + 3;
*** * ** * letterc = ** * + 3;
* ** ** ** = * * * + 3;
* *** **
**** * * * * * ** * *** ****** * ** * * ** ** ** **** * * ** * ***
** ** **
* * *** * *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
**** * ** **** * *
** **** * * ** ** **

int ****** argc, char *argv[]) {
** ** ** * char **** *
*** * char letteri;
* ** * ** ** char * *
** * * **** char **
**** * ** char ** **
** ** *
* *** * * * **** *** input the letter to encode: ** * *
*** **
* * * * ** * * * * * * * * ** * **** ** * ** ** *** * *** * ****** *
* * * ** * * ****** +3;
** * *** * * * * *** +3;
****** * * * * * * +3;
** * * ** * ** * +3;
* ** ** * *** +3;
* ** * **** **
* * ** ** **
* * *** * *** *** * * * * ** ** * ** * * ** ** * * ** **
*** * * **
**** * **** return 0;
}


INPUT
** **** * **
* ** ** *
OUTPUT
* * * * *** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
** * ** * **
* * ** ** ** ***** ***

int * * argc, char ** * {
** ** ** char ****
* * ***** char **
**** * * *** char *
** *** * char *****
**** ** **** char * *
** * ** * **
* * * * ** ** *** * * * input the *** to * * ** * * * ****
** ** * ***
* ** * **** ** * * * *** * * * * ** *** * * * * ** * * * * * ** *
******* * * *
** * *** * * letter = letter + 3;
* * *** * * ** = * + 3;
* * * ** * ** * * * = ** ** + 3;
* * * *** * ***** = * + 3;
** ** * * * ** = *** + 3;
** *** *
* * * * ** * ** * * ** * ** ** *** * letter is * * * * *** * * ** *** *
* * * * *
** ** * ***** return 0;
}

INPUT
** * * * **
**** *** *
* *
* ** ** **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * * * * ****

int main(int argc, char *argv[]) {
* * *** *** * * ** ******* lettera;
** * * * * * * ** * **** letterb;
*** ** ** * * * *** *** letterc;
** * ** ** * * **** * **** letterd;
*** * *** *** *** lettere;
***** ** **** * * ** ****
** ** ** ** ** ** * * ** *** ** * %c %c %c **** **** * * ****** ** * *** ** ** * * *****
* ** * * ** * * **** ** = lettera + 3;
**** * **** * **** ****** = letterb + 3;
******* *** * * * **** = letterc + 3;
*** ** ***** * * * **** ** = letterd + 3;
** **** ** ***** * ** * = lettere + 3;
* * * * * *** ** *** * * * * ** * *
** * * ** * * * ** * * * *** * * * %c %c %c * * ** * letterb, * * * * *** * * **
*** ** * * * *
* *** **** * *** 0;
}

*** *
*
** *** *
* *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.139
©2016-2024

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 169 views
12,783 questions
183,443 answers
172,219 comments
4,824 users